Answer:
[tex]Var = 1.9[/tex]
Step-by-step explanation:
Given
[tex]p = \frac{1}{20}[/tex] i.e. 1 per 20cc of water
[tex]n = 40[/tex] -- sample size
Required
The variance
This is calculated using:
[tex]Var = np(1 - p)[/tex]
So, we have:
[tex]Var = 40 * \frac{1}{20} * (1 - \frac{1}{20})[/tex]
[tex]Var = 40 * \frac{1}{20} * \frac{19}{20}[/tex]
[tex]Var = 2 * \frac{19}{20}[/tex]
[tex]Var = \frac{38}{20}[/tex]
[tex]Var = 1.9[/tex]
A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation.
p(x, y) y
0 1 2
x 0 0.10 0.03 0.01
1 0 08 0.20 0.06
2 0.05 0.14 0.33
(a) Given that X = 1, determine the conditional pmf of Y�i.e., pY|X(0|1), pY|X(1|1), pY|X(2|1).
(b) Given that two hoses are in use at the self-service island, what is the conditional pmf of the number of hoses in use on the full-service island?
(c) Use the result of part (b) to calculate the conditional probability P(Y ? 1 | X = 2).
(d) Given that two hoses are in use at the full-service island, what is the conditional pmf of the number in use at the self-service island?
Answer:
(a): The conditional pmf of Y when X = 1
[tex]p_{Y|X}(0|1) = 0.2353[/tex]
[tex]p_{Y|X}(1|1) = 0.5882[/tex]
[tex]p_{Y|X}(2|1) = 0.1765[/tex]
(b): The conditional pmf of Y when X = 2
[tex]p_{Y|X}(0|2) = 0.0962[/tex]
[tex]p_{Y|X}(1|2) = 0.2692[/tex]
[tex]p_{Y|X}(2|2) = 0.6346[/tex]
(c): From (b) calculate P(Y<=1 | X =2)
[tex]P(Y\le1 | X =2) = 0.3654[/tex]
(d): The conditional pmf of X when Y = 2
[tex]p_{X|Y}(0|2) = 0.025[/tex]
[tex]p_{X|Y}(1|2) = 0.150[/tex]
[tex]p_{X|Y}(2|2) = 0.825[/tex]
Step-by-step explanation:
Given
The above table
Solving (a): The conditional pmf of Y when X = 1
This implies that we calculate
[tex]p_{Y|X}(0|1), p_{Y|X}(1|1), p_{Y|X}(2|1)[/tex]
So, we have:
[tex]p_{Y|X}(0|1) = \frac{p(y = 0\ n\ x = 1)}{p(x = 1)}[/tex]
Reading the data from the given table, the equation becomes
[tex]p_{Y|X}(0|1) = \frac{0.08}{0.08+0.20+0.06}[/tex]
[tex]p_{Y|X}(0|1) = \frac{0.08}{0.34}[/tex]
[tex]p_{Y|X}(0|1) = 0.2353[/tex]
Using the format of the above formula for the rest, we have:
[tex]p_{Y|X}(1|1) = \frac{0.20}{0.34}[/tex]
[tex]p_{Y|X}(1|1) = 0.5882[/tex]
[tex]p_{Y|X}(2|1) = \frac{0.06}{0.34}[/tex]
[tex]p_{Y|X}(2|1) = 0.1765[/tex]
Solving (b): The conditional pmf of Y when X = 2
This implies that we calculate
[tex]p_{Y|X}(0|2), p_{Y|X}(1|2), p_{Y|X}(2|2)[/tex]
So, we have:
[tex]p_{Y|X}(0|2) = \frac{p(y = 0\ n\ x = 2)}{p(x = 2)}[/tex]
Reading the data from the given table, the equation becomes
[tex]p_{Y|X}(0|2) = \frac{0.05}{0.05+0.14+0.33}[/tex]
[tex]p_{Y|X}(0|2) = \frac{0.05}{0.52}[/tex]
[tex]p_{Y|X}(0|2) = 0.0962[/tex]
Using the format of the above formula for the rest, we have:
[tex]p_{Y|X}(1|2) = \frac{0.14}{0.52}[/tex]
[tex]p_{Y|X}(1|2) = 0.2692[/tex]
[tex]p_{Y|X}(2|2) = \frac{0.33}{0.52}[/tex]
[tex]p_{Y|X}(2|2) = 0.6346[/tex]
Solving (c): From (b) calculate P(Y<=1 | X =2)
To do this, where Y = 0 or 1
So, we have:
[tex]P(Y\le1 | X =2) = P_{Y|X}(0|2) + P_{Y|X}(1|2)[/tex]
[tex]P(Y\le1 | X =2) = 0.0962 + 0.2692[/tex]
