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Should the Us government regulate sugar? In once sentence write down what you are preparing to argue or what stance you are going to take. This will help you to create a starting point for your idea

Answer:

A complete third electron shell holds 8 electrons

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hope it helps...

have a great day!!

Answer:

8

Explanation:

Answer:

Since resistance is proportional to length   R = K L / A

the resistance of each piece would be R / 10 = 10 ohms

A copper wire is the conductor wire. If the wire is cut into 10 equal lengths,  the resistance of each piece will be 10 ohms.

Resistance is the opposition to the flow of electrons in the conductor wire.

Given is the total resistance of the wire is 100 ohms.

Resistance is directly proportional to the length of the wire.  When the wire is cut into 10 pieces, the new resistance will be

[tex]\dfrac{R}{10} =\dfrac{100}{10} =10 \:\rm ohms[/tex]

Hence, the resistance of each piece will be 10 ohms.

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Answer: D

The force decreases inversely proportional to 1/r(squared)

Explanation:

I looked it up im sure this is correct

Answer:

option d

Explanation:

Two objects are attracted to each other by a gravitational force F. ... As the distance r from the center of the planet increases, what happens to the force of gravity on the rocket? The force decreases inversely proportional to 1/r(squared) A spacecraft is orbiting Earth with an orbital radius r.

the force of gravity is represented as

F = GM1M2/r²

now the mass of warth and rocket is considered to be constant and G is a universal constant so it can be said

F is inverse to r²

therefore as the value of r increases that is distance between earth and rocket increases the force decreases

(Follows inverse square law)

Answer:

62.8 μC

Explanation:

Here is the complete question

The volume electric charge density of a solid sphere is given by the following equation: ρ = (0.2 mC/m⁵)r²The variable r denotes the distance from the center of the sphere, in spherical coordinates. What is the net electric charge (in μC) of the sphere if the radius of the sphere is 0.5 m?

Solution

The total charge on the sphere Q = ∫∫∫ρdV where ρ = volume charge density = 0.2r² and dV = volume element in spherical coordinates = r²sinθdθdrdΦ

So,  Q =  ∫∫∫ρdV

Q =  ∫∫∫ρr²sinθdθdrdΦ

Q =  ∫∫∫(0.2r²)r²sinθdθdrdΦ

Q =  ∫∫∫0.2r⁴sinθdθdrdΦ

We integrate from r = 0 to r = 0.5 m, θ = 0 to π and Φ = 0 to 2π

So, Q =  ∫∫∫0.2r⁴sinθdθdrdΦ

Q =  ∫∫∫0.2r⁴[∫sinθdθ]drdΦ

Q =  ∫∫0.2r⁴[-cosθ]drdΦ

Q =  ∫∫0.2r⁴-[cosπ - cos0]drdΦ

Q =  ∫∫∫0.2r⁴-[-1 - 1]drdΦ

Q =  ∫∫0.2r⁴-[- 2]drdΦ

Q =  ∫∫0.2r⁴(2)drdΦ

Q =  ∫∫0.4r⁴drdΦ

Q =  ∫0.4r⁴dr∫dΦ

Q =  ∫0.4r⁴dr[Φ]

Q =  ∫0.4r⁴dr[2π - 0]

Q =  ∫0.4r⁴dr[2π]

Q =  ∫0.8πr⁴dr

Q =  0.8π∫r⁴dr

Q =  0.8π[r⁵/5]

Q = 0.8π[(0.5 m)⁵/5 - (0 m)⁵/5]

Q = 0.8π[0.125 m⁵/5 - 0 m⁵/5]

Q = 0.8π[0.025 m⁵ - 0 m⁵]

Q = 0.8π[0.025 m⁵]

Q = (0.02π mC/m⁵) m⁵

Q = 0.0628 mC

Q = 0.0628 × 10⁻³ C

Q = 62.8 × 10⁻³ × 10⁻³ C

Q = 62.8 × 10⁻⁶ C

Q = 62.8 μC

Answer:

The correct answer is "22.27 hours".

Explanation:

Given that:

Radioactive isotope activity,

= 490,000 Bq

Activity,

= 110,000 Bq

Time,

= 48 hours

As we know,

⇒ [tex]A = A_0 e^{- \lambda t}[/tex]

or,

⇒ [tex]\frac{A}{A_0}=e^{-\lambda t}[/tex]

By taking "ln", we get

⇒ [tex]ln \frac{A}{A_0}=- \lambda t[/tex]

By substituting the values, we get

⇒ [tex]-ln \frac{110000}{490000} = -48 \lambda[/tex]

⇒    [tex]-1.4939=-48 \lambda[/tex]

                 [tex]\lambda = 0.031122[/tex]

As,

⇒ [tex]\lambda = \frac{ln_2}{\frac{T}{2} }[/tex]

then,

⇒ [tex]\frac{ln_2}{T_ \frac{1}{2} } =0.031122[/tex]

⇒ [tex]T_\frac{1}{2}=\frac{ln_2}{0.031122}[/tex]

         [tex]=22.27 \ hours[/tex]  

Answer: The voltage needed is 35.7 V

Explanation:

Assuming that the resistors are arranged in parallel combination.

