Answer:
Sedimentation and decantation
Explanation:
Sedimentation and decantation: Mixture is kept undisturbed for some time. After some time, sand being heavier and insoluble in water, settles down at the bottom of container. Now, water is poured into another container to separate it from sand.
Answer:
evaporation or destillation
Explanation:
When sand is added to water it either hangs in the water or forms a layer at the bottom of the container. Sand therefore does not dissolve in water and is insoluble. It is easy to separate sand and water by filtering the mixture. Salt can be separated from a solution through evaporation.
18. If the pH of a strong acid solution is known to be 3.25, what is the [H+)?
(b) what is the pOH of this solution?
10. As electrons move through the electron-transport chain,
they lose energy, which is used to form
A. NAD.
B. ADP
C. ATP.
D. GBP
Answer:
NAD
Explanation:
mark me brainlist please
Answer:
They lose energy which is used to form ATP
best way to separate a solid from a liquid what separation technique is needed
Answer:
Filtiration technique
Explanation:
what is mean by measurement
Answer:
Measurement is defined as the act of measuring or the size of something. An example of measurement means the use of a ruler to determine the length of a piece of paper. ... Extent, quality, or size as determined by measuring; dimension. A waist measurement of 32 inches.
Explanation:
The comparison o unknown quantity with known standard quantity is called measurement.
career in chemistry list ten
Answer:
Analytical Chemist
Forensics
Toxicologist
Biochemist
Chemical Engineer
Laboratory Technician
Pharmacologist
Chemical Technician
Materials Scientist
Environmental Chemist
What temperature scale is used in the ideal gas equation
Answer:
kelvin scale?
Explanation:
i`m not 100% on this one
The solubility of solids______ when the temperature is increased.
A. increases
B. decreases
C. does not change
Calculate the weight of CuO formed when 200g of Copper carbonate is heated.(Atomic weight of Copper-64,Carbon-12,Oxygen-16)
Answer:
129 g of CuO
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
CuCO₃ —> CuO + CO₂
Next, we shall determine the mass of CuCO₃ that decomposed and the mass of CuO produced from the balanced equation. This can be obtained as follow:
Molar mass of CuCO₃ = 64 + 12 + (16×3)
= 64 + 13 + 48
= 124 g/mol
Mass of CuCO₃ from the balanced equation = 1 × 124 = 124 g
Molar mass of CuO = 64 + 16
= 80 g/mol
Mass of CuO from the balanced equation = 1 × 80 = 80 g
SUMMARY:
From the balanced equation above,
124 g of CuCO₃ decomposed to produce 80 g of CuO.
Finally, we shall determine the mass of CuO produced by the decomposition of 200 g of CuCO₃. This can be obtained as follow:
From the balanced equation above,
124 g of CuCO₃ decomposed to produce 80 g of CuO.
Therefore, 200 g of CuCO₃ will decompose to produce
= (200 × 80)/124 = 129 g of CuO.
Thus, 129 g of CuO was obtained from the reaction.
list three factors that affect the rate of a chemical reaction
Answer: 1) temperature, 2) add a catalyst, and 3) concentrations
Explanation: A rise in temperature adds kinetic energy to the reactants, leading to more frequent, and energetic collisions, which will often accelerate the reaqction. A catalyst is an agent that helps the reaction move forward more quickly by offering a substrate that aids in orienting the reactants for more efficient reaction. A higher concentration increases the chances of collisons that result in products.
an atom with six protons and eight neutrons is a(n)___
a. isotope of nitrogen
b. standard carbon atom
c. isotope of carbon
d. isotope of oxygen
Answer:
standard carbon atom
Explanation:
Answer:
Explanation:
This is an isotope of carbon, more specifically, carbon-14. Carbon 14 has 6 protons, making the element carbon, and eight neutrons since 14-6 = 8.
The levels of carbon dioxide in the atmosphere a. began decreasing when the burning of fossil fuels increased. b. are estimated to be higher than at any time in the past 420,000 years. c. are high but not higher than the highest estimated levels in the last 420,000 years. d. peaked around 1950 and have begun slowly decreasing since then.
