Box Plot for Problem #12​

Answer:1132858

Step-by-step explanation:

The total carbon dioxide the country emit over the course of the 10 year period would be 1,132,858 kilotons.

What is rate of decrease?

The rate of decrease is a constant amount of deduction from a fixed or primary amount.

Here, the carbon dioxide emits by the country per year is 130,000 kilotons.

The rate of decrease of the carbon dioxide emission per year would be 3.1%.

In the 1st year, the carbon dioxide emission = 130,000 kilotons.

In the 2nd year, the carbon dioxide emission = 130,000 × (100-3.1)/ 100 kilotons = 125,970 kilotons.

In the 3rd year, the carbon dioxide emission = 125,970 × (100-3.1)/ 100 kilotons = 122,064.93 kilotons.

In the 4th year, the carbon dioxide emission = 122,064.93 × (100-3.1)/ 100 kilotons = 118,280.92 kilotons.

In the 5th year, the carbon dioxide emission = 118,280.92 × (100-3.1)/ 100 kilotons = 114,614.21 kilotons.

In the 6th year, the carbon dioxide emission = 114,614.21 × (100-3.1)/ 100 kilotons = 111,061.17 kilotons.

In the 7th year, the carbon dioxide emission = 111,061.17 × (100-3.1)/ 100 kilotons = 107,618.27 kilotons.

In the 8th year, the carbon dioxide emission = 107,618.27 × (100-3.1)/ 100 kilotons = 104,282.1 kilotons.

In the 9th year, the carbon dioxide emission = 104,282.1 × (100-3.1)/ 100 kilotons = 101,049.35 kilotons.

In the 10th year, the carbon dioxide emission = 101,049.35 × (100-3.1)/ 100 kilotons = 97,916.82 kilotons.

Hence, total carbon dioxide emission by that country over 10 years = (130,000 + 125,970 + 122,064.93 + 118,280.92 + 114,614.21 + 111,061.17 + 107,618.27 + 104,282.1 + 101,049.35 + 97,916.82) kilotons = 1,132,857.77 kilotons ≈ 1,132,858 kilotons.

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Answer:

a) The total engine volume is 30.3265 in³

b) the mass of air contained in the engine is 0.00129 lbm

c) The efficiency of the engine is 55.6%

Step-by-step explanation:

Given the data in the question;

The configuration is in line with four-stroke, four-cylinder engine.

Bore ( d ) = 3.17 in

Stroke ( L ) = 3.48 in

compression ratio ( r ) = 10.6 : 1

First, we calculate the swept Volume V₁ = π/4 × d²L

we substitute

V₁ = π/4 × (3.17 )² × (3.48) = 27.4655 in³

Now, Compression Ration; r = Vs + Vc / Vc

r = (V₁ + V₂) / V₂

we substitute

10.6 = (27.4655 + V₂) / V₂

10.6V₂ = 27.4655 + V₂

10.6V₂ - V₂ = 27.4655

9.6V₂ = 27.4655

V₂ = 2.861 in³

So

a) total engine volume

[tex]V_{BDC[/tex] = V₁ + V₂

we substitute

[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³

[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³

[tex]V_{BDC[/tex] = 30.3265 in³

Therefore, The total engine volume is 30.3265 in³

b) The mass of air

given that; T = 540°R, P = 14.7 psia

we know that; PV = mRT   { R is constant }

we solve for m

m = PV / RT

we substitute

m = (14.7 × 30.3265)  / ( 0.3704 × 1728 )540

m = 445.79955 / 345627.648

m = 0.00129 lbm

Therefore, the mass of air contained in the engine is 0.00129 lbm

c) The efficiency

from table { properties of air}

At 540°R; u₁ = 92.04 BTu/lbm, u[tex]_r[/tex]₁ = 144.32

Now process 1 - 2 ( Isentropic )   u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂  = V₁/V₁ = r

so,  u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂ = r

144.32  / u[tex]_r[/tex]₂ = 10.6

u[tex]_r[/tex]₂ = 144.32/10.6

u[tex]_r[/tex]₂ = 13.61

Thus, at u[tex]_r[/tex]₂ = 13.61, u₂ = 235 BTU/lbm, T₂ = 1340°R

Now, we know that;

P₁V₁/T₁ = P₂V₂/T₂  ⇒ (P₁/V₁)r = P₂/T₂

⇒ ( 14.7 / 540 )10.6 = P₂/1340

P₂ = 386.664 psia  

process 2 - 3; constant volume heat addition;