For the resistors arranged in parallel combination:

[tex]\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}[/tex]

We are given:

[tex]R_1=20\Omega\\R_2=20\Omega\\R_3=200\Omega[/tex]

Using above equation, we get:

[tex]\frac{1}{R}=\frac{1}{20}+\frac{1}{20}+\frac{1}{200}\\\\\frac{1}{R}=\frac{10+10+1}{200}\\\\R=\frac{200}{21}=9.52\Omega[/tex]

Calculating the voltage by using Ohm's law:

[tex]V=IR[/tex]         .....(1)

where,

V = voltage applied

I = Current = 3.75 A

R = Resistance = [tex]9.52\Omega[/tex]

Putting values in equation 1, we get:

[tex]V=3.75\times 9.52\\\\V=35.7V[/tex]

Hence, the voltage needed is 35.7 V

There are six different ways to arrange those resistors.

Each way leads to a different answer.

You didn't tell us how you want them connected.

The attached drawing shows them all.

Explanation:

[tex]which \: language \: is \: this[/tex]

[tex]pls \: write \: in \: english[/tex]

[tex]then \: only \: i \: can \: answer \: u[/tex]

[tex]otherwise \: sry[/tex]

Answer: the iris

Explanation: I looked it up

Answer:

Iris

Explanation:

Because (iris) has muscles that can expand/contract depends to the amount of light that pupil needs to process/figure out images.

Answer:

0.913

Explanation:

k.e=1/2mv square

k.e=1/2×0.078g×23.4256m/s square

k.e=0.913J

The kinetic energy when the lemming is 2.00 m above the ground is approximately 2.56 J (Joules).

To calculate the kinetic energy (KE) of the lemming when it is 2.00 m above the ground, we need to consider the change in its potential energy (PE) as it falls.

The potential energy at a height h is given by:

PE = m g h

Where:

m is the mass of the lemming (0.0780 kg)

g is the acceleration due to gravity (9.8 m/s²)

h is the height above the ground

Given:

Height of the cliff (h) = 5.36 m

Velocity of the lemming (v) = 4.84 m/s

Height above the ground (h') = 2.00 m

The lemming will lose potential energy as it falls from the cliff, which is converted into kinetic energy. Therefore, the kinetic energy when it is 2.00 m above the ground is equal to the difference between its total initial kinetic energy and the potential energy at that height.

Initial potential energy at the top of the cliff:

PE_initial = m g h

Potential energy when it is 2.00 m above the ground:

PE_final = m * g * h'

The change in potential energy is given by:

ΔPE = PE_final - PE_initial

The kinetic energy (KE) when it is 2.00 m above the ground:

KE = ΔPE = -ΔPE (due to energy conservation)

Let's calculate the potential energy at the top of the cliff and when it is 2.00 m above the ground:

PE_initial = m ×g × h

= 0.0780 kg × 9.8 m/s² × 5.36 m

PE_initial ≈ 4.09 J

PE_final = m ×g × h'

= 0.0780 kg ×9.8 m/s² ×2.00 m

PE_final ≈ 1.53 J

The change in potential energy (ΔPE) is:

ΔPE = PE_final - PE_initial = 1.53 J - 4.09 J

ΔPE ≈ -2.56 J

Since the change in potential energy is equal to the kinetic energy, the kinetic energy when the lemming is 2.00 m above the ground is approximately 2.56 J (Joules).

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Answer:

dhfhffuththt9tr8tujtngigjtjrjrjrurur

Answer:

2.8 seconds

Explanation: Given that a simple pendulum that consists of a massless 2.00-meter length of rope attached to a 5.00-kg mass at one end. What is the period of oscillation for this simple pendulum

The parameters given are :

Length = 2 m

Mass = 5kg

Using the formula below

T = 2 pi × sqrt ( L / g )

Substitute all the parameters into the formula.

T = 2 × 3.143 × sqrt ( 2 / 9.8 )

T = 2 × 3.143 × 0.4517

T = 2.838 s

Therefore, the period of oscillation for this simple pendulum is 2.8 s approximately.

Answer:

Send a clear photo again

Explanation:

And tag me

Answer:

the radio can tune wavelengths between 1.88 and 5.97 m

Explanation:

The signal that can be received is the one that is in resonance as the impedance of the LC circuit.

