Consider rolling two fair dice and observing the number of spots on the resulting upward face of each one. Letting A be the event that at least one of the dice results in 6 spots on its upward face, and E be the event that exactly one of the dice results in 6 spots on its upward face, give the value of P(E|A). (Note: This value can be easily obtained by looking at p. 2.3 of the class notes and using a reduced sample space. In fact, such an approach makes the solution so trivial, that for this problem, you don’t have to give any justification for your answer.)

Answer:

42

Step-by-step explanation:

(adjacent straight angles sum up to 180)

3x+54=180

x=42

Answer:

7 boxes

Step-by-step explanation:

We can use ratios to solve

12 bars            42 bars

----------    = ---------------

2 boxes      x boxes

Using cross products

12x = 2 *42

12x = 84

Divide by 12

12x/12 = 84/12

x = 7

Answer:

12

Step-by-step explanation:

x = 1 and y = 9 so 3x1 + 9 = 12 as 3 x 1 is 3 and adding 9 to it will give 12

Answer:

[tex]log_5 \ 125 = 3[/tex]

Step-by-step explanation:

[tex]log_5 \ 125 = log_2 \ 5^3 = 3 \times log_5 \ 5 = 3 \times 1 = 3[/tex]

The value of [tex]$\log _{5} 125$[/tex] can be estimated utilizing the logarithm rule. The value of [tex]$\log _{5} 125$[/tex] exists 3.

The logarithm stands for the inverse function of exponentiation. In logarithm base must be raised to yield a given number for an exponent.

Given:

[tex]$\log _{5} 125$[/tex]

Estimate the value of the given logarithm, we get

[tex]$\log _{5} 125=\log _{5}(5)^{3}$[/tex]

[tex]$\log _{5} 125=3 \log _{5} 5$[/tex]

From logarithm rule [tex]$\log m^{n}=n \log m$[/tex], we get

[tex]$\log _{5} 125=3 \times 1$[/tex]

[tex]$\log _{5} 125=3$[/tex]

Therefore, the value of [tex]$\log _{5} 125$[/tex] is 3.

To learn more about logarithm

https://brainly.com/question/26240264

#SPJ2

An inverse function is y = k/x

replace x and y with the given values:

6 = k/18

Solve for k by multiplying both sides by 18:

k = 108

1. Find the equation and solve for k: y varies inversely as x and y = 6 when x = 18.

[tex]\sf{The \: relation \: y \: varies \: inversely \: as \: x \: translates \: to \: y = \frac{k}{x}.}[/tex]

Substitute the values to find k:

[tex]\sf\rightarrow{y= \frac{k}{x} }[/tex]

[tex]\sf\rightarrow{6= \frac{k}{18} }[/tex]

[tex]\sf\rightarrow{k=(6)(18)}[/tex]

[tex]\sf\rightarrow{K={\color{magenta}{108}}}[/tex]

[tex]\sf{The \: equation \: of \: variations \: is \: y={ \color{red}{ \frac{108}{x} }}}[/tex]

[tex]{\huge{\color{blue}{━━━━━━━━━━━━}}}[/tex]

#CarryOnMath⸙

Answer:

7 square root 9^4

Step-by-step explanation:

Second-degree price discrimination occurs when a company charges a different price for different quantities consumed, such as quantity discounts on bulk purchases.

mark me brainliestt :))

Answer:

4080 gm

Step-by-step explanation:

To bake one cake, it will take us 650 gm flour and 30 gm sugar. When we add both of them together, it gives 680 gm (650+30). But this is only for one cake. To find the total amount of flour and sugar needed to bake 6 cakes, we will have to multiply 680 by 6. That will give you 4080 gm which is your final answer.

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

A graphing calculator does a nice job of graphing these equations.

__

The very steep slope suggests the graph will need somewhat different vertical and horizontal scales in order to show anything useful.

9514 1404 393

Answer:

Step-by-step explanation:

a) Let p and d represent the prices of a bag of popcorn and a drink, respectively.

Mohamed's purchase is ...

  2p +3d = 18.25

Miguel's purchase is ...

  4p +2d = 27.50

__

b) We can subtract half the second equation from the first to get an equation for the cost of a drink.

