Describe what is happening in each of the phases of cellular division with what you observe from the photomicrographs in the lab instructions (describe and compare both).

Answer:

True

Explanation:

Nitrogen is a fundamental component of both inorganic and organic compounds, where it is the main constituent of biomolecules such as nucleic acids (DNA, RNA) and proteins. The nitrogen cycle refers to the biogeochemical processes by which nitrogen circulates between the components of an ecosystem, i.e., between organisms (like plants and decomposers), and non-living things (i.e., soil, water, air). This cycle consists of several processes which include, among others, nitrogen fixation (i.e., the process by which nitrogen in the atmosphere is converted into ammonia), nitrification (i.e., the oxidation of ammonia is oxidized into nitrite and subsequent transformation of nitrites into nitrates), denitrification (where nitrate is reduced), anaerobic ammonia oxidation and putrefaction.

The correct answer is option C) The new mice population size is a result of density-independent regulation.

The carrying capacity might be affected by different factors, known as limiting factors, which might be a result of the population density (for example, competition) or might be density-independent. This last case refers to dense-independent factors, and among these, we can mention human impact or natural disasters (fires, volcanic eruption, flooding). Natural disaster causes damages in an ecosystem, reducing the available resources such as food or shelter, and consequently decreases the number of individuals. Natural disasters reduce the carrying capacity of the environment

In the exposed example, mice got to stabilize on the island. The population had enough food and no predators. But the occurrense of the huricane reduced drastically the population size. This is an example of a natural dissaster acting as a limiting dense-independent factor affecting the population size.

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OMG I'm a business study Student so I really don't know about this stuff

Answer:

2KNO3

Explanation:

Pls mark it brainliest

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Answer:

The answer is B.) 2KNO3

Explanation:

Answer:

ok where is it

we can help only if there is something attached

According to Hardy-Weinberg, when a population is in equilibrium, it will have the same allelic frequencies generation after generation, meaning that they are stable, they are not evolving.

When any evolutive force is acting on the population, this equilibrium breacks, and allelic and genotypic frequencies change through generations, differing from the expected ones.  

A) Option 7 is the correct answer ⇒ 0.41

B) Option 6 is the correct answer ⇒ 120

C) Option 7 is the correct answer ⇒ 3.84

D) Option 1 is the correct answer ⇒ The class represents a population that is in H-W equilibrium

E) Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

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Allelic frequencies in a locus are represented as p and q, referring to the

allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (H0m0zyg0us  dominant), 2pq (H3ter0zygous), q² (H0m0zyg0us recessive). Populations in H-W equilibrium will get the same

allelic frequencies generation after generation.

The sum of the allelic frequencies equals 1, this is p + q = 1.

In the same way, the sum of genotypic frequencies equals 1, this is

p² + 2pq + q² = 1

Being

 p the dominant allelic frequency,

 q the recessive allelic frequency,

 p² the h0m0zyg0us dominant genotypic frequency

 q² the h0m0zyg0us recessive genotypic frequency

 2pq the h3ter0zyg0us genotypic frequency

Situation: Through PCR, we have determined the PER3 genotypes for a class of students as follows:

 H4/H4 = 125 individuals;

 H4/H5 = 85 individuals;

 H5/H5=24 individuals.

⇒ Total number of individuals= 125 + 85 + 24 = 234

⇒ Genotypic frequencies, F(xx):

 F(H4/H4) = 125/234 =0.534

 F(H4/H5) = 85/234 = 0.363

 F(H5/H5) = 24/234 = 0.102

⇒ Allelic frequencies, f(x):

 f(H4) = p = F(H4/H4) + 1/2 F(H4/H5) = 0.534 + 0.363/2 = 0.534 + 0.182 = 0.716

 f(H5) = q = F(H5/H5) + 1/2 F(H4/H5) = 0.102 + 0.363/2 = 0.102 + 0.182 = 0.284

Questions:

A)  According to the theoreticall frame, we know that 2pq is the h3ter0zygous genotypic frequency. So,  

F(H4/H5) = 2pq = 2 x 0.716 x 0.284 = 0.408 ≅ 0.41 ⇒ Option 7 is the correct answer.

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B)  According to the theoreticall frame, we know that p² is the h0m0zyg0us genotypic frequency. So,

p = 0.716

p² = 0.5126 ≅ 0.513 ⇒ This is the genotypic frequency.

To calculate the number of individuals carrying this genotype, we need to multiply it by the total number of

individuals.

H4/H4 individuals = p² x total number of individuals = 0.513 x 234 = 120

Option 6 is the correct answer.

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C)  Up to here we know that 2pq = 0.41 and p² = 0.513

Now we need to calculate q ²

q = 0.284, then q² = 0.284² = 0.08

These are the expected frequencies if the population was in H-W equilibrium.

