Find the circumference of a circle with a diameter of 50 centimeters. Round your answer to the nearest
centimeter.

Answer:

86°

Step-by-step explanation:

180° is the sum of all angles in a triangle

The two angles given are 68° and 26°

The equation is : 180° - 68° - 26° = x°

180° - 68° - 26° = 86°

x° = 86°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

standard deviation

Step-by-step explanation:

Answer:

Orange

Step-by-step explanation:

As the chance of choosing orange is 18% which is the least.

Answer:

2）=2

4）=3

5）=5

8）=-1

Step-by-step explanation:

just divide the number by the number with variable

Answer:

(2k, k)

Step-by-step explanation:

x + y = 3k

x - y = k

Add the equations.

2x = 4k

x = 2k

2k + y = 3k

y = k

Answer: (2k, k)

Answer:

6.8

Step-by-step explanation:

The number is already rounded to the nearest tenth and hundredth.

here you go it's too easy

Step-by-step explanation:

Explanation is in the attachment .

Hope it is helpful to you ❣️☪️❇️

Answer:

1.5%

Step-by-step explanation:

house value x property tax rate = property taxes

70,000 x property tax rate = 1050

property tax rate = 1050/70000

property tax rate = .015 0r 1.5%

Answer:

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

Step-by-step explanation:

Given the data :

35, 26, 31, 17, 46, 30, 28, 21, 26, 34, 15, 27, 7, 18, 16, 57

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

The next to highest frequency group has a frequency of 4 and the highest frequency of 6

Total frequency, n = (1 + 4 + 6 + 3 + 1 + 1) = 16

Answer:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

( − ∞ , ∞ )

Set-Builder Notation:

{ x | x ∈ R }

Step-by-step explanation:

hope that helps bigger terms

Answer:

Yes, it is appropriate

Step-by-step explanation:

Given

See attachment for pie chart

Required

Is the pie chart appropriate

The attached pie chart displays the distribution of each of the 4 genre. The partition occupied represents the measure of each genre.

Answer:

12 x sin(85)

12x 0.99619

155.40

Solution:

12 x sin (85) = 11.95 (Since sin85 is 0.996194)

So, the answer is 11.95.

Answer:

[tex]\frac{a}{c}[/tex] = [tex]\frac{3}{20}[/tex]

Step-by-step explanation:

[tex]\frac{a}{c}[/tex] = [tex]\frac{a}{b}[/tex] × [tex]\frac{b}{c}[/tex] = [tex]\frac{2}{5}[/tex] × [tex]\frac{3}{8}[/tex] = [tex]\frac{6}{40}[/tex] = [tex]\frac{3}{20}[/tex]

Answer:

[tex]\sigma = 1.8[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4}& {5} \ \\ P(x) & {0.2} & {0.1} & {0.1} & {0.2} & {0.2}& {0.2} \ \end{array}[/tex]

Required

The standard deviation

First, calculate the expected value E(x)

[tex]E(x) = \sum x * P(x)[/tex]

So, we have:

[tex]E(x) = 0 * 0.2 + 1 * 0.1 + 2 * 0.1 + 3 * 0.2 + 4 * 0.2 + 5 * 0.2[/tex]

[tex]E(x) = 2.7[/tex]

Next, calculate E(x^2)

[tex]E(x^2) = \sum x^2 * P(x)[/tex]

So, we have:

[tex]E(x^2) = 0^2 * 0.2 + 1^2 * 0.1 + 2^2 * 0.1 + 3^2 * 0.2 + 4^2 * 0.2 + 5^2 * 0.2[/tex]

[tex]E(x^2) = 10.5[/tex]

The standard deviation is:

[tex]\sigma = \sqrt{E(x^2) - (E(x))^2}[/tex]

[tex]\sigma = \sqrt{10.5 - 2.7^2}[/tex]

[tex]\sigma = \sqrt{10.5 - 7.29}[/tex]

[tex]\sigma = \sqrt{3.21}[/tex]

[tex]\sigma = 1.8[/tex] --- approximated

For now, I'll focus on the figure in the bottom left.

Mark the point E at the base of the dashed line. So point E is on segment AB.

