Determine the kinetic energy of a 600-kg roller coaster car that is moving at a speed of 18 m/s.

Answers

Answer 1

Answer:

97200 J

Explanation:

Applying,

K.E = mv²/2.................. Equation 1

Where K.E = Kinetic Energy, m = mass of the roller coaster car, v = velociety of the roller coaster car.

From the question,

Given: m = 600 kg, v = 18 m/s

Substitute these values into equation 1

K.E = (600×18²)/2

K.E = 97200 J.

Hence the kinetic energy of the car is 97200 J


Related Questions

can someone answer this please

Answers

It is copper because it is the most maleable

calculate the pressure in atm of .68 mol of H at 298K and occupying 4.5 L

Answers

Answer:

3.7 atm

General Formulas and Concepts:

Atomic Structure

Moles

Gas Laws

Ideal Gas Law: PV = nRT

P is pressureV is volumen is number of molesR is gas constantT is temperature

Explanation:

Step 1: Define

Identify variables

[Given] n = 0.68 mol H

[Given] T = 298 K

[Given] V = 4.5 L

[Given] R = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] P

Step 2: Find Pressure

Substitute in variables [Ideal Gas Law]:                                                          P(4.5 L) = (0.68 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)(298 K)Multiply [Cancel out units]:                                                                               P(4.5 L) = (0.055828 L · atm · K⁻¹)(298 K)Multiply [Cancel out units]:                                                                               P(4.5 L) = 16.6367 L · atmIsolate P [Cancel out units]:                                                                             P = 3.69705 atm

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

3.69705 atm ≈ 3.7 atm

La aparición del microscopio ha permitido la creación de nuevas áreas de estudio, tanto en la___________________________

Answers

Answer:

En la mejora de la investigación y la medicina.

Explicación:

La aparición del microscopio ha permitido la creación de nuevas áreas de estudio, tanto en la mejora de la investigación como en la medicina. La invención del microscopio nos permite crecer y desarrollarnos en el campo de la investigación y el estudio. Con este microscopio, los científicos pudieron descubrir la estructura de la célula, así como las partículas subatómicas que están presentes dentro del átomo. Gracias a este microscopio, los científicos pudieron crecer y desarrollarse en el campo de la creación de nuevos medicamentos.

will give brainliest. In the Solubility lab, sugar was the and water was the solute / solution O solution / solute solute / solvent solvent/solute​

Answers

Answer:

Sugar was the solute and water was the solvent.

Identify the total number of moles involved in the reaction
2C4H10(g) + 13 O2(g) – 10 H2O(g) + 8 CO2(g)

Answers

Answer:

33 moles

Explanation:

The given chemical reaction is 2C₄H₁₀(g) + 13 O₂(g) → 10H₂O(g) + 8CO₂(g)

The number of moles of each reactant are as follows;

Butane, C₄H₁₀ = 2 moles of (g) + 13 (g) → 10H₂O(g) + 8CO₂(g)

Oxygen gas, O₂ = 13 moles

Water, H₂O = 10 moles

Carbon dioxide, CO₂ = 8 moles

The total number of moles, n = (2 + 13 + 10 + 8) = 33

∴ The total number of moles involved in the reaction, n = 33 moles.

what two factors affect the pressure in a solid

Answers

There are four main factors that can affect the reaction rate of a chemical reaction:

Reactant concentration. Increasing the concentration of one or more reactants will often increase the rate of reaction. ...

Physical state of the reactants and surface area. ...

Temperature. ...

Presence of a catalyst.

please make me brainlist answer

How many grams of silver nitrate will be needed to produce 8.6 g of silver?