The expected number of individuals with each genotype are:

 H4/H4 = 0.513 x 234 = 120 individuals

 H4/H5 = 0.41 x 234 = 96 individuals

 H5/H5= 0.08 x 234 = 18 individuals

The observed number of individuals with each genotype are:

 H4/H4 = 125 individuals

 H4/H5 = 85 individuals

 H5/H5=24 individuals

X² = ∑ (Observed - Expected)²/Expected)

X² = ((125-120)²/120) + ((85 - 96)²/96) + ((24-18)²/18)

X² = 0.21 + 1.26 + 2 =

X² = 3.47

The clossest option is option 7 = 3.84. The difference might be related to decimals and rounding.

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D)  The correct answer is  1 ⇒ The whole class represents a population that is in Hardy-Weinberg equilibrium

The null hypothesis always predict that populations are in H-W equilibrium.

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E)  

 X² = 3.47

 Freedom degrees = n - 1 = 3 - 1 = 2

 Table p value: 7.82

 Significance level, 5% = 0.05

 Table value/Critical value = 5.991

5.991 > 0.347

Meaning that the difference between the observed individuals and the expected individuals is statistically  significant. Not probably to have differe by random chances. There is enough evidence to reject the null

hypothesis.

Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

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Answer:

Produces energy for the cell by respiration

Explanation:

The glucose obtained from food is broken down to pyruvic acid in the cytoplasm. This pyruvic acid is broken down into oxygen, water and energy rich ATP molecules in the Mitochondria.

Answer:

All forms of pollution pose a serious threat to biodiversity, but in particular nutrient loading, primarily of nitrogen and phosphorus, which is a major and increasing cause of biodiversity loss and ecosystem dysfunction. ... In addition, nitrogen compounds can lead to eutrophication of ecosystems.

Answer:

Pollination, the transfer of pollen from flower-to-flower in angiosperms or cone ... In angiosperms, the process of seed development begins with double ...

Missing: x3 ‎| Must include: x3

Answer:

I, II, III

Explanation:

Allosteric regulation is a common mechanism of regulation of enzyme activity, which generally involves key enzymes in metabolic pathways. Allosteric modulation occurs when a substance/molecule called 'allosteric regulator' binds to an enzyme at a site other than the enzyme's active site, thereby triggering a conformational change in the enzyme and thus affecting its activity. Moreover, covalent modifications such as phosphorylation, acetylation, methylation, etc, are also involved in the regulation of enzymatic activity in metabolic pathways. For example, phosphorylation is a type of reversible covalent modification of proteins consisting of the addition of phosphate groups at specific amino acid residues (i.e., serine, threonine, and tyrosine) by specific enzymes known as protein kinases. Phosphorylation alters the three-dimensional (3D) structure of proteins, thereby turning the substrate or cellular pathway to active and/or inactive. Finally, both transcriptional and post-transcriptional mechanisms are also able to control the expression of enzymes involved in signaling pathways. Transcriptional mechanisms are capable of limiting the amount of mRNA that is produced from a given gene (in this case, an enzyme encoding gene), whereas post-transcriptional mechanisms such as, for example, RNA interference pathways, control the translation of messenger RNA (mRNA) molecules into proteins.

Answer:

OAmalOHopeO

Plants have multicellular haploid and multicellular diploid stages in their life cycle.

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Answer: The MSDS lists the hazardous ingredients of a product, its physical and chemical characteristics (e.g. flammability, explosive properties), its effect on human health, the chemicals with which it can adversely react, handling precautions, the types of measures that can be used to control exposure

Explanation:

Answer: Touch.

Explanation:

Cilia are short, mobile prolongations which contain a central structure made up of microtubules and proteins, enveloped by the cytosol and the plasma membrane. They are involved in cell movement, transport of materials, displacement of fluids, among others. Cilia are important for many biological processes, such as the senses of taste, hearing, smell, sight and balance.

For example, each taste bud of the tongue is made up of a set of cells, among which are the taste cells that have cilia that come into contact with the substances dissolved in the mouth by saliva. As for the sense of hearing, when there is a sound, the endolymph in the cochlea moves and this stimulates the cilia of the internal sensitive cells, which communicate with the acoustic nerve that informs the brain of what the sound is like. In the sense of smell, the receptors are the olfactory cilia of the olfactory neurons, which are located in the mucosa of the upper portion of the nostril, above the level of the superior concha. In the sense of vision, cones and rods are the two types of photoreceptor cells that capture light energy and convert it into electrical signals. They are highly specialized cells and can be differentiated into several regions: an outer segment, an inner segment containing the nucleus and a synaptic terminal. The outer segments are modified cilia and consist of flattened membranous sacs or disks.  As for the balance system, the vestibular system consists of the utricle and the saccule, which are chamber-shaped organs filled with endolymph. The maculae of the saccule are located in a vertical plane and effectively capture the accelerations of the upward and downward movements of the head, and therefore of the gravitational forces. The hair cells of the maculae are responsible for transforming the mechanical energy produced by movement into nerve signals. The activity of these cells is determined by their morphofunctional polarization or ciliary organization, which is different in the utricle and in the saccule.

