Consider this right triangle. What is the value of sin(B)?

Answer:

1.043

Step-by-step explanation:

Decimal multiplier to increase by x% is computed as:-

100% + x%

The decimal multiplier to increase by 4.3% would be

100% +4.3% = 104.3%

To remove% we divide the number by 100, so the number will become

Hence, The decimal multiplier to increase by 4.3% = 1.043

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Answer:

10 square inches

Step-by-step explanation:

that is the procedure above

Answer:

Area=10.167=10.2

Step-by-step explanation:

Area=1/2ab sin c

area= 1/2(7)(9.4)sin18

area = 10.167=10.2

this is for delta math

Answer:

B. 56° and 38°

Step-by-step explanation:

The sum of each of the two angles sums up to 90° ;

A.) 13° and 77°

Sum of A ; (13 + 77)° = 90°

B.) 56° + 38°

Sum = 56° + 38° = 94°

C) 37° and 53°

Sum = 37° + 53° = 90°

D.) 42° and 48°

Sum = 42° + 48° = 90°

Hence, the pair of degree measure which does not belong is B. 56° and 38°

Answer:

x = 25

Step-by-step explanation:

Given a line parallel to a side of the triangle and intersecting the other 2 sides then it divides those sides proportionally, that is

[tex]\frac{40}{24}[/tex] = [tex]\frac{x}{15}[/tex] ( cross- multiply )

24x = 600 ( divide both sides by 24 )

x = 25

Answer:

Exact Form:

x = 2 √ 2 − 1 3 , − 2 √ 2 − 1 3

Decimal Form:

x = 2.49509379 , − 3.16176045

Step-by-step explanation:

Simplify the decimals as needed

9514 1404 393

Answer:

  5196 m

Step-by-step explanation:

The difference in elevation is found by subtracting one elevation from the other. Usually, we're interested in the positive difference, so we subtract the smaller number from the larger.

  5040 -(-156) = 5040 +156 = 5196

The difference in elevation is 5196 meters.

Answer:

3408

Step-by-step explanation:

Answer:

The volume increases at 35.71cm^3/min

Step-by-step explanation:

Given

[tex]PV^{1.4} = C[/tex]

[tex]V = 400cm^3[/tex]

[tex]P =80kPa[/tex]

[tex]\frac{dP}{dt} =-10kPa/min[/tex]

Required

Rate at which volume increases

[tex]PV^{1.4} = C[/tex]       [tex]V = 400cm^3[/tex]       [tex]P =80kPa[/tex]

Differentiate: [tex]PV^{1.4} = C[/tex]  

[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = \frac{d}{dt}C[/tex]

By differentiating C, we have:

[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = 0[/tex]

Rewrite as:

[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} + V^{1.4}*\frac{dP}{dt} = 0[/tex]

Solve for [tex]\frac{dV}{dt}[/tex]

[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} =- V^{1.4}*\frac{dP}{dt}[/tex]

[tex]\frac{dV}{dt} =- \frac{V^{1.4}*\frac{dP}{dt} }{P*(1.4)*V^{0.4}}[/tex]

Substitute values

[tex]\frac{dV}{dt} =- \frac{400^{1.4}*-10 }{80*(1.4)*400^{0.4}}[/tex]

[tex]\frac{dV}{dt} =\frac{400*10 }{80*1.4}[/tex]

[tex]\frac{dV}{dt} =\frac{4000 }{112}[/tex]

[tex]\frac{dV}{dt} =35.71cm^3/min[/tex]

Answer:

"fair" srry im only in 8th so im d.u.m

Step-by-step explanation:

Answer:

[tex]Shaded = 212.5cm^2[/tex]

Step-by-step explanation:

Given

See attachment

Required

The shaded region

First, calculate the area of the complete rectangle

[tex]Area =Length * Width[/tex]

[tex]Area = 14cm * 25cm[/tex]

[tex]Area = 350cm^2[/tex]

Next, calculate the area of the triangle

[tex]Area = \frac{1}{2} * Base * Height[/tex]

[tex]Area = \frac{1}{2} *25cm * 11cm[/tex]

[tex]Area = 137.5cm^2[/tex]

Subtract the area to calculate the shaded region area

[tex]Shaded = 350cm^2 - 137.5cm^2[/tex]

[tex]Shaded = 212.5cm^2[/tex]

9514 1404 393

Answer:

  (b)  (x – 4)^2 + (y – 6)^2 = 16

Step-by-step explanation:

The equation for a circle with center (h, k) and radius r is ...

