Consider the probability that more than 99 out of 157 software users will not call technical support. Assume the probability that a given software user will not call technical support is 56%. Approximate the probability using the normal distribution

Answers

Answer 1

Answer:

[tex]P(x>99)= 0.468[/tex]

Step-by-step explanation:

From the question we are told that:

Sample size 157

Sample mean

[tex]\=x =np[/tex]

[tex]\=x =157*0.56[/tex]

[tex]\=x = 87.92[/tex]

Generally the equation for Standard deviation is mathematically given by

[tex]\sigma=\sqrt{npq}[/tex]

[tex]\sigma=\sqrt{157*0.56*0.44}[/tex]

[tex]\sigma =6.22[/tex]

Therefore

[tex]P(x>99)=P(z>(\frac{99.5-87.92)}{6.22})[/tex]

[tex]P(x>99)=P(z>1.86)[/tex]

[tex]P(x>99)= 0.468[/tex]


Related Questions

Social media is popular around the world. Statista provides estimate of the number of social media users in various countries in as well as the projections for . Assume that the results for surveys in the United Kingdom, China, Russia, and the United States are as follows.

Use Social Media United Kingdom China Russia United States
Yes 480 215 343 640
No 320 285 357 360

Required:
a. Conduct a hypothesis test to determine whether the proportion of adults using social media is equal for all four countries. What is the p-value? Using a .05 level of significance, what is your conclusion?
b. What are the sample proportions for each of the four countries? Which country has the largest proportion of adults using social media?
c. Using a 0.05 level of significance, conduct multiple pairwise comparison tests among the four countries. What is your conclusion?

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

The data table :

Use of SM _UK _China _ Russia _US _ col total

Yes ______480 __215 ___343 __640 _ 1678

No _______320 _ 285 ___357__ 360 _ 1322

Row Total__ 800 _500 __ 700_ 1000_ 3000

H0 : p1 = p2 = p3 = p4

H1 : p1 ≠ p2 ≠ p3 ≠ p4

Test statistic :

χ² = Σ(observed - Expected)² / Expected

Expected value of each cell = (Row total * column total) / N

N = grand total

Expected Values:

447.467 _279.667 _ 391.533 _ 559.333

352.533 _ 220.333 _ 308.467 _ 440.667

χ²=(2.36536+14.9527+6.01605+11.6337+3.00232 18.9793+7.63611+14.7665) = 79.352

Degree of freedom, df = (row-1)*(column-1) = (2 - 1) * (4 - 1) = 1 * 3 = 3

Using the Pvalue from Chisquare calculator :

Pvalue(79.352, 3) = 0.00000000001

Decision region :

Reject H0 ; If Pvalue < α

α = 0.05

Since 0.000000001 < 0.05 ; Reject H0 and conclude that not all population proportion are equal.

Sample proportion :

Phat = number of yes, x / total

For UK, Phat = 480/800 = 0.6

For China , Phat = 215/500 = 0.43

For Russia , Phat = 343/700 = 0.49

For US, Phat = 640/1000 = 0.64

Determine if the triangles below are similar. If they are, give the rule that you used to determine similarity.

Answers

The triangles are similar due to SAS congruence postulate rule.

What are Similar Triangles?

Similar Triangles are defined as two triangles with the same shape, equal pair of corresponding angles, and the same ratio of the corresponding sides. The triangles that like one another but may not be exactly the same size are said to be similar triangles. When two objects have the same shape but different sizes, they can be said to be similar. This indicates that identical shapes superimpose one another when enlarged. The term "Similarity" refers to this characteristic of like shapes.

Given triangles are similar due to SAS congruence postulate rule.

SAS or Side-Angle-Side Similarity Criterion,

According to the SAS similarity theorem, If any two of the first triangle's sides are exactly proportional to those of the second triangle, and if the angle created by these two sides of each individual triangle is equal, then the two triangles must be similar triangles.

