Answer:
1. 2 M
2. 2 M
Explanation:
1. Determination of the final concentration.
Initial Volume (V₁) = 2 L
Initial concentration (C₁) = 6 M
Final volume (V₂) = 6 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
6 × 2 = C₂ × 6
12 = C₂ × 6
Divide both side by 6
C₂ = 12 / 6
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
2. Determination of the final concentration.
Initial Volume (V₁) = 0.5 L
Initial concentration (C₁) = 12 M
Final volume (V₂) = 3 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
12 × 0.5 = C₂ × 3
6 = C₂ × 3
Divide both side by 3
C₂ = 6 / 3
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
A scientist observes the cells of a newly discovered animal under a
microscope. Which of the following cell parts is the scientist likely to find?
A. Cell membrane, chloroplasts, and a nucleus
B. Cell wall, cell membrane, and ribosomes
O C. Cell wall, chloroplasts, and lysosomes
D. Cell membrane, ribosomes, and a nucleus
Answer:
D
Explanation:
The rest have characteristics of a plant cell
Write the overall balanced equation for the reaction:
N2O4(g) + CO → NO(g) + CO2(g)+NO2(g)
Answer:
This reaction has infinite ways to be balanced
Explanation:
To balance this equation we can use the algebraic method:
N2O4(g) + CO → NO(g) + CO2(g)+NO2(g)
Where we write each molecule as a letter:
A + B → C + D + E
Then, we write the equations according the number of atoms of each molecule. That is:
Oxygen → 4A + B = C + 2D + 2E (1)
Nitrogen → 2A = C + E (2)
Carbon → B = D (3)
Then, we have to give 1 arbitral number for a letter. For example:
B = 1; D = 1
(1) 4A + 1 = C + 2 + 2E
4A = C + 2E + 1
2A = C + E (2) Twice (2):
4A = 2C + 2E
Subtracting (1) in (2)
C + 2E + 1 = 2C + 2E
C + 1 = 2C
1 = C
Si 1 = C:
4A + 1 = 1 + 2 + 2E
4A = 2 + 2E (1)
y:
2A = 1 + E (2)
Twice:
4A = 2 + 2E
As (1) and (2) are the same equation:
This reaction has infinite ways to be balancedFor example:
N2O4(g) + CO → NO(g) + CO2(g)+NO2(g)
how many atoms are in 14 moles of cadium
Answer:
14x6.02x10^23=8.428x10^23 atoms
Answer:
atoms are in 14 moles of cadmium. Cadmium is present in some foods and is emitted when fossil fuels like as coal and oil is used, smoking cigarettes. It is used in craft glazes, metal batteries, and coatings. We know that 1 mole of Cadmium (Cd contains) 6.023*1023 atoms, which is Avogadro's number
Explanation:
My swimming pool is rectangular (16 feet by 34 feet) and has a depth of 6 feet. Lets imagine that my pool water is full to the top and is heated by a laser that emits photons with a wavelength of 520 nm. The starting temperature of my pool is a chilly 52 degrees Celsius. How many moles of photons would be required to heat the pool to a balmy 80 degrees Celsius
Answer:
Number of moles of photons required = 5.04 × 10⁴ moles
Explanation:
The energy of a photon can be calculated from Planck's equation E = hc/λ
Where h = 6.63 × 10-³⁴ Js and c, the velocity of light = 3.0 × 10⁸ m/s
Energy of one mole of photons = N₀ × hc/λ
wavelength of photon, λ = 520 nm = 5.20 × 10-⁷ m
Energy of one mole of photons = 6.02 × 10²³ × 6.63 × 10−³⁴ × 3 × 10⁸/5.20 × 10-⁷
Energy of one mole of photons = 2.30 × 10⁵ J/mol
Energy required to raise the temperature of a given mass of a substance, E = mcΔT
Where m is mass of substance, c is specific heat capacity, ΔT is temperature difference
Mass ofnwternin the pool = volume × density
Volume of water = Volume of swimming pool
Volume of water = 16 × 34 × 6 ft³ = 3264 ft³
1 ft³ = 28316.8 cm³; 3264 ft³ = 28316.8 × 3264 = 92426035.2 cm³
Density of water = 1 g/cm³
Mass of water = 92426035.2 cm³ × 1 g/cm³ = 92426035.2g
ΔT = 80°C - 50°C = 30°C, c = 4.18 J/g/K
Energy required to raise 92426035.2 g water by 30° C = 92426035.2 × 4.18 × 30
Energy required = 1.16 × 10¹⁰ J
Hence, number of moles of photons required = 1.16 × 10¹⁰ J/2.30 × 10⁵ J/mol
Number of moles of photons required = 5.04 × 10⁴ moles
The pressure on 200 milliliters of a gas at constant
temperature is changed from 380 torr to 760 torr. The new
volume of the gas is
answerA) 100 mL
Explanation:
At constant temperature and number of moles, Using Boyle's law
Given ,
V₁ = 200 mL
V₂ = ?
