Answer: salt , higher.
Explanation:
Doing it right now
Answer:
salt, higher
Explanation:
edge
What is the mole fraction of Ba(OH)2 in an aqueous solution that contains 22.8% Ba(OH)2 by mass?
Answer:
0.03
Explanation:
22.8 g Ba(OH)2 (1 mol Ba (OH)2/ 171.34 g) = 0.133 mol Ba (OH)2
77.2 g H2O (1 mol H2O/18 g) = 4.29 mol H2O
X= molar fraction= mol Ba(OH)2/ mol total
X= 0.133/ (0.133+4.29) = 0.03
0.03 is the mole fraction of [tex]Ba(OH)_2[/tex] in an aqueous solution that contains 22.8% [tex]Ba(OH)_2[/tex] by mass.
What is a mole fraction?The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.
Moles of [tex]Ba(OH)_2[/tex]
Moles = [tex]\frac{mass}{molar \;mass}[/tex]
Moles = [tex]\frac{22.8 g Ba(OH)_2}{171.34 g}[/tex]
= 0.133 mol [tex]Ba (OH)_2[/tex]
Moles of [tex]H_2O[/tex]
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{77.2 g H_2O}{18 g}[/tex]
= 4.29 mol [tex]H_2O[/tex]
The mole fraction of [tex]Ba(OH)_2[/tex]
[tex]\frac{mol Ba(OH)_2}{total \;mol}[/tex]
= 0.03
0.03 is the mole fraction of [tex]Ba(OH)_2[/tex] in an aqueous solution that contains 22.8% [tex]Ba(OH)_2[/tex] by mass.
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After brushing, Fluffy's fur has a charge of +8.0 x 10' coulombs and her plastic brush has a charge of -1.4 x 10-8 coulombs. If the distance between the fur and
brush is roughly 5.0 * 10 meters, what is the approximate magnitude of the force between them?
(k = 9.0 * 10 newtonmeters/coulomb?)
A 5.0 x 106 newtons
B.
2.0 x 10-4 newtons
C
4.0 x 106 newtons
D. 2.5 x 10 newtons
Reset
Next
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SUS
Answer:
jeez thats some calculus stuff right there im pretty sure its b
Explanation:
Which situation describes why a rock sinks in water?
A. Air pressure is greater than the buoyant force.
B. The force of gravity is greater than the buoyant force.
c. The buoyant force is greater than the force of gravity.
D. The rock is less dense than water.
Answer:
b
Explanation:
How many moles of calcium chloride are contained in a 333 gram sample?
*
A) 8.82 moles
B) 0.333 moles
C) 4.30 moles
D) 0 3.00 moles
Answer & Explanation:
The molar mass of calcium chloride is 110.98 g/mol. We can use this information to solve this problem. We can set up our equation like this..
[tex]\frac{333 g(CaCl2)}{} *\frac{1mol(CaCl2)}{110.98g(CaCl2)}[/tex]
Multiply straight across on the top and straight across on the bottom.
[tex]\frac{333}{110.98}[/tex]
Now divide.
[tex]\frac{333}{110.98}=3.00[/tex]
So, there are 3.00 moles of calcium chloride contained in a 33 gram sample which is answer choice D.
Which of these Electromagnetic waves has the most kinetic energy and can be
dangerous?
O radio waves
O gamma rays
O ultraviolet waves
O visible light
Answer:
Gamma Rays.
Explanation:
Gamma-ray photons have the highest energy in the EMR spectrum and their waves have the shortest wavelength.
What does “moving slow” mean to a geologist?
A landslide can be defined as a mass movement of material (e.g., rocks), which moves down a steep slope. A geologist is an expert that studies SLOW-MOVING landslides on a geological scale.
Landslides can occur suddenly or more slowly over long periods of time.
On a geological scale, landslides occur slowly so they are imperceptible to humans.
A geologist is a professional who investigates landslides on a geological scale, which is coarse on a human time-frame.
In conclusion, a geologist is a professional who investigates SLOW-MOVING landslides on a geological scale.
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B. If the sand you ran across has a specific-heat capacity of 835 J/(kgºc),
how much energy must be added to a 2-kilogram pile of it to increase its
temperature from 40°C to 50°C? Show your work. (3 points)
Answer: 16700 Joules
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat absorbed = ?
m = mass of sand = 2 kg
c = heat capacity = [tex]835J/kg^0C[/tex]
Initial temperature = [tex]T_i[/tex] = [tex]40^0C[/tex]
Final temperature= [tex]T_f[/tex] = [tex]50^0C[/tex]
Change in temperature ,[tex]\Delta T=T_f-T_i=(50-40)^0C=10^0C[/tex]
Putting in the values, we get:
[tex]Q=2kg\times 835J/kg^0C\times 10^0C[/tex]
[tex]Q=16700J[/tex]
16700 J of energy must be added to a 2-kilogram pile of it to increase its temperature from 40°C to 50°C
Which of the following is an example of a Lewis base?
O A. H+
B. BF3
O C. NH3
O D. H20+
Answer:
O C. NH3 is an example of a lewis base
I AM GIVING BRAINLIEST PLEASEEEEEE HELPPPPPPPPPP I NEEDDDDDDDD HELPPP PLEASE
How many grams of solute are needed to make 2.66L of a 1.99M C 12 H 22 O 11 solution?
Answer:
1812g
Explanation:
So molarity is moles/litres or M= mol/liter (lets apply this formula to find moles)
M=mol/L
1.99=mol/2.66
Moles= 5.2934 moles of C12H22O11
Next step is quite simple, we know molar mass of C12H22O11 is 342.3 g/mol so we simply multiply the moles we get to molar mass we are left with the grams needed,
5.2934 moles of C12H22O11 * 342.3 g C12H22O11 /mol = 1812g
(I have left out decimal places, you can caculate this and add them if you desire)
identify as the following as an element or a compound. its not multiple choice a) NaCI b) AR d) 02 c) CH4 d) 02 e) CI
Answer:
A. compound (NaCl)
B. element (note: it should be Ar. AR is not an element or compound.)
c. compound (CH4)
d. element (O2)
e. element (Cl)
Explanation:
Element is single and by its self. A compound is multiple elements put together.
1. Which gas will move faster through a small opening hydrogen or oxygen? *
A)hydrogen
B) oxygen
Answer:
hydrogen
Explanation:
What is the pH of a 6.50 x 10-3 M KOH solution?
Answer:
11.81
Explanation:
We'll begin by writing the balanced dissociation equation for KOH. This is given below:
KOH —> K+ + OH-
Next, we shall determine the concentration of Hydroxide ion, [OH-]. This is illustrated below:
From the balanced equation above,
We can see that 1 mole of KOH produced 1 mole of OH-.
Therefore, 6.50x10^-3 M KOH will also produce 6.50x10^-3 M OH-.
Next, we shall determine the pOH of the solution. This is illustrated below:
pOH = –Log [OH-]
[OH-] = 6.50x10^-3 M
pOH = –Log 6.50x10^-3
pOH = 2.19
Finally, we can determine the pH of the solution as follow:
pH + pOH = 14
pOH = 2.19
pH + 2.19 = 14
Collect like terms
pH = 14 – 2.19
pH = 11.81
Therefore, the pH of the solution is 11.81
The pH of a 6.50 x 10-3 M KOH solution is 11.81 which is alkaline.
pH is a measure of how acidic or basic a solution is. Ph has a range from 0 to 14. pHs with less than 7 show acidity, while a pH of greater than 7 indicates a base/ alkalinity. , pH of 7 shows the solution is neutral.
KOH is a strong base, Upon dissociation,it gives
KOH -> K⁺ + OH⁻
Here, 1 mole of KOH produced 1 mole of OH-.
Therefore, 6.50 x 10-3 M KOH will prodce 6.50 x 10-3 M H
Now, we first determine the pOH of the solution with the equation:
pOH = –Log [OH-]
[OH-] = 6.50x10^-3 M
pOH = –Log 6.50x10^-3
pOH = 2.19
Now, we know that
pH + pOH = 14
Having gotten that
pOH = 2.19,
pH + 2.19 = 14
pH = 14 – 2.19
pH = 11.81
Therefore, the pH of the KOH solution is 11.81 which is alkaline.
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Ummmm!! Can somebody please help me answer this question
Answer: is A because when the apple fell on him while he was thinking about the forces of nature he quickly studied it and sort of discovered it. That’s when he discovered gravity well it took him a while but he still did it. Hope it helped.
33 types of clouds and locations
Answer:
Cirrus
Cirrus cloudsCirrus clouds are delicate, feathery clouds that are made mostly of ice crystals. Their wispy shape comes from wind currents which twist and spread the ice crystals into strands.
Cirrostratus
Cirrostratus cloudsCirrostratus clouds are thin, white clouds that cover the whole sky like a veil. These clouds are most commonly seen in the winter, and can cause the appearance of a halo around the sun or the moon.
Cirrocumulus
Cirrocumulus cloudsCirrocumulus clouds are thin, sometimes patchy, sheet-like clouds. They sometimes look like they’re full of ripples or are made of small grains.
Mid-level Clouds (6,500-23,000 feet)
Altocumulus
Altocumulus cloudsAltocumulus clouds have several patchy white or gray layers, and seem to be made up of many small rows of fluffy ripples. They are lower than cirrus clouds, but still quite high. They are made of liquid water, but they don’t often produce rain.
Altostratus
Altostratus cloudsAltostratus clouds are gray or blue-gray mid-level clouds composed of ice crystals and water droplets. The clouds usually cover the entire sky.
Nimbostratus
Nimbostratus cloudsNimbostratus clouds are dark, gray clouds that seem to fade into falling rain or snow. They are so thick that they often blot out the sunlight.
Low Clouds (less than 6,500 feet)
Cumulus
Cumulus cloudsCumulus clouds look like fluffy, white cotton balls in the sky. They are beautiful in sunsets, and their varying sizes and shapes can make them fun to observe!
Stratus
Stratus cloudsStratus cloud often look like thin, white sheets covering the whole sky. Since they are so thin, they seldom produce much rain or snow. Sometimes, in the mountains or hills, these clouds appear to be fog.
Cumulonimbus
Cumulonimbus cloudCumulonimbus clouds grow on hot days when warm, wet air rises very high into the sky. From far away, they look like huge mountains or towers.
Stratocumulus
Stratocumulus cloudStratocumulus clouds are patchy gray or white clouds that often have a dark honeycomb-like appearance.
Special Clouds
Contrails
(Photo of white streaks of contrails in the sky) Contrails are made by high-flying jet airplanes. They are still clouds, though, because they are made of water droplets condensed from the water vapor in the exhaust of the jet engines.
Weather prediction: Contrails can provide information about the layers of moisture in the sky.
Mammatus clouds
Mammatus cloudsMammatus clouds are actually altocumulus, cirrus, cumulonimbus, or other types of clouds that have these pouch-like shapes hanging out of the bottom. The pouches are created when cold air within the cloud sinks down toward the Earth.
Orographic clouds
Orographic cloudsOrographic clouds get their shape from mountains or hills that force the air to move over or around them. They can also be formed by sea breezes and often appear as lines where two air masses meet.
Lenticular clouds
Lenticular clouds are shaped like lenses or almonds or...flying saucers! They may get their shape from hilly terrain or just the way the air is rising over flat terrain.
(Hope this helps) Sky
Why is the reaction SO2 + H20 → H2SO2 not balanced?
A. The oxygen atoms are in two molecules on one side, but one in
the other.
O
B. There are more molecules on one side than on the other.
O
C. There are more oxygen atoms on one side than on the other.
O
D. The sulfur atom is in different places in reactant and product
molecules
SUBMIT
Answer: C
# The main reason why the reaction above can not be balanced is:
This chemical reaction SO2 + H2O -> H2SO2 is not correctly written.
It must be: SO2 + H2O -> H2SO3
Explanation:
Note 1:
H2SO2 can be produced by the other chemical reaction:
2H2O + SCl2 -> 2HCl + H2SO2
....
Note 2: Answer A is false
As you can see in the reaction SO2 + H2O -> H2SO3, the oxygen atoms are in two molecules on one side, but one in the other - However, this reaction is written correctly.
Note 3: Answer D is false
Of course the Sulfur atom must be placed in different places: in reactant and product molecules.
Note 4: Answer B is false
There are different kinds of chemical reactions, and this is normal that there are more molecules on one side than on the other.
The answer is C
The correct way to balance the reaction, would be to write it as SO2 + H2O → H2SO3
Answer A is incorrect.
The oxygen atoms in the reaction SO2 + H2O -> H2SO3 are in two compounds on one end but on the other, it is in just one.
Answer D is wrong.
The sulfur atom has to be in the reactants and the products.
Answer B is not correct.
There are many types of chemical reactions . One side commonly has more atoms than the other.
A flask containing 500 liters of hydrogen gas was collected under a pressure of 980mmHg. What will be the volume if the pressure is changed to 900mmHg?
Answer:
80
Explanation:
im not rlly sure exactly but i think thats the anser
A community includes
A. all of the living organisms in a specific place at a specific time,
B. all plants, animals, minerals, and water in a specific place at a specific time,
C. only the plants in a specific place at a specific time.
D. only the animals in a specific place at a specific time.
Answer:
answer: A. all of the living organisms in a specific place at a specific time
Explanation:
If 50.0 g of KCl reacts with 50.0 g of O2 to produce KClO3 according to the following equation, how many grams of KClO3 will be formed? Word and Formula equation.
Answer:
A. 82.2g of KClO3
B. Word equation:
50g of KCl react with 50g of O2 to produce 82.2g of KClO3
C. Formula equation:
2KCl + 3O2 —> 2KClO3
Explanation:
The balanced equation for the reaction. This is given below:
2KCl + 3O2 —> 2KClO3
Next, we shall determine the masses of KCl and O2 that reacted and the mass of KClO3 produced from the balanced equation. This is illustrated below:
Molar Mass of KCl = 39 + 35.5 = 74.5g/mol
Mass of KCl from the balanced equation = 2 x 74.5 = 149g
Molar Mass of O2 = 16x2 = 32g/mol
Mass of O2 from the balanced equation = 3 x 32 = 96g
Molar Mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol
Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g
Summary:
From the balanced equation above:
149g of KCl reacted.
96g of O2 reacted.
245g of KCl were produced.
Next, we shall determine the limiting reactant. This is illustrated below:
From the balanced equation above,
149g of KCl reacted with 96g of O2.
Therefore, 50g of KCl will react with = (50 x 96)/149 = 32.21g of O2.
Since a lesser mass of O2 ( i.e 32.21g) than what was given (i.e 50g) is needed to react completely with 50g of KCl, therefore, KCl is the limiting reactant and O2 is the excess reactant.
A. Determination of the mass of KClO3 produced from the reaction.
In this case the limiting reactant will be used.
From the balanced equation above,
149g of KCl reacted To produce 245g of KClO3.
Therefore, 50g of KCl will react to produce = (50 x 245)/149 = 82.2g of KClO3.
Therefore, 82.2g of KClO3 is produced from the reaction.
B. Word equation:
50g of KCl react with 50g of O2 to produce 82.2g of KClO3.
C. Formula equation:
2KCl + 3O2 —> 2KClO3
The mass of [tex]\rm KClO_3[/tex] produced has been 82.1085 g.
The word equation for the reaction has been: 50 gram potassium chloride reacts with 50 g oxygen to give 82.1085 g potassium chlorate.
The formula equation has been, [tex]\rm 2\;KCl\;+\;3\;O_2\;\rightarrow\;2\;KClO_3[/tex].
The balanced chemical equation for the reaction has been given as:
[tex]\rm 2\;KCl\;+\;3\;O_2\;\rightarrow\;2\;KClO_3[/tex]
Computation for Mass of Potassium chlorate:From the balanced chemical equation, 2 moles of KCl reacts with 3 moles of oxygen to give 2 moles of [tex]\rm KClO_3[/tex].
The moles of reactants have been given as:
[tex]\rm Moles=\dfrac{mass}{molar\;mass}[/tex]
The moles of 50 g KCl has been given as:
[tex]\rm Moles\;KCl=\dfrac{50}{74.55} \\Moles\;KCl=0.67\;mol[/tex]
The moles of KCl available has been 0.67 mol.
The moles of 50 g [tex]\rm O_2[/tex] has been given as:
[tex]\rm Moles\;O_2=\dfrac{50}{32}\\Moles\;O_2=1.5625\;mol[/tex]
The moles of 50 g [tex]\rm O_2[/tex] has been 1.5625 mol.
From the balanced equation, for 2 moles KCl, 3 moles oxygen has been required. For 0.67 mol KCl, oxygen required has been:
[tex]\rm 2\;mole\;KCl=3\;moles\;O_2\\0.67\;mol\;KCl=\dfrac{3}{2}\;\times\;0.67\;mol\;O_2\\0.67\;mol\;KCl=1.005\;mol\;O_2[/tex]
The available moles of oxygen has been 1.5625 mol. Thus, oxygen has been excess reactant and KCl has been limiting reactant.
The moles of [tex]\rm KClO_3[/tex] produced has been given as:
[tex]\rm 2\;mol\;KCl=2\;mol\;KClO_3\\0.67\;mol\;KCl=\dfrac{2}{2}\;\times\;0.67\;mol\;KClO_3\\0.67\;mol\;KCl=0.67\;mol\;KClO_3[/tex]
The moles of [tex]\rm KClO_3[/tex] produced has been 0.67 mol.
The mass of [tex]\rm KClO_3[/tex] produced has been:
[tex]\rm Mass=Moles\;\times\;molar\;mass\\Mass\;KCl=0.67\;\times\;122.55\;\\Mass\;of\;KCl=82.1085\;g[/tex]
The mass of [tex]\rm KClO_3[/tex] produced has been 82.1085 g.
The word equation for the reaction has been:
50 gram potassium chloride reacts with 50 g oxygen to give 82.1085 g potassium chlorate.
The formula equation has been, [tex]\rm 2\;KCl\;+\;3\;O_2\;\rightarrow\;2\;KClO_3[/tex].
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Relate dark matter to the development of the universe after the Big Bang. In 3-5 sentences, speculate on how the development of the universe would have been different if there had been no dark matter. In your answer, use the term structures.
Please answer this and ill mark you as brainliest
Answer:
Dark matter also called baronic matter is the matter that makes up 27% of the universe.
In 1933 it was determined as that mass that cannot be seen, that is, the non-visible mass of outer space.
Dark matter also plays a central role in the formation of structures and the evolution of galaxies and has measurable effects on the anisotropy of cosmic microwave background radiation. The composition of this matter is unknown today.
The dark matter component has considerably more mass than the "visible" component of the Universe.
Explanation:
There are certain researchers who say that the appearance of dark matter was before the appearance of the big bang.
A relevant fact of this matter is that dark matter exerts gravity, and that gravity affects the movements of objects.
Despite the fact that nothing is known about its origin, astronomers have amply demonstrated that dark matter plays a determining role in the formation of galaxies and galactic clusters, which could not maintain their cohesion without its existence, but many doubt that it is the remainder / remnant or product of a big bang.
Proper lane placement can include positioning your car...
A. away from other cars.
B. 36 inches from the right or left line.
C. one inch from either lane line.
Proper lane placement can include positioning your car 36 inches from the right or left line. Therefore, option B is correct.
What is lane positioning ?Using different lane positions to make adjustments for potential problems and create larger space between car and problem situations. Lane position is the placement of car in the center, on the right, or on the left of a lane. The width of a lane is twelve feet on most highways or streets.
There are three main positions are lane position 1 is center of lane, lane position 2 is left side, and lane position 3 is right side. Position 2 is left side of lane is for car.
Position 3 is a vehicle placement to the right when a restriction to path of travel or your line of sight occurs. Proper lane placement can include positioning your car 36 inches from the right or left line.
Thus, option B is correct.
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PLEASE HELP LOL ‼️‼️
Accoring to KMT gases are_____
mostly empty space
or
very dense
or
organized
Answer:
Explanation:
mostly empty space
Is the equation Zn+HCl > ZnCL2+H2 unbalanced or balanced
Answer:
unbalanced
Explanation:
Cl and H have an extra atom
- Hope that helps! Please let me know if you need further explanation.
What is the hydronium concentration of a solution of ph 4.19M
Answer:
.000064565
Explanation:
H3O+=10^-pH
- Hope that helps! Please let me know if you need further explanation.
Explain what the Kb for aniline (C6H5NH2) tells you (Kb = 4.3 x 10-10).
Answer:
Explanation:
C₆H₅NH₂ + H₂O = C₆H₅NH₃⁺ + OH⁻
C₆H₅NH₃⁺ is also called anilinium ion . Thus we see that aniline reacts with water to form anilinium ion and forms OH⁻ ion . Due to it, it shows basic properties . The pH value of this aqueous solution is more than 7 . But it is a weak base because the concentration of OH⁻ formed is very less . It is so due to its less value of Kb . It has been explained as follows
Kb = [tex]\frac{[C_6H_5NH_3^+][OH^-]}{[C_6H_5NH_2][H_2O]}[/tex]
Since Kb is 4.3 x 10⁻¹⁰ which is very low value so concentration of OH⁻ that is [OH⁻] formed will also be very low . Hence it will be a weak base.
chemistry neutralization
Answer:
In chemistry, neutralization or neutralisation is a chemical reaction in which acid and a base react quantitatively with each other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present in the solution.
Explanation:
How many electrons with chlorine (Cl) in group 17 gain to become stable?
Answer:
Sodium is in group 1 so it has 1 valence electron (one electron in its outer shell). Sodium will be looking to lose its one valence electron in order to become more stable. Chlorine is in group 17 so it has 7 valence electrons, and therefore only needs to gain one valence electron to attain noble gas electron configuration (become stable with 8 valence electrons, just like the noble gases in group 18 have 8). Because the chlorine atom is trying to gain one electron, and the sodium atom is trying to lose one, sodium will give up its one valence electron to chlorine and the two atoms will form an ionic bond. Because chlorine is looking to gain just one electron and sodium is looking to lose the same number, the ratio of chlorine atoms to sodium atoms will be 1:1, one chlorine atom per one sodium atom.
Explanation:
The specific heat capacity of lead is 0.130 J/g-K. How much heat
is required to raise the temperature of 15.0 g of lead from 22.0 °C
to 37.0 °C?
Answer:
Q= 29.2 J
Explanation:
22°C=295K
37°C=310K
Q= mC dT
Q= (15.0 g) *(0.130 J/g-K)* (310 K-295K)
Q= 29.2 J
29.2 J is required to raise the temperature of 15.0 g of lead from 22.0 °C to 37.0 °C.
What is specific heat capacity?The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Given data:
22°C=295K
37°C=310K
Applying specific heat capacity formula:
Q= mC dT
Putting all the values in the formula:
Q= (15.0 g) X (0.130 J/g-K) X (310 K-295K)
Q= 29.2 J
Hence, 29.2 J is required to raise the temperature of 15.0 g of lead from 22.0 °C to 37.0 °C.
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NEED HELPPP PLSSSSSSSSSS
How do the particles of a gas differ from the particles of a solid?
Answer:
Gas is more open particles
Explanation: gas can flow
List and describe the steps of energy transfers that occur that allow a digital recording to be played through a speaker and ultimately become sound waves.
Answer:
1) Sound waves are stores as electrical signal in the digital recording.
2) the electrical signal of the digital recording is transcribed and sent to the voice coils.
3) the voice coil changes this electrical signal into varying magnetic fields.
4) The magnetic field pushes and pulls the diaphragm of the speakers.
5) the pushing and pulling of the diaphragm generates sound waves in the speaker.
