Can you pleasee help me with the Screenshot Below its Overdue.

Answer:

Step-by-step explanation:

Please be sure to include the directions when you post a question.  I will assume you want to graph this inequality 2x - y ≤ 5.  

2x - y = 5 is a linear function whose graph is that of a straight line.  Because of the ≤ sign, the solution set includes all points on this straight line PLUS all  points below it.

x - intercept:  Set y = 0 in 2x - y = 5 and solve the resulting equation for x:

2x - 0 = 5.  Then x = 5/2, and the x-intercept is (5/2, 0).

y-intercept:  Set x = 0 and solve for y:  2(0) - y = 5:  y = -5.  Then the y-intercept is (0, -5).  

Plot both points (5/2, 0) and (0, -5).  Draw a solid line through them.  Shade the area BELOW this line.

Answer: 72

Step-by-step explanation:

Ok, in her legs the options are:

2 jeans + 3 black pants + 1 skirt = 6 options.

on her torso the options are:

2 pinks shirts + 4 striped shirts = 6 options.

And on top of that she has:

2 hooded sweatshirts = 2 options.

The total number of combinations is equal to the product of options for each type of garmet; this is:

C = 6*6*2 =36*2 = 72

So she has 72 different outfits.

Answer:

It is 70 becouse of how many clothing ther is and u just mulytly

it tell me if im right or wrong

thanks stay safe

byebye

Step-by-step explanation:

Answer:

The slope of the graph is equal to 4

Step-by-step explanation:

When you do y2-y1 divided by x2-x1 you get the fraction 8/2 however when simplified you get 4, 8/2=4

Answer:

The slope is 4

Step-by-step explanation:

Why? Because the point (3,9) is labeled as x1 and y1 and the point (1,1) is labeled as x2 and y2, which means that the equation is set up as 1-9 / 1-3, which equals -8 / -2 , which turns out to be 4 when it is simplified. :)

Answer:

5 minutes

Step-by-step explanation:

Do a proportion

440/75= 1760/x

cross multiply

440x=1760(75)

simplify

132000/440

Answer:

1st  and second, unless you have already learned area of trapezoids. If you have, add third

Step-by-step explanation:

Answer: this is ez its

first

second

third

Step-by-step explanation:

Answer: 1.72 kilograms

Step-by-step explanation:

From the question, Ricardo is making a container of trail mix with 3.5 kilograms of nuts and he has 1.78 kilograms of almonds while the remaining of the nuts will be cashews.

To get the kilograms of cashews nuts that are needed, we subtract the kilograms of almonds from the total container. This will be:

= 3.5 kg - 1.78 kg

= 1. 72 kg

Answer:

28cm^2

Step-by-step explanation:

The area of a trapezoid is the bases added divided by two times the height.

(9+5)/2*4=7*4=28

28cm^2

Answer:

1.)

A=3

B=-6

2.)

1

3.)

(1,10)

Answer:

1.  Identify the values of a and b.            

a =  

✔ 3

and b =

✔ –6

2.   Find the x-coordinate of the vertex.

negative StartFraction b Over 2 a EndFraction  =

✔ 1

3.  Find the y-coordinate by evaluating the function at the x-value found in the previous step.

The vertex is

✔ (1, 10)

Answer:

C

Step-by-step explanation:

Answer:

2, 18, 56.52, It will double as well.

Step-by-step explanation:

First, multiply the radius by 9 to get the diameter, 18 inches. Then, multiply the diameter by 3.14(an approximation for pi) to get a circumference of about 56.52 inches.

If the diameter is doubled what happens to the circumference? Explain.

It will double because its like a second layer is added on,  and 56.52 x 2 = 113.04, which would be the doubled circumference.

Hope this helps! :)

Complete Question

Casey buys a bracelet. She pays for the bracelet and pays $0.72 in sales tax. The sales tax rate is 6%. What is the original price of the bracelet, before tax?

