Can someone help solve this?

Answer:

9^2 + 12^2 = x^2

81 + 144 = 225

225 ÷ 15 = 15

the answer for this question is 15

Step-by-step explanation:

Answer:

If this is asking for the set:

Z = {-3, -2, -1, 0, 1, 2, 3}

Step-by-step explanation:

Z is the set of all integers and it appears that you are being asked for the values in the set Z that are within the range:  -3 ≤x ≤ 3

Answer:

C. 6 nights in Washington, 4 nights in Atlanta, and 12 nights in Dallas

Step-by-step explanation:

Answer:

Step-by-step explanation:

The formula for this is

[tex]A(t)=P(1+r)^t[/tex] and we have everything but the P. Filling in:

[tex]1469=P(1+.038)^{30[/tex] and

[tex]1469=P(1.038)^{30[/tex] and

1469 = P(3.061403718) so

P = 479.85

Answer:

Reject H0

Step-by-step explanation:

Given :

H0: The frequencies are equal. H1: The frequencies are not equal

Category f0 A 10 B 30 C 30 D 10

Total f0 = (10 + 30 + 30 + 10) = 80

Expected frequency is the same for all categories :

Expected frequency = 1/4 * 80 = 20

χ² = Σ(observed - Expected)² / Expected

χ² = (10-20)^2 / 20 + (30-20)^2 /20 + (30-20)^2 / 20 + (10-20)^2 / 20

χ² = (5 + 5 + 5 + 5) = 20

Pvalue = 0.00017

Pvalue < α

Answer:

Step-by-step explanation:

18,  count the dots. The number line aka 0-7 is just showing the number of possible pets a person could have

Answer:

237.9 yards

Step-by-step explanation:

90-23=67

cos 67⁰=x/610

x=610 cos 67

x= 610 x 0.39

x=237.9 yards

Answer: [tex]x^2+4x+12[/tex]

Step-by-step explanation:

[tex]f(x)=x^2+8\\f(x+2)=(x+2)^2+8\\f(x+2)=x^2+4x+4+8\\f(x+2)=x^2+4x+12[/tex]

Answer:

[tex]{ \tt{4 log_{4}(3100) }} \\ = { \tt{4 log_{4}(775 \times 4) }} \\ = { \tt{4 log_{4}(775) + 4 log_{4}(4) }} \\ = { \tt{4( (\frac{ log_{10}775 }{ log_{10}4 } ) +1)}} \\ = { \tt{4(4.8 + 1)}} \\ = { \tt{23.2}}[/tex]

Answer:

10 meaters yes these answer is correct

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

6 + 6 = 12 seeds, which means that [tex]N = 12[/tex]

6 treated, which means that [tex]k = 6[/tex]

Five sprouted, which means that [tex]n = 5[/tex]

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076[/tex]

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Answer:

300

Step-by-step explanation:

Answer:

D. 5x^4+x^3-1

I am going to assume that you made a mistake in copying the sum.

If you put it in 100% correctly, the question wouldn't make sense.

[tex](4x^4-x^2-x)+(x^4+x^3+x^2-1)[/tex]

Solve, and you get D. [tex]5x^4+x^3-1[/tex]

I hope this helps!

Answer choices:

[tex]A.5x^4+2x^4-1 \\B.5x^4+2x^4+2x^2-1\\C.5x^4+x^4+2x^2-1\\D.5x^4+x^3-1[/tex]

Answer:

7×(8/6)=9.33

Step-by-step explanation:

7 is whole number

8/6 is the fraction

8/6 is 1.333

so, 7×1.333=9.33

Answer:

$3240

Step-by-step explanation:

hope it is well understood

Answer: 59300

Step-by-step explanation:

Answer:

[tex]x<\frac{6}{5}[/tex]

Refer to picture for number line

Step-by-step explanation:

To solve this inequality, we want to isolate the variable. We can do this my getting like terms onto one side

[tex]6x-7<2-\frac{3x}{2}[/tex]       [add both sides by 7]