  (2p +3d) -1/2(4p +2d) = (18.25) -1/2(27.50)

  2d = 4.50 . . . . . . simplify

  d = 2.25 . . . . . . divide by 2

  4p +2(2.25) = 27.50 . . . . substitute for d in the second equation

  4p = 23.00 . . . . . . . . . subtract 4.50

  p = 5.75 . . . . . . . . . divide by 4

The cost of a bag of popcorn is $5.75; the cost of a drink is $2.25.

Answer:

For example, 6(1001) + 3(110) = 6006 + 330 = 6336 is a palindrome. Since 11 is a factor of both 1001 and 110, we conclude that all four digit palindromes are divisible by 11.

Answer:

<5 and <7 are corresponding angles.

Step-by-step explanation:

<5 and <7 are corresponding angles.  They are on the same side of the transversal and on the same position on each of the parallel lines

Answer:

1 and 3 are the odd numbers that are less than 5. 0, 2 and 4 are the even numbers that are less than 5

Step-by-step explanation:

Answer:

Its speed is 14 mph.

Step-by-step explanation:

Given that regarding racer called The Whirlwind, its poster says that in 1/20 hour it covers 7/10 mile, to determine what is the Whirlwind’s speed in miles per hour the following calculation must be performed:

1/20 x 60 = 0.05 x 60 = 3 minutes

7/10 = 0.7

Therefore, every 3 minutes the Whirlwind travels 0.7 miles.

60/3 = 20

0.7 x 20 = 14

Thus, in an hour it travels 14 miles, with which its speed is 14 mph.

Answer:

1448

Step-by-step explanation:

24 × 63-64

Multiply 24 and 63 to get 1512.

1512-64

Subtract 64 from 1512 to get 1448.

answer

1448

Answer:

quadratic formula is ur answer for letter B

Answer:

B. L BAT = L CAT

Step-by-step explanation:

__________

Answer:

1/3a

Step-by-step explanation:

[tex] \frac{(a - 3)}{15a} \times \frac{5}{(a - 3)} = \frac{5}{15a} = \frac{1}{3a} [/tex]

Answer:

B-100 If the price of tacos is $1.75, th consumers will buy 100 tacos

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

[tex]A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right][/tex]

Using formula:

[tex]|A-\lambda \cdot I|= 0\\\\[/tex]

[tex]\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\[/tex]

[tex]\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\[/tex]

Answer:

Option B, The distribution of apple candy can be modeled as normal if Susan picks candies over 75 times

Step-by-step explanation:

The distribution of apple candies can be represented as normal curve and hence the sample proportion for this is true and can be drawn.

The rest other cases do not represent a normal distribution and hence it will not be easy to plot curve for these samples.

hence, option B is correct

Step-by-step explanation:

everything can be found in the picture

Answer: [tex]6x^3 +30x^2 +4x+20[/tex]

Step-by-step explanation:

[tex](6x^2 +4)(x+5)\\\\ =6x^3 +30x^2 +4x+20[/tex]

Answer:

hey um I cant see the picture

Answer:

In order to answer this properly, I would need to see the choices. However, I can tell you that:

-Each gallon of paint cost $15

-Karen spent $45 on yellow paint

-Karen spent $60 on blue paint

Step-by-step explanation:

Karen bought a total of 7 cans of paint, all the same price.

105/7=15.

15*3=45 (yellow paint)

15*3=60 (blue paint)

Hope this helps.

Answer:

16

Step-by-step explanation:

From the question given above, the following data were obtained:

1 = 1

2 = 4

3 = 9

4 =?

Observing the data, we can see that the numbers on the right side are simple the squares of the numbers on the left side. This is illustrated below:

1 = 1² = 1

2 = 2² = 4

3 = 3² = 9

Thus, we shall use the same logic to obtain that of 4. This is illustrated below:

4 = 4² = 16

Thus the answer to the question is 16.

Answer:

[tex]\$32[/tex]

Step-by-step explanation:

Let the cost of the game be [tex]x[/tex]. Since one-fourth of the cost of the game is equal to 8 dollars, we have the following equation:

[tex]\frac{1}{4}x=8[/tex]

Multiply both sides by 4 to isolate and solve for [tex]x[/tex]:

[tex]x=8\cdot 4=\boxed{\$32}[/tex]