Answer:

$12

Step-by-step explanation:

Let the original price of the bracelet before tax =x

Tax rate =6%

That means:

6% of x =$0.72

0.06x=0.72

Divide both sides by 0.06

x=$12

The original price of the bracelet, before tax is $12.

Answer:

sky im going with A

Step-by-step explanation:

Answer:

[tex]=144x^7y^6[/tex]

Step-by-step explanation:

[tex]16x^4y^2\left(9x^3y^4\right)\\\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}\\x^4x^3=\:x^{4+3}\\=16y^2\cdot \:9x^{4+3}y^4\\\mathrm{Add\:the\:numbers:}\:4+3=7\\=16y^2\cdot \:9x^7y^4\\\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}\\y^2y^4=\:y^{2+4}\\=16\cdot \:9x^7y^{2+4}\\\mathrm{Add\:the\:numbers:}\:2+4=6\\=16\cdot \:9x^7y^6\\\mathrm{Multiply\:the\:numbers:}\:16\cdot \:9=144\\=144x^7y^6[/tex]

Answer:

Step-by-step explanation:

2 x(4−3xy^2)/y

Answer:

[tex]D)4log_{12}x+\frac{1}{2} log_{12}(x^3-2)-5log_{12}(x+1)[/tex]

(4 log Subscript 12 Baseline x + one-half log Subscript 12 Baseline (x cubed minus 2) minus 5 log Subscript 12 Baseline (x + 1)

Step-by-step explanation:

Given the expression:

[tex]log_{12}\dfrac{x^4\sqrt{x^3-2} }{(x+1)^5}[/tex]

first apply the division law of logarithm:

[tex]log_{a}x/y=log_{a}x-log_{a}y[/tex]

[tex]log_{12}\dfrac{x^4\sqrt{x^3-2} }{(x+1)^5}=log_{12}x^4\sqrt{x^3-2}-log_{12}(x+1)^5[/tex]

Next, by addition law:[tex]log_{a}xy=log_{a}x+log_{a}y[/tex]

[tex]=log_{12}x^4+log_{12}\sqrt{x^3-2}-log_{12}(x+1)^5\\\\Log a^m=mLog a, Log \sqrt{x}=log x^{1/2}\\\\ =4log_{12}x+log_{12}(x^3-2)^{1/2}-5log_{12}(x+1)\\\\=4log_{12}x+\frac{1}{2} log_{12}(x^3-2)-5log_{12}(x+1)[/tex]

Answer:

Its D on edge

Step-by-step explanation:

Answer:

cosine I think

Step-by-step explanation:

The ratio of the perpendicular and the hypotenuse is given by the sine of the angle. Then the correct option is A.

Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.

The ratio of the leg opposite to an angle to the hypotenuse of a right triangle is called the sine of the angle.

The sine is given as the side opposite to the angle is known as perpendicular.

The ratio of the perpendicular and the hypotenuse is given by the sine of the angle.

More about the trigonometry link is given below.

https://brainly.com/question/22698523

#SPJ2

Answer:

D

Step-by-step explanation:

i took the test

The equivalent expressions of [tex](x^{6} )^{-3}[/tex] will be [tex](x )^{-18}[/tex].

Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.

To derive the equivalent expressions of some expression, we can either make it look more complex or simple. Usually, we simplify it.

The given expression is;

[tex](x^{6} )^{-3}[/tex]

Required to Determine the equivalent expression.

First, we need to evaluate the expression in the bracket:

Apply the following law of indices:

[tex](x^a)^b = x ^{ab}[/tex]

So:

[tex](x^{6} )^{-3}[/tex]

becomes

[tex](x )^{6 \times -3}\\\\[/tex]

[tex](x )^{-18}[/tex]

Hence: the equivalent expressions of [tex](x^{6} )^{-3}[/tex] will be [tex](x )^{-18}[/tex].

Learn more about expression here;

https://brainly.com/question/14083225

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Answer:

0° and 90°

Step-by-step explanation:

Bearing is simply the angle, clockwise, between the north direction and any other direction;

In the first image (on the left) B is exactly in the north direction as compared to A so the bearing is 0°;

In the other image, B is to the right of A, which is a clockwise rotation of 90° from the north direction.

