Answer:
[tex]EA = \frac{21 \times 15}{7} = 45 \\ { \tt{ \frac{21}{7} = \frac{x}{45} }} \\ x = 135[/tex]
please help
Evaluate 3^x for x = −2, x = 1, and x = 3.
A)1∕3, 0, 9
B) 9, 3, 27
C) 1∕9, 3, 27
D)1∕9, 9, 27
Step-by-step explanation:
1/3,0,9
9,3,27
1/9,3,27
The probability of drawing a red candy at random from a bag of 25 candies is 2/5.
After 5 red candies are removed from the bag, what is the probability of randomly drawing a red candy from the bag?
Please include an explanation!
Answer:
1/4
Step-by-step explanation:
Probability of red * number of candies
2/5 * 25 = 10
There are 10 red candies
25-10 = 15
There are 15 other candies
Remove 5 red
10-5 = 5 red candies
Now we have 5 red candies and 15 other candies= 20 candies
P(red) = red/total = 5/20 = 1/4
PLEASE HELP!! WHOEVER HELPS FIRST AND GETS IT CORRECT GETS BRAILIEST!! By the way, TWO people need to answer so I can mark brainliest.
Answer:
what's is the question anyway
A supervisor records the repair cost for 22 randomly selected VCRs. A sample mean of $75.50 and standard deviation of $18.07 are subsequently computed. Determine the 99% confidence interval for the mean repair cost for the VCRs. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
The t value for 99% CI for 21 df is 2.831.
The critical value that should be used in constructing the confidence interval is (64.593, 86.407).
Step-by-step explanation:
Now the sample size is less than 30 and also population standard deviation is not known.
Then we will use t distribution to find CI
t value for 99% CI for 21 df is TINV(0.01,21)=2.831
The margin of error is [tex]E=t\times\frac{s}{\sqrt{n}}\\\\=2.831\times\frac{18.07}{\sqrt{22}}\\\\=10.907[/tex]
Hence CI is[tex]CI=\overline{x} \pm E\\\\ =75.50 \pm 10.907\\\\=(64.593,86.407 )[/tex]
Uche is a cartographer. He picks a scale to fit a map of India onto a page of an atlas. The page is 121212 by 121212 inches, with 0.750.750, point, 75 inch margins on all 444 sides. India measures 3{,}2143,2143, comma, 214 kilometers from north to south and 2{,}9332,9332, comma, 933 kilometers from west to east. Uche wants the longest dimension of India to fit exactly in between the margins of the page. If kkk is the number of kilometers per inch in Uche's scale, which equation best models the situation
The scale ratio of a point A to another point B is the division of the length of B by the length of A. The best equation that models the situation is: [tex]10.5k= 3214[/tex]
The page dimension is:
[tex]Length = 12[/tex]
[tex]Width = 12[/tex]
The length and the width of Uche's book are equal; this means the pages of Uche's book have the shape of a square
The margin of 0.75 on either sided means the usable dimension is:
[tex]Length = 12 - 2 * 0.75 =10.5[/tex]
The dimension of India is:
[tex]Length = 3214[/tex]
[tex]Width =2933[/tex]
The longest side in India's dimension is:
[tex]Longest = 3214[/tex]
From Uche's book, the longest dimension is:
[tex]Longest = 10.5[/tex]
So, the scale equation is:
k * longest length of Uche's book = longest side of India
This gives:
[tex]k * 10.5 =3214[/tex]
[tex]10.5k =3214[/tex]
Read more about scale ratio at:
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A motel has a policy of booking as many as 150 guests in a building that holds 140. Past studies indicate that only 85% of booked guests show up for their room. Find the probability that if the motel books 150 guests, not enough seats will be available.
Answer:
0.0015 = 0.15% probability that if the motel books 150 guests, not enough seats will be available.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].
150 guests booked:
This means that [tex]n = 150[/tex]
85% of booked guests show up for their room.
