cos 0 = 12/15. find sin 0.

answer is

(Y)=-23,-14, -5,4,13

hope this will help you

Answer:

[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

2 = 2 × 1

6 = 2 × 3

GCF = 2

[tex]\frac{2 /2 }{6/2} =\frac{1}{3}[/tex]

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]\boxed{\frac{1}{3}}[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Simplify:}}\\\\\frac{2}{6}\\\\\boxed{\text{Finding the Factors:}}\\\\2: 2\\6 : 2,3\\\\\boxed{\text{The GCF would be 2.}}\\\\\frac{2}{6} =\frac{2/2}{6/2}=\boxed{\frac{1}{3}}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer: You have the correct answer. It's choice B

Domain = [tex]\left(-\infty, \frac{2}{5}\right)[/tex]

Nice work.

=========================================================

Explanation:

The domain of g(x) is found by setting 2-5x greater than or equal to 0 and solving for x. We're doing this to ensure that 2-5x is not negative.

[tex]2-5x \ge 0\\\\2 \ge 5x\\\\5x \le 2\\\\x \le \frac{2}{5}[/tex]

So we can plug in any number smaller than 2/5, or we can plug in 2/5 itself, into the g(x) function to get some output.

However, notice that if x = 2/5, then g(x) = 0. This then would feed into the f(x) function and lead to a division by zero error. Therefore, x = 2/5 must be kicked out of the domain of (f o g)(x). We keep everything else that we found earlier.

In short, the domain as an inequality is [tex]x < \frac{2}{5}[/tex], which is the same as saying [tex]-\infty < x < \frac{2}{5}[/tex] and that converts to the interval notation [tex]\left(-\infty, \frac{2}{5}\right)[/tex]

We don't use a square bracket because we don't want to include the endpoint 2/5.

Step-by-step explanation:

The sides with the variables are the same length, so make them equal.

x+2=2x-3

Get x alone on one side.

5=3x

Simplify.

5/3 = x

Answer:

5

Step-by-step explanation:

x+2 = 2x-3

+3 +3

x+5 = 2x

-x -x

x=5

Hope this helps! :)

Answer:

4

Step-by-step explanation:

1/2=0.5

2/0.5=1

4x1=4

Answer:

(1,-2)

Step-by-step explanation:

Choose any value for x that is in the domain to plug into the equation.

Choose 0 to substitute in for x to find the ordered pair.

(0, -19/6)

Choose 1 to substitute in for x to find the ordered pair.

Remove parentheses.

y= -19/6 + 7(1)/6

Simplify

y=2

Use the

x and y values to form the ordered pair.

(1,−2)

Answer:

60%

Step-by-step explanation:

[tex]percentage = \frac{24}{40} \times 100\% \\ = 60\%[/tex]

[tex]\Huge{\textbf{\textsf{{\purple{Ans}}{\pink{wer}}{\color{pink}{:}}}}} \\ [/tex]

[tex]percentage = \frac{24}{40} \times 100\% \\ = 60\%[/tex]

so answer is 60%

Given : Scale drawing of Angel's rectangular room is 5cm by 7 cm

We know that, Area of a rectangle is given by : Length × Width

⇒   Area of Angel's rectangular room = (5 cm × 7 cm) = 35 cm²

Given : The scale is 1 cm = 4 feet

⇒   Area of Angel's rectangular room in square feet = 35 × (4 feet)²

⇒   Area of Angel's rectangular room in square feet = 35 × 16 feet²

⇒   Area of Angel's rectangular room in square feet = 560 feet²

Answer: they are not equivalent be 3(6x+1) is 18x+3 and 21x stays the same so there for they are not equivalent to each other

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the given information, it is likely that the random variable(X) have the values below:

Let head be H

Let tail be T

So;

X(HH) = 2;

X(HT) = 1;

X(TH) = 1;

X(TT) = 0

The distribution can now be computed as:

[tex]p(X= TT) = \dfrac{1}{4}[/tex]

[tex]p(X=TH) = \dfrac{1}{4}[/tex]

[tex]p(X=HT) = \dfrac{1}{4}[/tex]

[tex]p(X=HH)= \dfrac{1}{4}[/tex]

Now, the expected value that is equivalent to the number of heads when the coin is flipped twice is:

[tex]E(X) = p(TT)*X(TT)+p(TH)*X(TH)+p(HT)*X(HT)+p(HH)*X(HH)[/tex]

[tex]E(X) = \dfrac{1}{4}\times 0 + \dfrac{1}{4}\times 1 + \dfrac{1}{4}\times 1 + \dfrac{1}{4}\times 2[/tex]

[tex]E(X) = 0 + \dfrac{1}{4}+ \dfrac{1}{4} + \dfrac{1}{2}[/tex]

[tex]E(X) =\dfrac{1+1+2}{4}[/tex]

[tex]E(X) =\dfrac{4}{4}[/tex]

E(X) = 1

[tex]E(X^2) = p(TT)*X(TT)^2+p(TH)*X(TH)^2+p(HT)*X(HT)^2+p(HH)*X(HH)^2[/tex]

