To solve this system of equations using substitution, what could be substituted in place of x in the second equation?
2y + x = 11
31 - y = -4
a. 2y – 11
b. 11 – 2y
c. 3x + 4
d. y - 4/3

Answer:

25

Step-by-step explanation:

Answer:

A≈376.99yd²

d= 10yd

h = 7yd

hope it helps

Answer:

D   2i

Step-by-step explanation:

Answer:

B. i√4

D. 2i

Step-by-step explanation:

The reference angle of -200° is 20°. If you think about it, the terminal arm will be in Q2. That means that it has a reference angle of 200-180 = 20°

Answer:

1 + 2 + 3 + ... + 2017

sum_(n=1)^2017 n = 2035153

Step-by-step explanation:

Answer:

-43

Step-by-step explanation:

f(x) = -2x^2+2x-3

Let x = 5

f(5) =-2(5)^2+2(5)-3

     = -2(25)+10-3

     =-50+10-3

     = -43

Answer:

D.

Step-by-step explanation:

we see a1 = 6.

that is the starting value. everything else then (to generate the new sequence elements) is added to this.

so, B and C are out.

and clearly, for every new sequence element we add -3. and we do this for every sequence element except for a1. so we add -3 (n-1) times.

therefore, only D is correct.

9514 1404 393

Explanation:

An exterior angle is equal to the sum of the remote interior angles. Define ∠PQR = 2q, and ∠QPR = 2p. The purpose of this is to let us use a single character to represent the angle, instead of 4 characters.

The above relation tells us ...

  ∠PRS = ∠PQR +∠QPR = 2q +2p

Then ...

  ∠TRS = (1/2)∠PRS = (1/2)(2q +2p) = q +p

and

  ∠TRS = ∠TQR +∠QTR . . . . . exterior is sum of remote interior

  q +p = (1/2)(2q) +∠QTR . . . . substitute for ∠TRS and ∠TQR

  p = ∠QTR = 1/2(∠QPR) . . . . . subtract q

__

For triangle ABC, draw line DE parallel to BC through point A. Put point D on the same side of point A that point B is on the side of the median from vertex A. Then we have congruent alternate interior angles DAB and ABC, as well as EAC and ACB. The angle sum theorem tells you that ...

  ∠DAB +∠BAC +∠CAE = ∠DAE . . . . a straight angle = 180°

Substituting the congruent angles, this gives ...

  ∠ABC +∠BAC +∠ACB = 180° . . . . . the desired relation

Answer: hello your question is poorly written attached below is the complete question

answer:

[tex]\sqrt{3}(cos(\frac{3\pi }{2}) + isin(\frac{3\pi }{2}))[/tex] --- ( option d )

Step-by-step explanation:

The correct option that represents a  square root of 3 as related to the question attached below is :

[tex]\sqrt{3}(cos(\frac{3\pi }{2}) + isin(\frac{3\pi }{2}))[/tex]

Answer:

D

Step-by-step explanation:

let's call the number "n", so we have a short term to talk about it

n will not exactly divisible by 5, because the remainder would be zero then.

since the remainder is 3, the number will be an integer that satisfies n = 5x + 3

example for 2x:

n = 5*2 + 3 = 13

if we devide 13 by 5, we would get 3 as remainder.

here the quotient would be 2 (the solution you get by dividing two numbers)

"x" is the quotient, so let's set it as 8

n = 5*8 +3

n = 43

checking it:

devide 43 by 5, you'll get 8 as the quotient and 3 as remainder.

hope it helps. Feel free to ask any question.

Step-by-step explanation:

1. Given,

Sides of the shape = 3y+9, 2y+4, y+3 and 2y+4

Therefore ,

Perimeter of the shape = Sum of all the sides

= (3y+9) + (2y+4) + (y+3) + (2y+4)

= 3y + 2y + y + 2y + 9 + 4 + 3 + 4

= 8y + 20 (Ans)

2. Given,

Side of the square = 5x - 2

Therefore,

Perimeter of the square = 4 × Sides = 4s

= 4 × (5x - 2)

= 4 × 5x + 4 × (-2)

= 20x - 8 (Ans)

Answer:

5/3

Step-by-step explanation:

Direct variation is of the form

y = kx

where k is a constant

Using the first set of point

9 = 5k

Divide by 5

9/5 = k

The equation becomes

y = 9/5 x

Using the second set of points

3 = 9/5 x

Multiply each side by 5/9

5/9 * 3 = 9/5 *5/9x

5/3 =x

Answer:

Floor=2*sqrt(11)

Step-by-step explanation:

Using Pythagoras theorem, we have

Wall^2+Floor^2=(Ladder)^2

Floor^2=12^2-10^2

Floor=sqrt(44)=2*sqrt(11)

Answer:The floor is 6m

Step-by-step explanation:

In this we have to solve to find B

First we know that  A^2+B^2+C^2 and we know A is 10 and C is 12 so now we are going square both 10 and 12 which would be 100 and 144 then we subtract each other 144-100=44 and lastly we are going to get the square root of 44 which is 6.