This means that [tex]p = 0.85[/tex]
Is the normal approximation suitable:
[tex]np = 150(0.85) = 127.5[/tex]
[tex]n(1-p) = 150(0.15) = 22.5[/tex]
Both greater than 10, so yes.
Mean and standard deviation:
[tex]\mu = E(X) = np = 150*0.85 = 127.5[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{150*0.85*0.15} = 4.3732[/tex]
Find the probability that if the motel books 150 guests, not enough seats will be available.
More than 140 show up, which, using continuity correction, is [tex]P(X > 140 + 0.5) = P(X > 140.5)[/tex], which is 1 subtracted by the p-value of Z when X = 140.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{140.5 - 127.5}{4.3732}[/tex]
[tex]Z = 2.97[/tex]
[tex]Z = 2.97[/tex] has a p-value of 0.9985.
1 - 0.9985 = 0.0015.
0.0015 = 0.15% probability that if the motel books 150 guests, not enough seats will be available.
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
f(x)= sqrt of x [0,9]
c =
Answer:
9/4
Step-by-step explanation:
f(x) is continuous and differentiable on (0,9).
We want to find c using the following equation.
f'(c)=(f(9)-f(0))/(9-0)
This will require us to find f'(x) first.
f(x)=sqrt(x) is the same as f(x)=(x)^(1/2)
Using power rule to differentiate this gives f'(x)=(1/2)(x)^(1/2-1) or simplified f'(x)=(1/2)x^(-1/2) or f'(x)=1/(2x^(1/2)).
So we want to solve:
(1/2)c^(-1/2)=(f(9)-f(0))/(9-0)
Simplify denominator on right:
(1/2)c^(-1/2)=(f(9)-f(0))/9
This will require us to find f(9) and f(0).
If f(x)=sqrt(x), then f(9)=sqrt(9)=3 and f(0)=sqrt(0)=0.
So we have the following equation so far:
(1/2)c^(-1/2)=(3-0)/9
Simplify numerator on right:
(1/2)c^(-1/2)=3/9
Multiply both sides by 2:
c^(-1/2)=6/9
Raise both sides to the -2 power:
c^(1)=(6/9)^(-2)
Note c^1=c:
c=(6/9)^(-2):
Note negative exponent means to find reciprocal of base to change exponent to opposite
c=(9/6)^2
Apply the second power:
c=81/36
Reduce by dividing top and bottom by 9:
c=9/4
This means the slope of the tangent to the curve f at x=9/4 is the same value as the slope of the secant line going through points (0,0) and (9,3).
Also 9/4 is between 0 and 9... According to the theorem we were suppose to get a value c between x=0 and x=9.
Confirmation:
Slope of the secant line is (3-0)/(9-0)=3/9=1/3.
Slope of the tangent line to curve f at x=9/4.
f'(x)=(1/2)x^(-1/2)
f'(9/4)=(1/2)(9/4)^(-1/2)
f'(9/4)=(1/2)(3/2)^(-1)
f'(9/4)=(1/2)(2/3)
f'(9/4)=1/3
They are indeed equal values (talking about the 1/3 from the secant and the tangent.)
9(5x + 1) ÷ 3y
From the expression above, provide an example of each of the following: sum, term, product, factor, quotient, and coefficient. If any are not present, write "not present." (ill give brainiest and if there is any troll answers I will report and take this down )
Answer
3y(5x+1)
Step-by-step explanation:
9*(5x+1)/3y
3(5x+1)y
Answer:
Step-by-step explanation:
sum: 5x + 1
factor: 3 which divides into 9 evenly
quotient: the answer to division: 9(5x + 1)/(3y) = 3(5x +1)/y
coefficent: this depends on what you have been told. In my day, there were two kinds of coefficents
numerical: 5 and 3
literal: x and y
Given that (-7,3) is on the graph of f(x), find the
corresponding point for the function
f(x) +5.
Enter the correct answer.