[tex]6x<9-\frac{3x}{2}[/tex]             [add both sides by 3x/2]

[tex]6x+\frac{3x}{2}<9[/tex]             [multiply both sides by 2]

[tex]12x+3x<18[/tex]          [add]

[tex]15x<18[/tex]                  [divide both sides by 15]

[tex]x<\frac{18}{15}[/tex]                     [simplify]

[tex]x<\frac{6}{5}[/tex]

Now that we have out inequality, we want to graph it. Since we know that [tex]x<\frac{6}{5}[/tex], that means we have an open circle. Since x is less than, the arrow would be pointing left.

Answer:

The midpoint is (1,-13.5)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates of the endpoints and divide by 2

(7+-5) /2 = 2/2 =1

To find the y coordinate of the midpoint, add the y coordinates of the endpoints and divide by 2

(-12+-15) /2 = -27/2 =-13.5

The midpoint is (1,-13.5)

Answer:

the first page :

x =20

the second page :

x = 45

Step-by-step explanation:

first question

to find angle BOC subtract 110 from 180( because 180 degrees is a straight line)

angle BOC = 70 degrees

this means that the angle opposite to it is also 70 degrees ( DOA)

now to find x, add up 110, 70, 70, 90, x to get 360

110 + 70 + 70 + 90 + x = 360

x = 20

second question :

every thing adds up to 360 degrees.

90 + 5x + x = 360

6x = 270

x = 45

Answer:

[tex]\sec y=\dfrac{q}{r}[/tex]

Step-by-step explanation:

Given that,

[tex]\sin y=\dfrac{7}{q}[/tex]

and

[tex]\tan y=\dfrac{7}{r}[/tex]

We need to find the value of [tex]\sec y[/tex]. We know that,

[tex]\sec\theta=\dfrac{1}{\cos\theta}[/tex]

Also,

[tex]\tan\theta=\dfrac{\sin\theta}{\cos\theta}\\\\\cos\theta=\dfrac{\sin\theta}{\tan\theta}[/tex]

Substitute all the values,

[tex]\cos y=\dfrac{\dfrac{7}{q}}{\dfrac{7}{r}}\\\\=\dfrac{7}{q}\times \dfrac{r}{7}\\\\\cos y=\dfrac{r}{q}[/tex]

So,

[tex]\sec y=\dfrac{1}{\dfrac{r}{q}}\\\\\sec y=\dfrac{q}{r}[/tex]

So, the correct option is (a) i.e. [tex]\sec y=\dfrac{q}{r}[/tex].

Answer:

a) 0.06% probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years.

b) 90.15% probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years.

c) 0.23% probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years.

Step-by-step explanation:

For questions a and b, the normal approximation to the binomial is used, while for question c, the central limit theorem is used.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

54% of companies surveyed outsourced some part of their manufacturing process in the past two to three years.

This means that [tex]p = 0.54[/tex]

555 of these companies are contacted.

This means that [tex]n = 555[/tex]

Mean and standard deviation: Normal approximation to the binomial:

[tex]\mu = E(X) = np = 555*0.54 = 299.7[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{555*0.54*0.46} = 11.74[/tex]

a. What is the probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years?

Using continuity correction, this is [tex]P(X \geq 338 - 0.5) = P(X \geq 337.5)[/tex], which is 1 subtracted by the p-value of Z when X = 337.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{337.5 - 299.7}{11.74}[/tex]

[tex]Z = 3.22[/tex]

[tex]Z = 3.22[/tex] has a p-value of 0.9994.

1 - 0.9994 = 0.0006

0.0006*100% = 0.06%

0.06% probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years.

b. What is the probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years?

Using continuity correction, this is [tex]P(X \geq 285 - 0.5) = P(X \geq 284.5)[/tex], which is 1 subtracted by the p-value of Z when X = 284.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{284.5 - 299.7}{11.74}[/tex]

[tex]Z = -1.29[/tex]

[tex]Z = -1.29[/tex] has a p-value of 0.0985.