[tex]P(Y\le1 | X =2) = 0.3654[/tex]
Solving (d): The conditional pmf of X when Y = 2
This implies that we calculate
[tex]p_{X|Y}(0|2), p_{X|Y}(1|2), p_{X|Y}(2|2)[/tex]
So, we have:
[tex]p_{X|Y}(0|2) = \frac{p(x = 0\ n\ y = 2)}{p(y = 2)}[/tex]
Reading the data from the given table, the equation becomes
[tex]p_{X|Y}(0|2) = \frac{0.01}{0.01+0.06+0.33}[/tex]
[tex]p_{X|Y}(0|2) = \frac{0.01}{0.40}[/tex]
[tex]p_{X|Y}(0|2) = 0.025[/tex]
Using the format of the above formula for the rest, we have:
[tex]p_{X|Y}(1|2) = \frac{0.06}{0.40}[/tex]
[tex]p_{X|Y}(1|2) = 0.150[/tex]
[tex]p_{X|Y}(2|2) = \frac{0.33}{0.40}[/tex]
[tex]p_{X|Y}(2|2) = 0.825[/tex]
8. When someone buys a ticket for an airline flight, there is a 0.0995 probability that the person will not show up for the flight. An agent for Air America wants to book 24 people on an airplane that can seat only 22. If 24 people are booked, find the probability that not enough seats will be available. You must show your work using a calculator function to receive credit.
Answer:
0.2952
Step-by-step explanation:
Not enough seats will be available if 23 or 24 people show up.
Required probability = 24C24(0.9005)24 + 24C23(0.9005)23*0.0995 = 0.2952
Consider vectors u and v, where u=(1,-1) and v=(1,1). What is the measure of the angle between the vectors? 0° 60° 90° 180°
Answer:
HEY THERE!
Step-by-step explanation:
the correct answer for your question is 90°
Answer:
The answer is c :)
Step-by-step explanation:
90 degrees
Graph g(x)=-8|x |+1.
Answer:
[tex] g(x)=-8|x |+1. = 9552815 \geqslant 6[/tex]
Points A, B and C are collinear . Point B is between A andSolve for given the following
Answer:
[tex]x = 7[/tex]
Step-by-step explanation:
Given
[tex]AC = 3x +3[/tex]
[tex]AB = -1+2x\\[/tex]
[tex]BC =11[/tex]
Required
Find x
We have:
[tex]AC = AB + BC[/tex]
So, we have:
[tex]3x + 3 = -1 + 2x + 11[/tex]
Collect like terms
[tex]3x - 2x = -1 + 11 - 3[/tex]
[tex]x = 7[/tex]
What is the y-coordinate of the point that divides the
directed line segment from J to k into a ratio of 2:3?
13
12+
11+
10
9
8
7+
v = ( my mom n Ilv2 – va) + ve
O 6
0-5
6+
05
5
07
5
4+
3+
1 27
Mi
Answer:
5
Step-by-step explanation:
took the test
The coordinates of the point that divides the line segment from J to K into a ratio of 2:3 are P(-5,7), and the y-coordinate is 7, the correct option is D.
What is the ratio?Ratio is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.
We are given that;
Ratio= 2:3
Now,
Let the point we are looking for be denoted as P(x,y), and let the ratio be 2:3, which means that the distance from J to P is 2/5 times the distance from J to K.
Using the distance formula, we can find the distance between J and K as:
d = sqrt((x2-x1)^2 + (y2-y1)^2)
= sqrt((-8 - (-3))^2 + (11 - 1)^2)
= sqrt(25 + 100)
= sqrt(125)
The distance from J to P is 2/5 of the total distance, which is:
(2/5)d = (2/5)sqrt(125) = 2sqrt(5)
Using the ratio formula, we get:
x = (3* (-3) + 2 * (-8)) / (3+2) = -5
y = (31 + 211) / (3+2) = 7
Therefore, by the given ratio answer will be 7.