P₁ = 60 kPa
P₂ = 120 kPa
The new volume of the gas is 100mL
Boyle's law is use to calculate the volume of a gas in relation with its pressure. The Boyle's law equation is as follows:
P1V1 = P2V2
Where;
P1 = initial pressure of the gas (torr)
P2 = final pressure of the gas (torr)
V1 = initial volume of the gas (mL)
V2 = final volume of the gas (mL)
According to the information of this question, the pressure on 200mL of a gas changed from 380 torr to 760 torr. Hence;
V1 = 200mL
V2 = ?
P1 = 380torr
P2 = 760torr
Using P1V1 = P2V2
V2 = P1V1/P2
V2 = (380 × 200) ÷ 760
V2 = 76000 ÷ 760
V2 = 100mL
Hence, the new volume of the gas is 100mL
Learn more: https://brainly.com/question/22467228
How many liters would you need to make a 0.8 M solution with 20 grams of lithium chloride?
Answer:
0.5875L
Explanation:
concentration = mole/ volume
n(LiCl) = 20 / (7 + 35.5) = 0.47 mol
volume = mole / conc.
volume = 0.47 /0.8
= 0.5875 dm³ = 0.5875L
Select the correct answer.
What is the molecularity of this elementary step?
A+ A+B-->C+D
A.
unimolecular
B.
bimolecular
c.
trimolecular
D.
tetramolecular
Answer: C not really sure thoo
100.0 g of water was placed in a simple, constant-pressure calorimeter. The temperature of the water was recorded as 295.0 K. A 20.0 g copper block was heated to 353.0 K and then dropped into the water in the calorimeter. What was the final temperature of the water if the specific heat capacities of copper is 0.385 J/g K
Answer:
[tex]296.05\ \text{K}[/tex]
Explanation:
[tex]m_w[/tex] = Mass of water = 100 g
[tex]c_w[/tex] = Specific heat of water = [tex]4.184\ \text{J/g K}[/tex]
[tex]m_c[/tex] = Mass of copper = 20 g
[tex]c_c[/tex] = Specific heat of copper = [tex]0.385\ \text{J/g K}[/tex]
[tex]\Delta T_w[/tex] = Temperature change in water = [tex](T-295)[/tex]
[tex]\Delta T_c[/tex] = Temperature change in cooper = [tex](353-T)[/tex]
T = Final temperature of the system
The heat balance of the system is given by
[tex]m_wc_w\Delta T_w=m_cc_c\Delta T_c\\\Rightarrow 100\times 4.184\times (T-295)=20\times 0.385\times (353-T)\\\Rightarrow 418400\left(T-295\right)=7700\left(353-T\right)\\\Rightarrow 418400T-123428000=2718100-7700T\\\Rightarrow T=\frac{1261461}{4261}\\\Rightarrow T=296.05\ \text{K}[/tex]
The final temperature of the water is [tex]296.05\ \text{K}[/tex].