[tex]E(X^2) = \dfrac{1}{4}\times 0^2+ \dfrac{1}{4}\times 1^2 + \dfrac{1}{4}\times 1^2 + \dfrac{1}{4}\times 2^2[/tex]

[tex]E(X^2) = 0 + \dfrac{1}{4}+ \dfrac{1}{4} + \dfrac{4}{4}[/tex]

[tex]E(X^2) =\dfrac{1+1+4}{4}[/tex]

[tex]E(X^2) =\dfrac{6}{4}[/tex]

[tex]E(X^2) =1.5[/tex]

Finally; To compute E²[X]

E²[X] = E[X]²

E²[X] = 1²

E²[X] = 1

Answer:

Dependent

Step-by-step explanation:

The first draw has 10 marbles, the second draw has 9 marbles and the color of those 9 marbles depends on the marble picked in the first draw so the events are dependent.

Answer:

Dependant

Step-by-step explanation:

It would be independent if you put the marble BACK, because at first it was 1/10 to get the white marble and then it became 1/9.

Answer:

18°

Step-by-step explanation:

Know that the intersection of two lines and the angles opposite each other are equal

3t+12=66

Subtract 12 from both sides

3t=54

Divide 3 from both sides

t=18

9514 1404 393

Answer:

  x ≈ 13.7

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

  tan(58°) = 22/x

  x = 22/tan(58°) ≈ 13.747

The value of x is about 13.7 units.

Answer:

5328.78

Step-by-step explanation:

formula:

[tex]P(1+\frac{i}{n})^{n*t}\\2600(1+\frac{.08}{12})^{12*9}\\\\2600(1.006667)^{108}=5328.77861305[/tex]

this rounds to 5328.78

Answer: 0.2

Step-by-step explanation:

1 divided by 5 = 0.2

Answer:

0.2

Step-by-step explanation:

1/5 = 1 divided by 5.

This will also apply to any fraction

Fraction = Numerator divided by Denominator

Answer:

c. -x + 3x + 7  = 2x+7

Step-by-step explanation:

f(x) = 3x +1 and g(x) = x - 6

f-g = 3x +1 - ( x - 6)

Distribute the minus sign

     = 3x+1 - x+6

     = 2x +7

Answer:

530.929158457

Step-by-step explanation:

13x13= 169 x pi= 530.929158457

Answer:

B is the correct answer

Step-by-step explanation:

6(9+6)=54+36

6(15)=90

90=90

Answer:

Step-by-step explanation:

It's -3

The answer would be 30 because the triangle is 10, the circle is 5, and each black triangle is 2 which would be 10 plus 5 which is 15 then times 2 which is 30.

Answer:

20?

Step-by-step explanation:

If 3 triangles = 30 they we could assume that each triangle = 10

10 + 10 + 10 = 30

If one triangle = 10 then the 2 circles would = 5 in the 2nd equation

10 + 5 + 5 = 20

If 1 circle = 5 then the 1 full squares would = 4

5 + 4 + 4 = 13

1 triangle = 10 , 1 circle = 5, Half a square = 2

10 + 5 * 2 = ?

Using PEMDAS we would multiply 2 and 5 first to get 10

10 + 10 = 20

Answer:

135 cm

Step-by-step explanation:

Let Jose's height = x

The mean of their heights = 150

Given the Heights:

150cm, 170cm, 140cm, 155cm

The mean is the sum if the heights divided by the number of people

Here :

(150 + 170 + 140 + 155 + x) / 5 = 150

(615 + x) / 5 = 150

615 + x = 750

x = 750 - 615

x = 135 cm

Answer:

(-3,-2)

(-3,4)

(3,4)

(3,-3)

Step-by-step explanation:

Answer:

cant see nun mind showing it

Answer:

14 - 3i

Step-by-step explanation:

Distribute the minus sign amongst the second equation:

(16 - 6i) - (2 - 3i) = 16 - 6i - 2 + 3i

Solve:

16 - 6i - 2 + 3i:

16 - 2 - 6i +3i

14 - 3i

Hope this helps!

Answer:

D. V=314.2cm³

Step-by-step explanation:

The volume of the cone is:

V=pi×r²×h/3=pi×5²×12/3=100×pi=314.2cm³

Answer: D) 314.2 [tex]cm^3[/tex]

Step-by-step explanation:

The formula for finding the volume of a right cone is [tex]V=\pi r^2\frac{h}{3}[/tex]

r is the radius and h is the height/altitude.

We can sub these values in and solve

[tex]V=\pi (5^2)(\frac{12}{3} )\\V=\pi (25)(4)\\V=100\pi[/tex]

Let's sub in 3.14 for [tex]\pi[/tex] since that is a close estimate

[tex]V=(100)(3.14)\\V=314[/tex]

The volume is about 314.

Our closest answer to that is D so that is the correct choice.

Step-by-step explanation:

You need to multiply the row and column to get the numbers

for example the block with row 3 column 3,the answer is 3 x 3= 9

each spinner can land on any of the points it has, thus each of the number have the same possibility.

Answer:

[tex]thank \: you[/tex]