Learn more about the ratio here:
brainly.com/question/13419413
#SPJ7
Each of the 8 cats in a pet store was weighed. Here are their weights (in pounds): 6,6, 10, 6, 8, 7, 14, 12 Find the median and mean weights of these cats. If necessary, round your answers to the nearest tenth. Median: pounds Х X ? Mean: pounds
Answer:
Median: 7.5
Mean: 8.6
Step-by-step explanation:
Median = the average of the 2 middle numbers of the set in ascending order, 6, 6, 6, 7, 8, 10, 12, 14
(7+8)/2 = 2
Mean = the sum of the numbers divided by the number of values
6 + 6+ 6+ 7 +8 +10 +12 +14/8
69/8
8.625
If f(x) = 4x ^ 2 - 4x - 8 and g(x) = 2x ^ 2 + 3x - 6 then f(x) - g(x) * i * s
Answer:
[tex]4 {x}^{2} - 4x - 8 - (2 {x}^{2} + 3x - 6) = 4 {x}^{2} - 4x - 8 - 2 {x}^{2} - 3x + 6 = 2 {x}^{2} - 7x - 2[/tex]
Mark jogs 10 miles in 2 hours.
Come up with a ratio that shows the distance in miles to the time taken
in hours. Simplify your ratio if needed.
Mark draws one card from a standard deck of 52. He receives $ 0.30 for a heart, $ 0.55 for a queen and $ 0.90 for the queen of hearts. How much should he pay for one draw
Answer
$0.1346
Explanation:
Find probability of each card and the value of each card and then add them together.
Probability of getting a heart = 13/52
Price of one heart =$0.30
Pay for one heart = 13/52×0.30=$0.075
Probability of getting a queen =4/52
Price of one queen =$0.55
Pay for one queen =4/52×$0.55=$0.0423
Probability of getting a queen of hearts =1/52
Price of one queen =$0.90
Pay for one queen =1/52×$0.90=$0.0173
Therefore the pay for one draw= $0.075+$0.0423+$0.0173=$0.1346
A cyclist rides his bike at a speed of 6 miles per hour. What is this speed in miles per minute how many miles will the cyclist travel in 20 minutes? Do not round your answers.
Answer:
1 mile per 10 minutes
Step-by-step explanation:
A carpet expert believes that 9% of Persian carpets are counterfeits. If the expert is right, what is the probability that the proportion of counterfeits in a sample of 686 Persian carpets would differ from the population proportion by greater than 3%
Answer:
0.0060 = 0.6% probability that the proportion of counterfeits in a sample of 686 Persian carpets would differ from the population proportion by greater than 3%
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
A carpet expert believes that 9% of Persian carpets are counterfeits.
This means that [tex]p = 0.09[/tex]
Sample of 686:
This means that [tex]n = 686[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.09[/tex]
[tex]s = \sqrt{\frac{0.09*0.91}{686}} = 0.0109[/tex]
What is the probability that the proportion of counterfeits in a sample of 686 Persian carpets would differ from the population proportion by greater than 3%?
Proportion lower than 9% - 3% = 6% or higher than 9% + 3% = 12%. The normal distribution is symmetric, thus these probabilities are equal, so we can find one of them and multiply by 2.
Probability it is lower than 6%
p-value of Z when X = 0.06. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.06 - 0.09}{0.0109}[/tex]
[tex]Z = -2.75[/tex]
[tex]Z = -2.75[/tex] has a p-value of 0.0030
2*0.0030 = 0.0060
0.0060 = 0.6% probability that the proportion of counterfeits in a sample of 686 Persian carpets would differ from the population proportion by greater than 3%
An internet cafe charges a fixed amount per minute to use the internet. The cost of using the
internet in dollars is, y = 3/4x. If x is the number of minutes spent on the internet, how many
minutes will $6 buy?
er
Answer:
x = 8 minutes
Step-by-step explanation:
Given that,
An internet cafe charges a fixed amount per minute to use the internet.
The cost of using the internet in dollars is,
[tex]y=\dfrac{3}{4}x[/tex]
Where
x is the number of minutes spent on the internet
We need to find the value of x when y = $6.
So, put y = 6 in the above equation.
[tex]6=\dfrac{3}{4}x\\\\x=\dfrac{6\times 4}{3}\\\\x=8\ min[/tex]
So, 8 minutes must spent on internet.
help me with 2 excersise , thanks a lot
Answer: I do not know what you mean, but you could do burpees, and sit ups.
