Can someone help me find the answer?

Answer:

mean ≈ 25.45

Step-by-step explanation:

mean is calculated as

mean = [tex]\frac{sum}{count}[/tex]

We require the sum for both classes

class A

mean = [tex]\frac{sum}{9}[/tex] = 40 ( multiply both sides by 9 )

sum = 9 × 40 = 360

class B

mean = [tex]\frac{sum}{24}[/tex] = 20 ( multiply both sides by 24

sum = 24 × 20 = 480

Total sum for both classes = 360 + 480 = 840 , then mean for both classes is

mean = [tex]\frac{840}{33}[/tex] ≈ 25.45 ( to 2 dec. places )

Answer:

The answer is below

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

If a point A(x, y) is translated a units right and b units up, the new point is at A'(x + a, y + b).

If a point A(x, y) is reflected across the line y = -x, the new point is at A'(-y, -x).

If a point A(x, y) is rotated counterclockwise by 270 degrees, the new point is at A'(y, -x).

Let us assume that triangle ABC has vertices at A(-6, -1), B(-3, -3) and C(-1, -2).

If it is moved 5 units to the right and 2 units up, the new point is at A'(-1, 1), B'(1, -1) and C'(3, 0). If it is reflected across the line y = -x, the vertices are at A"(-1, 1), B"(1, -1) and C"(0, -3). If it is then rotated counterclockwise about the origin by 270°, the new point is at A'"(-1, -1), B"'(1, 1), C"'(3, 0)

Answer:

FALSE

Step-by-step explanation:

First, define y and x.

In statistics, we have what we call variables. Variables are items or symbols that can take on various values. We have dependent variables - whose values are derived from other variables in an equation - and independent variables - whose values are given and are used to determine the values of dependent variables.

Usually, y represents the dependent variable while x represents the independent variable. So the simplest form of regression equation is

y = f (x)

Said as "y is a function of x"

A logistic regression equation can be used to calculate y when x values are given.

Here, the independent variable function (the X function) is a logistic function and it is used to find a binary dependent variable (a Y value, out of two possible values).

In logistic regression equations, the value of Y is not numerical like 1, 0.2, 3/4, and so on. It is categorical, e.g.

Black/White, Gain/Lose, Pass/Fail, Eat/Drink, etc.

Answer:

[tex]Given:[/tex] Δ ABC ≈ ΔDEF

[tex]therefor:[/tex] A(ΔABC)/A(ΔDEF)=(BC)²/(EF)²

⇒ 34/A(ΔDEF)=9²/(13.5)²

⇒34/A(ΔDEF)=81/182.25

⇒A(ΔDEF)=34×182.25/81

⇒Area of ΔDEF=76.5 cm²

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Hope it helps...

Have a great day!!!

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Each point moves to the same distance on the other side of the mirror line. The slope of the mirror line is 1, so the points move along a line perpendicular to that, one with a slope of -1. You can make sure the distances are the same by counting the grid squares.

Answer:

if you mean 15k as is 15 thousand then the answer would be 15,010

AS IN THE PICTURE...........

Answer:9oooooooooooooooooooooooooooooooooooo

Step-by-step explanation:

Answer:

42

Step-by-step explanation:

2,​4,6,10,​16,26,​___

The pattern is adding the previous two numbers to get the next number

2+4 = 6

4+6 = 10

6+10 = 16

10+16 = 26

16+26 =42

Use Bayes Theorem to compute that probability. I will denote bath as [tex]B[/tex] and nap as [tex]N[/tex], the probability will be denoted as [tex]P(B)[/tex] or [tex]P(N)[/tex].

By Bayes Theorem

[tex]P(B\mid N)=\frac{P(N\mid B)\cdot P(B)}{P(N)}[/tex]

Which reads,

"What is the probability of [tex]B[/tex] given [tex]N[/tex]".

We know that [tex]P(N\mid B)[/tex] is 1 because we already took a bath. So the formula simplifies to,

[tex]P(B\mid N)=\frac{P(B)}{P(N)}[/tex]

Now insert the data,

[tex]P(B\mid N)=\frac{1/5}{4/5}=\boxed{\frac{1}{4}}[/tex]

So the probability that you will take a bath is [tex]0.25[/tex] after you have taken a nap.