The final temperature of the water when placed in a calorimeter is 296.05K
HOW TO CALCULATE FINAL TEMPERATURE:
The final temperature of water placed in a calorimeter can be calculated using the following expression:Q(water) = - Q(copper)(m × c × ∆T) water = - {m × c × ∆T} copperWhere;
Mass of water = 100 gSpecific heat of water = 4.184 J/g KMass of copper = 20 gSpecific heat of copper = 0.385 J/g KTemperature change in water = T - 295KTemperature change in copper = T - 353K100 × 4.184 × (T - 295) = - {20 × 0.385 × (T - 353)}418.4T - 123428 = - (7.7T - 2718.1)418.4T - 123428 = -7.7T + 2718.1418.4T + 7.7T = 123428 + 2718.1426.1T = 126146.1T = 126146.1 ÷ 426.1T = 296.05KTherefore, the final temperature of the water when placed in a calorimeter is 296.05K.Learn more at: https://brainly.com/question/10987564?referrer=searchResults
A 3mL sample of a 200 Molar solution is left open on a lab
counter for two weeks, after which the concentration of the solution is 6 M. What is the new volume of the solution?
Answer: New volume of the solution is 100 mL.
Explanation:
Given: [tex]V_{1}[/tex] = 3 mL, [tex]M_{1}[/tex] = 200 M
[tex]M_{2}[/tex] = 6 M, [tex]V_2[/tex] = ?
Formula used to calculate the new volume of solution is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\200 M \times 3 mL = 6 M \times V_{2}\\V_{2} = \frac{200 M \times 3 mL}{6 M}\\= 100 mL[/tex]
Thus, we can conclude that new volume of the solution is 100 mL.
Question 3 of 10
Which best explains why the sun maintains its size and shape?
A. Pressure caused by high temperatures are balanced by gravity.
B. The sun burns from its core to its surface.
C. Forces exerted by orbiting planets cause the sun to rotate.
SUBMIT
Answer:A
Explanation:
What is the difference between chemical change and physical change
Answer:
In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not. However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed.
Laughing gas can decompose into nitrogen and oxygen
Nitrous oxide decomposes into nitrogen and oxygen, according to 2 N2O (g) -> 2 N2 (g) + O2 (g). ... In an experiment, a stream of N2O is passed through a tube 25 mm in diameter and 20 cm long. The flow rate of the gas is 0.75 L/min.
The formula for the pH of a solution of hydronium ions is given by the logarithmic equation pH= -log[h3o^+], where [H3o^+] is the hydronium ion concentration. Find the pH of a certain agricultural product with the hydronium ion concentration of 4.7x10^-4
The pH is =?
Answer:
pH = 3.3
Explanation:
Step 1: Given data
Concentration of hydronium ions in the agricultural product ([H₃O⁺]): 4.7 × 10⁻⁴ M
Step 2: Calculate the pH of the agricultural product
We will use the definition of pH.
pH = -log [H₃O⁺]
pH = -log 4.7 × 10⁻⁴
pH = 3.3
Since the pH < 7, the agricultural product is acidic.
If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?
Answer:
412 g Cl₂
General Formulas and Concepts:
Atomic Structure
Reading a Periodic TableMolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:
Step 1: Define
[Given] 3.50 × 10²⁴ molecules Cl₂
[Solve] grams Cl₂
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})[/tex][DA] Divide/Multiply [Cancel out units]: [tex]\displaystyle 412.072 \ g \ Cl_2[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
412.072 g Cl₂ ≈ 412 g Cl₂
Pls help ASAP it’s timing meeee!!!!!
Which of the following accurately describes the function of the muscular
system?
O A. To prevent and fight disease
B. To provide support for the body
C. To get rid of wastes and excess water
D. To allow the body to move
A chemistry student heated 2.255 g of oxygen gas in the presence of 5.145
Answer:
a
Explanation:
Final volume of a .50 M H3PO4 solution prepared from 50 mL of a 6 M H3PO4 solution
Answer:
600 mL
Explanation:
From the question given above, the following data were obtained:
Initial concentration (C₁) = 6 M
Initial volume (V₁) = 50 mL
Final concentration (C₂) = 0.5 M
Final volume (V₂) =?
Using the dilution formula (i.e C₁V₁ = C₂V₂) we can obtain the final volume as illustrated below:
C₁V₁ = C₂V₂
6 × 50 = 0.5 × V₂
300 = 0.5 × V₂
Divide both side by 0.5
V₂ = 300 / 0.5
V₂ = 600 mL
Thus, the final volume is 600 mL
करताह!
