Describe and correct the error in determining the formula for the sequence below

Answer:

3.1416

Step-by-step explanation:

A=pi*r^2, differentiate with respect to t both sides

dA/dt=2*pi*r*dr/dt

dA/dt=2*pi*5*(0.1)

dA/dt=pi=3.1416 cm^2/sec

Step-by-step explanation:

since the user is listed as beginner, I was wondering, if (while correct) the answer should be based on differentiation (rather advanced topic).

I thought originally this would be about sequences.

and I wondered about the start value.

in any case, here a different view.

the area of a circle is

Ac old = pi × r²

now, r is increasing by 0.1

Ac new = pi×(r+0.1)² = pi×(r² + 0.2r + 0.01) =

= pi×r² + pi×0.2r + pi×0.01 =

= Ac old + pi×0.2r + pi×0.01

so, the increase of the area is

pi×0.2r + pi×0.01

for r=5

pi×0.2×5 + pi×0.01

pi×1 + pi×0.01 = pi + p×0.01 = pi×(1 + 0.01) =

= pi×(1 + (radius change)²)

now, it depends on what your teacher wants to see here.

a "digital stair case" 0.1 by 0.1 increase/sequence approach ?

in this case you might also want to calculate the above with r=4.9 (as only with the last 0.1 step r reaches 5).

and either the r=4.9 (result a tiny bit less than pi) or r=5 (result a tiny bit larger than pi) is correct, of simply the value in the middle (practically pi).

or it was meant to be a continuous increase (not step by step).

in which case we need then to calculate the limit with "radius change" going to 0. which delivers pi as rate result (as with the differentiation).

Answer:

-18/x+3

Step-by-step explanation:

Answer:

A = 22.5 cm^2

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh where b is the base and h is the height

A = 1/2(5)(9)

A = 45/2

A = 22.5 cm^2

[tex]\begin{gathered} {\underline{\boxed{ \rm {\red{Area \: \: of \: \: triangle \: = \: \frac{1}{2} \: \times \: base \: \times \: height}}}}}\end{gathered}[/tex]

[tex]\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: \frac{1}{2} \: \times \: 5 \: cm \: \times \: 9 \: cm[/tex]

[tex]\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: \frac{1}{2} \: \times \: 45 \: cm[/tex]

[tex]\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: \frac{45 \: {cm}^{2} }{2} \: \\ [/tex]

[tex]\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: \cancel\frac{45}{2} \: \: ^{22.5 \: {cm}^{2} } \: \\ [/tex]

[tex]\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: 22.5 \: {cm}^{2} [/tex]

Hence , the area of triangle is 22.5 cm²

Answer:

[tex]s=6\sqrt{3}[/tex]

Step-by-step explanation:

In any 30-60-90 triangles, the sides are in ratio [tex]x:x\sqrt{3}:2x[/tex], where [tex]x[/tex] is the side opposite to the 30 degree angle and [tex]2x[/tex] is the hypotenuse of the triangle.

In the given diagram, the hypotenuse is marked as 12 miles. Therefore, the side opposite to the 30 degree angle must be [tex]12 \div 2=6[/tex] miles. The final leg, [tex]s[/tex], must then represent the [tex]x\sqrt{3}[/tex] part of our ratio, hence [tex]\implies \boxed{6\sqrt{3}}[/tex]

Step-by-step explanation:

2997

81

×

37

=2997

it just a simple calculation just multiply the numbers

(2/7)m - (1/7) = 3/14

2m/7 =(3/14) + (1/7)

2m/7 = (3/14) + 2(1/7)

here we are multiplying 2 with 1/7 to make the denominator same for addition.

2m/7 = (3/14) +(2/14)

2m/7 = (3 + 2)/14

2m/7 = 5/14

2m = (5 *7)/14

2m = 35/14

2m = 5/2

m = 5/4

m = 1.25

So the value of "m" is 1.25

Answer:

N=18

Step-by-step explanation:

Hope it will help you

If it does pls give me Brainlest

Have a nice day

Answer:

18

Step-by-step explanation:

use the concept of similarity and enlargement.

[tex] \frac{15}{n} = \frac{5}{6 } [/tex]

[tex]n = \frac{15 \times 6}{5} [/tex]

[tex]n = 18[/tex]

Answer:

the third one

the line extends in both ways forever

Answer:

AC is about 4.29

Step-by-step explanation:

we need to use simple trigonometry for this problem

the tangent of an angle is the ratio between the opposite side and the adjacent side

so the tangent of the angle 35º is BC / AC

tan(35) is about 0.7

this means that BC / AC = 0.7

we know BC is 3

so 3 / AC = 0.7

3 = 0.7(AC)

AC is about 4.29

Answer:

[tex]B)\ x=43[/tex]

Step-by-step explanation:

One is given a circle with many secants within the circle. Please note that a secant refers to any line in a circle that intersects the circle at two points. A diameter is the largest secant in the circle, it passes through the circle's midpoint. One property of a diameter is, if a triangle inscribed in a circle has a side that is a diameter of a circle, then the triangle is a right triangle. One can apply this to the given triangle by stating the following:

[tex]x+47+90=180[/tex]

Simplify,

[tex]x+47+90=180[/tex]

[tex]x+137=180[/tex]

Inverse operations,

[tex]x+137=180[/tex]

[tex]x=43[/tex]

Answer:

y=0x+9. Hope this helped.

