Dark skin ( a result of increased melanin production in equatorial populations), is likely a response to ultraviolet radiation because UV radiation causes:

Answers

Answer 1

Answer: Skin cancer

Explanation:

Melanin is a pigment derived from an amino called acid tyrosine. The most common form of melanin is called eumelanin, which is a polymer of dihydroxyindole carboxylic acids and their reduced forms. When a person is exposed to the ultraviolet light (UV) from the sun, the melanocytes will produce eumelanin to prevent the skin from burning and damage to the cell nuclei (where DNA is found) of the epidermis. This melanin production causes the skin to darken. The eumelanin in the skin then acts as a natural sunscreen by blocking the damaging effects of sunlight. So, skin darkens when exposed UV light, thus providing greater protection when needed by producing more eumelanin, but it also becomes more likely to develop melanoma, which is a type of skin cancer. This is because UV rays damage the DNA of skin cells. The DNA (deoxyribonucleic acid) is the genetic material that has the instructios to the growth and functioning of an organisms). Skin cancers begin when eumelanin protection is not sufficient and this damage affects the DNA of the genes that control the growth of skin cells. This results in a tumor, which is the uncontrolled growth of cells (in this case, skin cells) because there will be a mutation in DNA that affects the function of the cells.


Related Questions

the flowers of the ____ bloom with sunrise and close with sunset.​

Answers

Daylillies, or hemerocallis

Describe the normal process of osteogenesis for compact and spongy bone using the three different types of bone cells and their functions

Answers

Answer:

Osteoblasts penetrate the disintegrating cartilage and replace it with spongy bone. This forms a primary ossification center. Ossification continues from this center toward the ends of the bones. After spongy bone is formed in the diaphysis, osteoclasts break down the newly formed bone to open up the medullary cavity.

Many of the phenotypes of DiGeorge syndrome have been traced back to one of the genes that is in the deleted region, TBX1. Some of the evidence for the important role of TBX1 in DiGeorge syndrome came from individuals who have some of the symptoms of DiGeorge syndrome without having the typical deletion. Closer examination showed that some of these individuals had SNV in the TBX1 gene. Which of the following SNVS would be most likely to create a similar phenotype to the deletion?
A. A variant in the promoter region of TBX1 that increases its expression
B. A variant in the intronic region of TBX1 that does not affect splicing. X
C. A nonsense variant near the 5' end of the TBX1 gene.
D. A silent variant near the 5' end of the TBX1 gene.

Answers

Answer:

D. A silent variant near the 5' end of the TBX1 gene.

Explanation:

TBX1 gene is wild type human being. It gives instructions for making protein called T-box 1. It plays an important role in tissue formation and organs during embryonic development.

Which is true if energy in ecosystem

Answers

Explanation:

energy flows in only one direction through an ecosystem.

Explain why it is not advisable for two sickle cell carriers to marry.​

Answers

Answer:

it results in pleiotropic effect and caused death of an offspring.

What are three techniques that can be used to show that the electron transport chain is found on the matrix side of the inner mitochondrial membrane. Select all that apply.

Answers

Answer:

Explanation:

Step 1: Generating a Proton Motive Force

The hydrogen carriers (NADH and FADH2) are oxidised and release high energy electrons and protons

The electrons are transferred to the electron transport chain, which consists of several transmembrane carrier proteins

As electrons pass through the chain, they lose energy – which is used by the chain to pump protons (H+ ions) from the matrix

The accumulation of H+ ions within the intermembrane space creates an electrochemical gradient (or a proton motive force)

Step Two: ATP Synthesis via Chemiosmosis

The proton motive force will cause H+ ions to move down their electrochemical gradient and diffuse back into matrix

This diffusion of protons is called chemiosmosis and is facilitated by the transmembrane enzyme ATP synthase

As the H+ ions move through ATP synthase they trigger the molecular rotation of the enzyme, synthesising ATP

Step Three: Reduction of Oxygen

In order for the electron transport chain to continue functioning, the de-energised electrons must be removed

Oxygen acts as the final electron acceptor, removing the de-energised electrons to prevent the chain from becoming blocked

Oxygen also binds with free protons in the matrix to form water – removing matrix protons maintains the hydrogen gradient

In the absence of oxygen, hydrogen carriers cannot transfer energised electrons to the chain and ATP production is halted

que contiene el condón?

Answers

Answer:

plss translate it in English so i Can easyly answer it.

Explanation:

Thank you.

Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these alleles are at Hardy-Weinberg equilibrium, what is the frequency of the disease-causing CFTR alleles in this population

Answers

Answer:

0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

- Frequency of the CFTR allele q = 1/56.57 = 0.0177  

- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823

The energy source for active transport is ________ , while the force driving facilitated diffusion is ________.

Answers

Answer:

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Explanation:

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