Can any one you help me with this ?

Step-by-step explanation:

Triangle LNM is an adjecent interior angle

Answer:

I think it's C

Step-by-step explanation:

Let me know if it's incorrect.

Answer:

.

Step-by-step explanation:

.

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Answer:

  True

Step-by-step explanation:

Your calculator can tell you this is true. Or, you can simplify the given expression:

  [tex]\left(\dfrac{32}{3125}\right)^{2/5}=\left(\dfrac{2^5}{5^5}\right)^{2/5}=\dfrac{2^2}{5^2}=\boxed{\dfrac{4}{25}}[/tex]

__

The applicable rule of exponents is (a^b)^c = a^(bc).

9514 1404 393

Answer:

  p(x) = x³ -3x²+4x -2

Step-by-step explanation:

When the polynomial has real coefficients, the complex roots come in conjugate pairs. You are given one root as 1+i, so there is another that is 1-i.

Each root r gives rise to a factor (x -r). Then the three roots tell you the factorization is ...

  p(x) = (x -1)(x -(1+i))(x -(1-i))

The last two factors can be recognized as the factors of the difference of squares:

  ((x -1) +i)((x -1) -i) = (x -1)² -i²

  = (x² -2x +1) -(-1) = x² -2x +2

Now the whole polynomial can be seen to be ...

  p(x) = (x -1)(x² -2x +2) = x(x² -2x +2) -1(x² -2x +2)

  p(x) = x³ -2x² +2x -x² +2x -2 . . . . eliminate parentheses

  p(x) = x³ -3x²+4x -2

Answer:

i cant see the image

Step-by-step explanation:

Answer:

b. mutually exclusive.

Step-by-step explanation:

The given description is an illustration of mutually exclusive events.

Take for instance, when you roll a die;

It is impossible to have an outcome of 2 and 6 at the same time; these means that 2 and 6 are mutually exclusive.

In a nutshell, when two or more sates of events/states of nature can not happen at the same time; such events/states of nature are mutually exclusive.

Answer:

A. (–2, 4), one, three

Step-by-step explanation:

For a linear equation:

y = a*x + b

the point-slope form is:

(y - y₁) = m*(x - x₁)

Where we know that this line has the slope m, and passes through the point (x₁, y₁)

In this case, the equation:

(y + 2) = –1/3(x – 4)

is already in the point-slope form.

here we have:

y₁ = -2

x₁ = 4

then the point is (-2, 4)

m = -(1/3)

m = -1/3 means that when we move 3 units to the right, we need to move one unit down. (or the inverse, we can move one unit down and 3 to the right)

So, to complete the statement we have:

plot the point (-2, 4),  move one unit down, and three units over to find the next point on the line.

The correct option is A.

Step-by-step explanation:

Part A:

The two factors in 9(7+2x) are 9 and 7+2x

Part B:

First term: 9

Second term: 7+2x

Part C:

9(7+2x)

Open bracket

63+18x

The coefficient is 18x

A. The two factors are 9 and (7+2x).

B. In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.

C. The coefficient of the variable term is 18.

Given expression is;

                         [tex]9(7+2x)[/tex]

In given expression, there are two factors fist is 9 and second one is [tex](7+2x)[/tex]

In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.

To find the coefficient of variable term, we have to to expand given expression.

             [tex]9(7+2x)=63+18x[/tex]

The coefficient of the variable term is 18.

Learn more about the algebraic expression:

https://brainly.com/question/4344214

Answer:

14 inches

Step-by-step explanation:

Since F is inversely proportional to L,

[tex]f = \frac{k}{l} \\ when \: f = 40 \: l \: = 7 \\ \frac{k}{7} = 40 \\ k = 280 \\ when \: f = 20 \\ 20 = \frac{280}{l} \\ l = 14[/tex]

Given:

The two numbers are 1280 and 630.

To find:

The HCF of the given numbers.

Solution:

First write the given numbers in prime factorization form.

[tex]1280=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 5[/tex]

[tex]630=2\cdot 3\cdot 3\cdot 5\cdot 7[/tex]

Now the product of all the common prime factors is known as the HCF of 1280 and 630.

[tex]HCF=2\cdot 5[/tex]

[tex]HCF=10[/tex]

Therefore, the HCF of 1280 and 630 is 10.