Step-by-step explanation:

slope intercept form: y=mx+b

m represents slope

b represents the y intercept. Please give me the brainliest:)

Answer:

yes

Step-by-step explanation:

The complete sentence is,

A kite is a convex quadrilateral.

We have to given that,

To find a kite is which type of a quadrilateral.

We know that,

A quadrilateral known as a kite has four sides that may be divided into two pairs of neighboring, equal-length sides.

The two sets of equal-length sides of a parallelogram, however, are opposite one another as opposed to being contiguous.

Hence, The complete sentence is,

A kite is a convex quadrilateral.

Learn more about quadrilateral visit:

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Answer:

can't understand the language

Answer:

x>3

Step-by-step explanation:

8x - 2x > 12+ 6

-> 6x > 18

-> x > 3

[tex] \: \: \: \huge \rm{answer: \blue{ \boxed{ \rm{ \pink{x > 3}}}}}[/tex]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

[tex] \huge \blue{ \boxed{ \pink{\boxed{ \rm{ \blue{armed }\: account}}}}}[/tex]

➙[tex] \huge \rm8x-6>12+2x \\ \rm \huge8x-2x>12+6 \\ \huge\rm6x>18 \\ \huge \boxed{\rm{x>3}}[/tex]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖

I hope you understood!✏

➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Step-by-step explanation:

[tex] \huge \boxed{ \boxed{\rm{Hope \: this \: helps}}}[/tex]

9514 1404 393

Answer:

  B.  (2, -5)

Step-by-step explanation:

Reflection across the y-axis is the transformation ...

  (x, y) ⇒ (-x, y)

Rotation 180° about the origin is the transformation ...

  (x, y) ⇒ (-x, -y)

Applying the rotation after the reflection, we get ...

  (x, y) ⇒ (x, -y)

  (2, 5) ⇒ (2, -5)

_____

Additional comment

For these transformations, the order of application does not matter. Either way, the net result is a reflection across the x-axis.

Answer:

(2,-5)

Step-by-step explanation:

Answer:

d. this graph

Step-by-step explanation:

9514 1404 393

Answer:

  a) CP = SP/1.1

  b) CP = $59.50

  c) GST = $5.95

Step-by-step explanation:

a) Divide by the coefficient of CP.

  SP = 1.1×CP

  CP = SP/1.1

__

b) Use the formula with the given value.

  CP = $65.45/1.1 = $59.50

__

c) You can do this two ways: subtract CP from SP, or multiply CP by 0.1.

  GST = SP -CP = $65.45 -59.50 = $5.95

  GST = CP×0.10 = $59.50 × 0.10 = $5.95

Answer:

1/5

Step-by-step explanation:

Answer:

y=-2x

Step-by-step explanation:

first find the slope: (-2-(-4))/(1-2)=2/-1=-2 so m=-2

now we have y=-2x+b, to find b we plug in any of the points

so the equation is y=-2x

Answer:

Sin A = o/h

= 9/41

Step-by-step explanation:

since Sin is equal to opposite over hypotenuse, from the question, the opposite angle of A is 9 and hypotenuse angle of A is 41. Thus the answer for Sin A= 9/41

Answer:

D

Step-by-step explanation:

f(x)=-x(x-4)

f(x)=-x²+4x

-x²+4x=0

x(-x+4)=0

x=0, x=4

(2)

4x²-x-3=0

(4x²+3x)-(4x-3)=0

x(4x+3)-1(4x+3)=0

x=1, x=-3/4

Answer:

2.5/ft per sec

Step-by-step explanation:

its vertica.

The height of the ladder is decreasing at a rate of 24 ft/sec.

Pythagorean theorem states that for a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

We can apply this theorem only in a right triangle.

Example:

The hypotenuse side of a triangle with the two sides as 4 cm and 3 cm.

Hypotenuse side = √(4² + 3²) = √(16 + 9) = √25 = 5 cm

We have,

Let's denote the distance between the base of the ladder and the wall by x.

The length of the ladder = L.

Now,

L = 10 ft

dx/dt = 4 ft/sec

x = 6 ft.

The rate of change of the height of the ladder with respect to time.

Using the Pythagorean theorem, we have:

L² = x² + y²

Differentiating both sides with respect to time t, we get:

2L (dL/dt) = 2x(dx/dt) + 2y(dy/dt)

Substituting L = 10 ft, x = 6 ft, and dx/dt = 4 ft/sec.