Answers

Answer:

13.5g of AgNO3 will be needed

Explanation:

Silver nitrate, AgNO3 contains 1 mole of silver, Ag, per mole of nitrate. To solve this problem we need to convert the mass of Ag to moles. Thee moles = Moles of AgNO3 we need. With the molar mass of AgNO3 we can find the needed mass:

Moles Ag-Molar mass: 107.8682g/mol-

8.6g * (1mol / 107.8682g) = 0.0797 moles Ag = Moles AgNO3

Mass AgNO3 -Molar mass: 169.87g/mol-

0.0797 moles Ag * (169.87g/mol) =

13.5g of AgNO3 will be needed

Using the periodic table, choose the more reactive nonmetal.
Br or As

Answers

Reactivity of non-metals depend on their ability to gain electrons. So, smaller is the size of a non-metal more readily it will attract electrons because then nucleus will be more closer to valence shell. ... Hence, Br is the non-metal which will be more reactive than At.

Answer:

br is more reactive than as

Magnesium is added to dilute hydrochloric acid. This makes bubbles of hydrogen and a colorless solution of magnesium chloride. Write down the name of one of the products of this reaction.

Answers

Answer:

The products are already in the question Hydrogen gas and Magnesium Chloride

Explanation:

2Mg +2HCl₂ = 2MgCl₂ + H₂ balanced equation if you need it

When any metal react with acid then salt and hydrogen gas is formed. Hydrogen gas and Magnesium Chloride are formed when Magnesium is added to dilute hydrochloric acid.

What is chemical reaction?

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

The products are Hydrogen gas and Magnesium Chloride. The balanced equation can be written as

Mg +2HCl[tex]\rightarrow[/tex] MgCl₂ + H₂

This makes bubbles of hydrogen and a colorless solution of magnesium chloride.

Therefore Hydrogen gas and Magnesium Chloride are formed when Magnesium is added to dilute hydrochloric acid.

Learn more about the chemical reactions, here:

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Do you think it matters if you
report 150 grams as 150
grams or 150.0 grams? Do
they mean the same thing?
Why or why not?

Answers

Answer:

yes I do think they mean the same thing

Explanation:

150 grams and 150 grams is the same thing and adding 0 to the end of a decimal does not change its value, you could even put 150.0000000 grams and it would still be equivalent to the other numbers

Which of these is correct?

Answers

Answer:

1.89 nol Cu(NO3)2

Explanation:

if you calculate it it will be 1.89

calculate the mass m of 6.50 moles n of kbr m

Answers

Answer:

773.51495 grams

Explanation:

1 moles KBr to grams = 119.0023 grams

6.5*119.0023 = 773.51495 grams

Porrrrrrffffffaaaaaavvvvvvooooorrrrrrr

Answers

Answer:

2.2)solido

2.3)Sólido cristalino

2.4)Sólido amorfo

PLEASE HELP

If 62.6 g of lead (II) chloride is produced, how many grams of lead (II) nitrate were reacted?

Answers

Answer: The mass of lead (II) nitrate required is 74.52 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of lead (II) chloride = 62.6 g

Molar mass of lead (II) chloride = 278.1 g/mol

Plugging values in equation 1:

[tex]\text{Moles of lead (II) chloride}=\frac{62.6g}{278.1g/mol}=0.225 mol[/tex]

The chemical equation for the reaction of lead (II) chloride and sodium nitrate follows:

[tex]Pb(NO_3)_2+2NaCl\rightarrow PbCl_2+2NaNO_3[/tex]

By the stoichiometry of the reaction:

1 mole of lead (II) chloride is produced from 1 mole of lead (II) nitrate

Then, 0.225 moles of lead (II) chloride will react with = [tex]\frac{1}{1}\times 0.225=0.225mol[/tex] of lead(II) nitrate

Molar mass of lead (II) nitrate = 331.2 g/mol

Plugging values in equation 1:

[tex]\text{Mass of lead (II) nitrate}=(0.225mol\times 331.2g/mol)=74.52g[/tex]

Hence, the mass of lead (II) nitrate required is 74.52 g

Vinegar, which contains acetic acid, is used in foods and has few safety concerns​. Hydrochloric acid is used in chemistry labs and requires the use of safety goggles and gloves. Why do the safety concerns for these two acids differ? 2 ... Acetic acid is a weak acid, and hydrochloric acid is a strong acid.