Answer:

not equivalent

equivalent

not equivalent

Step-by-step explanation:

25 is by itself already 5²

therefore

[tex] {25}^{m} = {5}^{2m} [/tex]

when we divide one time by 5, we simply take away 1 from the power making it

[tex] {5}^{2m - 1} [/tex]

the other options are wrong

[tex] {25}^{m - 1} [/tex]

would be right, if we have

[tex] {25}^{m} \div 25[/tex]

but we don't.

and

[tex] {25}^{2m - 1} [/tex]

would even square

[tex] {25}^{m} [/tex]

and then divide by 25. no, the original excision is nothing like that.

Answer:

1.92755 ,1.870320 i hope it will help you

Answer:

First bag's unit price=$1.92 per kg  Second bag's unit price=$1.87 per kg

Step-by-step explanation:

1.92 becomes 1.93

Answer:

sorry i dont know this answer

Answer:

4g+2x=r

Step-by-step explanation:

4g+r=2r-2x

collecting like terms

4g+2x=2r-r

4g+2x=r

Answer:

31

Step-by-step explanation:

Let the smallest integer be x.

Since the 4 integers are consecutive (they come right after the other),

2nd integer= x +1

3rd integer= x +1 +1= x +2

4th integer= x +2 +1= x +3

Sum of the integers= 122

x +x +1 +x +2 +x +3= 122

4x +6= 122

4x= 122 -6

4x= 116

x= 116 ÷4

x= 29

3rd number

= 29 +2

= 31

Answer:

x = 128.472

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The number of diners each day has a mean of 107 and a standard deviation of 60.

This means that [tex]\mu = 107, \sigma = 60[/tex]

Distribution of the daily average:

Over a month of 30 days, so [tex]n = 30, s = \frac{60}{\sqrt{30}} = 10.955[/tex]

The probability that a daily average over a given month is greater than x is 2.5%. Calculate x.

This is X when Z has a p-value of 1 - 0.025 = 0.975, so X when Z = 1.96. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]1.96 = \frac{X - 107}{10.955}[/tex]

[tex]X - 107 = 1.96*10.955[/tex]

[tex]X = 128.472[/tex]

So x = 128.472

Given:

The nth term of a sequence is:

[tex]n^2+5[/tex]

To find:

The first five terms of the given sequence.

Solution:

The given sequence is:

[tex]a_n=n^2+5[/tex]

For n=1,

[tex]a_1=1^2+5[/tex]

[tex]a_1=1+5[/tex]

[tex]a_1=6[/tex]

For n=2,

[tex]a_2=2^2+5[/tex]

[tex]a_2=4+5[/tex]

[tex]a_2=9[/tex]

For n=3,

[tex]a_3=3^2+5[/tex]

[tex]a_3=9+5[/tex]

[tex]a_3=14[/tex]

For n=4,

[tex]a_4=4^2+5[/tex]

[tex]a_4=16+5[/tex]

[tex]a_4=21[/tex]

For n=5,

[tex]a_5=5^2+5[/tex]

[tex]a_5=25+5[/tex]

[tex]a_5=30[/tex]

Therefore, the first five terms of the given sequence are 6, 9, 14, 21, 30.

Answer:

Range:

UCL = 4.73

LCL = 18.08

MEAN :

UCL = 27.115

LCL = 31.219

Step-by-step explanation:

Given the data:

The mean and range of each sample :

Sample __ Thread wear __ xbar __ R

1 ___31 __ 42 ___ 28 ____ 33.67 _14

2___ 26 _ 18 ____35____ 26.33 _17

3___25 __30 ___ 34____29.67 _ 9

4 __ 17 __ 25 ___ 21 _____ 21 ___ 8

5 __ 38 _ 29 ___ 35 _____ 34 __ 9

6 __ 41 __42 ___36 _____39.67_ 6

7 __ 21 __ 17 ___29 _____22.33 _12

8 __ 32 __26___28 ____ 28.67 _ 6

9 __ 41 __ 34 __ 33 ______ 36 __8

10__29___17___30 _____25.33_ 13

11 __26 __ 31 __ 40 _____32.33_ 14

12__23 __ 19 __ 45 _____12.33 __6

13 __17 __ 24 __ 32_____24.33__15

14 __43__ 35___17_____ 31.67 _ 26

15__18 ___25__ 29_____ 24 ___ 11

16__30___42___31 ____34.33__ 12

17__28___36 __ 32____ 32 ____8

18__40 __ 29 __ 31 ____33.33 __ 11

19__18 ___29__ 28____ 25 ____11

20_ 22 __ 34 __ 26 ___ 27.33 __12

Size per sample, sample size, n = 3

Number of samples, k = 20

We calculate the sample mean and range average :

