By visual inspection, determine the best-fitting model of the three types of regression for the data plot below.
A. Quadratic
B. Exponential
C. Linear
D. None of the above​

Answer:

2,196;    549;     131.76;     8;     175.68;      1339.56

Step-by-step explanation:

2,196 is the biggest number, so use that as the first number.

.25x2196=549

.06x2196=131.76

.08x2196=175.68

2196-(549+131.76+175.68)=1339.56

Answer: The expression is 7/2.

The equation your teacher has given you is an identity. We can prove this by transforming one side into the other. I'll transform the right hand side (RHS) into the left hand side (LHS).

This means I'll keep the LHS the same for each line. I'll only change the RHS. The goal is to get the same thing on both sides (I could go the other way around but I find this pathway is easier).

[tex]\tan^4(\theta)+\sec^2(\theta) = \sec^4(\theta)-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\sec^2(\theta)\right)^2-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\tan^2(\theta)+1\right)^2-\tan^2(\theta) \ \text{ ... see note 1}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+2\tan^2(\theta)+1-\tan^2(\theta)\\\\[/tex]

[tex]\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\tan^2(\theta)+1\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta)-1+1 \ \text{ ... see note 2}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta) \ \ \Large \checkmark\\\\[/tex]

So because we've arrived at the same thing on both sides, the original equation is an identity. It always true no matter what theta value you plug in, as long as theta is in the domain. So something like theta = pi/2 won't work because tan(pi/2) = undefined and sec(pi/2) = undefined. It's based on how cos(pi/2) = 0 and this value is in the denominator. Dividing by zero is undefined.

Consequently, this means all solutions to cos(theta) = 0 will be excluded from the domain. Everything else works.

Answer:

enlarge it

Step-by-step explanation:

I ft = 12 inches

Thus 8 in → 12 in makes the transformation larger.

Thus going from 8 in to 12 in is an enlargement

Answer:

0.23923444976

Answer:

108 squared centimeters

Step-by-step explanation:

Let's exchange π for 3:

area = πr^2

        = 3r^2

Now, as you can see, the radius of this circle is 6. Let's plug in the value of r:

area = 3r^2

        = 3 · 6^2

Simplify 6^2:

area = 3 · 6^2

        = 3 · 36

Multiply 3 by 36:

area = 3 · 36

area = 108

108 squared centimeters

Answer:

-2

Step-by-step explanation:

-10 x 12 x -4 + 40 x -2 x 6 - 2

-120 x -4 - 80 x 6 - 2

480 - 480 - 2

0 - 2

-2

Answer:

i) where the digits can repeat

1. 30

2. 50

3. 33

4. 55

5. 35

6. 53

ii) where the digits cannot be repeated

1. 30

2. 50

3. 35

4. 53

Answer jose needs to get 7 more A's because 5+7=12 so if 50+70=120 then he will need to get 7 more a's hope this helps :)

Step-by-step explanation:

Answer:

He needs 7 A's.

Step-by-step explanation:

The pictures.

Hope this helps!!! :)

Answer:

B. SAS

Step-by-step explanation:

Ratio of sides equal:

• 4/2= 6/3

So the 2 sides are congruent and also share same angle between.

• B. SAS is the similarity reason

Answer:

8= coefficients.

4ab=constant term

5b=number of terms

Step-by-step explanation:

when terms are being added and substrated in algebra expression, we can sometimes simplify the expression to produce an expression with fewer terms

LET ME KNOW IF IT HELPS

Answer:

Step-by-step explanation:

i. 5/12

ii. 1/8

iii. 11/24

iiii. 7/8

Answer:

The third one

Step-by-step explanation:

Just took the quiz

Answer:

3

Step-by-step explanation:

The value of x is 3 if the volume of the triangular prism is 54 cubic units.

a three dimensional shape can be defined as a solid figure or an object or shape that has three dimensions—length, width, and height.

Given that  volume of the triangular prism is 54 cubic units.

We have to find the value of x

The volume of the prism with triangular base is 54 unit³.

The base is a triangle with,

base = 4 units

height = x units

height of the prism = 3x

V= 6x²

54= 6x²

Divide both sides by 6

x² = 9

x=3

Hence, the value of x is 3 if the volume of the triangular prism is 54 cubic units.

