Answer:
Step-by-step explanation:
Given that:
[tex]P = \left[\begin{array}{ccc}0.22&0.20&0.65\\0.62&0.60&0.15\\0.16&0.20&0.20\end{array}\right][/tex]
For a steady-state of a given matrix [tex]\bar X[/tex]
[tex]\bar X = \left[\begin{array}{c}a\\b\\c\end{array}\right][/tex]
As a result P[tex]\bar X[/tex] = [tex]\bar X[/tex] and a+b+c must be equal to 1
So, if P[tex]\bar X[/tex] = [tex]\bar X[/tex]
Then;
[tex]P = \left[\begin{array}{ccc}0.22&0.20&0.65\\0.62&0.60&0.15\\0.16&0.20&0.20\end{array}\right]\left[\begin{array}{c}a\\b\\c\end{array}\right] =\left[\begin{array}{c}a\\b\\c\end{array}\right][/tex]
[tex]\implies \left\begin{array}{ccc}0.22a+&0.20b+&0.65c\\0.62a+&0.60b+&0.15c\\0.16a+&0.20b+&0.20c\end{array} \right = \left \begin{array}{c}a ---(1)\\b---(2)\\c---(3)\end{array}\right[/tex]
Equating both equation (1) and (3)
(0.22a+ 0.2b + 0.65c) - (0.16a + 0.2b + 0.2c) = a - c
0.06a + 0.45c = a - c
collect like terms
0.06a - a = -c - 0.45c
-0.94 a = -1.45 c
0.94 a = 1.45 c
[tex]c =\dfrac{ 0.94}{1.45}a[/tex]
[tex]c =\dfrac{ 94}{145}a --- (4)[/tex]
Using equation (2)
0.62a + 0.60b + 0.15c = b
where;
c = 94/145 a
[tex]0.62a + 0.60b + 0.15(\dfrac{94}{145}) a= b[/tex]
[tex]0.62a + 0.15(\dfrac{94}{145}) a= -0.60b+b[/tex]
[tex]0.62a + (\dfrac{141}{1450}) a= 0.40b[/tex]
[tex](0.62+\dfrac{141}{1450}) a= 0.40b[/tex]
[tex](\dfrac{62}{100}+\dfrac{141}{1450}) a= 0.40b[/tex]
[tex](\dfrac{1043}{1450})a= 0.40b[/tex]
[tex](\dfrac{1043}{1450})a= \dfrac{4}{10} b[/tex]
[tex](\dfrac{1043 \times 10}{1450 \times 4})a = \dfrac{4}{10} \times \dfrac{10}{4}[/tex]
[tex]b = (\dfrac{1043}{580}) a --- (5)[/tex]
From a + b + c = 1
[tex]a + \dfrac{1043}{580}a + \dfrac{94}{145} a = 1[/tex]
[tex]a + \dfrac{1043}{580}a + \dfrac{94*4}{145*4} a = 1[/tex]
[tex]a + \dfrac{1043}{580}a + \dfrac{376}{580} a = 1[/tex]
[tex]\dfrac{580+ 1043+376 }{580} a= 1[/tex]
[tex]\dfrac{1999}{580} a= 1[/tex]
[tex]a = \dfrac{580}{1999}[/tex]
∴
[tex]b = \dfrac{1043}{580} \times \dfrac{580}{1999}[/tex]
[tex]b = \dfrac{1043}{1999}[/tex]
[tex]c = \dfrac{94}{145} \times \dfrac{580}{1999}[/tex]
[tex]c= \dfrac{376}{1999}[/tex]
∴
The steady matrix of [tex]\bar X[/tex] is:
[tex]\bar X = \left[\begin{array}{c}\dfrac{580}{1999} \\ \\ \dfrac{1043}{1999}\\ \\ \dfrac{376}{1999}\end{array}\right][/tex]
Find the equation of a line with a slope of −1/2 that passes through the point −4, 10
Answer:
y - 10 = -1/2(x + 4)
General Formulas and Concepts:
Algebra I
Coordinates (x, y)
Point-Slope Form: y - y₁ = m(x - x₁)
x₁ - x coordinate y₁ - y coordinate m - slopeStep-by-step explanation:
Step 1: Define
Identify variables
m = -1/2
Point (-4, 10) → x₁ = -4, y₁ = 10
Step 2: Find
Substitute in variables [Point-Slope Form]: y - 10 = -1/2(x - -4)Simplify: y - 10 = -1/2(x + 4)Answer: [tex]y=-\frac{1}{2} x+8[/tex]
Step-by-step explanation:
An equation of a line can be in slope intercept form which is y=mx+b
m is the slope, b is the y intercept, x it the x coordinate, and y is the y coordinate. Since we know the slope is -1/2 and we know a x coordinate is -4 and a y coordinate is 10 we can sub them in and solve for the value of b.
