can someone help me solve for a ?

Answer:

Step-by-step explanation:

Change the mixed numbers to improper fractions.

Answer:

34, 650

Step-by-step explanation:

Given that,

The word = Mississippi

To find,

No. of different ways in which the letters of this word can be arranged = ?

Procedure:

Using the permutation rule as it is the case of repetition of identical items for finding the possibilities.

No. of letters in 'Mississippi' = 11

Letter 'i' appears = 4 times

Letter 's' appears = 4 times

Letter 'm' appears = 1 time

Letter 'p' appears = 2 times

So,

No. of possibilities = 11 ! ÷ (4 ! 4 ! 1 ! 2 !)

= (11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 *1)/(4 * 3 *2 * 1)(4 * 3 *2 * 1)(1)(2 * 1)

= 11 * 10 * 9 * 7 * 5

= 34,650

Answer:

The Exterior Angle of triangle LDR is angle d. The Remote Interior Angles are a and b.

The Exterior Angle of triangle PDR is angle 4. The Remote Interior Angles are angles 1 and 2

Explanation:

Interior angles are the angles that are inside the shape. The remote interior angles would be the 2 angles away from the exterior angle.

The exterior angle is the angle, made by the side of the shape and a line drawn out from an adjacent side.

I hope this helps!

Answer:

In LDR

In PDR

Exterior angle of a triangle is formed when one side of the triangle is extended .

Interior remote angles the angles in the triangle that do not lie on the extended side.

9514 1404 393

Answer:

  1. see below

  2. g(x) is f(x) translated left 2 and down 3

Step-by-step explanation:

1. The graphs are attached. F(x) is in red; g(x) is in blue.

__

2. The graph of g(x) = f(x -h) +k is the parent function translated by (h, k). Here we have (h, k) = (-2, -3), so g(x) is f(x) translated left 2 and down 3.

Answer:

[tex]Cold = \frac{1}{6}\ mins[/tex]

Step-by-step explanation:

The correct given parameters are:

[tex]Both = \frac{1}{4}\ mins[/tex]

[tex]Hot = \frac{1}{12}\ mins[/tex]

Required

Time taken by the cold water faucet

We have:

[tex]Cold + Hot = Both[/tex]

Make Cold the subject

[tex]Cold = Both -Hot[/tex]

So, we have:

[tex]Cold = \frac{1}{4}-\frac{1}{12}[/tex]

Take LCM

[tex]Cold = \frac{3-1}{12}[/tex]

[tex]Cold = \frac{2}{12}[/tex]

Divide by 2

[tex]Cold = \frac{1}{6}[/tex]

Answer:

32

Step-by-step explanation:

(-4)^2 -3(-4) +4=16+12+4

=32

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {32}}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]

[tex] {z}^{2} - 3z + 4[/tex]

Plugging "[tex] -4[/tex]" for all values of "[tex]z[/tex]", we have

[tex] = ({ - 4})^{2} - 3( - 4) + 4[/tex]

[tex] = ( - 4 \times - 4) + 12 + 4[/tex]

[tex] = 16 + 12 + 4[/tex]

[tex] = 32[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Mystique35 }}{\red{❦}}}}}[/tex]

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Answer:

  f = 3 units

Step-by-step explanation:

The ratios of side lengths in this 30°-60°-90° triangle are ...

  1 : √3 : 2

So, the ratio of interest is ...

  1 : √3 = √3 : f

We can see that the numbers in the second ratio are √3 times the numbers in the first ratio, so

  f = √3 × √3 = 3

  f = 3 units

Answer:

= -10d^4 + 12d^2s + 25d^2 - 30s

Answer:

0.0306

Step-by-step explanation:

I don't know if there is any significance to both being drawn at the same time. I'm going to say there isn't.

The first draw gives

9/49

Their is no replacement. That's because both marbles are drawn together. The second draw is

8/48

P(both red) = 9/49 * 8 / 48 = 3/98 = 0.03061 which rounds to 0.0306

9514 1404 393

Answer:

  b = 80 -6n . . . . boys who wear spectacles

Step-by-step explanation:

We know the ratio of boys who wear spectacles to those who don't is ...

