Mathematics High School

consider the equation k over x equals 12 where k is any number between 20 and 65 and X is a positive integer what are the possible values for x​

Answers

Answer 1
x could be the positive integers 2, 3, 4, or 5

Related Questions

Dan, Harry and Regan sell cars.
Dan sells x cars.
Harry sells 5 more cars than Dan.
Regan sells twice as many cars as Dan.
Write an expression, in terms of x, for the mean number of cars Dan, Harry and Regan sell.

Answers

Answer:

4X+5

Step-by-step explanation:

Dan : X

Harry: X+5

Regan: 2X

X+X+5+2X

Answer:

[tex]Mean = \frac{4x + 5}{3}[/tex]

Step-by-step explanation:

Given:

Dan sold = x

Harry sold 5 more than Dan, that is = x + 5

Regan sold twice as Dan = 2x

[tex]Mean = \frac{ Total \ cars \ sold}{number\ of \ them \ sold \ it }\\\\Mean = \frac{x + ( x+ 5) +2x }{3} = \frac{4x + 5}{3}[/tex]


A rope is 9 1/2 meters long. How many pieces can be cut from the rope if
each piece is to be 1/4 meter?

Answers

A rope is 9 1/2 m long because 1/4 m that is your answer because I need points

Solve 2x + 6 > 20. OLA X> 18 B. X>7 O c. x


someone help por favor​

Answers

your answer would be x>7 or B :)

Answer:

2x+6>20

2x>20-6

2x/2>14/2

x>7

So your answer would be B

6x-27=-3x

solve for x:D

Answers

Answer:

6×-27=-3×

+3×

9/9×=27/9

×=3

What’s 1/2 + 1/3? Y’all please help me . And when or if you can give me the answer can you do step-by-step on how you did that so I can do it myself next time?

Answers

Hi! 1/2 + 1/3 is 5/6.

2 + 3 = 5
2 X 3 = 6

= 5/6

I hope this helped if I can help in anyway I would be happy to help you. Goodluck :)

[tex]\longrightarrow{\green{\frac{5}{6}}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] \frac{1}{2} + \frac{1}{3} [/tex]

Since the denominators are unequal, we find the L.C.M (lowest common multiple) for both denominators.

The L. C. M for 2 and 3 is 6.

Now, multiply the L.C.M. with both numerator & denominator.

[tex] = \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} [/tex]

[tex]= \frac{3}{6} + \frac{2}{6} [/tex]

Now that the denominators are equal, we can add them.

[tex]= \frac{3 + 2}{6} \\ \\ = \frac{5}{6} [/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]

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