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Show that Cov(X, Y 1 Z) 5 Cov(X, Y) 1 Cov(X, Z). b. Let X1 and X2 be quantitative and verbal scores on one aptitude exam, and let Y1 and Y2 be corresponding scores on another exam. If Cov(X1, Y1) 5 5, Cov(X1, Y2) 5 1, Cov(X2, Y1) 5 2, and Cov(X2, Y2) 5 8, what is the covariance between the two total scores X1 1 X2 and Y1 1 Y2

Answers

Answer:

x11and x2. arevvvscores

Solve for x^2=18
Please help

Answers

Answer:

See below

Step-by-step explanation:

x^2 = 18

x = 18 sqrt

x = 4.24 or 4.2 (rounded to the nearest tenth)

If f(x) = 4x + 5 and fog(x) = 8x + 13 then find g(x).​

Answers

Answer:

given

f(x).4x+5

fog(x).8x+13

now

fog(x):8x+13

4x+5(g(x)):: 8x+13

g(x):: 8x+13/4x+5

Answer:

g(x) = 2x + 2

Step-by-step explanation:

One is given the following information:

f(x) = 4x + 5f o g (x) = 8x + 13

One is asked to find the following:

g(x)

Remember, (f o g (x)) is another way of representing a composite function. A more visual way of representing this composite function is the following (f(g(x)). In essence, one substitutes the function (g(x)) into the function (f(x)) in places of the varaible (x). Thus, represent this in the form of an equation:

f(g(x)) = 8x + 13

Substitute the given infromation into the equation:

4(g(x)) + 5 = 8x + 13

Solve for (g(x)) in terms of (x). Remember to treat (g(x)) as a single parameter:

4(g(x)) + 5 = 8x + 13

Inverse operations,

4(g(x)) + 5 = 8x + 13

4(g(x)) = 8x + 8

g(x) = (8x + 8) ÷ 4

g(x) = 2x + 2

What is the conjugate of
square root 8 - square root 9

Answers

Answer:

[tex]\sqrt{8}+\sqrt{9}[/tex]

Step-by-step explanation:

By definition, the conjugate of a binomial is when you switch the operator (either + or -) in between the terms. For example, the conjugate of [tex]a+b\sqrt{c}=a-b\sqrt{c}[/tex] as we are just changing the addition symbol (+) to a subtraction symbol (-).

Therefore, the conjugate of [tex]\sqrt{8}-\sqrt{9}[/tex] occurs when we change the subtraction symbol to an additional symbol, hence the answer is [tex]\boxed{\sqrt{8}+\sqrt{9}}[/tex]

Please help me on this

Answers

Answer:

gshwhsye

Step-by-step explanation:

gshshhshshshjsjsjsj

The difference of two numbers is 9. The sum of the two numbers is 15. What are the two numbers?

Answers

Let numbers be a and b

a+b=15--(1)a-b=9---(2)

Adding both

[tex]\\ \qquad\quad\sf\longmapsto 2a=24[/tex]

[tex]\\ \qquad\quad\sf\longmapsto a=\dfrac{24}{2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto a=12[/tex]

Put value in eq(2)

[tex]\\ \qquad\quad\sf\longmapsto 12-b=9[/tex]

[tex]\\ \qquad\quad\sf\longmapsto b=12-9[/tex]

[tex]\\ \qquad\quad\sf\longmapsto b=3[/tex]

What are the degree and leading coefficient of the polynomial?
- 3v² - 2v^3+ 6-8v

Answers

9514 1404 393

Answer:

degree: 3leading coefficient: -2

Step-by-step explanation:

The highest degree term is -2v^3. Its degree is 3, so the degree of the polynomial is 3. Its coefficient is -2, so the leading coefficient is -2.

From the observation deck of a skyscraper, Isabella measures a 67
angle of depression to a ship in the harbor below. If the observation deck is 824 feet high, what is the horizontal distance from the base of the skyscraper out to the ship? Round your answer to the nearest tenth of a foot if necessary.

Answers

The horizontal distance from the base of the skyscraper out to the ship is 349.8feet

Angle of elevation and depression

The angle situated above the hill is known as  the angle of depression

Given the following parameters

Height of the harbor = 824 feet

Angle of depression = 67degrees

According to SOH CAH TOA identity:

tan 67 = opp/adj
tan 67 = 824/d

d = 824/tan67
d = 349.8 feet

Hence the horizontal distance from the base of the skyscraper out to the ship is 349.8feet

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I need help asap with this question

Answers

In a trapezoid, the midline is the average of the two bases.