Hope this helps. :)

Answer:

Step-by-step explanation:

ΔABC has the vertices as A(1, 1), B(4, 1) and C(4, 5).

Rule for the transformation has been given as,

f(x, y) → (x - 5, -y - 2)

By this rule vertices of the transformed image will be,

A(1, 1) → A'(1 - 5, -1 - 2)

         → A'(-4, -3)

B(4, 1) → B'(4 - 5, -1 - 2)

          → B'(-1, -3)

C(4, 5) → C'(4 - 5, -5 - 2)

           → C'(-1, -7)

9514 1404 393

Answer:

Step-by-step explanation:

SOH CAH TOA is a mnemonic intended to remind you of the relevant trig relations.

  Sin = Opposite/Hypotenuse   ⇒   opposite = 15×sin(19°) ≈ 4.88 units

  Cos = Adjacent/Hypotenuse   ⇒   adjacent = 15×cos(19°) ≈ 14.18 units

Answer:

For plato users the correct option is D.

Step-by-step explanation:

D. 4.9 units, 14.2 units

Answer:

22

Step-by-step explanation:

The sum of the angles in a triangle are 180

Let the third angle be x

82+76+x = 180

158 +x = 180

x = 180-158

x =22

Now keep the,

Third unknown angle as y.

The formula we use,

→ Sum of all angles of triangle = 180°

Let's solve for y,

→ y + 82 + 76 = 180°

→ y + 158 = 180°

→ y = 180 - 158

→ [y = 22°]

Thus, option (B) is the answer.

Answer:

[tex]x = 0[/tex]

Step-by-step explanation:

[tex]3 |3x + 4| - 7 = 5[/tex]

[tex]3 |3x + 4 | = 12[/tex]

[tex] |3x + 4| = 4[/tex]

[tex]3x + 4 = 4[/tex]

[tex]3x = 0[/tex]

[tex]x = 0[/tex]

Answer:

Domain: input values, independent variables

Range: output vales, dependent variables

Step-by-step explanation:

Think of it like a graph: the domain are the x-values and the range is the y-values. if you're doing a problem with time, the time will go on the x-axis and cannot be influenced by the y-values, but the y-vales are depending on what the x-values are (independent/dependent). for the input/output, usually when solving equations on a graph, you plug in the x-value and find the y-value. you're INPUTTING the x-value to receive the OUPUT.

Domain = set of allowed inputs

The input x is the independent variable as it can do whatever it wants without relying on y.

-------------------------

Range = set of possible outputs

The output is the dependent variable. It depends on what the input x is. Often, we make y the output dependent variable.

-------------------------

For example, with y = 2x+5, we can plug in anything we want for x (it doesn't need to look to y for guidance or anything). Once we pick something for x, it will directly determine what y is.

Let's say we picked x = 10. That would mean y = 2x+5 = 2*10+5 = 25. The input x = 10 in the domain leads to y = 25 in the range. We see that the output y = 25 depends entirely on the independent input x = 10.

cto cto cto cto cto cto cto cto cto cto

Answer:

y = 3x + 5

Step-by-step explanation:

just by going through the options and plugging in values from the chart, you can guess and check

y = 3x + 5 is the only answer that works

5 = 0 + 5

11 = 6 + 5

23 = 18 + 5

etc.

hope this helps!

Answer:

-55 +11p

Step-by-step explanation:

-11(5-p)

Distribute

-11*5 -11*(-p)

-55 +11p

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that [tex]\mu = 8, \sigma = 1.5[/tex]

What is the probability that you have values between (6.5, 9.5)?

This is the p-value of Z when X = 9.5 subtracted by the p-value of Z when X = 6.5. So

X = 9.5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{9.5 - 8}{1.5}[/tex]

[tex]Z = 1[/tex]

[tex]Z = 1[/tex] has a p-value of 0.8413.

X = 6.5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{6.5 - 8}{1.5}[/tex]

[tex]Z = -1[/tex]

[tex]Z = -1[/tex] has a p-value of 0.1587

0.8413 - 0.1587 = 0.6826

0.6826 = 68.26% probability that you have values in this interval.