Answers

Answer:

acid

Explanation:

Which represents a balanced nuclear equation?

1) 23/11Na ——>24/11Mg+1/1H

2) 24/11Na ——>24/12Mg+0/-1e

3) 24/13Al ——>24/12Mg+0/-1e

4) 23/12Mg ——>24/12Mg+1/0n

Answers

Answer:

The correct option is 2.

Explanation:

In a nuclear reaction balanced we have that:

1. The sum of the mass number (A) of the reactants (r) is equal to the sum of the mass number of the products (p) [tex] \Sigma A_{r} = \Sigma A_{p} [/tex]

2. The sum of the atomic number (Z) of the reactants is also equal to the sum of the atomic number of the products [tex]\Sigma Z_{r} = \Sigma A_{p}[/tex]      

So, let's evaluate each option.

1) [tex]^{23}_{11}Na \rightarrow ^{24}_{11}Mg + ^{1}_{1}H[/tex]

The mass number of the reactant is:

[tex]A_{r} = 23 [/tex]

The sum of the mass number of the products is:

[tex] A_{p} = 24 + 1 = 25 [/tex]

This is not the correct option because it does not meet the first condition ([tex] \Sigma A_{r} = \Sigma A_{p}[/tex]).

2) [tex]^{24}_{11}Na \rightarrow ^{24}_{12}Mg + ^{0}_{-1}e[/tex]  

The mass number of the reactant and the products is:

[tex]A_{r} = 24 [/tex]

[tex] A_{p} = 24 + 0 = 24 [/tex]

Now, the atomic number of the reactants and the products are:

[tex]Z_{r} = 11 [/tex]

[tex] Z_{p} = 12 + (-1) = 11 [/tex]      

This nuclear reaction is balanced since it does meet the two conditions for a balanced nuclear equation, ([tex] \Sigma A_{r} = \Sigma A_{p}[/tex] and [tex] \Sigma Z_{r} = \Sigma Z_{p}[/tex]).  

3) [tex]^{24}_{13}Al \rightarrow ^{24}_{12}Mg + ^{0}_{-1}e[/tex]      

The mass number of the reactant and the products is:

[tex]A_{r} = 24 [/tex]

[tex] A_{p} = 24 + 0 = 24 [/tex]

Now, the atomic number of the reactants and the products are:

[tex]Z_{r} = 13 [/tex]

[tex] Z_{p} = 12 + (-1) = 11 [/tex]      

This reaction does not meet the second condition ([tex] \Sigma Z_{r} = \Sigma Z_{p}[/tex]) so this is not a balanced nuclear equation.

4) [tex]^{23}_{12}Mg \rightarrow ^{24}_{12}Mg + ^{1}_{0}n[/tex]

The mass number of the reactant and the products is:

[tex]A_{r} = 23 [/tex]

[tex] A_{p} = 24 + 1 = 25 [/tex]  

This reaction is not a balanced nuclear equation since it does not meet the first condition ([tex] \Sigma A_{r} = \Sigma A_{p}[/tex]).

Therefore, the correct option is 2.

I hope it helps you!

helo in this please I'm so kunfused ​

Answers

OPTION C is the correct answer.

In explosive combustion the rapid expansion of --------------- causes explosion and the production of ------------------

Answers

Answer:

Volume; high temperature and pressure

Explanation:

In an explosive combustion the rapid expansion of the volume causes explosion and the production of high temperature and pressure.

The substance is usually in a confined place and the expansion usually reaches a breaking point in which it is expelled from the space usually accompanied with a loud noise and high amount of temperature and pressure change thereby releasing its gas constituents.