Now, At T₃ = 3600°R, u₃ = 721.44 BTU/lbm, u[tex]_r[/tex]₃ = 0.6449

so, [tex]q_{in[/tex] =  u₃ -  u₂

we substitute

so, [tex]q_{in[/tex] =  721.44  -  235  = 486.44 BTU/lbm

Next, process 3 - 4; Isentropic  

u[tex]_r[/tex]₄/u[tex]_r[/tex]₃ = V₄/V₃ = r

u[tex]_r[/tex]₄ / 0.6449  = 10.6

u[tex]_r[/tex]₄ = 6.8359

At u[tex]_r[/tex]₄ = 6.8359; u₄ = 308 BTU/lbm

∴

Heat Rejection [tex]q_{out[/tex] = u₄ - u₁ = 308 - 92.04 = 215.96 BTU/lbm

so, [tex]W_{net[/tex] = [tex]q_{in[/tex] - [tex]q_{out[/tex]

[tex]W_{net[/tex] = 486.44 - 215.96

[tex]W_{net[/tex] = 270.48 BTU/lbm

so the efficiency; η[tex]_{thermal[/tex] = ([tex]W_{net[/tex] / [tex]q_{in[/tex] ) × 100%

η[tex]_{thermal[/tex] = ( 270.48 / 486.44  ) × 100%

η[tex]_{thermal[/tex] = ( 0.55604  ) × 100%    

η[tex]_{thermal[/tex] = 55.6%

Therefore, The efficiency of the engine is 55.6%

Answer: Midpoint: (2, 1)

Step-by-step explanation:

Midpoint formula: ((x1 + x2)/2 , (y1 + y2)/2)

(-4 + 8)/2 = 2

(-8 + 10)/2 = 1

Answer: (2, 1)

Answer:

tan theta = 8/15

Step-by-step explanation:

Sin is equal to opposite over hypotenuse. So it means that the side opposite from theta is 8, and the hypotenuse is 17.

To find the value of the adjacent side from theta, use the Pythagorean Theorem.

a^2 + b^2 = c^2

8^2 + b^2 = 17^2

64 + b^2 = 289

Subtract 64.

b^2 = 225

Take the square root.

b = 15.

So that means:

the side opposite from theta is 8,

the side adjacent from theta is 15,

the hypotenuse is 17.

Now we take tan, opposite over adjacent, and use the values from the triangle.

tan = opposite / adjacent

tan = 8/15.

Answer:

Part a:

Since the calculated z= 8.1649 falls in the critical region  z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.

Part b:

P (Type II Error)=  0.6628

Step-by-step explanation:

The null and alternate hypothesis are

H0: μ1 ≥ μ2   against the claim Ha: μ1 < μ2

This is left tailed test

The critical region for this test at 0.10 ∝ is z < ± 1.28

The test statistic

z= x1-x2/ s/√n

z= 66-61/ 3/√24

z= 5/0.61238

z= 8.16486

Since the calculated z= 8.1649 falls in the critical region  z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.

Part b:

P (Type II Error)  = P ( accept H0/ H0 is false)

z ( ∝)= X-u/s/√n

1.28= X-61/0.61238

X= 61.7838

So I will incorrectly fail to reject the null as long as a draw a sample mean that greater than 61.7838

 The probability of a Type II error is given by

P (z> 61.7838-66/24)

P (z>- 0.42161)

From the tables

P (z>- 0.42161)=  0.6628

Answer:

±6

Step-by-step explanation:

Given the mathematical expression;

√36 < √42 < √49

But, √36 = 6 * 6 = 6²

√49 = 7 * 7 = 7²

Simplifying further, we would substitute the new values respectively;

±[6] < √42 < ±[7]

Therefore, evaluating √36 is equal to ±6.

Ok send the picture so I can help you.

Answer:

what is the question? I can help

Step-by-step explanation:

Answer:

Step-by-step explanation: $5.40 + $0.54 now equals $5.94

Answer:

The wright answer is A

Step-by-step explanation:

[tex] \sqrt{20} = 4.47 \\ \frac{14}{3} = 4.67 \\ 4.47 < 4.5 < 4.67[/tex]

Answer:

no. who eat lunch special = 12

no. who eat dessert = 6

Step-by-step explanation:

Let x = no. who eat lunch special

y = no. who eat dessert

(1)    8x + 2y = 108             (2)    6x + 3y = 90

 Divide thru by 2                         Divide thru by 3

      4x + y = 54                          2x + y = 30

     -2x - y = -30

       2x = 24

         x = 12                               2(12) + y = 30

                                                    24 + y = 30

                                                            y = 6

Answer: 27

Step-by-step explanation:

Answer:

t

Step-by-step explanation:

A circle can be circumscribed about the given quadrilateral, the answer is: A. True.