PW = (YZ + TM) / 2

29 = (23 + 11x + 2) / 2

58 = 23 + 11x + 2

58 = 25 + 11x

11x = 33

x = 3

Hope this helps!

9. If a card is selected from a standard 52 card deck. What is the probability of selecting a face card or an Ace?

Answers

Well, you’ve got 26 face cards, one of which is an ace, and an additional ace. 27/52 is 52%, so you’ve got a 52% probability (51.9230)

a which matrix post multiplies to (1 3 3 4) to get (19 -3 75 13)​

Answers

Answer:

[19 -1 25 3.25]

Step-by-step explanation:

just take the elements from the resultant matrix and divide it by the corresponding elements in the given matrix to find the matrix that's being asked.

With one alarm clock, we have a 0.875 probability of being awakened. What is the probability of being awakened if we are using two alarm clocks?(

Answers

It will be the same bc two alarms will ring at the same time.

The probability will be the same for both clocks.

What is probability?

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

With one alarm clock, we have a 0.875 probability of being awakened.

The probability for the two clocks will be the same because both the clocks will ring at the same time.

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Find the reflection of the point (x,y) in the line y=mx+c​

Answers

Answer:

[tex]\displaystyle \left(\frac{-(m^{2}-1)\, x + 2\, m\, y - 2\, m \, c}{m^{2} + 1},\, \frac{(m^{2} - 1)\, y + 2\, m \, x + 2\, c}{m^{2} + 1}\right)[/tex].

Step-by-step explanation:

Consider the line that is perpendicular to [tex]y = m\, x + c[/tex] and goes through [tex](x,\, y)[/tex].

Both [tex](x,\, y)[/tex] and the reflection would be on this new line. Besides, the two points would be equidistant from the intersection of this new line and line [tex]y = m\, x + c[/tex].

Hence, if the vector between [tex](x,\, y)[/tex] and that intersection could be found, adding twice that vector to [tex](x,\, y)\![/tex] would yield the coordinates of the reflection.

Since this new line is perpendicular to line [tex]y = m\, x + c[/tex], the slope of this new line would be [tex](-1/m)[/tex].

Hence, [tex]\langle 1,\, -1/m\rangle[/tex] would be a direction vector of this new line.

[tex]\langle m,\, -1\rangle[/tex] (a constant multiple of [tex]\langle 1,\, -1/m\rangle[/tex] would also be a direction vector of this new line.)

Both [tex](x,\, y)[/tex] and the aforementioned intersection are on this new line. Hence, their position vectors would differ only by a constant multiple of a direction vector of this new line.

In other words, for some constant [tex]\lambda[/tex], [tex]\langle x,\, y \rangle + \lambda\, \langle m,\, -1 \rangle = \langle x + \lambda \, m,\, y - \lambda \rangle[/tex] would be the position vector of the reflection of [tex](x,\, y)[/tex] (the position vector of [tex](x,\, y)\![/tex] is [tex]\langle x,\, y \rangle[/tex].)

[tex]( x + \lambda \, m,\, y - \lambda )[/tex] would be the coordinates of the intersection between the new line and [tex]y = m\, x + c[/tex]. [tex]\lambda\, \langle m,\, -1 \rangle[/tex] would be the vector between [tex](x,\, y)[/tex] and that intersection.

Since that intersection is on the line [tex]y = m\, x + c[/tex], its coordinates should satisfy:

[tex]y - \lambda = m\, (x + \lambda \, m) + c[/tex].

Solve for [tex]\lambda[/tex]:

[tex]y - \lambda = m\, x + m^{2}\, \lambda + c[/tex].

[tex]\displaystyle \lambda = \frac{y - m\, x - c}{m^{2} + 1}[/tex].