Sample mean, x-- = Σxbar/n = 29.167

Range average, Rbar = ΣR/n = 11.4

The mean control limit :

x-- ± A2Rbar

From the x chart ;

A2 for n = 20 is A2 = 0.180

29.167 ± 0.180(11.40)

LCL = 29.167 - 0.180(11.40) = 27.115

UCL = 29.167 + 0.180(11.40) = 31.219

The Range control limit :

Rbar(1 ± 3(d3/d2))

From the R-chart :

d2 at n = 20 ; d2 = 3.735

d3 at n = 20 ; d3 = 0.729

LCL = 11.40(1 - 3(0.729/3.735)) = 4.725

UCL = 11.40(1 + 3(0.729/3.735)) = 18.075

Answer:

Factors of number 52

Factors of 52: 1, 2, 4, 13, 26 and 52.

Negative Factors of 52: -1, -2, -4, -13, -26 and -52.

Prime Factors of 52: 2, 13.

Prime Factorization of 52: 2 × 2 × 13 = 22 × 13.

Sum of Factors of 52: 98.

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Answer:

  x = 30 2/3

Step-by-step explanation:

Angles 4 and 5 are complementary, so we have ...

  m∠4 +m∠5 = 90°

  (2x +4) +(x -6) = 90

  3x -2 = 90 . . . . . . . . . collect terms

  3x = 92 . . . . . . . . . . add 2; next, divide by 3

  x = 92/3 = 30 2/3

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Answer:

  Tk 173.25

Step-by-step explanation:

The firm will break even if its cost is equal to its revenue. That is, the price of each item sold must equal the cost of producing it. To cover the fixed cost, a share of it must be added to each of the items sold. Then the break-even price for 80 items is ...

  price = variable cost + share of fixed cost

  price = Tk 60.75 +9000/80 = Tk 60.75 +112.50 = Tk 173.25

Answer:

their sizes vary

Step-by-step explanation:

their sizes vary

Answer:

AB

Step-by-step explanation:

From the question given above, we were told that triangle ABC is similar to triangle PTG.

Since both triangles are similar, the following assumptions hold:

PG / AC = PT / AB = TG / BC

Comparing the equation above with those given in the question, the missing part of the equation is AB

Answer: 12 dollars

Step-by-step explanation:

2x3x2=12

Easy math

Answer:

x = 2.7

Step-by-step explanation:

The given equation is :

[tex](3x)^2-10=56[/tex]

We need to solve it for x.

It can be rewrite as follows:

[tex]9x^2-10=56[/tex]

Adding 10 to both sides,

[tex]9x^2-10+10=56+10\\\\9x^2=66\\\\x=\sqrt{\dfrac{66}{9}}\\\\x=2.70[/tex]

So, the value of x is equal to 2.7.

Step-by-step explanation:

For a geometric sequence,

[tex]\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}[/tex]

1. The sequence is :

3, 13, 23, 33,...

[tex]\dfrac{13}{3}\ne \dfrac{23}{13}[/tex]

It is not geometric. It is false

2. The sequence is :

5, -25, 125, -625

[tex]\dfrac{-25}{5}=\dfrac{125}{-25}\\\\-5=-5[/tex]

So, the sequence is geometric as the common ratio is same. It is true.

Answer:

Option C

Step-by-step explanation:

Suppose that we have a given proposition p

We define the complement as:

"NOT p" or ¬p

So, if p is:

the dog is red

the complement is

the dog is NOT red.

The principal rule to work with this is:

if p is true, then ¬p is false

if p is false, then ¬p is true.

Here the proposition is:

p = "When 100 engines are shipped, all of them are free of defects."

When this is this is true, ¬p must be false.

when this is false, ¬p must be true.

Let's analyze the given options, first the incorrect ones:

A: "At most one of the engines is defective."

here if we have for example, two defective engines, then this proposition and the original proposition are false.

B: " All of the engines are defective."

Here if there is one defective engine, then this is false, and also is the original proposition.

D: "None of the engines are defective"

When the original proposition is true "When 100 engines are shipped, all of them are free of defects.", this proposition is also true (because none of the engines are defective)

Finally, the corrrect one

C "At least one of the engines is defective"

When the original proposition is true, there are no defective engines, so this is false.

While, if this is true, there is at least one defective engine, so the original proposition is false.

Then this is the correct option:

¬p = "At least one of the engines is defective"