OOH
DONE
Clear all
?
Is x=-2 a solution for the equation below?
Answer:
no
Step-by-step explanation:
-7+x^2-3x = 9+x-10
-7+(-2)^2-3*(-2) 9+(-2)-10
-7+4+6 9-12
3 > -3
if we substitute -2 to x, answer is not equal
Answer:
x= -2
-7 +x^2 - 3x = 9 +x - 10
-7 + (-2)^2 -3×(-2) = 9 + (-2) -10
-7 +4 +6 = 9 - 2 - 10
-7+10=9-12
3 =-3
Don't blame me if this is incorrect:)
An just finished taking statistics, and wants to do a survey on the average salary of Spring 2019 HCC graduates. She calculates that the standard error of the mean is $128.13 after she surveyed a group of students who reported an annual income of $43,650 and she knows the population standard deviation is $2,050, how many students were randomly sampled by An?
Answer:
The appropriate answer is "256".
Step-by-step explanation:
Given:
Standard error,
SE = 128.13
Standard deviation,
[tex]\sigma[/tex] = $2050
As we know,
⇒ [tex]SE = \frac{\sigma}{\sqrt{n} }[/tex]
or,
⇒ [tex]\sqrt{n}= \frac{\sigma}{SE}[/tex]
By substituting the values, we get
[tex]=\frac{2050}{128.13}[/tex]
[tex]=\frac{205000}{12813}[/tex]
[tex]n = (\frac{205000}{12813} )^2[/tex]
[tex]=255.98[/tex]
or,
[tex]=256[/tex]
please help, will give brainliest for correct answer
ain't it just 3 for each one unless i'm missing something
8 meters for every 2inches what is the area of 144 meters squared
9514 1404 393
Answer:
9 square inches
Step-by-step explanation:
The area is proportional to the square of the linear scale factor. We can use this to write the proportion ...
A/(144 m²) = ((2 in)/(8 m))²
A = (144·4/64) in² = 9 in²
The area representing 144 square meters is 9 square inches.
Divide into two triangles in a straight line
Step-by-step explanation:
I am not sure but is this question like this
if it's not i am sorry
f (-10) = ?
Evaluate piecewise functions
Answer:
f(- 10) = 150
Step-by-step explanation:
f(- 10) with t = - 10 corresponds to t ≤ - 10 with f(t) = t² - 5t , then
f(- 10) = (- 10)² - 5(- 10) = 100 + 50 = 150
for t=-10
f(t)=t²-5tSo
f(-10)
(-10)²-5(-10)100+50150Solve for x
A. 9
B. 10
C. 42
D. 12
Answer:
Option D, 12
Step-by-step explanation:
4x-8=80/2
or, 4x-8=40
or, 4x=48
or, x=12
Answer:
Given:-
m∠DEF= (4x-8) °
m DE= 80°
Using a property :- m ∠DEF= 1/2 (m DE)
[tex](4x-8)[/tex] ° [tex]= 1/2 (80)[/tex]
[tex](4x-8)[/tex]° [tex]=(40)[/tex] °
[tex]4x-8=40[/tex]
Add 8 to both sides:-
[tex]4x=48[/tex]
Divide both sides by 4:-
[tex]\frac{4x}{4}=\frac{48}{4}[/tex]
[tex]x=12[/tex]
OAmalOHopeO
Which side is the “adjacent” side to θ?
Answer:
third answer "a"
Step-by-step explanation:
What error, if any, did Noah make?
Answer:
breathing, jk buddy
Step-by-step explanation:
PLEASE HELPPPPPPPPP!!!!!!!!!!!
Amanda has 1 3/4yds of red ribbon and 7/8yds of green
ribbon. What is the total amount of ribbon that
Amanda has? (write answer as a fraction)
Answer:
21/8 yds or 2 5/8 yds
Step-by-step explanation:
First turn 1 3/4 yards into an improper fraction so you can add it to 7/8 yards.