Hence, the vector between the position of [tex](x,\, y)[/tex] and that of the intersection would be:

[tex]\begin{aligned} & \lambda\, \langle m,\, -1 \rangle \\= \; & \left\langle \frac{m\, (y - m\, x - c)}{m^{2} + 1},\, \frac{(-1)\, (y - m\, x - c)}{m^{2} + 1}\right\rangle \\ =\; &\left\langle \frac{-m^{2}\, x + m\, y - m\, c }{m^{2} + 1},\, \frac{-y + m\, x + c}{m^{2} + 1}\right\rangle \end{aligned}[/tex].

Add twice the amount of this vector to position of [tex](x,\, y)[/tex] to find the position of the reflection, [tex]\langle x,\, y \rangle + 2\, \lambda \,\langle m,\, -1 \rangle[/tex].

[tex]x[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & x + 2\, \lambda\, m \\ = \; & x + \frac{-2\, m^{2}\, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1} \\ =\; & \frac{-(m^{2} - 1) \, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].

[tex]y[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & y + (-2\, \lambda)\\ = \; & y + \frac{- 2\, y + 2\, m\, x + 2\, c}{m^{2} + 1} \\ =\; & \frac{(m^{2} - 1) \, y + 2\, m \, x + 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].

Jenna danced for 3 hours on Sunday, 2 hours on Monday and Tuesday, 1 hour on Thursday, 1.5 on Friday, and 2 hours on Saturday. She didn’t dance at all on Wednesday. What is the average number of hours she danced each day? Round your answer to the nearest tenth in an hour.

Answers

Sunday: 3 hours
Monday: 2 hours
Tuesday: 2 hours
Wednesday: 0 hours
Thursday: 1 hours
Friday: 1.5 hours
Saturday: 2 hours

3 + 2 + 2 + + 0 + 1 + 1.5 + 2 = 11.5

11.5 ÷ 7 = 1.6 hours on average

Which statements describe the data in the bar graph? Check all that apply.


People prefer rock music to any other type of music.

People prefer pop music to any other type of music.

The least favorite genre of music is blues.

The least frequent favorite genre is country.

Four times as many people prefer pop music to blues.

Answer:
People prefer pop music to any other type of music.

The least favorite genre of music is blues.

Four times as many people prefer pop music to blues.

Answers

Answer:

People prefer pop music to any other type of music.

The least favorite genre of music is blues.

Four times as many people prefer pop music to blues.

Answer:

B) People prefer pop music to any other type of music.

C) The least favorite genre of music is blues.

E) Four times as many people prefer pop music to blues.

Step-by-step explanation:

edge 2023

Part of the population of 6,750 elk at a wildlife preserve is infected with a parasite. A random sample of 50 elk shows that 3 of them are infected. How many elk are likely to be infected?

Answers

Answer:

405

Step-by-step explanation:

We can use a ratio to solve

3 infected           x infected

------------------ = ----------------

50 sampled     6750 population

Using cross products

3*6750 = 50x

Divide each side by 50

3*6750/50 = x

405

Answer:

Around 405 elk should be infected with the parasite.

Step-by-step explanation:

6,750/50=135

135 * 3 = 405

hope this helps :)

What is the shape of the cross section?

Answers

Answer:

Step-by-step explanation:

Triangular cross-section.

Answer:

it is a triangle cross-section

hope this answer helps you

Plz make me a brainlist

What type of counting problem is this?

Johnny is a very picky eater, so he likes to use a lot of condiments. He has ketchup, salt, pepper, and shredded cheese at his disposal. His mother tells him he may only make two additions to his meal (i.e., he can add condiments only twice, regardless of whether or not he already used them). How many different ways can Johnny improve his meal?
A.Combination with repetition
B.Combination without repetition
C.Permutation with repetition
D.Permutation without repetition

Answers

Answer:

option A

Step-by-step explanation:

Permutation is An arrangement of objects in an ORDER

but combination is the opposite.

In this question, There is a combination! I hope this helped! have a great day!