If you apply the pythagorean theorem for triangle ABC, you'll find that the hypotenuse is

a^2+b^2 = c^2

c = sqrt(a^2+b^2)

c = sqrt((8.4)^2+(8.4)^2)

c = 11.879393923934

which is approximate. Squaring both sides gets us to

c^2 = 141.12

So we know that AB = 11.879393923934 approximately which leads to (AB)^2 = 141.12

------------------------------------

Now focus on triangle CEB. This is a right triangle with legs CE and EB, and hypotenuse CB.

EB is half that of AB, so EB is roughly AB/2 = (11.879393923934)/2 = 5.939696961967 units long. This squares to 35.28

In short, (EB)^2 = 35.28 exactly. Also, (CB)^2 = (8.4)^2 = 70.56

Applying another round of pythagorean theorem gets us

a^2+b^2 = c^2

b = sqrt(c^2 - a^2)

CE = sqrt( (CB)^2 - (EB)^2 )

CE = sqrt( 70.56 - 35.28 )

CE = 5.939696961967

It turns out that CE and EB are the same length, ie triangle CEB is isosceles. This is because triangle ABC isosceles as well.

Notice how CB = CE*sqrt(2) and how CB = EB*sqrt(2)

------------------------------------

Now let's focus on triangle CED

We just found that CE = 5.939696961967 is one of the legs. We know that CD = 8.4 based on what the diagram says.

We'll use the pythagorean theorem once more

c = sqrt(a^2 + b^2)

ED = sqrt( (CE)^2 + (CD)^2 )

ED = sqrt( 35.28 + 70.56 )

ED = 10.2878569196893

This rounds to 10.3 when rounding to one decimal place (aka nearest tenth).

==============================================================

Now I'm moving onto the figure in the bottom right corner.

Draw a segment connecting B to D. Focus on triangle BCD.

We have the two legs BC = 3.7 and CD = 3.7, and we need to find the length of the hypotenuse BD.

Like before, we'll turn to the pythagorean theorem.

a^2 + b^2 = c^2

c = sqrt( a^2 + b^2 )

BD = sqrt( (BC)^2 + (CD)^2 )

BD = sqrt( (3.7)^2 + (3.7)^2 )

BD = 5.23259018078046

Which is approximate. If we squared both sides, then we would get (BD)^2 = 27.38 which will be useful in the next round of pythagorean theorem as discussed below. This time however, we'll focus on triangle BDE

a^2 + b^2 = c^2

b = sqrt( c^2 - a^2 )

ED = sqrt( (EB)^2 - (BD)^2 )

x = sqrt( (5.9)^2 - (5.23259018078046)^2 )

x = sqrt( 34.81 - 27.38 )

x = sqrt( 7.43 )

x = 2.7258026340878

x = 2.7

--------------------------

As an alternative, we could use the 3D version of the pythagorean theorem (similar to what you did in the first problem in the upper left corner)

The 3D version of the pythagorean theorem is

a^2 + b^2 + c^2 = d^2

where a,b,c are the sides of the 3D block and d is the length of the diagonal. In this case, a = 3.7, b = 3.7, c = x, d = 5.9

So we get the following

a^2 + b^2 + c^2 = d^2

c = sqrt( d^2 - a^2 - b^2 )

x = sqrt( (5.9)^2 - (3.7)^2 - (3.7)^2 )

x = 2.7258026340878

x = 2.7

Either way, we get the same result as before. While this method is shorter, I think it's not as convincing to see why it works compared to breaking it down as done in the previous section.

Answer:

Qu 2    =  10.3 cm

Qu 3.   = 2.7cm

Step-by-step explanation:

Qu 2. Shape corner of a cube

We naturally look at sides for slant, but with corner f cubes we also need the base of x and same answer is found as it is the same multiple of 8.4^2+8/4^2 for hypotenuse.

8.4 ^2 + 8.4^2 = sq rt 141.42 = 11.8920141 = 11.9cm

BD = AB =  11.9 cm  Base of cube.