Please give brainlist

Answer:

Expected value x= 35

linear transformation is defined as a + bx

here, b=4, a=1

The transformation is [tex]z=1+4x[/tex]

now, expected value, [tex]l_z=l_z(a+bx)[/tex]

[tex]=l(a)+l(bx)[/tex]

[tex]=a+b\:l\:x[/tex]

substitute the value of a=1, b=4 and l=35

[tex]l_z=1+4\times35[/tex]

[tex]=1+140[/tex]

[tex]=141[/tex]

So, the expected value of the transformed variable is 141.

OAmalOHopeO

=======================================================

Explanation:

Let's consider a set of three values such that they're all equal to 35

{35,35,35}

This rather boring set has a mean of 35 and it's hopefully very clear why this is the case. The terms "mean" and "expected value" are interchangeable.

If we multiply everything by 4, then we get the new set {140,140,140}

Then add 1 to everything and we arrive at {141,141,141}. You can quickly see that the mean here is 141.

-----------------------------

You could play around with that original set of 3 values to make things more interesting. Let's say we subtract 1 from the first item and add 1 to the last item. So we could have {35,35,35} turn into {34,35,36}. You should find that the mean is still 35 here.

If we quadruple each item, then we have {34,35,36} turn into {136,140,144}

Finally, add 1 to everything to get {137,141,145}. Computing the mean of this set leads to 141.

These are just two examples you could do to help see why the answer is D) 141

-----------------------------

In a more general theoretical sense, we're saying the following

Y = mX+b

E[Y] = E[m*X+b]

E[Y] = E[m*X] + E[b]

E[Y] = m*E[X] + b

where Y is the transformed variable based on the random variable X. In this case, m = 4 and b = 1. Also, E[X] = 35.

So,

E[Y] = m*E[X] + b

E[Y] = 4*35 + 1

E[Y] = 141

-----------------------------

Why go through all this trouble? Well consider that you know a certain distribution is centered around 35. Then consider that you want to convert those measurements to some other unit. This conversion process is us going from variable X to variable Y. Think of it like a batch conversion of sorts.

A more real world example would be something like "we know the average temperature is 35 degrees Celsius. The question is: what is the average temperature in Fahrenheit?" The numbers would be different, but the idea still holds up.

Answer:

Step-by-step explanation:

x1 y1  x2 y2

-4 3  3 1

ΔY -2    

ΔX 7    

slope= -  2/7    

Answer:

0.07

Step-by-step explanation:

0.70-0.63

Answer:

0.07

Step-by-step explanation:

subtract both and get ur answer

Answer:

12.56 m

Step-by-step explanation:

The circumference of a circle is given by

C  = 2 * pi *r

C = 2 * (3.14) * 2

C =12.56

Answer:

2520 ways

Step-by-step explanation:

Given

[tex]n = 10[/tex]

[tex]r = (2,3,5)[/tex]

Required

The number of selection

First, select 2 people from 10 in 10C2 ways.

There are 8 people, left.

Next, select 3 people from 8 in 8C3 ways.

There are 5 people left.

Lastly, select 5 from 5 in 5C5 ways

So, we have:

[tex]Total = ^{10}C_2 * ^8C_3 * ^5C_5[/tex]

Using combination formula

[tex]Total = 45 * 56 * 1[/tex]

[tex]Total = 2520[/tex]

Answer: (0;2)

3x + 2y = 4 | * (-5)

4x + 5y = 10 | * 2

-15x - 10y = -20

8x + 10y = 20

-15x - 10y + 8x + 10y = 20 - 20

x = 0

0 + 2y = 4

2y = 4

y = 2

(0; 2)

Solution :

Given :

a = (1, 2, 3, 4) ,    b = ( 4, 3, 2, 1),    c = (1, 1, 1, 1)     ∈   [tex]R^4[/tex]

a). (a.2c)b + ||-3c||a

Now,

(a.2c) = (1, 2, 3, 4). 2 (1, 1, 1, 1)

         = (2 + 4 + 6 + 6)

         = 20

-3c = -3 (1, 1, 1, 1)

     = (-3, -3, -3, -3)

||-3c|| = [tex]$\sqrt{(-3)^2 + (-3)^2 + (-3)^2 + (-3)^2 }$[/tex]

        [tex]$=\sqrt{9+9+9+9}$[/tex]

       [tex]$=\sqrt{36}$[/tex]

        = 6

Therefore,

(a.2c)b + ||-3c||a = (20)(4, 3, 2, 1) + 6(1, 2, 3, 4)  

                          = (80, 60, 40, 20) + (6, 12, 18, 24)

                         = (86, 72, 58, 44)

b). two vectors [tex]\vec A[/tex] and [tex]\vec B[/tex] are parallel to each other if they are scalar multiple of each other.

i.e., [tex]\vec A=r \vec B[/tex]   for the same scalar r.