We know that,

To circumscribe a circle about a quadrilateral means to place the quadrilateral inside the circle, such that the four vertices of the quadrilateral touches the circumference of the circle.

Opposite angles of a circumscribed polygon are supplementary.

Therefore, a circle can be circumscribed about the given quadrilateral, the answer is: A. True.

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Answer:

[tex]Period = \pi[/tex]

Step-by-step explanation:

Given

[tex]y = -\frac{1}{3} * \sin(2x)[/tex]

Required

The period

A sine function is represented as:

[tex]y =A \sin(Bx + C) + D[/tex]

Where

[tex]Period = \frac{2\pi}{B}[/tex]

By comparing:

[tex]y =A \sin(Bx + C) + D[/tex] and [tex]y = -\frac{1}{3} * \sin(2x)[/tex]

[tex]B = 2[/tex]

So, we have:

[tex]Period = \frac{2\pi}{2}[/tex]

[tex]Period = \pi[/tex]

Hence, the period of the function is [tex]\pi[/tex]

Answer:

95°

Step-by-step explanation:

95°

They are vertical angles.

Answer:

95 degree write it fast jakakkaoaoa

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

C. 4.

Answer:

the answer is A.

Step-by-step explanation:

Answer:

x5

Step-by-step explanation:

Answer: C.

Step-by-step explanation:

EDGE 2023

Answer:

Option B and D are correct

Step-by-step explanation:

Exponential functions are really useful in the real world situation. They can be used to solve following

a) Population Models

b) Determination of area and perimeters

c) Determine time related things such as half life, time of happening of an event etc.

d) Useful for solving financial problems such as computing investments etc.

Hence, option B and D

Answer:

B

Step-by-step explanation:

The median is the middle value of the data arranged in ascending order. If there is no exact middle value then it is the average of the values either side of the middle.

1,  3,  6,  8,  9,  9

           ↑ middle

median = [tex]\frac{6+8}{2}[/tex] = [tex]\frac{14}{2}[/tex] = 7 → B

Answer:

B. 7

Step-by-step explanation:

(6 + 8) ÷ 2 = 7

I hope this is right if its not im sorry

Answer: B. 183 cm^3

V = pi r^2 h/3

V = pi (5^2) (7/3)

V = pi (25) (2.33)

V = 183

Answer:

B.183 [tex]cm^{3}[/tex]

Step-by-step explanation:

Volume of cone is [tex]V=\pi r^{2} \frac{h}{3}[/tex]

where h=7 and r=5 (because r=d/2, where d=10)

V=[tex]5^{2}\frac{7}{3}\pi[/tex]

V=25·[tex]\frac{7}{3} \pi[/tex]

V=175/3[tex]\pi[/tex]

V=183.2595715 or 183 [tex]cm^{3}[/tex]

Answer:

There are 20 odd numbers between 10 and 50

Step-by-step explanation:

Here are all the odd numbers! Hope this helps!

11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49

Answer:

Answer:

[tex]sec 0=\frac{\sqrt{66} }{8}[/tex]

Step-by-step explanation:

[tex]Cot0=-4\sqrt{2}[/tex]

[tex]sec0=\frac{\sqrt{33} }{4\sqrt{2} }[/tex]

[tex]=\frac{\sqrt{33} }{4\sqrt{4} } *\frac{4\sqrt{2} }{4\sqrt{2} }[/tex]

[tex]=\frac{4\sqrt{66} }{32}[/tex]

[tex]=\frac{\sqrt{66} }{8}[/tex]

--------------------

hope it helps...

have a great day!!

You can fill the 10 gallon pail all the way up. After that, you can pour the water from the 10 gallon pail, into the 4 gallon pail 2 times. That will leave you with 2 gallons in the 10 gallon pail.

Cross multiply:

4 x 6 = 9x

24 = 9x

Divide both sides by 9

X = 24/9

X = 2.7 ( rounded to the nearest tenth)