The levels of carbon dioxide in the atmosphere are estimated to be higher than at any time in the past 420,000 years. That is option B
Carbon dioxide is a very harmful compound which is easily released into the atmosphere through burning of fossil fuels and other carbon compounds in plenty of air.
The released carbon dioxide rises to the upper atmosphere and blocks the radiation of solar energy back into the space. This precipitates a global temperature increase called the greenhouse effect.
According to Intergovernmental Panel on Climate Change (IPCC) in a current research discovered that CO2 concentration in the earth’s atmosphere is higher than at any point during the last 650,000 years. They where able to study this through the study of higher levels of CO2 concentration which coincide with higher temperatures.
Therefore the correct option is B which states that the levels of carbon dioxde in the atmosphere are estimated to be higher than at any time in the past 420,000 years.
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Molar mass of C^6H^12O^6
Answer:
The molar mass of C6 H12 O6 is 180.15588 g/mol.
Explanation:
3 point different between reactant and product
Answer:
reactants
The substance(s) to the left of the arrow in a chemical equation are called reactants. A reactant is a substance that is present at the start of a chemical reaction
Explanation:
product_The substance(s) to the right of the arrow are called products . A product is a substance that is present at the end of a chemical reaction. In the equation above, the zinc and sulfur are the reactants that chemically combine to form the zinc sulfide product.
There is a standard way of writing chemical equations. The reactants are all written on the left-hand side of the equation, with the products on the right-hand side. An arrow points from the reactants to the products to indicate the direction of the reaction:
reactants → products
Reactants
1. The substances used as starting materials and which react with one another are reactants.
2. Example: In this reaction Mg and O2 are reactants.
Products
1. The substances which are formed as a result of reaction are products.
2. Example: In this reaction MgO is a product.
Question 14 (Essay Worth 10 points) (03.05 MC) Use complete sentences to differentiate between acids and bases on the basis of touch. Give an example of each type.
Answer:
Acid is a molecule capable of donating hydrogen ion and they form aqueous solutions with a sour taste while base is a substance that accepts proton from proton donor and in aqueous solution, they have an astringent or bitter taste. Moreover, a good example for base is sodium hydrogen carbonate as baking soda or baking powder and for acid, the most common example is the acetic acid or vinegar.
Answer:
Well, for starters, bases mostly consist of soaps and cleaning products, acids consist of vinegar,lemon,and stuff like that. Most acids on the basis of touch can burn your skin or be very sour, unlike bases which are more soapy and have a cleaner touch.A good example of an acid is vinegar, which can be used for cleaning but can also be used for making foods, on the other hand. A good example of a base is dish soap. It is used for cleaning.
Explanation:
i just did the exam and got a 100
calculate the molecular formula of H2O
Which soil would most likely be found in the Arctic?
Answer:
The answer is B
Explanation:
Gelisols
An atom has mass number 23 and atomic number 11.
a) How many electrons are revolving around the nucleus?
b) How many electron shells are there in the atom?
A): The closest orbital to the nucleus, called the 1s orbital, can hold up to two electrons. This orbital is equivalent to the innermost electron shell of the Bohr model of the atom. It is called the 1s orbital because it is spherical around the nucleus. The 1s orbital is always filled before any other orbital.
process of heat treatment and it's meaning
Answer:
Heat treatment is the process of heating metal without letting it reach its molten, or melting, stage, and then cooling the metal in a controlled way to select desired mechanical properties. Heat treatment is used to either make metal stronger or more malleable, more resistant to abrasion or more ductile.
¿Como pasar 254 meses a minutos?
Por favor ayudaaa!!
Le doy corona a la respuesta
Answer:
Ver las respuestas abajo.
Explanation:
Este problema se puede resolver conociendo la relacion entre horas y minutos, sabemos que:
1 hora [h] → 60 minutos [min]
De esta manera:
2 [min] = 2/60 = 0.033 [h]
15 [min] = 15/60 = 0.25 [h]
30 [min] = 30/60 = 0.5 [h]
10 [min] = 10/60 = 0.166 [h]
6 [min] = 6/60 = 0.1 [h]
20 [min] = 20/60 = 0.33 [h]
5 [min] = 5/60 = 0.0833 [h]
write the balanced chemical equation for the following word equation. sodium+sulphate Acidsodium sulphate +hydrogen
Answer:
2NaOH+ H2SO4 → Na2SO4 + 2H2O
I HOPE ITS RIGHT IF NOT THEN SORRYHAVE A GREAT DAY :)
Answer:
Sodium+sulphate=Na2SO4
Acidsodium sulphate + hydrogen=Na2SO4+H2O
What is the balanced form of the chemical equation shown below?