Which of the following is the result of the equation below after completing the square and factoring? x^2-4x+2=10
A. (x-2)^2=14
B. (x-2)^2=12
C. (x+2)^2=14
D. (x+2)^2=8
9514 1404 393
Answer:
B. (x-2)^2=12
Step-by-step explanation:
The constant that completes the square is the square of half the coefficient of the x-term. That value is (-4/2)^2 = 4.
There is already a constant of 2 on the left side of the equal sign, so we need to add 2 to both sides to bring that constant value up to 4.
x^2 -4x +2 = 10 . . . . . . . given
x^2 -4x +2 +2 = 10 +2 . . . . complete the square (add 2 to both sides)
(x -2)^2 = 12 . . . . . . . . . write as a square
A system of equations is said to be redundant if one of the equations in the system is a linear combination of the other equations. Show by using the pivot operation that the following system is redundant. Is this system equivalent to a system of equations in canonical form?
a) x1 +x2 −3x3 = 7
b) −2x1 +x2 +5x3 = 2
c) 3x2 −x3 = 16
Answer:
prove that The given system of equations is redundant is attached below
Step-by-step explanation:
System of equations
x1 +x2 −3x3 = 7
−2x1 +x2 +5x3 = 2
3x2 −x3 = 16
To prove that the system is redundant we will apply the Gaussian elimination ( pivot operation )
attached below is the solution
(a) Find the average rate of change of the area of a circle with respect to its radius r as r changes from 2 to each of the following.
(i) 2 to 3
(ii) 2 to 2.5
(iii) 2 to 2.1
(b) Find the instantaneous rate of change when r =2.
Answer:
ai) 5pi
aii) 4.5pi
aiii) 4.1pi
b) 4pi
Step-by-step explanation:
a) Area of a circle is given by pi×r^2.
The average rate of change of the area of a circle from r=b to r=a is (pi×b^2-pi×a^2)/(b-a).
Let's simplify this.
Factor pi from the terms in the numerator:
pi(b^2-a^2)/(b-a)
Factor the difference of squares in the numerator:
pi(b-a)(b+a)/(b-a)
"Cancel" common factor (b-a):
pi(b+a).
So let's write a conclusive statement about what we just came up with:
The average rate of change of the area of a circle from r=b to r=a is pi(b+a).
i) from 2 to 3 the average rate of change is pi(2+3)=5pi.
ii) from 2 to 2.5 the average rate of change is pi(2+2.5)=4.5pi.
from 2 to 2.1 the average rate of change is pi(2+2.1)=4.1pi.
b) It looks like a good guess at the instantaneous rate of change is 4pi following what the average rate of change of the area approached in parts i) through iii) as we got closer to making the other number 2.
Let's confirm by differentiating and then plugging in 2 for r.
A=pi×r^2
A'=pi×2r
At r=2, we have A'=pi×2(2)=4pi. It has been confirmed.
Suppose 44% of the children in a school are girls. If a sample of 727 children is selected, what is the probability that the sample proportion of girls will be greater than 41%
Answer:
0.9484 = 94.84% probability that the sample proportion of girls will be greater than 41%
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Suppose 44% of the children in a school are girls.
This means that [tex]p = 0.44[/tex]
Sample of 727 children
This means that [tex]n = 727[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.44[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.44*0.56}{727}} = 0.0184[/tex]
What is the probability that the sample proportion of girls will be greater than 41%?
This is 1 subtracted by the p-value of Z when X = 0.41. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.41 - 0.44}{0.0184}[/tex]
[tex]Z = -1.63[/tex]
[tex]Z = -1.63[/tex] has a p-value of 0.0516
1 - 0.0516 = 0.9884
0.9484 = 94.84% probability that the sample proportion of girls will be greater than 41%
An experimenter flips a coin 100 times and gets 59 heads. Find the 98% confidence interval for the probability of flipping a head with this coin.
Answer:
The 98% confidence interval for the probability of flipping a head with this coin is (0.4756, 0.7044).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
An experimenter flips a coin 100 times and gets 59 heads.
This means that [tex]n = 100, \pi = \frac{59}{100} = 0.59[/tex]
98% confidence level
So [tex]\alpha = 0.02[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.02}{2} = 0.99[/tex], so [tex]Z = 2.327[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.59 - 2.327\sqrt{\frac{0.59*0.41}{100}} = 0.4756[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.59 + 2.327\sqrt{\frac{0.59*0.41}{100}} = 0.7044[/tex]
The 98% confidence interval for the probability of flipping a head with this coin is (0.4756, 0.7044).