Answer:

54, 55, 56, 57, 58

Step-by-step explanation:

Answer:

56 problems

Step-by-step explanation:

Set up an equation.

[tex]\frac{3}{5}x<35<\frac{13}{20}x[/tex]

Why do we do this? We are told that she solved MORE than 60%, or [tex]\frac{3}{5}[/tex], and LESS than 65%, or [tex]\frac{13}{20}[/tex]. Therefore, if we set the TOTAL number of problems to x, we have an equation we can solve.

[tex]\frac{3}{5}x<35<\frac{13}{20}x\\[/tex]

Multiply all parts of the inequality by 20 to get rid of the denominators.

[tex]20*\frac{3}{5}x<20*35<20*\frac{13}{20}x\\ \\12x<700<13x[/tex]

Now we can solve TWO individual inequalities to isolate the x variable.

[tex]12x<700\\x<\frac{700}{12}\\x < 175/3\\x<58[/tex]

We can approximate 175/3 to about 58 (rounding down). We will sometimes round down when we have to deal with whole numbers.

The second inequality is as follows.

[tex]13x>700\\x>700/13\\x>53[/tex]

Therefore, we can combine the two inequalities.

[tex]53<x<58[/tex]

There were in between 53 and 58 questions. Since the number of questions must be a whole number, there can be 54, 55, 56, 57, OR 58. Why does 58 also work? When you plug 58 back into the original equation, you get that it STILL works. This is due to the fact that inaccuracies in computations allow you to round UP.

However, the last thing to keep in mind is that there are four sections with an equal number of questions. Meaning, the final answer has to be a multiple of four. The only multiple of 4 is 56; therefore, the final answer is 56.

Answer:

Hence the probability that the mean weight of the sample of 55 cows would differ from the population mean by less than 12 lbs is 0.66545.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Integration (4t√t+a)dt

[tex]\int \left ( 4 t\sqrt t +a \right )dt\\\\=\int\left ( 4 t^{(\frac{3}{2})} +a\right ) dt\\\\= 4\times 2\times \frac{t^{\frac{5}{2}}}{5} + a t\\\\= 8 \frac{t^{\frac{5}{2}}}{5} + a t[/tex]

Answer:

the total number of arrangements possible is 1,440 ways

Step-by-step explanation:

Given;

total number of kids = 5

total number of counselors, = 2

Since the counselors must sit together in any order, first treat them as a single option. This gives 6! possible arrangements for all the participants.

Also, If they can sit in any order, then the total possible arrangements = 2(6!)

                                            = 2( 6 x 5 x 4 x 3 x 2 x 1)

                                            = 1,440 ways

Therefore, the total number of arrangements possible is 1,440 ways

Seating arrangement is unique way in which people can sit. The number of seating arrangements possible in this case is 2520

If a work A can be done in p ways, and another work B can be done in q ways, then both A and B can be done in [tex]p \times q[/tex]  ways.

Remember that this count doesn't differentiate between order of doing A first or B first then doing other work after the first work.

Thus, doing A then B is considered same as doing B then A

In such situations, we need to model the situation with the view point which can be evaluated mathematically.

For give case, we can see that there are in total 7 seats. And 5 kids are to sit on them, with 2 camp counselors.

So 7 people have to sit on 7 seats.

But it is given that two counselors must sit together.

Now firstly, two counselors can choose 2 seats out of 7 seats in [tex]^7C_2 = \dfrac{7 \times 6}{2 \times 1} = 21[/tex] ways.

Then , in the rest of the 5 seats, 5 kids can arrange themselves in 5! ways(using permutations).

We have:

[tex]n! = n \times (n-1) \times (n-2) \times ... \times 2 \times 1\\\\5! =5\times 4\times 3\times 2\times 1 = 120[/tex]

Since each of this 120 arrangement is for each of 21 ways of counselors sitting, thus, there are 120 times 21 ways of those 7 people to sit (using rule of product), or total [tex]120 \times 21 = 2520[/tex]

Thus,

The number of seating arrangements possible in this case is 2520

Learn more about seating arrangements here:

https://brainly.com/question/13605688

Answer:

Step-by-step explanation:

If D can paint the room in 6 hours, in 1 hour she gets [tex]\frac{1}{6}[/tex] of the room painted;

If C can paint the room in x hours, in 1 hour she gets [tex]\frac{1}{x}[/tex] of the room painted.