[tex]y=mx+b\\10=(-\frac{1}{2})(-4)+b\\10=2+b\\10-2=2+b-2\\8=b[/tex]
The value of b is 8. We can now sub it in for our equation of the line. This time with x and y as variables.
y=-1/2x+8
use the following picture to classify the following statements as true or false
PLEASE HELP ME I HAVE TO PASS THIS TEST
30 POINTS
Answer:
Hi, there the answer is
These are the equations with exactly one solution
-5x + 12 = –12x – 12
-5x + 12 = 5x + 12
-5x + 12 = 5x – 5
Hope This Helps :)
Step-by-step explanation:
First degree equations
A first degree equation has the form
ax + b = 0
There are some special cases where the equation can have one, infinitely many or no solution
If , the equation has exactly one solution
If a=0 and b=0 the equation has infinitely many solutions, because it doesn't matter the value of x, it will always be true that 0=0
If a=0 and the equation has no solution, because it will be equivalent to b=0 and we are saying it's not true. No matter what x is, it's a false statement.
We have been given some equations, we only need to put them in standard form
-5x + 12 = –12x – 12
Rearranging
7x + 24 = 0
It has exactly one solution because a is not zero
.......................
-5x + 12 = 5x + 12
Rearranging
-10x + 0 = 0
It has exactly one solution because a is not zero
.......................
-5x + 12 = 5x – 5
Rearranging
-10x + 17 = 0
It has exactly one solution because a is not zero
.......................
-5x + 12 = -5x – 12
Rearranging
0x + 24 = 0
It has no solution, no matter what the value of x is, it's impossible that 24=0
Answer: These are the equations with exactly one solution
-5x + 12 = –12x – 12
-5x + 12 = 5x + 12
-5x + 12 = 5x – 5
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. y2(y2 − 4) = x2(x2 − 5) (0, −2) (devil's curve)
Answer:
Step-by-step explanation:
Given that:
[tex]y^2 (y^2-4) = x^2(x^2 -5)[/tex]
at point (0, -2)
[tex]\implies y^4 -4y^2 = x^4 -5x^2[/tex]
Taking the differential from the equation above with respect to x;
[tex]4y^3 \dfrac{dy}{dx}-8y \dfrac{dy}{dx}= 4x^3 -10x[/tex]
Collect like terms
[tex](4y^3 -8y)\dfrac{dy}{dx}= 4x^3 -10x[/tex]
[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]
Hence, the slope of the tangent line m can be said to be:
[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]
At point (0,-2)
[tex]\dfrac{dy}{dx}= \dfrac{4(0)^3 -10(0)}{4(-2)^3-8-(2)}[/tex]
[tex]\dfrac{dy}{dx}= \dfrac{0 -0}{4(-8)+16}[/tex]
[tex]\dfrac{dy}{dx}= 0[/tex]
m = 0
So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:
(y - y₁ = m(x - x₁))
y + 2 = 0(x - 0)
y + 2 = 0
y = -2
What’s the value of X????
X Y
-10 2
-15 3
-25 5
Determine whether y varies directly with x. If so, find the constant of variation and write the equation
Answer:
x = -5y
Step-by-step explanation:
x = ay
-10 = 2a
a = -5
x = ay
-15 = 3a
a = -5
x = ay
-25 = 5a
a = -5
Prove the formula that:
((∃x)(F(x)∧S(x))→(∀y)(M(y)→W(y)))∧((∃y)(M(y)∧¬W(y)))
⇒(∀x)(F(x)→¬S(x))
Step-by-step explanation:
Given: [∀x(L(x) → A(x))] →
[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]
To prove, we shall follow a proof by contradiction. We shall include the negation of the conclusion for
arguments. Since with just premise, deriving the conclusion is not possible, we have chosen this proof
technique.