  (4/5) : (1 -4/5) = 4 : 1

If we let b represent the number of boys who wear spectacles, then the number who don't is b/4. Then total number of boys is then b +b/4 = 5b/4. The number of girls in the classroom is this number less than 40.

Let's define a few groups:

Then the total of children who do not wear spectacles is ...

  n = b/4 +(1/3)(40 -5b/4)

  12n = 3b +(160 -5b) = 160 -2b . . . . multiply by 12

  2b = 160 -12n . . . . . . . . . . . . . add 2b-12n

  b = 80 -6n . . . . the desired relation, b = boys who wear spectacles

_____

Additional comment

The only values of n that make sense in this context are {8, 10, 12}, corresponding to {0, 15, 30} total girls and {40, 25, 10} total boys.

Answer:

1600 Rupees

Step-by-step explanation:

20 divided by 100 times 8000 will give you 1600 so the carpet costed him 1600

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Answer:

  (a)  y = −50x + 250

Step-by-step explanation:

In case you don't realize that the graph starts at 250 and decreases by 50 for each increase of 1 in x, you can see if any of the equations match the given points. The only one that does is the first one:

  y = -50x +250

Answer:

(a)  y = −50x + 250

Step-by-step explanation:

Answer:

Step-by-step explanation:

If we are looking for the time(s) that the ball is at a height of 15, we simply sub in a 15 for the height in the position equation and solve for t:

[tex]15=-16t^2+23t+7[/tex] and

[tex]0=-16t^2+23t-8[/tex]

Factor this however you factor a quadratic in class to get

t = .59 seconds and t = .85 seconds.

This means that .59 seconds after the ball was thrown into the air it was 15 feet off the ground. Then the ball reached its max height, gravity took over, and began pulling it back down to earth. The ball passes the height of 15 feet again on its way down after .85 seconds.

Answer:

11/2

Step-by-step explanation:

[tex]\frac{\frac{3}{4} + \frac{5}{8} }{\frac{3}{4} - \frac{1}{2} }[/tex]

= 3/4 + 5/8 = 11/8 (take LCM)

3/4 - 1/2 = 1/4 (take LCM)

11/8 ÷ 1 /4

= 11/8 x 4

= 11/2

Answered by Gauthmath

Answer:

A monomial in standard form is (essentially) the product of one or more factors: a constant coefficient and one factor for each variable in the expression.

Step-by-step explanation:

For example, in the monomial 4x2y3, the factors are 4, x2, and y3. First, the coefficient is 4. The next factor, x2, is the x-factor, whose degree is 2.

9514 1404 393

Answer:

  27/64

Step-by-step explanation:

The fraction being cubed is already in simplest form, so the cube is ...

  [tex]\left(\dfrac{3}{4}\right)^3=\dfrac{3^3}{4^3}=\boxed{\dfrac{27}{64}}[/tex]

Answer:

x | y

0 | 0

6 | 2

12 | 4

Step-by-step explanation:

Multiply each x value in the table by 1/3 to get 0, 2, and 4 for your y values.

Answer:

x    y

0    0

6    2

12   4

Step-by-step explanation:

Is means equals

The equation is

y = 1/3 x

Let x = 0

y = 1/3 (0) = 0

Let x = 6

y = 1/3 (6) = 2

Let x = 12

y = 1/3 (12) = 4

Answer:

Part A: 90 + 6x = 108

Part B: 3

Step-by-step explanation:

Part A:

Variable x = number of movie tickets purchased

18 × 5 + 6x = 108

90 + 6x = 108

Part B:

Variable y = number of people

18y + 1(7) = 61

18y + 7 = 61

18y = 54

y = 3

There were 3 people in this group.

Answer:

(c) [tex]x = 0.6[/tex] and [tex]x = 0.7[/tex]

(d) [tex](x,y) = (0.67,2.33)[/tex]

Step-by-step explanation:

Given

See attachment

First, we complete the table

[tex]y = -x + 3[/tex]                                               [tex]y = 2x + 1[/tex]

[tex]y = -0.6 + 3 = 2.4[/tex]                                   [tex]y = 2 * 0.6 + 1 = 2.2[/tex]

[tex]y = -0.7 + 3 = 2.3[/tex]                                   [tex]y = 2 * 0.7 + 1 = 2.4[/tex]