         X = X_c - X_L

         X = 1 / wC - w L

at the point of resonance the two impedance are equal so their sum is zero

         X_c = X_L

         1 / wC = w L

         w² = 1 / CL

         w = [tex]\sqrt{\frac{1}{CL} }[/tex]

let's look for the extreme values

C = 1  10⁻¹² F

         w = [tex]\sqrt{\frac{1}{ 1 \ 10^{-12} \ 1 \ 10^{-6}} }[/tex]

         w = [tex]\sqrt{1 \ 10^{18}}[/tex]

         w = 10⁹ rad / s

C = 10 10⁻¹² F

         w = [tex]\sqrt{\frac{1}{10 \ 10^{-12} \ 1 \ 10^{-6}} }[/tex]Ra 1/10 10-12 1 10-6

         w = [tex]\sqrt{0.1 \ 10^{18}}[/tex]Ra 0.1 1018

         w = 0.316 10⁹ rad / s

Now the angular velocity and the frequency are related

           w = 2π f

           f = w / 2π

the light velocity  is

           c = λ f

           λ = c / f

we substitute

          λ = c 2π/w

we calculate the two values

 C = 1 pF

          λ₁ = 3 10⁸ 2π / 10⁹

          λ₁= 18.849 10⁻¹ m

          λ₁ = 1.88 m

C = 10 pF

           λ₂ = 3 10⁸ 2π / 0.316 10⁹

           λ₂ = 59.65 10⁻¹ m

           λ₂ = 5.97 m

so the radio can tune wavelengths between 1.88 and 5.97 m

Answer:

a. 3.09 m/s^2

b. 322.52 N

Explanation:

The computation of the acceleration of the object and the tension of the string is as follows:

The acceleration of the system is a

= (m1 - m2) × g ÷ (m1 + m2)

= (48 - 25) × 9.81 ÷ (48 + 25)

= 3.09 m/s^2

b. The tension in the string is T

= 2 × m1 × m2 × g÷   (m1+m2)

= (2  × 48  × 25  ×  9.81) ÷  (48 + 25)

= 322.52 N

Answer:

The appropriate answer is "3761.69 N/C".

Explanation:

Given that:

Mass,

m = 4.99 g

or,

   = [tex]4.99\times 10^{-3} \ kg[/tex]

Charge,

q = 13 µC

or,

  = [tex]13\times 10^{-6} \ C[/tex]

As we know,

⇒ [tex]F=mg=Eq[/tex]

then,

⇒ [tex]E=\frac{mg}{q}[/tex]

By putting the values, we get

        [tex]=\frac{4.99\times 10^{-3}\times 9.8}{13\times 10^{-6}}[/tex]

        [tex]=3761.69 \ N/C[/tex]

Answer:

Explanation:

Use the equation

[tex]v^2=v_0^2+2a[/tex]Δx

In this dimension (the y dimension...the only one we have to care about for this problem), here's what we know:

a = -32 ft/s/s

v₀ = 0 m/s (since someone was holding the stone still before it was dropped)

v = 136 ft/s

Δx = ??

Filling in:

[tex]136^2=0^2+2(-32)[/tex]Δx so

Δx = [tex]\frac{136^2}{2(-32)}[/tex] so

Δx = -289 feet (negative because the stone dropped that many feet below the point from which it was dropped, but you would answer a height question with the positive of this number. If you were asked how far the stone dropped, it would be negative; if you're asked how tall the cliff is, that would be positive)

Answer:

The mass decreases

Explanation:

Just smart

Answer:If an object's speed changes, or if it changes the direction it's moving in,

then there must be forces acting on it. There is no other way for any of

these things to happen.

Once in a while, there may be a group of forces (two or more) acting on

an object, and the group of forces may turn out to be "balanced".  When

that happens, the object's speed will remain constant, and ... if the speed

is not zero ... it will continue moving in a straight line.  In that case, it's not

possible to tell by looking at it whether there are any forces acting on it

Answer:2

Explanation:

Answer:

HOPE IT HELPS YOU!!!

Explanation:

Mark FadedGirl25 as brainliest

Answer:

d. In dc steady state conditions, the voltages across the capacitors are constant and the currents through the capacitance are zero. The current through the inductors are constant and the voltage across the inductances are zero.

Explanation:

The current through a capacitor is given by i = CdV/dt where C = capacitance of capacitor and V = voltage across capacitor. At steady state dV/dt = 0 and V = constant. So, i = CdV/dt = C × 0 = 0.

So, in dc steady state, the voltage across a capacitor is constant and the current zero.

The voltage across an inductor is given by V = Ldi/dt where L = inductance of inductor and i = current through inductor. At steady state di/dt = 0 and V = constant. So, V = Ldi/dt = L × 0 = 0.