Thus, the only sense that does not depend on cilia to transmit stimuli is touch. The skin contains nerve endings, as well as glands, blood vessels and hair follicles. These nerve endings detect pain, touch, pressure and temperature.

Answer:

loss of biodiversity

Explanation:

Biodiversity- refers to the variety of life on Earth at all its levels, from genes to ecosystems, and can encompass the evolutionary, ecological, and cultural processes that sustain life.

loss in biodiversity affect food chains greatly

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Answer:

polar covalent bond

Explanation:

Answer:

The definition of stroke volume is the volume of blood pumped out of the left ventricle of the heart during each systolic cardiac contraction.

Explanation:

The stroke volume is the volume of blood pumped from the left ventricle per beat. It is calculated by using the measurements of ventricle volume from echocardiogram and subtracting the end systolic volume from end diastolic volume.

Answer:

Stroke volume is the volume of blood pumped out of the left ventricle of the heart during each systolic cardiac contraction

Explanation:

The left ventricle is one of the four chambers in the heart that pumps blood full of oxygen to the body.  Stroke volume is basically how much blood pumps out of it per beat.

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Answer:

The fruiting body is curved to improve absorption of water, while the hyphae are long to allow for reproduction.May 12, 2020

Explanation:

If it helps you mark me as a brainleast

Answer:

Explanation:

d

Answer:

absorbs water is a function of the integumentary system. hope it help you.

A function of the integumentary system is to grow new tissues. Thus, the correct option B.

The integumentary system may be defined as a unique type of system that primarily consists of the skin, hair, nails, and exocrine glands. It is the set of organs that construct an outermost layer of an animal or human body.

The integumentary system plays a significant role in the growth of new tissues within the body. The cells of the skin generally hold the mechanism of renewal or replacement of injured or damaged cells which are present on the epidermis part of a specific organ.

The integumentary system also protects the body from infections, and injuries provide defense against pathogens, etc.

Therefore, a function of the integumentary system is to grow new tissues. Thus, the correct option B.

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Positive feedback loop increases the response whereas a negative feedback loop decreases the response.

Positive feedback is the amplification of a body's response to a stimulus. For example, in childbirth, when the head of the fetus pushes up against the cervix (1) it stimulates a nerve impulse from the cervix to the brain (2).

A feedback mechanism resulting in the inhibition or the slowing down of a process.

Examples of processes that utilise negative feedback loops include homeostatic systems, such as thermoregulation (if body temperature changes, mechanisms are induced to restore normal levels), blood sugar regulation (insulin lowers blood glucose when levels are high ,glucagon raises blood glucose when levels are low).

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Explanation:

Less urine is produced this will help u

Answer:

it should be an true statement

Answer:

15%

Together, adenine and thymine compose 70% of the segment. This means that 30% of the section is composed of guanine-cytosine pairs. Since these two bases will be equal in quantity, 15% of the DNA section will be cytosine bases.

The correct description is as follows:

Nucleoside is a a compound consisting of a nitrogenous base (purine or pyrimidine) linked to a sugar e.g. adenosine.

Nucleotide is a compound consisting of a nucleoside linked to a phosphate group i.e. nucleoside + phosphate group = nucleotide

Therefore,

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Answer:

lack of oxygen in the water

Explanation:

The fish most likely died from lack of oxygen in the water. This is because fishes actually use their gills to extract and breathe in the oxygen from the water while also expelling carbon dioxide from their lungs. Similar to how humans breathe. When the water was boiled it caused the dissolved gases to be expelled, which includes oxygen. Therefore, without the necessary oxygen in the water, the fish ultimately suffocated.

Boiling the water reduce its amount of dissolved oxygen which is needed by the fish to breathe, that's why the fish died after few minutes.

Dissolved oxygen is the amount of oxygen present in the water.

The organisms live to consume dissolved oxygen to breathe.

The amount of dissolved oxygen is high in the current water like rivers than in the still water like pond.

If the amount of DO is high in the water, it causes bubble gas disease in the aquatic organisms.

If the amount of DO is low in the water than, fishes and other aquatic organism cant survive due to low oxygen level.

Thus, boiling the water reduce its amount of dissolved oxygen which is needed by the fish to breathe, that's why the fish died after few minutes.

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Answer:

Vitamins and minerals are considered essential nutrients—because acting in concert, they perform hundreds of roles in the body. They help shore up bones, heal wounds, and bolster your immune system. They also convert food into energy, and repair cellular damage.

Answer:

genes involved in the cell cycle following a mutation become oncogenes.