1 - 0.0985 = 0.9015

0.9015*100% = 90.15%

90.15% probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years.

c. What is the probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years?

Now we use the sampling distribution of the sample proportions, which have:

[tex]\mu = p = 0.54[/tex]

[tex]s = \sqrt{\frac{0.54*0.46}{555}} = 0.0212[/tex]

The probability is the p-value of Z when X = 0.48. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.48 - 0.54}{0.0212}[/tex]

[tex]Z = -2.84[/tex]

[tex]Z = -2.84[/tex] has a p-value of 0.0023.

0.0023*100% = 0.23%

0.23% probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years.

9514 1404 393

Explanation:

The attachment shows such a construction. Here are the steps.

1. Draw circle B with radius 3.5 cm

2. Mark a point X on the circle and draw circle X with the same radius. Mark the intersection points of circles B and X as points A and C.

3. Draw circles A and C with radii 5.2 cm. Mark the intersection point as point D so that X is on segment BD.

4. Finish by drawing kite ABCD.

Answer:

Assuming a constant rate of travel that is the same as yesterday, 416 miles in 8 hours.

Step-by-step explanation:

We are assuming that the first day's rate will be used in the second. After that, it is a proportions question. We divide 312 by 6 to get 52 miles an hour. Then, we multiply 8 hours by 52 miles to get 416 miles 8 hours.

Answer:4

Step-by-step explanation:

but they said it was a different day and they didn’t need to be in a position lol I just got the message and they sent it

Answer:

41.67%

Step-by-step explanation:

[tex]Z = \frac{x-\alpha}{\sigma}[/tex]     9-8.3 = 0.7/1.2 = 0.5833  1-0.5833 = 0.4167*10 = 41.67%

The probability of the individual sample which is greater then 9 cm is 0.2799601 .

'Probability is the extent to which an event is likely to occur, measured by the ratio of the favorable cases to the total number of cases possible.'

According to the given problem,

μ = 8.3 cm

σ = 1.2 cm

X ≈ N[tex](0,1)P(X < x )[/tex]

= P(Z = X - μ / σ)

here , X ≈ N (8.3 , [tex](1.2)^2)P(X > 9)[/tex]

= P[tex](Z > \frac{9-8.3}{1.2})[/tex]

⇒ P[tex](Z>0.583333)[/tex]

⇒ 1 - P[tex](Z<0.583333)[/tex]

⇒ 1 - 0.7200399 [ for greater surface area of the bell-curve ]

⇒ 0.2799601

Hence, we can conclude, the probability of individual sample is 0.2799601 .

Learn more about the probability here :brainly.com/question/23211929?#SPJ2

Answer:

i think your answer is 1/13

Step-by-step explanation:

Answer:

Volume is 167.6 yd³

Step-by-step explanation:

[tex]{ \boxed{ \bf{volume = \frac{1}{3}\pi {r}^{2} h}}} \\ { \sf{volume = \frac{1}{3} \times 3.14 \times {(4)}^{2} \times 10}} \\ \\ { \sf{volume = 167.6 \: {yd}^{3} }}[/tex]

Answer:

The alternative hypothesis is [tex]H_1: p > 0.6[/tex].

The critical value is [tex]Z_c = 1.645[/tex]

Step-by-step explanation:

It is claimed that proportion in favor of proportion A is greater than 60%.

This means that at the null hypothesis, we test if the proportion is of at most 60%, that is:

[tex]H_0: p \leq 0.6[/tex]

At the alternative hypothesis, we test if the proportion is more than 60%, that is:

[tex]H_1: p > 0.6[/tex]

What is (are) the critical value?

The critical value is the value of Z with a p-value 1 subtracted by the standard significance level of 0.05, since we are testing if the mean is more than a value, so, looking at the z-table, [tex]Z_c = 1.645[/tex]

Answer:

the answer is 96 sq. cm or B

Step-by-step explanation: