Calculate the time it takes for the voltage across the resistor to reach 17.0 v after the switch is closed.

Answers

Answer 1

In conclusion,it is not possible to calculate the time it takes for the voltage across the resistor to reach 17.0 V after the switch is closed.

To calculate the time it takes for the voltage across the resistor to reach 17.0 V after the switch is closed, we need to consider the time constant of the circuit. The time constant, denoted as τ (tau), is a measure of how quickly the voltage across a capacitor or an inductor changes.
In this case, we are dealing with a resistor, so we will focus on the time constant of an RC circuit. The time constant (τ) of an RC circuit is given by the product of the resistance (R) and the capacitance (C), τ = R * C.
Once we have the time constant (τ), we can calculate the time it takes for the voltage across the resistor to reach 17.0 V using the following formula:
t = τ * ln(Vf/Vi)
Where t is the time, ln denotes the natural logarithm, Vf is the final voltage (17.0 V), and Vi is the initial voltage (0 V in this case, as the switch is closed).
Let's say the resistance (R) is 10 Ω and the capacitance (C) is 0.1 F. Plugging these values into the formula,

we get:
τ = R * C

= 10 Ω * 0.1 F

= 1 second.
Now, substituting the values into the time formula, we have:
t = 1 second * ln(17.0 V/0 V)
Since ln(17.0 V/0 V) is undefined (division by zero), we cannot directly calculate the time it takes for the voltage to reach 17.0 V.
In conclusion, without additional information, it is not possible to calculate the time it takes for the voltage across the resistor to reach 17.0 V after the switch is closed.

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Related Questions

you blow across the open mouth of an empty test tube and produce the fundamental standing wave in the 14.0-cmcm-long air column in the test tube, which acts as a stopped pipe. the speed of sound in air is 344 m/sm/s.

Answers

When you blow across the open mouth of an empty test tube, you create a standing wave in the 14.0 cm-long air column inside the tube. This column of air acts as a stopped pipe. The speed of sound in air is given as 344 m/s. the frequency of the fundamental standing wave in the test tube is 614.3 Hz.

To find the frequency of the fundamental standing wave in the test tube, we can use the formula:
frequency = speed of sound / wavelength

Since the test tube is acting as a stopped pipe, we know that the length of the air column is equal to a quarter of the wavelength of the fundamental standing wave.
So, the wavelength of the fundamental standing wave in the test tube is four times the length of the air column, which is 4 * 14.0 cm = 56.0 cm.

Now, we can substitute the values into the formula:
frequency = 344 m/s / 56.0 cm

Before we can continue, we need to convert the wavelength from centimeters to meters:
56.0 cm = 0.56 m

Now, we can substitute the values and solve for the frequency:
frequency = 344 m/s / 0.56 m = 614.3 Hz

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4.45 mol of an ideal gas is expanded from 431 k and an initial pressure of 4.20 bar to a final pressure of 1.90 bar, and cp,m=5r/2. calculate w for the following two cases:

Answers

In both cases, the work done by the gas is 15244.6 J.

To calculate the work done by the gas in the two cases, we need to use the ideal gas law and the equation for work done in an expansion.

The ideal gas law is given by:

PV = nRT

The equation for work done in an expansion is given by:

w = -ΔnRT

Let's calculate the work done in each case.

Case 1:

Initial pressure (P1) = 4.20 bar

Final pressure (P2) = 1.90 bar

Number of moles (n) = 4.45 mol

Temperature (T) = 431 K

To calculate the work done, we need to find the change in moles (Δn):

Δn = n2 - n1

Δn = 0 - 4.45

Δn = -4.45 mol

Substituting the values into the equation for work done:

w = -ΔnRT

w = -(-4.45)(8.314 J/(mol·K))(431 K)

w = 15244.6 J

Therefore, in case 1, the work done by the gas is 15244.6 J.

Case 2:

Initial pressure (P1) = 4.20 bar

Final pressure (P2) = 1.90 bar

Number of moles (n) = 4.45 mol

Temperature (T) = 431 K

To calculate the work done, we need to find the change in moles (Δn):

Δn = n2 - n1

Δn = 0 - 4.45

Δn = -4.45 mol

Substituting the values into the equation for work done:

w = -ΔnRT

w = -(-4.45)(8.314 J/(mol·K))(431 K)

w = 15244.6 J

Therefore, in case 2, the work done by the gas is also 15244.6 J.

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Final answer:

One can calculate work done during isobaric or reversible adiabatic expansion of an ideal gas using thermodynamics principles, the ideal gas law, given values for pressure, volume, and mole quantity, and the specific heat capacity at constant pressure.

Explanation:

This problem is about thermodynamics and ideal gases. It can be solved by utilizing the first law of thermodynamics and the ideal gas law, along with the definition of isobaric, or constant pressure process.

The quantity w represents the work done by or on the system. In thermodynamics, work done by an expansion is generally considered to be negative. First, we need to convert our pressure to the same units as R (the ideal gas constant), which in this case is joules, so 1 bar = 100000 Pa.

The work done (w) during an isobaric process is given by w=-P(delta)V, where delta V is the volume change. Finding V1 is done using the ideal gas law equation PV=nRT. Because the process is isobaric, P, n, and R are all constant, simplifying the equation. Solving it, we then substitute back in the values we determined into the isobaric work equation.

The situation is more complex with cp,m=5r/2, which signifies a reversible adiabatic process. In this case, the work done by the system is described by a more complicated equation, which includes an integration over volume and requires knowledge of calculus.

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