20(dL/dt) = 12(4) + 2y(dy/dt)

Simplifying and solving for dy/dt.

dy/dt = (20/2y)(dL/dt) - 24

Now,

The height of the ladder.

Using the Pythagorean theorem again, we have:

y² = L² - x²

   = 100 - 36

   = 64

y = 8

Now,

Substituting y = 8 ft, dL/dt = 0

(since the length of the ladder is constant), and dx/dt = 4 ft/sec.

dy/dt

= (20/2(8))(0) - 24

= -24 ft/sec

Therefore,

The height of the ladder is decreasing at a rate of 24 ft/sec.

Learn more about the Pythagorean theorem here:

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Answer:

11.75

Step-by-step explanation:

The required triangle is attached below :

The triangle AFE has it's by the mid segment as BD ;as B is the mid-point of line EA ; and D is the mid-point of line FA ;

HENCE, The Length of the midsegment BD = 1/2FE

Hence, BD =. 1/2 * 23.5

BD = 23.5 / 2 = 11.75

We have to figure out what the product of DA is,

[tex]\begin{bmatrix}-1&2&3\\8&-4&0\\6&7&1\\ \end{bmatrix}\begin{bmatrix}1\\3\\5\\ \end{bmatrix}=\begin{bmatrix}a\\b\\c\\ \end{bmatrix}[/tex]

We know that,

[tex]\begin{bmatrix}a&b&c\\d&e&f\\g&h&i\\\end{bmatrix}\begin{bmatrix}x\\y\\z\\\end{bmatrix}=\begin{bmatrix}ax+by+cz\\dx+ey+fz\\gx+hy+iz\\\end{bmatrix}[/tex]

So,

[tex]a=-1\cdot1+2\cdot3+3\cdot5=-1+6+15=20[/tex]

[tex]b=8\cdot1+(-4)\cdot3+0\cdot5=8-12=-4[/tex]

[tex]c=6\cdot1+7\cdot3+1\cdot5=6+21+5=32[/tex]

So the solution is,

[tex]a,b,c=\boxed{20,-4,32}[/tex]

Hope this helps :)

The lub is 0.23[tex]\mathbf{\overline{43}}[/tex], while the glb is 0.2

The given set is presented as follows;

E = {0.2, 0.23, 0.234, 0.2343, 0.23434, 0.234343,...}

The least upper bound, lub, of a set, E, is known as the supremum of the set which is the number B such that all x ∈ E are of the value x  ≤ B, while there all y ∈ E has a x ∈ E such that t < x

Therefore;

The supremum, lub of the given set is 0.23[tex]\overline{43}[/tex]

The greatest lower bound, glb, b, also known as the infimum, is defined as follows;

b is the greatest lower bound if for all x ∈ E then x ≥ b

Given that b < t, then where x ∈ E, there exist a x < t

The glb of the given set is 0.2

Learn more about lub, supremum, glb, infimum, here;

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Answer:

First one: 2.5

Second: -6

8.5+69.5(5) = 147.5

150 - 147.5 = 2.5

8.5 + 69.5(5) = 356

350 - 356 = -6

ED2021

The residual for 2 phone lines is $2.5.

The residual for 5 phone lines is -$6.

The residual is the vertical distance separating the observed point from your expected y-value, or more simply put, it is the difference between the actual y and the predicted y.

In the question, we are asked to find the residual for 2 and 5 lines using the least-squares regression equation y = 8.5 + 69.5x and the actual costs given to us.

We know that the residual is the vertical distance separating the observed point from your expected y-value, or more simply put, it is the difference between the actual y and the predicted y.

Thus for 2 phone lines:-

Actual Cost = $150.

Predicted Cost, y = 8.5 + 69.5*2 = 147.5.

Residual = Actual Cost - Predicted Cost = 150 - 147.5 = $2.5.

Thus, the residual for 2 phone lines is $2.5.

Thus for 5 phone lines:-

Actual Cost = $350.

Predicted Cost, y = 8.5 + 69.5*2 = 356.

Residual = Actual Cost - Predicted Cost = 350 - 356 = -$6.

Thus, the residual for 2 phone lines is -$6.

Learn more about the residual in a least-square regression equation at

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Answer:

(-2, 2)

Step-by-step explanation:

If you have a point (x, y) and you do a dilation by a scale factor K centered at the origin, the new point will just be (k*x, k*y)

So, if the original point is (-8, 8)

And we do a dilation by a scale factor k = 1/4

Then the image of the point will be:

(-8*(1/4), 8*(1/4))

(-8/4, 8/4)

(-2, 2)

Answer:

[tex] { (\frac{3}{2} )}^{ - 2} \\ = { (\frac{2}{3}) }^{2} \\ = \frac{4}{9} \\ thank \: you[/tex]