It takes 4 hours to paint it together. Setting up the classic work equation gives us

[tex]\frac{1}{6}+\frac{1}{x}=\frac{1}{4}[/tex] and we need to solve for x. Multiply everything through by the LCM which is 12x:

[tex]12x(\frac{1}{6}+\frac{1}{x}=\frac{1}{4})[/tex] making our equation simplify to

2x + 12 = 3x and solve for x:

12 = x

C can paint the room alone in 12 hours.

9514 1404 393

Answer:

  2x +2y -8

Step-by-step explanation:

If the equal sides are 'a' and the third side is 'b', then the perimeter is ...

  P = a +a +b = 2a +b

The length of the third side is then ...

  b = P -2a . . . . . . subtract 2a from both sides

Substituting the given expressions, we find ...

  b = (10x +4y -18) -2(4x +y -5)

  b = 10x +4y -18 -8x -2y +10

  b = 2x +2y -8 . . . . the length of the third side

Answe YEAH BOIIIIII!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

[tex]\displaystyle f(x) = \frac{x + 3}{x - 2}[/tex] has no relative extrema when the domain is [tex]\mathbb{R} \backslash \lbrace 2 \rbrace[/tex] (the set of all real numbers other than [tex]2[/tex].)

Step-by-step explanation:

Assume that the domain of [tex]\displaystyle f(x) = \frac{x + 3}{x - 2}[/tex] is [tex]\mathbb{R} \backslash \lbrace 2 \rbrace[/tex] (the set of all real numbers other than [tex]2[/tex].)

Let [tex]f^{\prime}(x)[/tex] and [tex]f^{\prime\prime}(x)[/tex] denote the first and second derivative of this function at [tex]x[/tex].

Since this domain is an open interval, [tex]x = a[/tex] is a relative extremum of this function if and only if [tex]f^{\prime}(a) = 0[/tex] and [tex]f^{\prime\prime}(a) \ne 0[/tex].

Hence, if it could be shown that [tex]f^{\prime}(x) \ne 0[/tex] for all [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace[/tex], one could conclude that it is impossible for [tex]\displaystyle f(x) = \frac{x + 3}{x - 2}[/tex] to have any relative extrema over this domain- regardless of the value of [tex]f^{\prime\prime}(x)[/tex].

[tex]\displaystyle f(x) = \frac{x + 3}{x - 2} = (x + 3) \, (x - 2)^{-1}[/tex].

Apply the product rule and the power rule to find [tex]f^{\prime}(x)[/tex].

[tex]\begin{aligned}f^{\prime}(x) &= \frac{d}{dx} \left[ (x + 3) \, (x - 2)^{-1}\right] \\ &= \left(\frac{d}{dx}\, [(x + 3)]\right)\, (x - 2)^{-1} \\ &\quad\quad (x + 3)\, \left(\frac{d}{dx}\, [(x - 2)^{-1}]\right) \\ &= (x - 2)^{-1} \\ &\quad\quad+ (x + 3) \, \left[(-1)\, (x - 2)^{-2}\, \left(\frac{d}{dx}\, [(x - 2)]\right) \right] \\ &= \frac{1}{x - 2} + \frac{-(x+ 3)}{(x - 2)^{2}} \\ &= \frac{(x - 2) - (x + 3)}{(x - 2)^{2}} = \frac{-5}{(x - 2)^{2}}\end{aligned}[/tex].

In other words, [tex]\displaystyle f^{\prime}(x) = \frac{-5}{(x - 2)^{2}}[/tex] for all [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace[/tex].

Since the numerator of this fraction is a non-zero constant, [tex]f^{\prime}(x) \ne 0[/tex] for all [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace[/tex]. (To be precise, [tex]f^{\prime}(x) < 0[/tex] for all [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace\![/tex].)

Hence, regardless of the value of [tex]f^{\prime\prime}(x)[/tex], the function [tex]f(x)[/tex] would have no relative extrema over the domain [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace[/tex].