Answer: y-intercept

Step-by-step explanation:

Answer:.03x=6

Step-by-step explanation x=200 minutes

Answer:

200 minutes

Step-by-step explanation:

To find this, you should first set up an equation. Since you are trying to find the point where both plans cost the same, set them equal to each other. Let x be the cost for both. Write the equation:

[tex]16.95+0.05x=22.95+0.02x[/tex]

We place the x with the cost per minute because this is what you are trying to find. We add the cost per month.

Solve for x. Subtract 16.95 from both sides and simplify:

[tex]16.95-16.95+0.05x=22.95-16.95+0.02x\\0.05x=6+0.02x[/tex]

Subtract 0.02x from both sides:

[tex]0.05x-0.02x=6+0.02x-0.02x\\0.03x=6[/tex]

Divide both sides by 0.03:

[tex]\frac{0.03x}{0.03}=\frac{6}{0.03}\\ x=200[/tex]

At 200 minutes, the cost for both plans would be the same.

Answer:

The correct option is (D) [tex]y=\frac{4}{7}\ x+\frac{1}{7}[/tex].

Step-by-step explanation:

The two-point form for the equation of straight line is:

[tex](y-y_{1})=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\ (x-x_{1})[/tex]

The two points provided are:

A = (5, 3)

B = (12, 7)

Compute the equation of the trend line as follows:

[tex](y-y_{1})=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\ (x-x_{1})\\\\(y-3)=\frac{7-3}{12-5}\ (x-5)\\\\(y-3)=\frac{4}{7}\ (x-5)\\\\y-3=\frac{4}{7}\ x-\frac{20}{7} \\\\y=\frac{4}{7}\ x-\frac{20}{7}+3\\\\y=\frac{4}{7}\ x+\frac{-20+21}{7}\\\\y=\frac{4}{7}\ x+\frac{1}{7}[/tex]

Thus, the equation of the trend line is [tex]y=\frac{4}{7}\ x+\frac{1}{7}[/tex].

The correct option is (D).

Answer:

D

Step-by-step explanation:

Answer:

8ft. x 16ft.

Step-by-step explanation:

If each inch is scaled to 2 ft, then you simply multiply the values by two. The new scaled dimensions would be 8 x 16 ft. Hope this helps.

Answer:

85.375%

Step-by-step explanation:

We would be using the z-score formula which is

z = (x-μ)/σ, where

x is the raw score,

μ is the population mean, and

σ is the population standard deviation.

In the question, we are given:

x is the raw score = 47

μ is the population mean = Mean score = 43

σ is the population standard deviation = 3.8

z = (x-μ)/σ

z = (47- 43)/ 3.8

z = 4/3.8

z = 1.0526315789

The z score = 1.0526315789

Checking my z score on my normal distribution table,

The percentage of test takers that scored lower than you =

[1 - P(x>Z)] × 100

= ( 1 - 0.14625) × 100

= 0.85375 × 100

= 85.375%

Therefore, the percentage of test takers that scored lower than you is 85.375%

Answer:

140

Step-by-step explanation:

first multiply 17 by 14 to get 238 then dived 238 by 2 to get 140

Answer:

63x-8<23

63x<23+8

63x < 31

63. 63

x < 0.492

Answer:

6x -2y = 8

-6x+5y = 7

3y = 15

y = 5

6x - 2(5) = 8

6x - 10 = 8

6x = 18

x = 3

(3, 5)

Step-by-step explanation:

Answer:

The correct option is (D).

Step-by-step explanation:

The boxplot is a consistent way to exhibit the data-distribution based on, minimum, first quartile, median, third quartile and maximum.  

Therefore we can say it provides information about the location of the center, dispersion and skewness (measure of asymmetry) of the data.

The methods commonly used for depicting a frequency distribution are:

Out of these, one of the most general and extensively used devices of illustrating a frequency distribution is the histogram.