गर्मियों में घड़े का जल ठंडा क्यों होता है?
Answer:
I don't understand the question
Explanation:
what is your name
Answer the above pic
i bet no one can solve this correctly with steps
Answer:
solution given:
log k=4-[tex] \frac{200}{t} [/tex]
so,
On comparison
∆S°/R = 4
∆ S° = 4R
mousam brother is correct
hope it helps you have a good day
g A student determines the number of moles of water in a hydrated metal oxide by weighing a clean, dry crucible and lid while the crucible is empty, then reweighing the crucible and lid with a sample of the hydrate, heating the crucible and lid with a Bunsen burner and then reweighing the crucible and lid with the sample after cooling to room temperature. Which error will result in too high a value for the amount of water of hydration
The question is incomplete, the complete question is;
A student determines the number of moles of water in a
hydrated metal oxide by weighing a clean, dry crucible
and lid while the crucible is empty, then reweighing the
crucible and lid with a sample of the hydrate, heating the
crucible and lid with a Bunsen burner and then
reweighing the crucible and lid with the sample after
cooling to room temperature. Which error will result in
too high a value for the amount of water of hydration?
(A) The heating is conducted only once instead of the
three times recommended by the procedure.
(B) The lid is left off the crucible when it is weighed
with the hydrated oxide.
(C) The metal oxide reacts partially with oxygen in the
air, forming a compound in a higher oxidation state.
(D) Some of the heated oxide is spilled from the crucible
before it can be weighed.
Answer:
(D) Some of the heated oxide is spilled from the crucible
before it can be weighed.
Explanation:
It is possible to determine the number of moles of water in a hydrated metal oxide by weighing a clean, dry crucible and lid while the crucible is empty, then reweighing the crucible and lid with a sample of the hydrate. The crucible and lid with the sample are heated, cooled and reweighed.
As this process is going on, suppose some of the heated oxide is spilled from the crucible, then the mass of heated or anhydrous oxide decreases leading to a consequent increase in the number of moles of water in the hydrated metal oxide, hence the answer above.
The too high a value for the amount of water of hydration error is occur due to heating of given hydrated sample.
What is hydrated compounds?
Hydrated compounds are those compounds in which water molecule is present with the normal compound.
To get the correct value of weight of hydrated compound, first we have to weigh the empty crucible and lid and then with sample of compound in the crucible and lid. After this substract empty weigh of crucible & lid from the sample-crucible-lid weigh. If we substract the weigh from heated sample crucible and lid, then we get the error because the hydrated water molecule may decompose due to heating and moles of water increases.
Hence, error will occur if we heat the sample.
To know more about hydrated compound, visit the below link:
https://brainly.com/question/16275027
where do you think water vapor in air comes from?
How does publishing in scientific journals help ensure that science leads to
reliable results?
A. It allows results to be reviewed and reproduced by other
scientists.
B. It allows the public to decide if science is worthwhile.
C. It shows which experiments are the most popular with scientists.
D. It gives scientists a reason to do more experiments.
Answer:
A. it allows results to be reviewed and reproduced by other scientists.
What is the energy of a photon?
A. A photon has no energy.
B. The energy of a photon is hxc.
c. The energy of a photon is hx 2.
D. The energy of a photon is h* f.
What will change more solid NiCl2 is added
How many Liters are in 98.2 moles of neon?
Answer:
2200 L
Explanation:
There are 22.4 L in 1 mole of neon so if you have 98.2 L, then you have 98.2 mole x (22.4 L/mole) = 2200 L of neon.