To find height x we split into right angles

formula slant (base/2 )^2 x slope^2  = 11.8920141^2 - 5.94600705^2 =  sq rt 106.065

= 10.2987863

height therefore is x = 10.3 cm

EB = 5.9cm

BC = 3.7cm

CE^2  = 5.9^2 - 3.7^2  = sqrt 21.12 = 4.59565012 = 4.6cm

2nd triangle ED = EC- CD

= 4.59565012^2- 3.7^2 = sq rt 7.43000003 =2.72580264

ED = 2.7cm

x = 2.7cm

Answer:

[tex](a)\ m = \frac{4}{3}[/tex] --- slope of OA

[tex](b)\ y = \frac{4}{3}x[/tex] --- the equation

Step-by-step explanation:

Given

The attached graph

Solving (a): Slope of OA

First, we identify two points on OA

[tex](x_1,y_1) = (0,0)[/tex]

[tex](x_2,y_2) = (3,4)[/tex]

So, the slope (m) is:

[tex]m = \frac{y_2 -y_1}{x_2 - x_1}[/tex]

This gives:

[tex]m = \frac{4-0}{3-0}[/tex]

[tex]m = \frac{4}{3}[/tex]

Solving (b): The equation

This is calculated as:

[tex]y = m(x - x_1) + y_1[/tex]

Recall that:

[tex](x_1,y_1) = (0,0)[/tex]

[tex]m = \frac{4}{3}[/tex]

So, we have:

[tex]y = \frac{4}{3}(x - 0) + 0[/tex]

[tex]y = \frac{4}{3}(x)[/tex]

[tex]y = \frac{4}{3}x[/tex]

Answer: (-1, 2)

Step-by-step explanation:

It's a counter-clockwise rotation, that means (x, y) changes to (y, -x).

(-2, -1) ⇒ (-1, -(-2)) ⇒ (-1, 2)

If it's a clockwise rotation, then (x, y) will change to (-y, x)

(-2, -1) ⇒ (-(-1), -2) ⇒ (1, -2)

Answer:

m=5

n=-3

Step-by-step explanation:

3m+2m=9

3m-3n=24

3(5)+2(-3)=9

15-6=9 correct

Answer:

The remainder is 3x - 4

Step-by-step explanation:

[Remember] [tex]\frac{Dividend}{Divisor} = Quotient + \frac{Remainder}{Divisor}[/tex]

So, [tex]Dividend = (Quotient)(Divisor) + Remainder[/tex]

In this case our dividend is always P(x).

Part 1

When the divisor is [tex](x - 1)[/tex], the remainder is [tex]4[/tex], so we can say [tex]P(x) = (Quotient)(x - 1) + 4[/tex]

In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x - 1) = 0[/tex]

When solving for [tex]x[/tex], we get

[tex]x - 1 = 0\\x - 1 + 1 = 0 + 1\\x = 1[/tex]

When [tex]x = 1[/tex],

[tex]P(x) = (Quotient)(x - 1) + 4\\P(1) = (Quotient)(1 - 1) + 4\\P(1) = (Quotient)(0) + 4\\P(1) = 0 + 4\\P(1) = 4[/tex]

--------------------------------------------------------------------------------------------------------------

Part 2

When the divisor is [tex](x + 3)[/tex], the remainder is [tex]104[/tex], so we can say [tex]P(x) = (Quotient)(x + 3) + 104[/tex]

In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x + 3) = 0[/tex]

When solving for [tex]x[/tex], we get

[tex]x + 3 = 0\\x + 3 - 3 = 0 - 3\\x = -3[/tex]

When [tex]x = -3[/tex],

[tex]P(x) = (Quotient)(x + 3) + 104\\P(-3) = (Quotient)(-3 + 3) + 104\\P(-3) = (Quotient)(0) + 104\\P(-3) = 0 + 104\\P(-3) = 104[/tex]

--------------------------------------------------------------------------------------------------------------

Part 3

When the divisor is [tex](x^2 - x + 1)[/tex], the quotient is [tex](x^2 + x + 3)[/tex], and the remainder is [tex](ax + b)[/tex], so we can say [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

From Part 1, we know that [tex]P(1) = 4[/tex] , so we can substitute [tex]x = 1[/tex] and [tex]P(x) = 4[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

When we do, we get:

[tex]4 = (1^2 + 1 + 3)(1^2 - 1 + 1) + a(1) + b\\4 = (1 + 1 + 3)(1 - 1 + 1) + a + b\\4 = (5)(1) + a + b\\4 = 5 + a + b\\4 - 5 = 5 - 5 + a + b\\-1 = a + b\\a + b = -1[/tex]

We will call [tex]a + b = -1[/tex] equation 1

From Part 2, we know that [tex]P(-3) = 104[/tex], so we can substitute [tex]x = -3[/tex] and [tex]P(x) = 104[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

When we do, we get:

[tex]104 = ((-3)^2 + (-3) + 3)((-3)^2 - (-3) + 1) + a(-3) + b\\104 = (9 - 3 + 3)(9 + 3 + 1) - 3a + b\\104 = (9)(13) - 3a + b\\104 = 117 - 3a + b\\104 - 117 = 117 - 117 - 3a + b\\-13 = -3a + b\\(-13)(-1) = (-3a + b)(-1)\\13 = 3a - b\\3a - b = 13[/tex]

We will call [tex]3a - b = 13[/tex] equation 2

Now we can create a system of equations using equation 1 and equation 2

[tex]\left \{ {{a + b = -1} \atop {3a - b = 13}} \right.[/tex]

By adding both equations' right-hand sides together and both equations' left-hand sides together, we can eliminate [tex]b[/tex] and solve for [tex]a[/tex]

So equation 1 + equation 2:

[tex](a + b) + (3a - b) = -1 + 13\\a + b + 3a - b = -1 + 13\\a + 3a + b - b = -1 + 13\\4a = 12\\a = 3[/tex]

Now we can substitute [tex]a = 3[/tex] into either one of the equations, however, since equation 1 has less operations to deal with, we will use equation 1.

So substituting [tex]a = 3[/tex] into equation 1:

[tex]3 + b = -1\\3 - 3 + b = -1 - 3\\b = -4[/tex]

Now that we have both of the values for [tex]a[/tex] and [tex]b[/tex], we can substitute them into the expression for the remainder.

So substituting [tex]a = 3[/tex] and [tex]b = -4[/tex] into [tex]ax + b[/tex]:

[tex]ax + b\\= (3)x + (-4)\\= 3x - 4[/tex]

Therefore, the remainder is [tex]3x - 4[/tex].

Answer:

1/5

Step-by-step explanation:

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

probability that the ticket drawn has a number which is a multiple of 5 =

Number of tickets that are a multiple of 5 / total number of tickets

Multiple of 5 = 5, 10, 15, 20

there would be 4 tickets that would be a multiple of 5

= 4/20

To transform to the simplest form. divide both the numerator and the denominator by 4

= 1/5

Answer:

A

Step-by-step explanation:

since it's negative so it will get smaller

Answer:

The first graph

Step-by-step explanation:

Given

[tex]y = -(2)^x - 1[/tex]

Required

The graph

Set the exponent part to get the minimum/maximum of the graph

So, we have:

[tex]y = 0 - 1[/tex]

[tex]y = - 1[/tex]

The above implies that the curve passes through the y-axis at [tex]y = - 1[/tex].

By comparing the two graphs, we can conclude that the first represents [tex]y = -(2)^x - 1[/tex] because it passes through [tex]y = - 1[/tex]

Answer:

10 is the correct answer

Answer:

Go with the third option 10!

i hope this helped!

Answer: Yes it is a function.

This is because any x input leads to exactly one y output.

The graph passes the vertical line test. It is impossible to draw a single vertical line through more than one point on the parabolic curve.

Answer:

[tex]Area = 123.55 m^2[/tex]

Step-by-step explanation:

Given

[tex]Area = 1330ft^2[/tex]

Required

Convert to [tex]m^2[/tex]

To convert from square feet to square meter, we simply divide by 3.281^2

So, we have:

[tex]Area = \frac{1330}{3.281^2}m^2[/tex]

[tex]Area = \frac{1330}{10.765}m^2[/tex]

[tex]Area = 123.55 m^2[/tex]

Answer:

There are 824 deer in the preserve.

Step-by-step explanation:

Since to determine the number of deer in a game preserve, a conservationist catches 412 deer, tags them and lets them loose, and later, 316 deer are caught, 158 of them are tagged, to determine how many deer are in the preserve you must perform the following calculation:

316 = 100

158 = X

158 x 100/316 = X

50 = X

50 = 412

100 = X

824 = X

Therefore, there are 824 deer in the preserve.

Answer:

D

Step-by-step explanation:

Answer:

B

substract the variables

Answer:

The correct answer is 3x-2

Step-by-step explanation:

It gives you the expression for JM and LM, and it asks for JL. Therefore, if you take away LM from JM, you are left with JL. You must subtract 2x-6 from 5x-8.

∴5x-8-(2x-6)

Do not forget to distribute the negative since you are subtracting, so instead of subtracting 6 from 8, you will be adding 6 to 8 because two negatives make a positive.