C2H5OH() + O2(9)
H2O() + CO2(9)
A. C2H5OH() + 302(9) — 3H20() + 2002(9)
B. 2C2H5OH() + O2(g) – 5H20(1) + CO2(g)
C. C2H20(1) + 202(9)
-
H20(1) + 2C02(9)
D. C2H5OH() + O2(g) → H20(1) + CO2(g)
Answer:
C2H5OH +3O2 = 2Co2+ 3H2O
Explanation:
The balanced chemical equation is C2H5OH + 302 → 3H20 + 2CO2.
What is balanced chemical equation?A balanced chemical equation is one in which the count of atoms in all of the molecules is equivalent on both sides of the equation. The balancing of a particular chemical equation is governed by the Law of Conservation of Mass.
Balancing chemical equation is shown as below:
It can be seen that the count of carbon atom in left side 2 on the other hand the count of carbon in right side only one. By multiply with 2 in right side of the reaction , equation will be balanced.
Therefore, the balanced chemical equation is C2H5OH + 302 → 3H20 + 2CO2.
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Convert 500.45 g to kg (do not use Scientific Notation)
Answer:
To convert grams to kilograms, you divide the number of grams you have by 1000. So, 800 g = 800/1000 = 0.8 kg.
Explanation:
why metals are not often used to
make clothes
Answer:
They would be to heavy and you would be really stiff
Explanation:
Imagine walking in a suit made of iron or tin
You would feel like the Tin Man
You would be stiff
Metals are hard and heavy
please solve this question
Answer:
b) it gets accumulated in the respiratory system which then halts or slows down the supply of oxygen to the brain hence leading to death
HELLPP ASAP, FIRST PERSON WITH THE CORRECT ANSWER WILL RECEIVE BRAINLIEST
How are the number of valence electrons and the types of ions related?
Answer:
"The number of electrons in an atom's outermost valence shell governs its bonding behaviour."
Explanation:
Credits to:
https://socratic.org/questions/how-do-valence-electrons-affect-chemical-bonding
Make sure to put in your own words
Hopefully this helps
Answer:
The number of electrons in an atom's outermost valence shell governs its bonding behaviour. ... They need to lose only one or two valence electrons to form positive ions with an s²p⁶ configuration. NONMETALS. Nonmetals tend to attract additional valence electrons to form either ionic or covalent bonds.
500kg, 42m, 675g, and 10m/s are all examples of what typed of data?b
500kg, 42m, 675g, and 10m/s are all examples of a: continuous data.
A numerical data can be defined as a data set that is expressed in numbers only or a data set consisting of numbers rather than words. A numerical data is also known as a quantitative data.
Generally, numerical data are classified into two (2) main categories and these are;
Discrete data: a discrete data is a data set in which the number of possible values are either finite or countable. Some examples are; the value of a fair die, number of pen in a box, number of eggs in a crate, etc.Continuous data: a continuous data is a data set that has infinitely many possible values and as such those values cannot be counted, which simply means they are uncountable. Any data (quantity) such as mass, height, volume, weight, density, velocity, length, pressure, temperature, speed, distance, time are generally classified as continuous data.In conclusion, mass (500 kg), height (42m), mass (675g), and speed (10m/s) are all examples of a: continuous data.
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Which type of bonds can carbon atoms form with other carbon atoms? (1 point)
O double, triple, and quadruple bonds
O single and double bonds
O double and triple bonds
O single, double, and triple bonds
Answer:
single, double, and triple bonds
Sarah measures out 151 grams of SO2. How many moles is this? Express your answer to three significant figures.
Answer:
[tex]\boxed {\boxed {\sf 2.36 \ mol \ SO_2}}[/tex]
Explanation:
We are asked to convert grams to moles. We will use the molar mass and dimensional analysis to perform this conversion.
