Answer:As the name implies, the Bump and Run Reversal (BARR) is a reversal pattern that forms after excessive speculation drives prices up too far, too fast. Developed by Thomas Bulkowski, the pattern was introduced in the June-97 issue of Technical Analysis of Stocks and Commodities and also included in his book, the Encyclopedia of Chart Patterns.
THIS AIN'T MINE
Answer:
to collide with (something) with a moderately forceful impact; thump.
Explanation:
How do you find mass in physics
is solar system a natural system or human-made system
Answer:
Natural
Explanation:
Answer:
It's a Natural System
Explanation:
When the Solar System was formed Human didn't even exist. the planets clashed and a lot of changes happened to create earth and different planets.
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
low-friction wheels and as the bullet struck the target, the target with
bullet embedded bullet sped off with a velocity of 6.0 ms.
Calculate the velocity of the bullet just before it hit the stationary
target.
Answer:
306 m/s
Explanation:
Law of conservation of momentum
m1v1 + m2v2 = (m1+m2)vf
m1 is the bullet's mass so it is 0.1 kg
v1 is what we're trying to solve
m2 is the target's mass so it is 5.0 kg
v2 is the targets velocity, and since it was stationary, its velocity is zero
vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s
plugging in, we get
(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)
(0.1)(v1) + 0 = 30.6
(0.1)(v1) = 30.6
v1 = 306 m/s
The initial velocity of the bullet can be determined from the total momentum of the system. The velocity of the bullet was 306 m/s.
What is momentum ?Momentum of a body is the product of its mass and velocity. For a collision, the momentum before and after collision will be the same for the colliding system.
Let m1 and m2 be the masses and u be the initial velocity and v is the final velocity.
then, m1 u1 + m2 u2 = m1 v1 + m2 v2.
Given m1 = 5 kg
m2 = 0.1 kg
The velocity of the combined mass v = 6 m/s.
The momentum of the target is zero since it was stationary.
(0.1 × u1) = (0.1 + 5)6 m/s
(0.1 × u1) = 30.6 m/s
then u1 = 30.6/0.1 = 306 m/s
Therefore, the velocity of the bullet before hitting was 306 m/s.
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What is the net force on a refrigerator that you push with an applied force of 125 N to the right and the (sliding) friction between the floor and the fridge is 95 N to the left? (b) As you increase the force applied to the fridge, will the friction force also increase? Explain. Hint: remember the force of friction between solid surfaces does not depend on speed
Answer:
hola
Explanation:
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Can someone help me with these questions pls
+
1. Energy due to motion is
_______ energy
Answer:
Kinetic energy
Explanation:
The energy associated with an object's motion is called kinetic energy. A speeding bullet, a walking person, and electromagnetic radiation like light all have kinetic energy.
Kinetic energy. For example, a walking person.
Why is it important for body cell to have twice and many chromosomes as sex cells?
Answer:
Why sex cells only need half the number of chromosomes compared to other cells in the body? As gametes are produced, the number of chromosomes must be reduced by half. Why? The zygote must contain genetic information from the mother and from the father, so the gametes must contain half of the chromosomes found in normal body cells.
Explanation:
Brainliest Plzz
Answer:
During Mitosis, the chromosomes split at G2 Phase.
An impulse of 12.2kg m/s is delivered to an object whose initial momentum is 4.5kgm/s. What is the object's final momentum?
Answer:
Object's final momentum = 16.7 kg-m/s
Explanation:
Given that,
Impulse, J = 12.2 kg-m/s
Initial momentum, [tex]P_i=4.5\ kg-m/s[/tex]
We need to find the object's final momentum. We know that the impulse is equal to the change in momentum. So,
Impulse = change in momentum
[tex]J=P_f-P_i\\\\P_f=J+P_i\\\\P_f=12.2+4.5\\\\P_f=16.7\ kg-m/s[/tex]
So, the object's final momentum is 16.7 kg-m/s.
Given:
Impulse, [tex]J = 12.2 kg-m/s[/tex]Initial momentum, [tex]P_i = 4.5 \ kg-m/s[/tex]We know the relation,
→ [tex]Impulse = Change \ in \ momentum[/tex]
or,
→ [tex]J = P_f-P_i[/tex]
then,
→ [tex]P_f = J+P_i[/tex]
By substituting the values,
[tex]= 12.2+4.5[/tex]
[tex]= 16.7 \ kg-m/s[/tex]
Thus the above answer is right.
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What is 1.2 x 10^5 in standard form?
The standard form of the given exponential function is 120000.
By putting the number as a base and the number of repetitions as a little number to its upper right, a representation of repeated multiplications of the same number is known as an exponential form.
It is simpler to write repeated multiplication using base and exponents in the exponential form.
The equation f(x) = aˣ, in which the input variable x appears as an exponent and a as the base, describes an exponential function.
So, the given exponential function is,
1.2 x 10⁵
Here, 10 is the base and 5 is the exponent.
10⁵ = 100000
Therefore, the standard form of the given equation is,
1.2 x 100000 = 120000
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A sledgehammer is an example of what kind of simple machine?
A. Wheel and axle
o
B. Screw
c
C. Wedge
D. Lever
SUS
I am 95 percent sure the answer in C
Answer: C
Explanation:
