A mathematics teacher wanted to see the correlation between test scores and homework. The homework grade (x) and test grade (y) are given in the accompanying table. Write the linear regression equation that represents this set of data, rounding all coefficients to the nearest tenth. Using this equation, find the projected test grade, to the nearest integer, for a student with a homework grade of 34.

SOMEONE HELP ME WITH THIS RIGHT NOW. please

Answer:

B

Step-by-step explanation:

To find f(- 2) substitute x = - 2 into f(x)

f(- 2) = - 2(- 2)³ + (- 2)² + 4(- 2) - 3

        = - 2(- 8) + 4 - 8 - 3

        = 16 + 4 - 8 - 3

        = 9 → B

Answer:

B

Step-by-step explanation:

√((-20)²+21²)=√(400+441)=√841=29

cos θ=-20/29

sec θ=-29/20

[tex]5[/tex] ✅

Step-by-step explanation:

[tex]14 + {6}^{2} \div ( - 4) \\ \\ \: = 14 + \frac{6 \times 6}{ - 4} \\ \\ \: = 14 - \frac{36}{4} \: \\ \\ = 14 - 9 \\\\ \: = 5[/tex]

Note:-

[tex]\sf\purple{BODMAS\: rule.}[/tex]

B = Brackets

O = Orders

D = Division

M = Multiplication

A = Addition

S = Subtraction

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]

Answer:

12.5

Step-by-step explanation:

14+6²÷(-4)

=14+6×6÷(-4)

=14+36÷(-4)

=50÷-4

=12.5

Answer:

13680

Step-by-step explanation:

Since we have number from 0 to 39 inclusive, there are 40 number all together.

Now there are 20 odd numbers and 20 even numbers since half of the the numbers are odd and half even.

Now, since we require 3 numbers for our locker combination which are either all even or all odd, the number of ways we can arrange 3 numbers from 20 when the order matters is ²⁰P₃ = 6480 ways for either odd or even numbers. So, for both odd and even numbers, we have the sum of even and odd number of ways ²⁰P₃ + ²⁰P₃ = 2 × ²⁰P₃ = 2 × 6480 = 13680. So, we have 13680 combinations of locks.

Answer: -7

Step-by-step explanation:

Well since where going below degrees the answer would be -7 because it is closer to 1

Given:

Toilet rolls com in packs of 4 and 9.

4-pack is priced at £2.04.

9-pack is priced at £4.68.

To find:

The pack that has better value by calculating the price per roll.

Solution:

We have, the 4-pack is priced at £2.04.

So, the price per roll for this pack is:

[tex]\dfrac{2.04}{4}=0.51[/tex]

In the pack of 4 rolls the price per roll is £0.51.

It is given that, the 9-pack is priced at £4.68.

So, the price per roll for this pack is:

[tex]\dfrac{4.68}{9}=0.52[/tex]

In the pack of 9 rolls the price per roll is £0.52.

Since the price per roll in the pack of 4 rolls is less that the price per roll in the pack of 9 rolls because 0.51 < 0.52, therefore the pack of 4 rolls has better value.

SOH = Sine Opposite Hypotenus

CAH = Cosine Adjacent Hypotenus

TOA = Tangent Opposite Adjacent

Based on the key I wrote above, TOA is what you will use. Starting from angle Z look at the opposite side and adjacent side. (Opposite = 21 and Adjacent = 20) Make sure you're not looking at the hypotenus which is the side that is always across from the 90° angle.

Going by opposite over adjacent, that would be 21/20

The answer is the first choice 21/20

Answer:

Cantidad de aprobados= 25

Step-by-step explanation:

Dada la siguiente información:

Reproado= 45%

Aprobado= 55%

Cantidad de alumnos= 45 alumnos

Para calcular la cantidad de aprobados, debemos utiliar la siguiente formula:

Cantidad de aprobados= cantidad de alumnos*porcentaje aprobados

Cantidad de aprobados= 45*0.55

Cantidad de aprobados= 25

Answer:

Step-by-step explanation:

[tex]\sf 5(x - 10) = 30 - 15x[/tex]

[tex]\sf 5x-50=30-15x[/tex]

[tex]\sf 5x-50+50=30-15x+50[/tex]

[tex]\sf 5x=-15x+80[/tex]

[tex]\sf 5x+15x=-15x+80+15x[/tex]

[tex]\sf 20x=80[/tex]

[tex]\sf \frac{20x}{20}=\frac{80}{20}[/tex]

[tex]\sf x=4[/tex]

Answer:

m<UVW = 156°

Step-by-step explanation:

Given:

m<PVW = 130°

m<UVP = 26°

Required:

m<UVW

Solution:

m<UVP + m<PVW = m<UVW (Angle Addition Postulate)

Substitute in the given values

26° + 130° = m<UVW

156° = m<UVW

m<UVW = 156°

Answer:

Step-by-step explanation:

Hope this helps u !!

The LCM of 2a(4a² + 10a + 13)(4a² + 13 - 10a).

Least Common Multiple, often known as the Lowest Common Multiple, is denoted by the acronym LCM. The lowest number that may be divided by both numbers is known as the least common multiple (LCM) of two numbers. It can also be computed using two or more numbers.

The smallest number among all the common multiples of the provided numbers is the least common multiple of two or more numbers.

We have,

16[tex]a^4[/tex] + 4a² + 169 and 8a³ +2a(2a + 13) + 16a²

First, 16[tex]a^4[/tex] + 4a² + 169

= (4a²)² + (2a)² + (13)²

= (4a²)² + 2 . 4a² . 13 + (13)² + 4a² + 104a²

= (4a² + 13)² - (10a)²

= (4a + 13 - 10a) (4a + 13 + 10a)

= (13 - 6a)(13 + 14a)

Second, 8a³ +2a(2a + 13) + 16a²

= 8a³ + 4a² + 26a + 16a²

= 8a³ + 20a² + 26a

= 2a(4a² + 10a + 13)

So, the LCM is

= 2a(4a² + 10a + 13)(4a² + 13 - 10a)

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Answer:

18.9 km²

Step-by-step explanation:

Formula for area of a triangle: [tex]\frac{1}{2}bh[/tex]

0.5(7 × 5.4) = 18.9 km²

Answer:

A = 1/2 bh

1/2 x 7 x 5.4

= 18.9km2

Answer:

The expanded form of 6,398 is 6000 + 300 + 90 + 8

Answer:

Step-by-step explanation:

The center of the circle is the midpoint of the two end points of the diameter.

Formula

Center = (x2 + x1)/2 , (y2 + y1)/2

Givens

x2 = 4

x1 = - 10

y2 = 6

y1 = - 2

Solution

Center = (4 - 10)/2, (6 - 2)/2

Center = -6/2 , 4/2

Center = - 3 , 2

So far what you have is

(x+3)^2 + (y - 2)^2 = r^2

Now you have to find the radius.

You can use either of the endpoints to find the radius.

find the distance from (4,6) to (-3,2)

r^2 = ( (x2 - x1)^2 + (y2 - y1)^2 )

x2 = 4

x1 = -3

y2 = 6

y1 = 2

r^2 = ( (4 - -3)^2 + (6 - 2)^2 )

r^2 = ( (7)^2 + 4^2)

r^2 = ( 49 + 16)

r^2 = 65

Ultimate formula is

(x+3)^2 + (y - 2)^2 = 65

The radius is √65 = 8.06

Answer:

Al cabo de una semana, 2187 personas han participado en la cadena, y al cabo del quinto día se habrán donado $1215000.

Step-by-step explanation:

Dado que tres hermanas deciden comenzar una cadena, donando cada una a tres personas $5.000 en un mismo día; con la condición que a quienes ellas ayuden también deberán hacer lo mismo con tres personas al día siguiente, para determinar, al cabo de una semana, cuántas personas han participado en la cadena, y finalizado el quinto día cuánto dinero se ha donado, se deben realizar los siguientes cálculos:

3^7 = X

2,187 = X

(3^5) x 5000 = X

243 x 5000 = X

1,215,000 = X

Por lo tanto, al cabo de una semana, 2187 personas han participado en la cadena, y al cabo del quinto día se habrán donado $1215000.

Answer:

Step-by-step explanation:

Two similar triangles have a scale factor of 2 : 3.

7a. The ratio of their perimeters is 2 : 3.

As the sides are 2 : 3, the perimeters which are sums of all sides will also be 2 : 3

True

7b. The ratio of their areas is 4 : 6. True or False

As the sides are 2 : 3, the areas which are the products of two sides will be in the ratio of 2*2 : 3*3 = 4 : 9

False

7c. Their perimeters could be 14 cm and 21 cm. True or False

As the perimeter ratio for 14cm and 21 cm is 14 : 21 = 2 : 3 which complies with 7a. So they could be the perimeters.

True

7d. Two corresponding sides could be 6 in and 7 in. True or False

As the corresponding sides of 6in and 7in, the ratio is 6 : 7 and is different from 2 : 3.  So they cannot be corresponding sides.

False

Answer:

Step-by-step explanation:

7a. perimeter=3 sides added so the ratio is the same

The ratio of their perimeters is 2 : 3.

True

7b. area= sidexside so the ratio is 2x2:3x3 = 4:9

The ratio of their areas is 4 : 6.

False

7c. 14:21 =2:3

Their perimeters could be 14 cm and 21 cm.

True

7d. 6:7 <> 2:3

Two corresponding sides could be 6 in and 7 in.

False

Answer:

x=ln 24

Step-by-step explanation:

e^x=24

If we take the ln of both sides

ln e ^x= ln 24

x=ln 24

A polygon is a planar figure characterised by a limited number of straight-line segments joined to create a closed polygonal chain in geometry. The given statement is True.

A polygon is a planar figure characterised by a limited number of straight-line segments joined to create a closed polygonal chain in geometry. A polygon is defined as a bounded planar region, a bounding circuit, or both.

The given statement is true and can be observed in the given image below.

Hence, the given statement is True.

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Step-by-step explanation:

answer is in picture see

hope it helpful

Answer:

(7,7)

is not solution of following point

Answer:

Line m

Step-by-step explanation:

The line is labeled with an m.

Answer:I hope this could help !ut the answer is 4

Step-by-step explanation:

2 of them left so there are 4 left

Answer: [tex]1.663\times 10^{30}\ gm[/tex]

Step-by-step explanation:

Given

Population of dust particle doubles every 30 minutes

If the initial sample is 21 grams

The model to predict the population will be

[tex]\Rightarrow P=21\cdot 2^{2t}[/tex]

Where t=time in hours

A day has 24 hours . So, for 2 days time is 48 hours

Population is given by

[tex]\Rightarrow P=21\cdot 2^{2\times 48}\\\\\Rightarrow P=21\times 2^{96}\\\\\Rightarrow P=1.663\times 10^{30}\ gm[/tex]

Answer:

[tex]P(New\ House) = \frac{1}{6}[/tex]

Step-by-step explanation:

Given

See attachment

Required

[tex]P(New\ House)[/tex]

This is calculated as:

[tex]P(New\ House) = \frac{New\ House}{Total}[/tex]

From the attachment, we have:

[tex]New\ House = 60^o[/tex]

[tex]{Total}= 360^o[/tex] --- total angle in a pie chart

Note that the measurements must be converted to degrees (if not already in degrees).

So, we have:

[tex]P(New\ House) = \frac{60}{360}[/tex]

Simplify

[tex]P(New\ House) = \frac{1}{6}[/tex]

Answer:

$10,667.66

Step-by-step explanation:

The formula for calculating the compound interest is expressed as:

A = P(1+r/n)^nt

P is the principal = $9000

r is the rate = 3%

time t = 6years

n = 1/4

Substitute

A = 9000(1+0.03/(1/4))^6/4

A = 9000(1+0.03(4))^1.5

A = 9000(1+0.12)^1.5

A = 9000(1.12)^1.5

A = 9000(1.1853)

A = 10,667.67

Hence the amount after 6 years is $10,667.66

Answer:

In picture

Step-by-step explanation:

Brainliest please

As both the angles are linear, their sum is equal to 180°

i.e m<EFG+m<GFH = 180

=>( 2n+17 )+(4n+37) = 180

=> 6n + 54 = 180

=> 6n = 180-54

=>6n =126

=> n= 21

m<EFG = 2(21)+17 = 59°

m<GFH =4(21)+37 =121°

Given: ∠EFG and ∠GFH are a linear pair

We know that: Sum of the angles which make a linear pair should be equal to 180°

⇒  ∠EFG + ∠GFH = 180°

Given :

∠EFG = 2n + 17

∠GFH = 4n + 37

⇒  2n + 17 + 4n + 37 = 180°

⇒  6n + 54 = 180°

⇒  6n = 180 - 54

⇒  6n = 126

⇒  n = 21°

Substituting the value of n in ∠EFG and ∠GFH, We get:

⇒  ∠EFG = 2(21) + 17 = (42 + 17) = 59°

⇒  ∠GFH = 4(21) + 37 = (84 + 37) = 121°