1. Molar MassThe molar mass is the mass of 1 mole of a substance. These values are found on the Periodic Table because they are equivalent to the atomic masses, but the units are grams per mole instead.
We are given a mass of sulfur dioxide (SO₂). Look up the molar masses of the individual elements.
Sulfur (S): 32.07 g/mol Oxygen (O): 15.999 g/molNotice that the formula of the compound contains a subscript. The subscript after O means there are 2 moles of oxygen in 1 mole of sulfur dioxide. We must multiply oxygen's molar mass before adding sulfur's.
O₂: 15.999 * 2 = 31.998 g/mol SO₂= 32.07 + 31.998 = 64.068 g/mol2. Convert Grams to Moles
Now we will use dimensional analysis to convert grams to moles. From the molar mass, we know there are 64.068 grams of sulfur dioxide per mole, so we can set up a ratio.
[tex]\frac {64.068 \ g \ SO_2} {1 \ mol \ SO_2}[/tex]
We are converting 151 grams to moles, so we multiply by this value.
[tex]151 \ g \ SO_2 *\frac {64.068 \ g \ SO_2} {1 \ mol \ SO_2}[/tex]
Flip the ratio so the units of grams of sulfur dioxide cancel.
[tex]151 \ g \ SO_2 *\frac {1 \ mol \ SO_2}{64.068 \ g \ SO_2}[/tex]
[tex]151 *\frac {1 \ mol \ SO_2}{64.068 }[/tex]
[tex]\frac {151}{64.068 } \ mol \ SO_2[/tex]
[tex]2.356870825 \ mol \ SO_2[/tex]
3. RoundThe original measurement of grams (151) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 6 in the thousandth place tells us to round the 5 in the hundredth up to a 6.
[tex]2.36 \ mol \ SO_2[/tex]
151 grams of sulfur dioxide is approximately 2.36 moles of sulfur dioxide.
How does a balanced chemical equation represent the conservation of
matter in a chemical reaction?
1. There are more atoms in the reactants than in the products.
2. The type of matter in the products is different from the type of matter in
the reactants.
3. The number of atoms of each element in the reactants equals the number
of atoms of each element in the products.
4. There are fewer atoms in the reactants than in the products
Answer:
The correct answer would be 3. The number of atoms of each element in the reactants equals the number of atoms of each element in the products.
Explanation:
The law of conservation of matter states that energy cannot be created or destroyed, only transfered. Thus, option 3 is correct.
A 1.732 g sample of iron is heated in air. It oxidizes to form a product with a mass of 2.205 g.
What is the empirical formula of the product?
Answer:
A 1.732 g sample of iron is heated in air. It oxidizes to form a product with a mass of 2.205 g. What is the empirical formula of the product? FeO 4. Caffeine is made of 49.48% carbon, 5.19% hydrogen, 28.85% nitrogen, and 16.48% oxygen by mass.
Explanation:
The empirical formula of the product formed by the reaction of iron and oxygen is FeO.
Let's consider the following generic chemical equation:
Fe + O₂ ⇄ FexOy
According to the law of conservation of mass, the sum of the masses of the reactants is equal to the sum of the masses of the products. The mass of O₂ that reacted, and remains in the oxide is:
[tex]mFe + mO_2 = mFexOy\\mO_2 = mFexOy - mFe = 2.205 g - 1.732 g = 0.473 g[/tex]
The oxide has 1.732 g of Fe and 0.473 g of oxygen and a total mass of 2.205 g. To determine the empirical formula, we need to calculate the percent composition.
[tex]\%Fe = \frac{mFe}{mFexOy} \times 100 \% = \frac{1.732 g}{2.205 g} \times 100 \% = 78.55\%[/tex]
[tex]\%O = \frac{mO}{mFexOy} \times 100 \% = \frac{0.473 g}{2.205 g} \times 100 \% = 21.45\%[/tex]
Now, we will divide each percentage by the atomic mass of the element.
[tex]Fe: 78.55/55.85 = 1.406\\O: 21.45/16.00 = 1.340[/tex]
Finally, we divide both numbers by the smallest one.
[tex]Fe: 1.406/1.340 \approx 1 \\O: 1.340/1.340 = 1[/tex]
The empirical formula of the product is FeO.
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