[tex]y = -0.8 + 3 = 2.2[/tex]                                   [tex]y = 2 * 0.8 + 1 = 2.6[/tex]

[tex]y = -0.9 + 3 = 2.1[/tex]                                   [tex]y = 2 * 0.9 + 1 = 2.8[/tex]

So, we have:

[tex]\begin{array}{ccc}x & {y = -x + 3} & {y = 2x + 1} & {0.5} & {2.5} & {2} & {0.6} & {2.4} & {2.2} & {0.7}&{2.3} & {2.4} & {0.8}&{2.2} & {2.6} & {0.9}&{2.1} & {2.8} & {1}&{2} & {3} \ \end{array}[/tex]

Solving (c): Between which values is y

The values of y are for both equations are closest at:

[tex]x = 0.6[/tex] and [tex]x = 0.7[/tex]

Hence, the solution is between

[tex]x = 0.6[/tex] and [tex]x = 0.7[/tex]

Solving (d): Approximated value of the solution

We have:

[tex]y = -x + 3[/tex]

[tex]y = 2x + 1[/tex]

[tex]y=y[/tex]

So:

[tex]-x + 3 = 2x + 1[/tex]

Collect like terms

[tex]2x + x = 3 - 1[/tex]

[tex]3x= 2[/tex]

Divide both sides by 3

[tex]x = 0.67[/tex]

Substitute [tex]x = 0.67[/tex] in [tex]y = -x + 3[/tex]

[tex]y =-0.67 + 3[/tex]

[tex]y =2.33[/tex]

So, the solution is:

[tex](x,y) = (0.67,2.33)[/tex]

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Answer:

  see attached

Step-by-step explanation:

The graph of g(x) is a vertically scaled version of the graph of f(x). The scale factor is 1/2, so vertical height at a given value of x is 1/2 what it is for f(x). This will make the graph appear shorter and fatter than for f(x).

The graph of g(x) is attached.

Answer:

u = -3/5

Step-by-step explanation:

5(u-3) - 3 = -3(-6u + 4) - 3u

(5u - 15) - 3 = (18u - 12) - 3u

5u - 18 = 15u - 12

-18 = 10u - 12

-6 = 10u

u = -6/10

u = -3/5

Step-by-step explanation:

Option B

The length of side will be 2m...

hope it helps

Answer:

The right answer is "0.70".

Step-by-step explanation:

The given query seems to be incomplete. Please find below the attachment of the full query.

By using the Bayes' theorem, we get

⇒  [tex]P[(X<4)|(X \geq 2)] = \frac{P(2 \leq X < 4)}{P(X \geq 2)}[/tex]

By putting the values, we get

                                     [tex]=\frac{[P(2)+P(3)]}{[1-P(0)-P(1)]}[/tex]

                                     [tex]=\frac{(0.20+0.15)}{1-0.20-0.30}[/tex]

                                     [tex]=\frac{0.35}{0.5}[/tex]

                                     [tex]=0.70[/tex]

Answer:

-11

Step-by-step explanation:

I am going to assume that it is -x^2-5y^3.

-(4^2)-5(-1^3)

-16-5(-1)

-16+5

-11

Answer:

- 11

Step-by-step explanation:

If x = 4,  y = -1

then,

        - x^2 - 5y^3 = - (4)^2 - 5(-1)^3

                            = - 16 + 5

                            = - 11

Answer:

a) 0 is stable when n = odd

b) 0 is semi-stable when n = even

c) 0 is unstable when n is odd

Step-by-step explanation:

Th differential equation for this question

dx/dt = x^n

n = positive integer

a) value of n where 0 is stable

0 is stable when x^n is replaced with -x^n

because considering n to be an odd number

-x^n > 0 when x < 0    while -x^n < 0 when x > 0

∴ In this scenerio we can conclude that 0 is stable when  n = odd number

b) Value of n where 0 is Semi-stable

assuming n is an even number

x^n > 0  for all the values of x

c) Value of n where 0 is unstable

lets assume n is odd

when n < 0,  xⁿ < 0

when n > 0,  xⁿ > 0

i.e. 0 is asymptotically unstable when n is an odd number

Answer:

The three answers I can think of are migration, immigration, and emigration.

Step-by-step explanation:

Hope this helps!