So, in dc steady state, the voltage across an inductor is zero and the current constant.

So, In dc steady state conditions, the voltages across the capacitors are constant and the currents through the capacitance are zero. The current through the inductors are constant and the voltage across the inductances are zero.

The answer is d.

This is convex lens .

hence It's a converging lens .

The picture shown is a type of converging lens. The correct option is A.

A converging lens, also known as a convex lens, is a type of optical lens that is thicker in the middle than at the edges. It is shaped like a curved-outward disc and is commonly used in optical systems such as cameras, telescopes, and microscopes. When light passes through a converging lens, it bends inward and converges at a focal point located on the other side of the lens.

This focal point is determined by the curvature of the lens and its refractive index, which affects how much the light is bent. The distance between the lens and the focal point is called the focal length, and it determines the magnification and the image size produced by the lens. Converging lenses are used in many applications that require focusing and magnifying light, such as correcting vision problems and creating images in photography and microscopy.

Therefore, The correct answer is converging lens.

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Answer:

The angular velocity of the wheels is 276.314 radians per second.

Explanation:

The wheels are rolling, which is a combination of rotation and translation, whose center of rotation is the point of contact between the wheel and the ground and the geometrical center of the skateboard experiments pure translation. Then, the angular velocity can be found by using the following kinematic expression:

[tex]\omega = \frac{v}{R}[/tex] (1)

Where:

[tex]\omega[/tex] - Angular velocity, in radians per second.

[tex]v[/tex] - Velocity of the wheel at its center, in inches per second.

[tex]R[/tex] - Radius of the wheel, in inches.

If we know that [tex]v = 404.8\,\frac{in}{s}[/tex] and [tex]R = 1.465\,in[/tex], then the angular velocity of the wheels are:

[tex]\omega = \frac{404.8\,\frac{in}{s} }{1.465\,in}[/tex]

[tex]\omega = 276.314\,\frac{rad}{s}[/tex]

The angular velocity of the wheels is 276.314 radians per second.

Answer:

the voltage will be the same across all resistors

Explanation:

the total voltage supplied to the circuit will remain the same across all resistors

Answer:

to focus the link light

Explanation:

Because the lens is flexible and elastic, it can change its curved shape to focus on objects and people that are either nearby or at a distance. ... The ciliary muscles, which are part of the ciliary body, are attached to the lens and contract or release to change the lens shape and curvature.

Answer:

to focus the link light

Explanation:

vote brainliest I never got voted brainliest plssss

Answer:

   v = 4.1 m / s

Explanation:

Velocity is defined by the relation

          v =[tex]\frac{dx}{dt}[/tex]

 we perform the derivative

         v = 4.1 m / s

Another way to find this magnitude is to see that the velocity on the slope of a graph of h vs t

        v = [tex]\frac{\Delta x}{\Delta t}[/tex]

        Δx = v Δdt + x₀

        h=   4.1 t + 5.5

         v = 4.1 m / s

         x₀ = 5.5 m

Answer:

44.72m/s

Explanation:

use th formula:vf²=vi²at

and then substitute the values

remember the units

If there is no air resistance, the speed of the free falling object from the same height will be the same. Therefore, the ratio of speed of the stone to that of rock for 2 seconds falling will be 1 : 1.

An object freely falling under the force of gravitation is called the free falling body. Here, the acceleration of the object is the acceleration due to gravity.

For a freely falling body, the velocity v = g t

where g is the acceleration due to gravity and for earth g is 9.8 m/s².

Everybody falls with the same rate freely under the acceleration due to gravity if there is no air resistance at all.

Here, the time t = 2 s

then v = 9.8 m/s² × 2 s = 19.6 m/s.

the speed of both the rock and stone will be 19.6 m/s in the absence of air resistance. Hence, the ratio of their speed is 1 : 1.

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Answer:

a) increases.

b) remains the same.

c) increases.

d) increases.

e) increases.

f) increases.

Explanation:

a)

       [tex]C = \epsilon_{0}*\frac{A}{d} (1)[/tex]

       where ε₀ = permitivitty of  free space

                   A = area of one of the plates

                   d=  plate separation

b)  

        [tex]C = \frac{Q}{V} (2)[/tex]

c)

d)

       [tex]U = \frac{1}{2}* C*V^{2} (3)[/tex]

e)

       [tex]V = E*d (4)[/tex]

f)

       [tex]u = \frac{U}{v} = \frac{\frac{1}{2}* C*V^{2}}{A*d} =\frac{1}{2}* \epsilon_{0}*\frac{A*V^{2} }{A*d*d} = \frac{1}{2} *\epsilon_{0}*E^{2} (5)[/tex]