If you have 3 moles of a gas at a pressure of 2.5 atm and a volume of 8 liters, what is the temperature?
a. 57.86 K
b. 0.81 K
c. 25 K
d. 81.26 K

Answers

Answer:

d

Explanation:

pv=nrt

2.5×1.01×10^5×8×10^-3=3×8.31×T

T=

The value of the temperature can be determined by ideal gas law and the temperature will be 0.81 K.

What is temperature ?

The average kinetic energy of particular atoms and molecules in a system is measured by the temperature.

What is ideal gas Law?

Ideal gas law explain the relationship between pressure. temperature and volume.

Ideal gas law can be expressed as, PV=nRT.

where, P is pressure. V is volume , n is number of moles ,R is gas constant and T is temperature. It is given that, n= 3 mole, P = 2.5 atm, V = 8 L, T=?, R = 8.31.

Calculation of temperature by using ideal gas law is shown as:

Now, put the values of given data in ideal gas law equation.

T = PV/nR

=2.5×8/3×8.32

= 0.81 K

Therefore, the temperature will be 0.81K.

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Adding a catalyst to a system at equilibrium lowers the activation energy required by a system, which system, which shifts the equilibrium position toward the products.

True or false?

Answers

Answer: False

Explanation: Took the test

Answer:

False

Explanation:

Fossil fuels are considered to be:
a.
irreplaceable resources
c.
renewable resources
b.
nonrenewable resources
d.
hazardous wastes


Please select the best answer from the choices provided

A
B
C
D

Answers

A irreplaceable resources

If you add 25.0 mL of water to 125 mL of a 0.150 M LiOH solution, what will be the molarity of the resulting diluted solution? 0.0450 M LiOH 0.0647 M LiOH 0.125 M LiOH 0.134 M LiOH

Answers

Answer:

solute in a fixed volume of solution

Concentration(c) = number of moles of solute(n) / volume of solution (v)

25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.

original solution molarity - 0.150 M

number of moles of LiOH in 1 L - 0.150 mol

number of LiOH moles in 0.125 L - 0.150 mol/ L x 0.125 L = 0.01875 mol

when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases

new volume - 125 mL + 25 mL = 150 mL

therefore new molarity is

c = 0.01875 mol / 0.150 L = 0.125 M

answer is 0.125 M

Explanation:

did this answer got right

Answer:

0.125

Explanation:

Just completed the test and got it correct.

If a student has 125 mL of a 4.00 M CuSO4 solution and needs a 1.50 M solution, what volume do they need to dilute it to?

Answers

Answer:

333.3mL

Explanation:

Using the formula as follows:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information provided in this question,

C1 = 4.00M

C2 = 1.50M

V1 = 125mL

V2 = ?

Using C1V1 = C2V2

4 × 125 = 1.5 × V2

500 = 1.5V2

V2 = 500/1.5

V2 = 333.3mL

Therefore, the CuSO4 solution needs to be diluted to 333.3mL to make 1.50 M solution.

Heterogéneo de tres fases y un componente.

Answers

Un sistema heterogéneo de 3 fases y 1 componente puede ser:



Sólido (hielo)
Líquido (agua)
Gaseoso (vapor)

3 upper M n upper O subscript 2 (s) plus 4 upper A l (s) right arrow 2 upper A l subscript 2 upper O subscript 3 (g) plus 3 upper M n (s). What is the enthalpy of the reaction?

Answers

Answer: The enthalpy of the reaction is -1791.31 kJ.

Explanation:

Enthalpy change is the difference between the enthalpies of products and the enthalpies of reactants each multiplied by its stoichiometric coefficients. It is represented by the symbol [tex]Delta H^o_{rxn}[/tex]

[tex]\Delta H^o_{rxn}=\sum (n \times \Delta H^o_{products})-\sum (n \times \Delta H^o_{reactants})[/tex]        .....(1)

For the given chemical reaction:

[tex]3MnO_2(s)+4Al(s)\rightarrow 2Al_2O_3(s)+3Mn(s)[/tex]

The expression for the enthalpy change of the reaction will be:

[tex]\Delta H^o_{rxn}=[(2 \times \Delta H^o_f_{(Al_2O_3(s))}) + (3 \times \Delta H^o_f_{(Mn(s))})] - [(3 \times  \Delta H^o_f_{(MnO_2(s))}) + (4 \times \Delta H^o_f_{(Al(s))})][/tex]

Taking the standard heat of formation values:

[tex]\Delta H^o_f_{(Al_2O_3(s))}=-1675.7kJ/mol\\\Delta H^o_f_{(Al(s))}=0kJ/mol\\\Delta H^o_f_{(MnO_2(s))}=-520.03kJ/mol\\\Delta H^o_f_{(Mn(s))}=0kJ/mol[/tex]

Plugging values in the above expression:

[tex]\Delta H^o_{rxn}=[(2 \times (-1675.7))+(3 \times 0)] - [(3 \times (-520.03))+(4 \times 0)]\\\\\Delta H^o_{rxn}=-1791.31 kJ[/tex]

Hence, the enthalpy of the reaction is -1791.31 kJ.

The table shows the specific heat of four substances—brick, dry soil, paper, and water. If all four substances were exposed to sunlight for the same amount of time, which substance would heat up the fastest?

Answers

Answer:

Brick

Explanation:

.................

1. What is the volume of 4.00g of aluminum at STP?

Answers

Answer:

22.4cm³

Explanation:

Avogadro's law shows that Avogadro's volume is 22.4

A chemist has three different acid solutions. The first acid solution contains 15 % 15% acid, the second contains 35 % 35% and the third contains 80 % 80% . They want to use all three solutions to obtain a mixture of 190 190 liters containing 30 % 30% acid, using 2 2 times as much of the 80 % 80% solution as the 35 % 35% solution. How many liters of each solution should be used

Answers

Answer:

First solution = 133L

Second solution = 19L

Third solution = 38L

Explanation:

As we want to make 190L of a 30%=0.3 solution we can write:

190L*0.3 = a*0.15 + b*0.35 + c*0.80

Where a, b and c are the volume of first, second and third acid solutions, respectively.

The volume of c is twice volume of b:

c = 2b

And the volume of the 3 solutions is equal to 190L:

190L = a+b+c

190L = a+3b

190L*0.3 = (190-3b)*0.15 + b*0.35 + 2b*0.80

57 = 28.5-0.45b+0.35b+1.6b

28.5 = 1.5b

b = 19L

c = 2*19L

c = 38L

a = 190L - 19L - 38L

a = 133L

A circuit is set up with two parallel resistors, each of a resistance of 250Ω.
b. If another resistor of resistance 300Ω is added in series with these two parallel resistors, what is the total
resistance?
c. If a voltage of 120V is put across the circuit in b, what will the current be in the circuit?

Answers

Answer:

425 and 0.28A

Explanation:

Resistance for resistors in parallel

1/ R = 1/250 +1/250

=0.008

R = 1/ 0.008 = 125

Total resistance

R= 125+ 300

=425

...

V= IR

I= V/R

I = 120/425

= 0.28 A

2P(s) + X(g) ↔ P2X(g) at 20°C, Keq= 4.0 Initially, 2.0 moles of P(s) and 1.0 mole of X(g) are put into a 1.0L flask and allowed to react until they reach equilibrium. The molarity of P2X (g) present at equilibrium is: a. 1.0 M b. 0.8 M c. 0.4 M d. 0.1 M

Answers

Answer:

b. 0.8 M

Explanation:

Based on the reaction, Keq is defined as:

Keq = 4.0 = [P2X] / [X]

As P is a pure solid, its concentration is not taken into account

The initial concentration of X is 1.0mol/L = 1M, the equilibrium concentrations are:

[X] = 1M - X

[P2X] = X

Where X is the reaction coordinate

Replacing:

4.0 = X / 1-X

4.0 - 4.0X = X

4.0 = 5.0X

0.8M = X = [P2X]

Right answer is:

b. 0.8 M
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