Carboxylic acids and alcohols react via dehydration and condensation to produce a/an _______ and water.

Question options:



amine




ether




polymer




ester

Answers

Answer 1

Answer:

ester

Explanation:

Carboxylic acids and alcohols react in the presence of strong acid to produce an ester and water. The two carbon chains come together, which is the condensation, and then water is generated, which is dehydration. The resulting compound is an ester.


Related Questions

2.50 L of 0.700 M phosphoric acid reacts with 5.25 moles of sodium hydroxide. How many moles of hydrogen ions will completely neutralize the moles of hydroxide ions present in this amount of sodium hydroxide? a) 0.583 b) 1.75 c) 3.00 d) 15.75 e) 5.25

Answers

Answer:

5.25 moles of protons. Option e

Explanation:

Reaction between phosphoric acid and sodium hydroxide is neutralization.

We can also say, we have an acid base equilibrium right here:

H₃PO₄  +  3NaOH →  Na₃PO₄  +  3H₂O

Initially we have 5.25 moles of base.

We have data from the acid, to state its moles:

M = mol/L, so mol = M . L

mol = 1.75 moles of acid

If we think in the acid we know:

H₃PO₄  →  3H⁺  +  PO₄⁻³

We know that 1 mol of acid can give 3 moles of protons (hydrogen ions)

If we have 1.75 moles of acid, we may have

(1.75 . 3) /1 = 5.25 moles of protons

These moles will be neutralized by the 5.25 moles of base

H₃O⁺  +  OH⁻  ⇄  2H₂O     Kw

In a titration of a weak acid and a strong base, we have a basic pH

A clean-burning automobile engine emits about 5 lb of C atoms in the form of CO2 molecules for every gallon of gasoline it consumes. The average American car is driven about 12,000 miles per year. Using this information, check the statement that the average American car releases its own weight in carbon into the atmosphere each year. List the assumptions you make to solve this problem.

Answers

Solution :

1 lb = 453.592 g

1 gallon = 3785 g

For every 5 gallon gasoline = 5 lb of C is found

                                              = 5 x 453.592 g of C atoms

                                              = 2267.96 g of C atoms

Assume the consumption of car = 15 miles per kg of gasoline

The amount of gasoline used per year  [tex]$=\frac{12000}{15}$[/tex]

                                                                   = 800 kg

In gallons = [tex]$\frac{800}{3.785} = 211.36\text{ gallons}$[/tex]    

5 gallons will produce = 2267.96 g of C atoms

Therefore,  

211.36 gallons will produce = [tex]$\frac{211.36 \times 2267.96}{5}$[/tex]

                                             = 95871.21 g

                                             = 95.87 kg

or                                           = 25.32 gallon

Consider the following equation for the combustion of acetone (C3H6O), the main ingredient in nail polish remover.
C3H6O(l) + 4O2(g) → 3CO2(g) + 3H2O(g) ΔHrxn = −1790kJ
If a bottle of nail polish remover contains 143 g of acetone, how much heat would be released by its complete combustion? Express your answer to three significant figures.

Answers

Molar mass of Acetone

C3H6O3(12)+6+1658g/mol

Now

1 mol releases -1790KJ heat .

Moles of Acetone:-

143/58=2.5mol

Amount of heat:-

2.5(-1790)=-4475kJ

The overall order of an elementary step directly corresponds to its molecularity.

a. True
b. False

Answers

Answer:

true

Explanation:

Chemical reactions can exhibit different rate constants at differing: Select the correct answer below: initial concentrations volumes of container temperatures none of the above

Answers

Explanation:

Chemical reactions can exhibit different rate constants at differing:

i)initial concentrations

ii)volumes of container

iii) temperatures

iv)none of the above.

The rate constant of a reaction is constant at a particular temperature.

It is not depending on the initial concentration of the reactants. It varies with temperature.

Thus, among the given options the correct answer is Temperatures.

Chemical reactions can exhibit different rate constant at different temperatures. Hence, the correct option is temperature.

What is a rate constant?

The rate constant is the proportionality constant in the equation that expresses the relationship between the rate of a chemical reaction and the concentrations of the reacting substances.

Chemical reactions proceed at vastly different speeds depending on the nature of the reacting substances, the type of chemical transformation, the temperature, etc.