  (x -h)^2 +(y -k)^2 = r^2

You want the equation for a circle with center (4, 6) and radius 4. That equation is ...

  (x -4)^2 +(y -6)^2 = 16

Answer:

B; (x – 4)2 + (y – 6)2 = 16

Step-by-step explanation:

correct on edge

Answer:

4.605170185988091

Step-by-step explanation:

ln 100 = 4.605170185988091

e^4.605170185988091 = 100

Step-by-step explanation:

100=1 log 10(1)=0

I hope this is helpful for you

Answer:

A.

Null:

H0: u= 5.65

Alternative:

H1: u > 5.65

B.

The test statistic

Xbar = 6.24

u = 5.65

S = 1.24

N = 57

T = 6.24-5.65/(1.24/√57)

= 0.59/(1.24/7.5498)

= 0.59/0.1642

Test statistic = 3.593

C.

With alpha = 0.05

Df = n-1 = 57-1 = 56

T critical = 1.673

D.

If t test > 1.673 reject the null hypothesis

3.593>1.673, reject the null hypothesis

We conclude that there is enough evidence that the technique helped the participants to learn more.

Answer:

Greg is 28.

Step-by-step explanation:

Greg's age is y.

y - 5 = 23

y - 5 + 5 = 23 + 5

y = 28

Answer:

ifeywifheb

Step-by-step explanation:

hkefewib

Answer:

y = 2/5x + 1/5

Step-by-step explanation:

First, plug in the slope.

y = mx+b

y = 2/5x + b

Then, plug in the point given, in order to find b.

-1 = 2/5(-3) + b

-1 = -6/5 + b

1/5 = b

So the final equation is:

y = 2/5x + 1/5

Answer:

13122

Step-by-step explanation:

a(n) = 6 * 3^(n -1)

a(8) = 6* 3^7

3^7 = 2187

a(8) =6 * 2187

a(8) = 13122

Given:

ABC is an isosceles triangle in which AC =BC.

D and E are points on BC and AC such that CE=CD.

To prove:

Triangle ACD and BCE are congruent​.

Solution:

In triangle ACD and BCE,

[tex]AC=BC[/tex]                  (Given)

[tex]AC\cong BC[/tex]

[tex]\angle C\cong m\angle C[/tex]                  (Common angle)

[tex]CD=CE[/tex]                  (Given)

[tex]CD\cong CE[/tex]

In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.

[tex]\Delta ACD\cong \Delta BCE[/tex]           (SAS congruence postulate)

Hence proved.

Answer:

Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD

∴∠ABD=∠ACE (opposite angle of sides of a triangle ) ....(1)

Then BE−DE=CD−DE

ORBC=CE......................................(2)

In ΔABD and ΔACE

∠ABD=∠ACE ( From 1)

BC=CE (from 2)

AB=AC ( GIven)

∴ΔABD≅ΔACE

So AD=AE [henceproved]

Answer:

50/50

Step-by-step explanation:

It's random

Answer:

10/35

Step-by-step explanation:

4*2.5=10

14*2.5=35

4/14=10/35

9514 1404 393

Answer:

  ΔWZT ~ ΔWXY

Step-by-step explanation:

Angle XWY and angle ZWT are vertical angles, so congruent.

The sides on either side of those angles are proportional:

  WZ/WX = WT/WY

  11/22 = 10/20 = 1/2

so, we can claim similarity by the SAS Theorem.

  ΔWZT ~ ΔWXY

Answer:

Step-by-step explanation:

(0,2). y=mx+b or 2=-2 × 0+b, or solving for b: b=2-(-2)(0).

Answer:

the required equqtion is x-y=2

. ( m →(N v Q)) →((M→N) v (M→Q))

2.((T v U) → V) → (T → (U → V)) wut tyhe hell is this

Answer:

parallel

Step-by-step explanation:

the slope of each line is 5/6 which means the lines are parallel

Answer:

Option c (Upper tailed) is the correct choice.

Step-by-step explanation:

Given that:

The average attendance is:

= 74,900

We will have to test:

⇒ [tex]H_0:\mu \leq \mu_0[/tex]

or,

   [tex]H_0: \mu \leq 74,900[/tex]

Verses,

⇒ [tex]H_1: \mu> \mu_0[/tex]

or,

    [tex]H_1: \mu >74,900[/tex]

The other given alternatives aren't connected to the given scenario. So the above is the correct one.