[tex] \LARGE{ \boxed{ \red{ \rm{Answer}}}}[/tex]
☃️ Chemical formulae ➝ [tex]\sf{Ca_3(PO_4)_2}[/tex]
How to find?For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
[tex] \boxed{ \sf{No. \: of \: moles = \frac{Given \: weight}{Molecular \: weight} }}[/tex]
Solution:Atomic weight of elements:
Ca = 40P = 31O = 16❍ Molecular weight of [tex]\sf{Ca_3(PO_4)_2}[/tex]
= 3 × 40 + 2 × 31 + 8 × 16
= 120 + 62 + 128
= 310 g/mol
❍ Given weight: 20 g
Then, no. of moles,
⇛ No. of moles = 20 g / 310 g mol‐¹
⇛ No. of moles = 0.0645 moles
⚘ No. of moles of Calcium phospate in the given weight = 0.0645 moles.
━━━━━━━━━━━━━━━━━━━━
Answer:
The answer is 0.08molExplanation:
To find the number of moles in calcium phosphate we use the formula
[tex]n \: = \frac{m}{M} [/tex]
where
n is the number of moles
M is the molar mass
m is the mass of the substance
To find the number of moles we must first find the molar mass
Chemical formula for calcium phosphate is
Ca3( PO4)2
Ca = 40 , P = 31 , O = 16
So the Molar mass of calcium phosphate is
M( Ca3( PO4)2 ) = (20×3) + 2( 31 + (16×4)
= 60 + 2( 31 + 64)
= 60 + 2(95)
= 60 + 190
Molar mass of calcium phosphate =
250g/mol
Mass = 20 g
So we have
[tex]n = \frac{20g}{250g/mol} [/tex]
We have the final answer as
n = 0.08 molHope this helps you