Given [tex]\vec p[/tex] is parallel to [tex]\vec a[/tex], for the same scalar r, we have

[tex]$\vec p = r (1,2,3,4)$[/tex]

[tex]$\vec p = (r,2r,3r,4r)$[/tex]   ......(1)

Let [tex]\vec q = (q_1,q_2,q_3,q_4)[/tex]   ......(2)

Now given [tex]\vec p[/tex]  and  [tex]\vec q[/tex] are perpendicular vectors, that is dot product of [tex]\vec p[/tex]  and  [tex]\vec q[/tex] is zero.

[tex]$q_1r + 2q_2r + 3q_3r + 4q_4r = 0$[/tex]

[tex]$q_1 + 2q_2 + 3q_3 + 4q_4 = 0$[/tex]  .......(3)

Also given the sum of [tex]\vec p[/tex]  and  [tex]\vec q[/tex] is equal to [tex]\vec b[/tex]. So

[tex]\vec p + \vec q = \vec b[/tex]

[tex]$(r,2r,3r,4r) + (q_1+q_2+q_3+q_4)=(4, 3,2,1)$[/tex]

∴ [tex]$q_1 = 4-r , \ q_2=3-2r, \ q_3 = 2-3r, \ q_4=1-4r$[/tex]   ....(4)

Putting the values of [tex]q_1,q_2,q_3,q_4[/tex] in (3),we get

[tex]r=\frac{2}{3}[/tex]

So putting this value of r in (4), we get

[tex]$\vec p =\left( \frac{2}{3}, \frac{4}{3}, 2, \frac{8}{3} \right)$[/tex]

[tex]$\vec q =\left( \frac{10}{3}, \frac{5}{3}, 0, \frac{-5}{3} \right)$[/tex]

These two vectors are perpendicular and satisfies the given condition.

c). Given terminal point is [tex]\vec a[/tex] is (-1, 1, 2, -2)

We know that,

Position vector = terminal point - initial point

Initial point = terminal point - position point

                  = (-1, 1, 2, -2) - (1, 2, 3, 4)

                  = (-2, -1, -1, -6)

d). [tex]\vec b = (4,3,2,1)[/tex]

Let us say a vector [tex]\vec d = (d_1, d_2,d_3,d_4)[/tex]  is perpendicular to [tex]\vec b.[/tex]

Then, [tex]\vec b.\vec d = 0[/tex]

     [tex]$4d_1+3d_2+2d_3+d_4=0$[/tex]

     [tex]$d_4=-4d_1-3d_2-2d_3$[/tex]

There are infinitely many vectors which satisfies this condition.

Let us choose arbitrary [tex]$d_1=1, d_2=1, d_3=2$[/tex]

Therefore, [tex]$d_4=-4(-1)-3(1)-2(2)$[/tex]

                      = -3

The vector is (-1, 1, 2, -3) perpendicular to given [tex]\vec b.[/tex]

Answer:

Step-by-step explanation:

A positive cubic function graphed in the coordinate plane tends from lower left to upper right while a negative cubic function tends from the upper left to lower right. That graph is D (graph A is the positive cubic. Note the difference between "lower left to upper right" and "upper left to lower right")

Answer:

m is -12/7 and b is -64/7

Step-by-step explanation:

Use rise over run (change in y / change in x) to find the slope, m:

(-4 - 8) / (-3 + 10)

= -12/7

So, m is -12/7.

Plug in this value and a point into y = mx + b, then solve for b:

y = mx + b

-4 = -12/7(-3) + b

-4 = 36/7 + b

-64/7 = b

So, m is -12/7 and b is -64/7

The linear function is given by:

[tex]y = -\frac{12}{7}x - \frac{64}{7}[/tex]

Where:

A linear function is modeled by:

[tex]y = mx + b[/tex]

In which:

In this problem, the points are (−10,8) and (−3,-4).

The slope is given by change in y divided by change in x, hence:

[tex]m = \frac{-4 - 8}{-3 - (-10)} = -\frac{12}{7}[/tex]

Hence:

[tex]y = -\frac{12}{7}x + b[/tex]

It goes through point (−3,-4), hence when [tex]x = -3, y = -4[/tex], which is used to find b.