For a given reaction, the speed of the reaction will vary with the temperature, the pressure, and the amounts of reactants present.

The rate constant goes on increasing as the temperature goes up, but the rate of increase falls off quite rapidly at higher temperatures.

On the other hand, the volume of the container, initial concentration does not affect the rate constant.

Therefore, Chemical reactions can exhibit different rate constant at different temperatures. Hence, the correct option is temperature.

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9. How can you separate sugar from a sugar solution contained in a glass without taste? Explain​

Answers

Answer:

See explanation

Explanation:

Sugar is a polar crystalline substance. The sugar crystal is capable of dissolving in water since it is polar.

When sugar dissolves in water, a sugar solution is formed. If I want to separate the sugar from the water in the solution, I have to boil the solution to a very high temperature.

When I do that, the water in the sugar solution is driven off and the pure sugar crystal is left behind.

A rock originally has 2200 atoms of 235U and no 207Pb. It now has 800 atoms of 235U. Assuming the only chemical process is the radioactive decay of uranium to lead, what is the age of the rock

Answers

Answer:

[tex]Age=1040.55 million\ years[/tex]

Explanation:

From the question we are told that:

Initial Rock atoms [tex]a_1=2200atoms of 235^U[/tex]

Final Rock atom [tex]a_2=800 of  235^U[/tex]

Age of half life 713 million years

Generally the equation for Age is mathematically given by

[tex]\frac{1}{2^n}=\frac{800}{2200}[/tex]

[tex]\frac{1}{2^n}=\frac{1}{2.750}[/tex]

[tex]n=1.46[/tex]

Therefore

[tex]Age=713*1.46[/tex]

[tex]Age=1040.55 million\ years[/tex]

A 0.4272 g sample of an element contains 2.241 x 10 ^21 atoms . what is the symbol of the element?

Answers

Answer:

Likely [tex]\rm In[/tex] (indium.)

Explanation:

Number of atoms: [tex]N = 2.241 \times 10^{21}[/tex].

Dividing, [tex]N[/tex], the number of atoms by the Avogadro constant, [tex]N_A \approx 6.023 \times 10^{23} \; \rm mol^{-1}[/tex], would give the number of moles of atoms in this sample:

[tex]\begin{aligned} n &= \frac{N}{N_{A}} \\ &\approx \frac{2.241 \times 10^{21}}{6.023 \times 10^{23}\; \rm mol^{-1}} \approx 3.72 \times 10^{-3}\; \rm mol \end{aligned}[/tex].

The mass of that many atom is [tex]m = 0.4272\; \rm g[/tex]. Estimate the average mass of one mole of atoms in this sample:

[tex]\begin{aligned}M &= \frac{m}{n} \\ &\approx \frac{0.4272\; \rm g}{3.72 \times 10^{-3}\; \rm mol} \approx 114.82\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

The average mass of one mole of atoms of an element ([tex]114.82\; \rm g \cdot mol^{-1}[/tex] in this example) is numerically equal to the average atomic mass of that element. Refer to a modern periodic table and look for the element with average atomic mass [tex]114.82[/tex]. Indium, [tex]\rm In[/tex], is the closest match.

The symbol of the element is In

Stoichiometry

From the question, we are to determine the identity of the element

First, we will determine the number of moles of sample present

Using the formula

[tex]Number \ of\ moles = \frac{Number\ of \ atoms }{Avogadro's\ constant}[/tex]

Number of moles of the sample = [tex]\frac{2.241\times 10^{21} }{6.022\times 10^{23} }[/tex]

Number of moles of the sample = 0.003721355 mole

Now, we will determine the Atomic mass of the sample

From the formula,

[tex]Atomic\ mass = \frac{Mass}{Number\ of\ moles}[/tex]

Therefore,

Atomic mass of the sample = [tex]\frac{0.4272}{0.003721355}[/tex]

Atomic mass of the sample = 114.8 amu

The element that has an atomic mass of 114.8 amu is Indium. The symbol of Indium is In.

Hence, the symbol of the element is In.

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During the postabsorptive state, metabolism adjusts to a catabolic state.

a. True
b. False

Answers

Answer:

The postabsorptive state (also called the fasting state) occurs when the food is already digested and absorbed, and it usually occurs overnight, when you sleep (if you skip meals for some days, you will enter in this state).