1 3/4 as an improper fraction is 7/4 yds
7/4 yds = 14/8 yds
14/8 yds + 7/8 yds = 21/8 yds
So the total amount of ribbon Amanda has is 21/8 yds or 2 5/8 yds
HELP PLS !!! Pls pls pls pls pls pls pls pls pls
Answer:
x=7
Step-by-step explanation:
6x+11=7x+4
If a triangular pyramid has a base area of 10ft and a height of 6ft, what is the volume?
. 20ft^3
. 40ft^3
.60ft^3
.80ft^3
.120ft^3
Answer: 20 ft³
Step-by-step explanation:
volume of triangular pyramid = [tex]\frac{1}{3} bh[/tex]
b = base area = 10 fth = height = 6 ftTherefore, the volume is:
[tex]\frac{1}{3} *10*6=\frac{1}{3}*60=\frac{60}{3}=20[/tex]
Which quadrilateral has equal diagonals
Select one:
a. trapezoid
b. rectangle
c. parallelogram
d. rhombus
Answer:
Option b: Rectangle
Explanation:
Give branliest pls ;)
Identify the segments that are parallel, if any, if ∠ADH≅∠ECK.
A. AE || CB
B. AD|| CB
C. none of these
D. AC|| CD
9514 1404 393
Answer:
C. none of these
Step-by-step explanation:
The given information tells us ΔACD is isosceles, but gives no information about any lines that might conceivably be parallel.
if there are 5 routes to travel between A and B, how many options are there for a person to travel form A to B and retrun back?
Answer:
25
Step-by-step explanation:
in a group of 60 students, 30 can speak nepali only and 15 can speak English only how many can speak english and nepali students
Answer:
45 is the Answer
Step-by-step explanation:
Hope its helpful
Select the correct answer.
What is V200in simplest form?
OA. 2/10
OB.
1072
O C. 100/2
OD
20/10
Darot
Answer:
It is 10√2
Step-by-step explanation:
[tex] = \sqrt{200} \\ = \sqrt{2 \times 100} \\ = ( \sqrt{2} ) \times ( \sqrt{100} ) \\ = \sqrt{2} \times 10 \\ = 10 \sqrt{2} [/tex]
Find all complex solutions of 2x^2+x+6=0. (If there is more than one solution, separate them with commas.)
Answer:
x=-1/4+i*sqrt(47)/4 and x=x=-1/4-i*sqrt(47)/4
Step-by-step explanation:
Using quadratic formula, x=(-1±sqrt(1-48))/4.
x=-1/4+i*sqrt(47)/4 and x=x=-1/4-i*sqrt(47)/4
Answer:
If you do not understand any steps, please feel free to comment down below.
which of the following expressions are equivalent to 36x + 24y? choose all that apply
6x (6+4y) 6(6x + 4y) 12(36x + 24y) 12(3x + 2y) 4y(9x + 6) 4(9x + 6y)
The following expressions are equivalent to 36x + 24y is 6(6x+4y).
6x(6+4y)
6(6x+4y)
12(3x+2y)
4(9x+6y)
We have,
What is the expression?The expression consists of numbers and arithmetic operators. It does not contain equality or inequality symbols. The expression consists of unknown variables
36x + 24y
=6(6x)+6(4y)
=6(6x+4y)
Therefore, The following expressions are equivalent to 36x + 24y is 6(6x+4y).
To learn more about the expression visit:
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Use the graph of the parabola to identify the domain and range of the function.
Answer:
C
Domain (-x,x): (-inf, inf)
Range (-y,y): [1, 0)
Step-by-step explanation:
Domain is -x to x which is the lowest x value marked to the parabola to the highest. Since their are arrows indicating that the parabola continues both ways, the domain is infinite both ways. The range has the endpoint of one and the continuation of 0 (you can tell by the brackets [], (), [), or (]; [ <- endpoint; ( or ) <- continuation), the range is [1, 0). :)