[tex]y = -\frac{12}{7}x + b[/tex]

[tex]-4 = \frac{36}{7} + b[/tex]

[tex]b = -\frac{64}{7}[/tex]

Hence, the equation is:

[tex]y = -\frac{12}{7}x - \frac{64}{7}[/tex]

You can learn more about linear functions at https://brainly.com/question/24808124

Answer:

Solution given:

Centre (h,k)=(-6,-2)

end points are:

A[tex]\bold{(x_{1},y_{1})=(-1,-9) \:and \:B(x_{2},y_{2})=(-11,5)}[/tex]

Now

distance between A to M is:

AM=[tex]\sqrt{(h-x_{1})²+(k-y_{1})²}[/tex]

AM=[tex]\sqrt{(-6+1)²+(-2+9)²}=8.6[/tex]units

again

distance between B to M is:

BM=[tex]\sqrt{(h-x_{2})²+(k-y_{2})²}[/tex]

BM=[tex]\sqrt{(-6+11)²+(-2-5)²}=8.6[/tex]units

again

Since AM=BM=8.6units

so

M is the centre of the circle.:Yes

Answer: A line parallel to one side of a triangle and intersects the other two sides divides the two sides of the triangle proportionally.

Got this straight from Edmentum

Step-by-step explanation:

Answer:

The ratio of BF to FC is proportional to the ratio of GB to AG. Similarly, the ratio of IC to BI is proportional to the ratio of HC to AH.

Step-by-step explanation:

This is the actual answer for question 7 the one above is question 8

:)

Since this is a right triangle, we can use the Pythagorean Theorem.

Pythagorean Theorem: a^2 + b^2 = c^2

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 147

b = sqrt(147) = 7 sqrt(3) miles

Hope this helps!

Answer:

The perimeter of the triangle is 40.

Step-by-step explanation:

The sum of legs for a right triangle is 12:

[tex] a + b = 21 [/tex]

[tex] a = 21 - b [/tex]   (1)

And their product is:

[tex] a*b = 40 [/tex]   (2)

By entering eq (1) into (2) we have:

[tex] (21 - b)b = 40 [/tex]                          

[tex] 21b - b^{2} - 40 = 0 [/tex]  

We can find the value of "b" by solving the above quadratic equation.

[tex] b_{1} = 2.1 [/tex]

[tex] b_{2} = 18.9 [/tex]

Since the two values satisfy the equation, we can use either of them to find "a". We will use b₁.      

[tex] a = 21 - 2.1 = 18.9 [/tex]                                                                              

Now, the hypotenuse of the right triangle is given by:

[tex] h = \sqrt{a^{2} + b^{2}} = \sqrt{(18.9)^{2} + (2.1)^{2}} = 19 [/tex]

Hence, the perimeter is:

[tex] P = a + b + h = 18.9 + 2.1 + 19 = 40 [/tex]

Therefore, the perimeter of the triangle is 40.

I hope it helps you!          

Answer:

3 / 16

Step-by-step explanation:

Let The total amount = x

Fraction eaten on first day = 1/4x

Fraction left = x - 1/4x = 3/4x

Fraction of amount left eaten on second day = 3/4 of 3/4x

3/4 * 3/4x = 9/16x

Fraction left :

3/4x - 9/16x = (12x - 9x) /16 = 3/16x

Hence, fraction left = 3/16

Answer:

m A = 63

m C = 27

Step-by-step explanation:

to find the angle of a use trigonometry by doing, cos-1(17/38) = 63

to find C, we know angles in a triangle add to 180. We know the right angle is 90 degrees so do 90 + 63 = 153

180 - 153 = 27

so C = 27 degrees

Answer:

He is incorrect.

Step-by-step explanation:

4500 x ( 1 + 1.50%)^3

= 4500 x 1.045678

= 4705.551000

4705.551000 < 4750

Carlos is not correct, because the amount at the end of the 3 years of compounding is £4705.65 not more than £4750.

Compound interest is the interest on savings calculated on both the initial principal and the accumulated interest from previous periods.

The formula used to find the compound [tex]A=P(1+\frac{r}{100})^{nt}[/tex]

Given that, Carlos invests £4500 for 3 years.

He receives compound interest of 1.5% per year.

Here, amount =4500(1+1.5/100)³

= 4500(1+0.015)³

= 4500(1.015)³

= 4500×1.0457

= £4705.65

Carlos is not correct, because the amount at the end of the 3 years of compounding is £4705.65 not more than £4750.

To learn more about the compound interest visit:

https://brainly.com/question/14295570.

#SPJ2

Answer:

The correct answer 8486.

Step-by-step explanation:

Given:

Troy - P pr principle amount = 10000

rate = 9%

time = 60-22 = 38

intrest at every three months so time = t = 38*4 = 132

Nicohlas

P = x

rate = 10%

time = 60 -45 = 15

every month compounded = 15*12=180

solution:

the formula of compound intrest = P (1 + r/n)^(nt)

where n = number of counded intrests per year

puting formula for troy=

10000 (1+9/4)^132

= 294,322.96 .....1

now for nicolas

I = x(1+10/12)^180

x = 294,322.96/(1+10/12)^180

= 8486.