Terry, a student, performs a titration. He completes these steps as part of his titration procedure: 1. He cleans and rinses a burette with standardized base. 2. He fills the burette with standardized base solution. 3. He reads and records the initial burette volume. 4. He adds a base from the burette to an acid. 5. He observes a color change in the Erlenmeyer flask. 6. He stops the addition of base from the burette. 7. He reads and records the final burette volume. Which steps will provide information needed to calculate the volume of base needed to reach the equivalence point? A. 1 and 6 B. 3 and 7 C. 3, 4, and 6 D. 1, 2, and 7
Answer:
D
Explanation:
D is the answer because 2 is needed to know
Answer:
B) 3 and 7
Explanation:
i just took the test
You have a cold gas of atoms, and you observe that if you shine light consisting of photons with energy 10 eV through the gas, some free electrons are observed, implying that a photon of this energy is able to ionize an atom in the gas. (a) If you find that the emitted electrons from the gas have a kinetic energy of 1 eV, what is the ionization energy of the cold atom
Answer:
Ionization Energy = 9 eV
Explanation:
If we apply the law of conservation of energy to the given situation, we will get the following equation:
[tex]Energy\ of\ Photon = Ionization\ Energy + Kinetic\ Energy\ of\ Electron\\[/tex]
where,
Energy of Photon = 10 eV
Ionization Energy = ?
Kinetic Energy of Electrons = 1 eV
Therefore,
[tex]10\ eV = Ionization\ Energy + 1\ eV\\Ionization\ Energy = 10\ eV - 1\ eV[/tex]
Ionization Energy = 9 eV
a. Explain why the pie pans flew off the van de Graaf generator
b. Give a detailed explanation of why the rabbit fur and the plastic rod were attracted to each other after we rubbed them together but not before
c. Describe two things you could change to increase the force of electrical attraction between two objects (this is about Coluomb's Law).
Answer:
Static energy is an energy between two charges.
Explanation:
a). A van de Graff generator builds up a positive electric charge on the dome by separating the negative static electric charges from the positive static charge using a quickly moving belt. The positive charge collects on the large metal dome of the generator. When the charge builds up is large enough, a lighting like spark can shoot from the dome to a grounded discharge rod.
Like electric charges always repel each other, and oppositely electric charges will attract each other. When the aluminum pans are being charged by the van de Graff generator, then each of them attain the same positive polarity similar with the dome. Thus, positive charge starts to accumulate over the surface of each of the pie pan. Each aluminum pan repels the others. These repulsive forces between the pans are so strong that they succeed in overcoming the gravity force and thus the top of the pan is pushed away from the generator's dome.
b). Static electricity is produced by a concentration of negative and positive electric charges. Like charges pushes away each other while unlike charges pulls each other.
Objects generally have same numbers of positive charges as well as negative charges. And if there is any small imbalance in numbers of the charges on the object, it is charged.
Negative charges easily torn away from the materials like the fur or hair. Also, the negative charges are held on other materials like the plastics. If we rub a plastic rod with fur, the negative charges will get transferred from fur to rod. The rod gets negatively charged and the fur is positively charged. As a result, the rabbit fur and the plastic rod were attracted to each other.
c). Coulomb's law stated that :
[tex]$F=\frac{KQ_1Q_2}{d^2}$[/tex] .............(i)
where, [tex]$Q_1$[/tex] and [tex]$Q_2$[/tex] are the charges of two objects d is the distance between two objects.
As from the above equation, we can say that force of electrical attraction between two objects depends on the charges and the distance between objects.
1. The electrical force between two charged object is inversely proportional to the distance of separation between two objects.
Decreasing separation distance (d) between the objects will increase its attraction force.
2. And, increasing the charges of two objects(+ve and -ve) increases the force of attraction between two objects.
Given that the nucleophilic substitution reaction used 5.0 mL of t-pentyl alcohol and 12.0 mL of conc. hydrochloric acid to produce t-pentyl chloride, what is the theoretical yield of t-pentyl chloride, in grams
Answer:
4.90 g
Explanation:
Given that:
volume of t-pentyl alcohol = 5 mL
the standard density of t-pentyl alcohol = 0.805 g/mL
Recall that:
density = mass(in wt) /volume
mass = density × volume
mass = 0.805 g/mL × 5 mL
mass = 4.03 g
Volume of HCl used = 12 mL
The reaction for this equation is shown in the image attached below.
From the reaction,
88.15 g of t-pentyl alcohol reacts with concentrated HCl to yield 106.59 g pf t-pentyl chloride.
4.03 g of t-pentyl alcohol forms,
[tex]= \dfrac{106.59 \ g \times 4.03 \ g}{88.15 \ g}[/tex] of t-pentyl chloride.
Therefore,
Theoretical yield of t-pentyl chloride = 4.90 g