The catabolic state is the metabolic breakdown of molecules into simpler ones, releasing energy (heat) and utilizable resources.

Now, when you are in a postabsorptive state, the glucose levels start to drop, then the body starts to depend on the glycogen stores, which are catabolized into glucose, this is defined as the start of the postabsorptive state.

So yes, as the postabsorptive states, catabolic processes start to happen, so the statement is true.

CAN HF USED TO CLEAVE ETHERS EXPLAIN

Answers

Answer:

no

Explanation:

Fluoride is not nucleophilic (having the tendency to donate electrons) enough to allow for the use of HF to cleave ethers in protic media(protic solvents are polar liquid compounds that have dissociable hydrogen atoms). The rate of reaction is comparably low, so that heating of the reaction mixture is required.

If 0.650 mL of benzaldehyde reacts with enough of the Grignard reagent, calculate the theoretical yield (in grams) of the alcohol product. Show calculation with units for full credit.

Answers

Answer:

Theoretical yield of 1-Phenyl-1-propanol in grams = 0.871 g

Explanation:

A Grignard reagent is any of the numerous organic derivatives of magnesium (Mg) which are commonly represented by the general formula RMgX (where R is a hydrocarbon radical e.g. methyl, ethyl, propyl, etc.; and X is a halogen atom, e.g. chlorine, bromine, or iodine)

A Grignard reaction converts an aldehyde to a secondary alcohol. In the grignard reaction involving benzaldehyde as in this experiment, the grignard reagent used is ethyl magnesium bromide, EtMgBr, and the resulting product is 1-Phenyl-1-propanol, a secondary alcohol. The reaction is shown in the figure attached below.

Mass of benzaldehyde in 0.650 mL = density × volume

Density of Benzaldehyde = 1.044 g/mL

Mass of benzaldehyde = 1.044 g/mL × 0.650 mL = 0.6786 g

Molar mass of benzaldehyde = 106 g/mol

Molar mass of 1-Phenyl-1-propanol = 136 g/mol

Mass of = mass of benzaldehyde × mole ratio of 1-Phenyl-1-propanol and benzaldehyde

Mass of 1-Phenyl-1-propanol = 0.6786 g × (136 g/mol)/(106 g/mol) = 0.871 g

Therefore, the theoretical yield of 1-Phenyl-1-propanol in grams = 0.871 g

Write the functional isomers of C2H6O?

Answers

Answer:

See explanation

Explanation:

Isomers are molecules which have the same molecular formula but different structural formulas. Sometimes, isomers may even contain different functional groups.

The formula C2H6O may refer to an ether or an alcohol. The compound could be CH3CH2OH(ethanol) or CH3OCH3(methoxymethane).

Hence, the functional isomers of the formula C2H6O are ethanol and methoxymethane.

How many grams of Ag2CO3 will precipitate when excess K2CO3 solution is added to 56.0 mL of 0.671 M AgNO3 solution?

Answers

Answer:

The mass of silver carbonate precipitated is 5.18 grams.

Explanation:

Molarity of the silver nitrate solution = 0.671 M

Volume of the silver nitrate solution = 56.0 mL

[tex]1 mL = 0.001 L\\56.0 mL = 56.0\times 0.001 L=0.0560 L[/tex]

Moles of silver nitrate = n

[tex]Molarity=\frac{\text{Moles of compound}}{\text{Volume of solution in Liters}}\\\\0.671 M=\frac{n}{0.0560 L}\\n=0.671 M\times 0.0560 L=0.0376 mol[/tex]

Moles of silver nitrate used = 0.0376 mol

[tex]K_2CO_3+2AgNO_3\rightarrow Ag_2CO_3+2KNO_3[/tex]

According to the reaction, 2 moles of silver nitrate gives 1 mole of silver carbonate, then 0.0376 moles of silver nitrate:

[tex]=\frac{1}{2}\times 0.0376 mol=0.0188 \text{mol of }Ag_2CO_3[/tex]

Moles of the silver carbonate formed = 0.0188 mol

Molar mass of silver carbonate = 275.7453 g/mol

Mass of silver carbonate :

[tex]=275.7453 g/mol\times 0.0188 mol=5.1840 g\approx 5.18 g[/tex]

The mass of silver carbonate precipitated is 5.18 grams.