11z/(z+3) = 13 - i , z∈C please solve it

Answers

[tex]\frac{11z}{z+3}=13-i,z\in\mathbb{C}[/tex]

First, multiply both sides by [tex]z+3[/tex],

[tex]11z=(13-i)(z+3)[/tex]

[tex]13z+39-iz-3i=11z[/tex]

Collect terms and put z on the left,

[tex]2z-iz=3i-39[/tex]

[tex]z(2-i)=3i-39[/tex]

[tex]z=\frac{3i-39}{2-i}[/tex]

Division of complex numbers is defined by multiplying both denominator and numerator with complex conjugate of the denominator,

[tex]z=3\frac{(i-13)(2+i)}{(2-i)(2+i)}[/tex]

Multiply out,

[tex]z=3\frac{2i-1-26-13i}{5}[/tex]

[tex]z=3\frac{-11i-27}{5}[/tex]

The result is,

[tex]z=-\frac{81}{5}-\frac{33}{5}i[/tex]

Hope this helps :)

pls help !
hopefully you can read the whole thing :))

Answers

Answer:

answer is A

Step-by-step explanation:

option A is the answer

Step 3: Write the equation of the line that passes through the point (4,−1)
(
4
,

1
)
that is parallel to the line 2−3=9

Answers

Answer:

-

Step-by-step explanation:

-

Michael is 4 times as old as Brandon and is also 27 years older than Brandon.
How old is Brandon?

Answers

Answer:

9

Step-by-step explanation:

b = Brandon

4b=b+27

-b   -b

-------------

3b = 27

----   ----

3      3

b = 9

Brandon is 9 years old.

Mark bought seeds, 5 packets of carrot seeds, 2 packets of
bean seeds, and 3 packets of pea seeds. If he randomly
selects 4 packets to plant, what is the probability that he
selects 2 packets of carrots, 1 packet of beans, and 1 packet
of peas?

Answers

Answer:

4/10=2/5 therefore the answer to 2/5

81×81+68×68-2×81×68

Answers

Answer:

First by "BODMAS" we will sove multiplication

81×81+68×68-2×81×68

now first we will solve addition

=6561+4624-11016

=11185-11016

=169

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

A slide is also called a translation.
ird
True
O False

Answers

Answer:

trueeeee

Step-by-step explanation:

Slide (translation) -- a transformation that slides a figure a given distance in a given direction. A slide is also called a translation. Flip (reflection) -- a transformation creating a mirror image of a figure on the opposite side of a line. A flip is also called a reflecti


Suppose $12,000 is deposited into an account paying 5.5% interest, compounded continuously.
How much money is in the account after five years if no withdrawals or additional deposits are
made?

Answers

Answer:

$15798.4

Step-by-step explanation:

We will have to use this formula A = Peᵃᵇ

A = Final amount

P = Initial amount (12,000)

e = Mathematical constant: 2.7183

a = Interest rate (5.5% or 0.055)

b = Years

So our equation will look like this

A = 12,000e⁵ ⁰·⁵⁵

A = 12,000(2.7183)·²⁷⁵

A = 12,000(1.316533)

A = 15798.396

Simplify i to the 31st power

Answers

Answer:

?

How did you simplify

formula of a square minus b square​

Answers

Answer:

(a+b)(a-b)

Step-by-step explanation:

[tex]\\ \sf\longmapsto (a+b)(a-b)[/tex]

[tex]\\ \sf\longmapsto a(a-b)+b(a-b)[/tex]

[tex]\\ \sf\longmapsto a^2-ab+ba-b^2[/tex]

[tex]\\ \sf\longmapsto a^2-ab+ab-b^2[/tex]

[tex]\\ \sf\longmapsto a^2-b^2[/tex]

According to the question

[tex]\large\bf{\orange{ \implies}} \: \tt \: {a}^{2} \: - \: {b}^{2} [/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: (a + b) \quad \: (a - b)[/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: a \: (a - b) \quad \: b \: (a - b)[/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: ab \: + \: ba \: - \: {b}^{2} [/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: ab \: + \: ab \: - \: {b}^{2} [/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: \cancel{ab} \: + \: \cancel{ab} \: - \: {b}^{2} [/tex]

[tex]\large\bf{\pink{ \implies}} \: \tt \: {a}^{2} \: - \: {b}^{2} [/tex]

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