In this case it is provided that Anne wants the display of prizes to show how many homes are available for home buyers with various  budgets.

So, Anne can set range of budget values and assign the number of buyers with various  budgets.

From the provided data the range of budget values can be set as:

Less than $50,000

$50,000 - $100,000

$100,000 - $150,000

$150,000 - $200,000

$200,000 - $250,000

$250,000 - $300,000

$300,000 - $350,000

Thus, the histogram data display is best for Anne's purpose.

The correct option is (D).

This question is based on the concept of statistics. Therefore, the histogram data display is best for Anne's purpose. Hence, the correct option is D, histogram.

Given:

Anne wants to create a data display to summarize prices of the 264 homes for sale in her  area. A sample of the data is shown below.

$72,000, $129,500, $132,000, $149,400, $152,000, $183,500, $225,000, $289,000, $348,000.

According to the question,

As we know that, the boxplot is consistent way to exhibit the data distribution based on the minimum, first quartile, median, third quartile and maximum.  

Therefore, it provides information about the location of the center, dispersion and skewness (measure of asymmetry) of the data.

The following methods commonly used for depicting a frequency distribution are:

Out of these, one of the most extensively used devices of illustrating a frequency distribution is the histogram.

In this question it is provided that, Anne wants the display of prizes to show how many homes are available for home buyers with various  budgets.

Thus, Anne can set range of budget values and assign the number of buyers with various budgets.

From the given data the range of budget values can be written as:

Less than $50,000

$50,000 - $100,000  

$100,000 - $150,000

$150,000 - $200,000

$200,000 - $250,000

$250,000 - $300,000

$300,000 - $350,000

Therefore, the data display is best for Anne's purpose. Hence the correct option is D, histogram.

For more details, prefer this link:

https://brainly.com/question/23370669

Answer:

i think the answer is 1 dont take my word for it though

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

The absolute value of -4 is 4, therefore |-4|/|-4| = 4/4 = 1

Answer:

see below

Step-by-step explanation:

8.

We have to use the law of cosines to find AB

c^2 = a^2 + b^2 − 2ab cos(C)

AB^2 = 14^2 + 24^2 - 2 * 14 *24 cos(91)

AB^2 =196 +576 - 672 cos(91)

AB^2 =783.7280171

Taking the square root of each side

AB =27.99514

Rounding to the nearest tenth

AB = 28

(If the lengths are supposed to have the variable A)

AB = 28A

9.

Using the law of sines

sin 84              sin A

--------------  = -------------

22                     9

Using cross products

9 sin 84 = 22 sin A

Divide each side by 22

9 sin 84 /22 = sin A

.406849866 = sin A

Taking the inverse sin of each side

24.00710132 = A

To the nearest tenth

A = 24

Answer:

AB = 28 ft; m<A = 24 deg

Step-by-step explanation:

8.

Since you are not given an angle and its opposite side, you cannot start with the law of sines. You must use the law of cosines.

[tex] c^2 = a^2 + b^2 - 2ab \cos C [/tex]

[tex] c^2 = (14~ft)^2 + (24~ft)^2 - 2(14~ft)(24~ft) \cos 91^\circ [/tex]

[tex] c^2 = 196~ft^2 + 576~ft^2 - 672~ft^2(-0.01745) [/tex]

[tex] c = \sqrt{783.73~ft^2} [/tex]

[tex] c = 27.995~ft [/tex]

AB = c = 28 ft

9.

[tex] \dfrac{\sin A}{a} = \dfrac{\sin B}{b} = \dfrac{\sin C}{c} [/tex]

[tex] \dfrac{\sin A}{a} = \dfrac{\sin B}{b} [/tex]

[tex] \dfrac{\sin A}{9~km} = \dfrac{\sin 84^\circ}{22~km} [/tex]

[tex] \sin A = \dfrac{9~km~\sin 84^\circ}{22~km} [/tex]

[tex] \sin A = 0.40685 [/tex]

[tex] A = \sin^{-1} 0.40685 [/tex]

[tex] A = 24^\circ [/tex]