Sodium peroxide (Na2O2) is often used in self-contained breathing devices, such as those used in fire emergencies, because it reacts with exhaled CO2 to form Na2CO3 and O2. How many liters of respired air can react with 96.7 g of Na2O2 if each liter of respired air contains 0.0755 g of CO2

Answers

Answer:

725.15 L

Explanation:

The balanced chemical equation for the reaction between Na₂O₂ and CO₂ is the following:

Na₂O₂ + CO₂ → Na₂CO₃ + 1/2 O₂

From the stoichiometry of the reaction, 1 mol of Na₂O₂ reacts with 1 mol CO₂. So, the stoichiometric ratio is 1 mol Na₂O₂/1 CO₂.

Now, we convert the mass of reactants to moles by using the molecular weight (Mw) of each compound:

Mw (Na₂O₂) = (23 g/mol x 2) + (16 g/mol x 2) = 78 g/mol

moles Na₂O₂ = 96.7 g/(78 g/mol) = 1.24 mol Na₂O₂

Mw (CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol

moles CO₂ = 0.0755 g/(44 g/mol) = 1.71 x 10⁻³ mol CO₂

Now, we calculate the number of moles of CO₂ we need to completely react with the mass of Na₂O₂ we have:

1.24 mol Na₂O₂ x 1 mol CO₂/1 mol Na₂O₂ = 1.24 mol CO₂

In 1 L of respired air we have 1.71 x 10⁻³ mol CO₂ (0.0755 g), so we need the following number of liters to have 1.24 mol of CO₂:

1.24 mol CO₂ x 1 L/1.71 x 10⁻³ mol CO₂ = 725.15 L

A 250-mg sample of carbon from wood underwent 15300 carbon-14 disintegrations in 36 hours. Estimate the time since the death of the sample.

Answers

Answer:

The correct answer is - 9935 years approximately.

Explanation:

Let z be the age in years to be found:

(15300 disintegrations) x (1.0 g / 0.250 g) / (1.84×10^4 disintegrations)

= 3.3260

half life of carbon = (1/2)^(z/5730 yr)

Solve for z

3.3260 = (1/2)^(z/5730)

Take the log of both sides:

log 3.3260  = (z/5730) log (1/2)

log 3.3260 / log (1/2) = z/5730

z = 5730 log 3.3260 / log (1/2)

= 1.73378816*5730

= 9935 years approximately.

How many grams of sodium nitrate (NaNO3) are needed to
prepare 100 grams of a 15.0 % by mass sodium nitrate
solution?

Answers

Answer:

15.0 g

Explanation:

15.0% =0.150

100.0 g × 0.150= 15.0g

Sodium nitrate is "an inorganic compound with the formula of NaNO₃.

What is an inorganic compound?

Inorganic compound is "a chemical compound that lacks carbon–hydrogen bonds".

15% = 0.15

100.0 g × 0.15= 15g

Hence, 15g of Sodium nitrate are needed to prepare 100 gms of a 15% by mass sodium nitrate.

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what are the major specials presents in a solution of a strong acid like HCl

Answers

Answer:

hydrogen ions (H⁺) and chloride ions (Cl⁻)

Explanation:

Hydrochloric acid (HCl) is a strong acid. That means that the compound dissociates completely into ions when is dissolved in water, as follows:

HCl → H⁺ + Cl⁻

The equilibrium is completely shifted to the right side (products). Thus, it is considered that the concentration of the non-dissociated compound (HCl) is negligible, and the major specials present in the solution are the hydrogen ions (H⁺) and chloride ions (Cl⁻).

How to solve this problem step by step

Answers

Answer:

[tex]V_2= 736mL[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the combined gas law:

[tex]\frac{P_2V_2}{T_2}= \frac{P_1V_1}{T_1}[/tex]

Thus, we solve for the final volume by solving for V2 as follows:

[tex]V_2= \frac{P_1V_1T_2}{T_1P_2}[/tex]

Now, we plug in the variables to obtain the result in milliliters and making sure we have both temperatures in Kelvins:

[tex]V_2= \frac{1.20atm*735mL*279K}{(112+273)K*660/760atm}\\\\V_2= \frac{1.20atm*735mL*279K}{(112+273)K*660/760atm}=736mL[/tex]

Regards!