A car traveling 7/10 of a mile per minute will travel _ miles in 10 minutes
Answer:
7 miles
Step-by-step explanation:
* means multiply
7/10 * 10 = 7
the All-star appliance shop sold 10 refrigerators, 8 ranges, 12 freezers, 12 washing machines, and 8 clothes dryers during January. Freezers made up what part of the appliances sold in January?
Answer:
Freezers made up [tex]\frac{6}{25}[/tex] = 24% of the appliances sold in January.
Step-by-step explanation:
We have that:
10 + 8 + 12 + 12 + 8 = 50 parts were sold in January.
Freezers made up what part of the appliances sold in January?
12 of those were freezers, so:
[tex]\frac{12}{50} = \frac{6}{25} = 0.24[/tex]
Freezers made up [tex]\frac{6}{25}[/tex] = 24% of the appliances sold in January.
4/5×1 1/9÷2 2/3. please help me
Answer:
1/3
Step-by-step explanation:
when you change the mixed numbers to improper fractions, you get 4/5 * 10/9 ÷ 8/3. you can flip the 8/3 to 3/8 and change the division sign to multiplication, because dividing by a fraction is the same as multiplying by its reciprocal. you can cancel some things and ultimately you get 1/3
Whoever helps me with this question I will give them brainliest
Hi there I hope you are having a great day :) I am pretty sure that you do 280 degrees around angle so i would say you would add 63 + 73 + 83 = 219 then you would take away it 280 - 219 = 61 so y must equal to 61 this is because we can see a z shape and a z shape adds up to 280.
Hopefully that helps you.
Find the slope of the line that passes through the two points. 4,4 & 4,9
HELPPPPPPP
Answer:
is 22
Step-by-step explanation:
Answer:
It doesn't have a slope?
Step-by-step explanation:
Knowing that the slope equation is y2-y1/x2-x1
9-4 5
----- = ------ = 0
4-4 0
this means that the slope is 0...
find the value of Y in the figure above .
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Answer:
x = 37y = 22Step-by-step explanation:
Consecutive interior angles are supplementary.
(x -20)° +(4x +15)° = 180°
5x = 185 . . . . . . . . . . . . . . divide by °, add 5
x = 37 . . . . . . . . . . . . divide by 5
__
74° +(5y -4)° = 180°
5y = 110 . . . . . . . . . . . divide by °, subtract 70
y = 22 . . . . . . . . . . divide by 5
Please guys help to solve this problem
9514 1404 393
Answer:
300
Step-by-step explanation:
Since nobody failed, the number who passed one or the other was 100%.
P(O + W) = P(O) +P(W) -P(O&W)
100% = 80% +70% -P(O&W)
P(O&W) = 50% = 150 students
If 150 students are 50% of the examinees, then 100% will be 300 students.
Answer:
[tex]300[/tex]hope it helps
#CARRYONLEARNINGFind the volume of the cone. Round to the nearest hundredth.
Answer:
Step-by-step explanation:
volume of cone=1/3 πr²h
=1/3×π×5²×11
=275/3 ×3.14
≈287.33 in³
x(x-y) - y( x- y) simplify
Step-by-step explanation:
x²-xy-xy+y²
x²+2xy+y²
hope it helps
20. (06.07 )
The graph below plots the values of y for different values of
20
15
10
5
5
Which correlation coefficient best matches the data plotted on the graph? (1 point)
-0.5
0
0.25
0.90
I need help nowww!! 16 points
Answer:
A: x = 0
B: x = All real numbers
Step-by-step explanation:
A.
Any number to the power of (0) equals one. This applies true for the given situation; one is given an expression which is as follows;
[tex](6^2)^x=1[/tex]
Simplifying that will result in;
[tex]36^x=1[/tex]
As stated above, any number to the power of (0) equals (1), thus (x) must equal (0) for this equation to hold true.
[tex]36^0=1\\x=0[/tex]
B.
As stated in part (A), any number to the power (0) equals (1). Therefore, when given the following expression;
[tex](6^0)^x=1[/tex]
One can simplify that;
[tex]1^x=1[/tex]
However, (1) to any degree still equals (1). Thus, (x) can be any value, and the equation will still hold true.
[tex]x=All\ real \ numbers[/tex]