To learn more on Three dimensional figure click:

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Answer:

10x² + 11x - 6

Step-by-step explanation:

The area (A) is the product of the sides, that is

A = (2x + 3)(5x - 2) ← expand using FOIL

   = 10x² - 4x + 15x - 6 ← collect like terms

   = 10x² + 11x - 6

Answer:

4x+11

Step-by-step explanation:

you have to add the like terms,in this case the like terms are 7 and 4.4x isn't a like term cause it has a variable.

so you just have to add 7+4

4x+11

I hope this helps

Step-by-step explanation:

hope this may help you tq

Answer:

Step-by-step explanation:

a). In ΔABC and ΔEDC,

Since, AB and DE are parallel and AE is a transversal,

Therefore, ∠CAB ≅ ∠CED [Alternate interior angles]

m∠D = m∠B = 90°

ΔABC ~ ΔEDC [By AA property of similarity of two triangles]

b). Therefore, by the property of similar triangles,

"Corresponding sides of two similar triangles are proportional"

[tex]\frac{DC}{BC}= \frac{DE}{AB}[/tex]

[tex]\frac{60}{200}=\frac{40}{AB}[/tex]

AB = [tex]\frac{40\times 200}{60}[/tex]

     = 133.33

     ≈ 133.3 ft

Answer:

Rs.6420

Step-by-step explanation:

we know that A=P(1+r/100)

7488=P(1+8/100)2

7488*10000/108*108=P

P=Rs.6420

Answer:

Principal=Rs.45000 ; And Amount=Rs.52488.

Step-by-step explanation:

For finding Principal i used the formula:[ x(1+8/100)^2-x] =C.I ( where x = P)

And for Amount : Sum of principal and interest.

Hope so, you liked my solution.

Answer:

1.

= Here,

cost of pen = 3+4 ( x ) = 7x

costs of two pen = 7x

cost of three pencils = 71 - 7x = 64x

cost of 1 pencil = 64/3

= 21.333334

c

Answer:

195.06

Step-by-step explanation:

area of circle = πr^2 = π8^2 = 64π

area of triangle = 1/2 x 4 x 3 = 6

area of shape = 64π-6 = 195.061929 = 195.06

Answer:

5

Step-by-step explanation:

[tex]5^{2}[/tex] = 25

25 * 2 = 50

50 - 3 = 47

Hope that this helps!

Answer:

Step-by-step explanation:

let the number be x

Square of a number: x²

Twice the square of a number = 2*x² = 2x²

Three less than twice the square of a number = 2x² - 3

2x² - 3 = 47     {Add 3 to both sides}

2x² = 47 + 3

2x² = 50        {Divide both sides by 2}

 x² = 50/2

x² = 25          Take square root

x = √25

x = 5

Answer:

The answer is "C" f(x)= x+ 4 and g(x)= x^3 - 1

Step-by-step explanation:

all you have to do is replace the x in "G" with the "F" function

F(x) = x+4  and  G(x) = x^3-1

===========================================================

Explanation:

Let's try choice A to see if it works or not

G(x) = (x+4)^3

G( F(x) ) = ( F(x)+4 ) ^3 .... replace every x with F(x)

G( F(x) ) = ( x-1+4 ) ^3 .... plug in F(x) = x-1

G( F(x) ) = (x+3)^3

This isn't the same as (x+4)^3 - 1. You can confirm this with a graph or a table of values. We cross choice A off the list.

------------

Let's try choice B

G(x) = x+4

G( F(x) ) = F(x)+4

G( F(x) ) = x^3-1 + 4

G( F(x) ) = x^3 + 3

Similar to choice A, this isn't the same as (x+4)^3-1. We can cross this off the list as well.

--------------

Now choice C

G(x) = x^3 - 1

G( F(x) ) = ( F(x) )^3 - 1

G( F(x) ) = (x+4)^3 - 1

We found the final answer.

The simplification of the expression [tex]xy-5x+y^2xy-5x+y ^2[/tex]  gives - 335.

Usually, simplification involves proceeding with the pending operations in the expression.

Simplification usually involves making the expression simple and easy to use later.

Given;

[tex]xy-5x+y^2xy-5x+y ^2[/tex]

Substitute x = -3 and y = 5.

[tex]-3\times 5-5\times -3+5^2\times -3\times 5-5\times -3+5 ^2[/tex]

= -15 + 15 - 375 + 15 + 25

= -335

Learn more about simplification;

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Answer:

Domain is all real numbers, and range is all numbers greater than or equal to -2.  If thee was anything you didn't understand let me know.  

Step-by-step explanation:

The domain is what x values work, or it may be better to say the horizontal axis.  is there any number you cannot use?  if you cannot tell, this is a parabola, like x^2.  Is there any number you cannot plug into x^2.  The answer is no, the domain for all parabolic functions is all real numbers.

The range you really want to look at visually here.  Range is y values you can get, or values on the vertical axis.  I would also compare it to x^2 again.  You should know you can make it as high as you want, here is the same.  but at -2, there is no point below that.  so the range is -2 and up

The other options are just specific numbers.  you can disprove those by choosing a number not on their lists.  For the domain literally any other number.  For range any number not on the list greater than -2