How many atoms are in .45 moles of P4010

Answers

Answer:

5×6.02×1023

Explanation:

there are 5×6.02×1023 molecules of p4010 in 5mole. there are four P atoms in a single molecule of p4010

What will be the equilibrium temperature when a 245 g block of lead at 300oC is placed in 150-g aluminum container containing 820 g of water at 12.0oC?

Answers

Answer:

The correct approach is "12.25°C".

Explanation:

Given:

Mass of lead,

mc = 245 g

Initial temperature,

tc = 300°C

Mass of Aluminum,

ma = 150 g

Initial temperature,

ta = 12.0°C

Mass of water,

mw = 820 g

Initial temperature,

tw = 12.0°C

Now,

The heat received in equivalent to heat given by copper.

The quantity of heat = [tex]m\times s\times t \ J[/tex]

then,

⇒ [tex]245\times .013\times (300-T) = 150\times .9\times (T-12.0) + 820\times 4.2\times (T-12.0)[/tex]

⇒             [tex]3.185(300-T) = 135(T-12.0) + 3444(T-12.0)[/tex]

⇒             [tex]955.5-3.185T=135T-1620+3444T-41328[/tex]

⇒                         [tex]43903.5 = 3582.185 T[/tex]

⇒                                  [tex]T = 12.25^{\circ} C[/tex]

PLEASE HELP ASAP MOLES TO MOLECULES

Answers

Answer:

4.77mol is the correct answer

4.77 mol, is the answer:)

In what order do electrons fill orbitals?
A. Orkjtals s, p, and then d fill in one energy level before starting the
next level.
B. Before pairing, 1 electron occupies each sand porbital.
C. Electrons fill orbitals in order of increasing orbital energy.
D. The p orbitals fill before the s orbitals in an energy level.
SUBMIT

Answers

Answer:

c......................

Answer:

electrons will fill the lowest energy orbitals first and then move up to higher energy orbitals only after the lower energy orbitals are full

Si enfriamos mercurio de 100C. Calcular la cantidad de calor que se debe restar sabiendo que la masa de mercurio es de 1800gr

Answers

Answer:

I do not speak Spanish.

Explanation:

Draw the structure of the neutral product formed in the reaction of dimethyl malonate and methyl vinyl ketone.

Answers

Answer:

Explanation:

The reaction between dimethyl malonate which is an active methylene group with an (∝, β-unsaturated carbonyl compound) i.e methyl vinyl ketone is known as a Micheal Addition reaction. The reaction mechanism starts with the base attack on the β-carbon to remove the acidic ∝-hydrogens and form a carbanion. The carbanion formed(enolate ion) attacks the methyl vinyl ketone(i.e. a nucleophilic attack at the β-carbon) to give a Micheal addition product, this is followed by the protonation to give the neutral product.

g A high altitude balloon is filled with 1.41 x 104 L of hydrogen gas (H2) at a temperature of 21oC and a pressure of 745 torr. What is the volume of the balloon at a height of 20 km, where the temperature is -48oC and the pressure is 63.1 torr

Answers

Answer:

1.27 × 10⁵ L

Explanation:

Step 1: Given data

Initial pressure (P₁): 745 TorrInitial volume (V₁): 1.41 × 10⁴ LInital temperature (T₁): 21 °CFinal pressure (P₂): 63.1 TorrFinal volume (V₂): ?Final temperature (T₂): -48 °C

Step 2: Convert the temperatures to the Kelvin scale

We will use the following expression.

K = °C + 273.15

K = 21 °C + 273.15 = 294 K

K = -48 °C + 273.15 = 225 K

Step 3: Calculate the final volume of the balloon

We will use the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂/ T₁ × P₂

V₂ = 745 Torr × 1.41 × 10⁴ L × 225 K/ 294 K × 63.1 Torr

V₂ = 1.27 × 10⁵ L

An unknown element, X, reacts with potassium to form the compound K2X. In other compounds this element also can accommodate up to 12 electrons rather than the usual octet. What element could X be

Answers

Answer:

Se

Explanation:

First of all, we must note that any element that we must choose is an element that is in group sixteen.

Elements of groups 16 have six electrons in their outermost shell which can be used for bond formation thereby yielding a total of twelve electrons on the valence shell.

However, this is only possible for the heavier members of the group 16 (from sulphur downwards) which are able to expand their octet.

Oxygen can not expand its octet hence it is not the answer.

An electron moved from shell n = 2 to shell n = 1. What most likely happened during the transition?

Answers

When electron goes from a higher shell to lower shell then it loses energy .

So, when an electron moved from shell n = 2 to shell n = 1 then a photon of energy is released.

How much of a 24-gram sample of Radium-226 will remain unchanged at the end of three half-life periods?

Answers

Answer:

The right answer is "3 g".

Explanation:

Given:

Initial mass substance,

[tex]M_0=24 \ g[/tex]

By using the relation between half lives and amount of substances will be:

⇒ [tex]M=\frac{M_0}{2^n}[/tex]

        [tex]=\frac{24}{2^3}[/tex]

        [tex]=3 \ g[/tex]

Thus, the above is the correct answer.

Which of the following are examples of physical properties of ethanol? Select all that apply.

The boiling point is 78.37°C

It is a clear, colorless liquid

It is flammable

It is a liquid at room temperature

Answers

Ethanol is: flammable, liquid at room temperature, the boiling point is 78.37 ° C.

C. A sample may contain any or all of the following ions Hg2 2, Ba 2, and Al 3. 1) No precipitate forms when an aqueous solution of NaCl was added to the sample solution. 2) No precipitate forms when an aqueous solution of Na2SO4 was added to the sample. 3) A precipitate forms when the sample solution was made basic with NaOH. Which ion or ions were present. Write the net ionic equation(s) for the the reaction (s).

Answers

Answer:

Al^3+

Explanation:

Solubility rules tell us what substances are soluble in water. Since NaCl was added and no precipitate was observed, the mercury II ion is absent.

Addition of Na2SO4 does not form a precipitate meaning that Ba^2+ is absent.

If a precipitate is formed when NaOH is added, the the ionic reaction is as follows;

Al^3+(aq) + 3 OH^-(aq) ------> Al(OH)3(s)

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Why has April 15 come to be know as tax day ? please help me please help me In fiction, which of the following is a reason to start a new paragraph?A. All of theseB. When a new character joins the story.C. When a character gives a list.D. When a character describes himself or herself. ABC Corporation owns a factory. They are selling the factory to Amalgamated Corp. The lawyer for ABC Corporation writes the deed with all of the required elements, and it is signed by Bill Smith. Bill is the president of ABC Corporation, but it doesn't say so on the deed, nor is there a corporate seal. Is this a valid real estate transaction Porque las enzimas actuan sobre algunas sustancias outline the significances of passion death and Resurrection of Jesus to Christians today Buenos das. Me llamo Enrique Pea. Cmo _[blank]_ usted? Required: a. Compute gross profit, the goods available for sale, and the cost of goods sold for the merchandiser. Hint: Not all information may be necessary. b. Use the above information from a service company and from a merchandiser to compute net income.Kleiner Merchandising CompanyAccumulated depreciation $ 700Beginning inventory 10,000Ending Inventory 6,000Expenses 1,950Net Purchases 11,900Net Sales 19,500Krug Service CompanyExpenses $ 8,400Revenues 24,000Cash 650Prepaid rent 660Accounts payable 200Equipment 2,200 The function f(x) = log4x is dilated to become g(x) = f (1/3x).What is the effect on f(x)? A person's food choices may be influenced bya personal tasteb availabilityc Culture d health conditions If f(x) =3x^2 +1 and g(x) = 1 -x, what is the value of (f-g) (2)? Find the value(s) of a in the domian of f for which f(a)=1. f (x)=x^2+2x-2 Suppose the national mean annual salary for a school administrator is $91,000 a year. A school official took a sample of 25 school administrators in the state of Ohio to learn about salaries in that state to see if they differed from the national average.77,600 76,000 90,700 97,200 90,700101,800 78,700 81,300 84,200 97,60077,500 75,700 89,400 84,300 78,70084,600 87,700 103,400 83,800 101,30094,700 69,200 95,400 61,500 68,800(a) Formulate hypotheses that can be used to determine whether the population mean annual administrator salary in Ohio differs from the national mean of $91,000.H0: 91,000Ha: > 91,000H0: > 91,000Ha: 91,000H0: 91,000Ha: < 91,000H0: < 91,000Ha: 91,000H0: = 91,000Ha: 91,000(b) The sample data for 25 Ohio administrators is contained in the file named Administrator.What is the test statistic for your hypothesis test in part (a)? (Round your answer to three decimal places.)What is the p-value for your hypothesis test in part (a)? (Round your answer to four decimal places.)p-value = (c) At = 0.05,can your null hypothesis be rejected? What is your conclusion?Reject H0. We can conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.Do not reject H0. We cannot conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary. Reject H0. We cannot conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.Do not reject H0. We can conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.(d) Repeat the preceding hypothesis test using the critical value approach.State the null and alternative hypotheses.H0: 91,000Ha: > 91,000H0: > 91,000Ha: 91,000H0: 91,000Ha: < 91,000H0: < 91,000Ha: 91,000H0: = 91,000Ha: 91,000Find the value of the test statistic. (Round your answer to three decimal places.)State the critical values for the rejection rule. Use = 0.05. (Round your answer to three decimal places. If the test is one-tailed, enter NONE for the unused tail.)test statistictest statisticState your conclusion.Reject H0. We can conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.Do not reject H0. We cannot conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary. Reject H0. We cannot conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.Do not reject H0. We can conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary. On July 1, 2021, Clearwater Inc. purchased 9,300 shares of the outstanding common stock of Mountain Corporation at a cost of $213,000. Clearwater will have significant influence over the financial and operating policies of Mountain. Mountain had 31,000 shares of outstanding common stock. Assume the total book value and fair value of identifiable net assets is $660,000. Both companies have a January through December fiscal year. The following data pertains to Mountain Corporation during 2021:Dividends declared and paid, Jan. 1June 30 $11,700 Dividends declared and paid, Jul. 1Dec. 31 $11,700 Net Income, January 1June 30 $13,700 Net Income, July 1December 31 $17,700 Required:a. Prepare the entry to record the original investment in Mountain.b. Compute the goodwill (if any) on the acquisition.c. Prepare the necessary entries (other than acquisition) for 2021 under the equity method. Which detail best shapes the central idea that the Japanese art of boat building is taught using unconventional learning methods? School of Hard Knots by Alex Hanson The typical apprenticeship with a Japanese traditional boatbuilder lasts six years, during which an apprentice can expect to spend a lot of time sweeping the shop floor and sharpening tools while watching the master ply his trade. Work is conducted in silence, questions are answered elliptically, if at all, and, by the end, the master will have withheld key pieces of knowledge that the apprentice is expected to acquire through guile or outright theft. Even in Japan, where traditional crafts are revered, this system is too grueling, too much at odds with modern life, to survive.It is no wonder, then, that as a generation of Japanese boatwrights has retired, their knowledge has retired with them.Vermont boatbuilder Douglas Brooks is trying to ensure that the centuries-old designs for fishing boats and water taxis don't follow these craftsmen to the grave. For more than two decades, Brooks has researched traditional boatmaking in Japan, and has done short, nontraditional apprenticeships to record boat designs. Ordinarily, no Westerner would have a hope of learning in a few weeks what usually takes years of patient observation to acquire. "They're willing to teach me because they realize what's about to be lost," Brooks says. The challenge of preserving this art is largely pedagogical, and that's the subject of "Ways of Learning," a slide talk Brooks gives through the Vermont Humanities Council's speakers bureau.Through his talk, Brooks has stimulated a debate about how traditional crafts are handed down. His American audiences expect collegiality and dialogue between student and teacher and are often shocked to hear about the Japanese method. Write the expression as an exponent with a base 2 and find its value:2^4*2 A man ordered 5 times as many boxes of ballpoint pens as boxes of felt-tip pens. Ballpoint pens cost $ 4.33 per box, and felt-tip pens cost $.3.45 If the man's order of pens totaled $75.30, how many boxes of each type of pen did he buy? HELP!!! 15 points. picture below Find the value of y if [2is 130 and [4is 2y.142.3 what planet needs oxygen in order for individuals to live on ?