Consider ∀x(L(x) → A(x)) ∧ ¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]
We need to show that the above expression is unsatisfiable (False).
¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]
∃x¬((L(x) ∧ ∃y(L(y) ∧ H(x, y))) → ∃y(A(y) ∧ H(x, y)))
∃x((L(x) ∧ ∃y(L(y) ∧ H(x, y))) ∧ ¬(∃y(A(y) ∧ H(x, y))))
E.I with respect to x,
(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ ¬(∃y(A(y) ∧ H(a, y))), for some a
(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ (∀y(¬A(y) ∧ ¬H(a, y)))
E.I with respect to y,
(L(a) ∧ (L(b) ∧ H(a, b))) ∧ (∀y(¬A(y) ∧ ¬H(a, y))), for some b
U.I with respect to y,
(L(a) ∧ (L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b
Since P ∧ Q is P, drop L(a) from the above expression.
(L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b
Apply distribution
(L(b) ∧ H(a, b) ∧ ¬A(b)) ∨ (L(b) ∧ H(a, b) ∧ ¬H(a, b))
Note: P ∧ ¬P is false. P ∧ f alse is P. Therefore, the above expression is simplified to
(L(b) ∧ H(a, b) ∧ ¬A(b))
U.I of ∀x(L(x) → A(x)) gives L(b) → A(b). The contrapositive of this is ¬A(b) → ¬L(b). Replace
¬A(b) in the above expression with ¬L(b). Thus, we get,
(L(b) ∧ H(a, b) ∧ ¬L(b)), this is again false.
This shows that our assumption that the conclusion is false is wrong. Therefore, the conclusion follows
from the premise.
15
Sum of 5x^2+2x and 4-x^2
Answer:
4x^2 + 2x + 4
Step-by-step explanation:
5x^2 + 2x + 4 - x^2
4x^2 + 2x + 4
Answer:
2(2x^2 + x + 2)
Step-by-step explanation:
5x^2+2x + 4-x^2
Re arrange so like terms are next to each other
Keep the same symbol that is at the front of the term when moving it
5x^2 - x^2 + 2x + 4
We will just do the first part first
5x^2 - x^2
5x^2 - 1x^2 (is the same thing as above)
So because they are like terms (are both x^2)
We can just minus 1 from 5
5-1=4
So 4x^2
Now the equation is
4x^2 + 2x + 4
This is as small as it gets but you can also bring it to this
4, 2 and 4 all are divisible by 2 so
2(2x^2 + x + 2)
Which inequality represents all numbers x on a number line that are farther from −8 than from −4?
Answer:
x - 8>-4-x
Step-by-step explanation:
Looking at x - 8>-4-x
Collect the like terms;
x+x > -4 + 8
2x < 4
x > 4/2
x < 2
Since the values of x are greater than 2,this shows that they are positive values and will be farther from -8 than -4
Which pair of expressions below are equivalent?
a. 7(2n) and 9
b. 3n + 5n and 15n
c. 4(2n-6) and 8n - 24
d. 7(2n) and 72n
Answer:
The answer is C
Hope this helped!
simplify the expression (2r^4y4xy^2) completely
Step-by-step explanation:
we can simplify the stuff inside the parentheses to
[tex] \frac{ {x}^{3} }{2y} [/tex]
now we need to multiply it with itself, giving us
[tex] \frac{ {x}^{6} }{4 {y}^{2} } [/tex]
so yeah, D is the correct answer
[tex]4 \sqrt{(3x}^{3} [/tex]
write in exponential form
Answer:
[tex]4(3x)^{\frac{3}{2} }[/tex]
Step-by-step explanation:
Find all real zeros of the function y = -7x + 8
9514 1404 393
Answer:
x = 8/7
Step-by-step explanation:
The only real zero of this linear function is the value of x that makes y=0:
0 = -7x +8
7x = 8 . . . . . . add 7x
x = 8/7 . . . . . .divide by 7
If anyone can do this for me step by step i will give you 30 points please help me out
Answer:
after 10 months
Step-by-step explanation:
Let x be the number of months and y be the amount they still owe.
Sin Ian borrows $1000 from his parents, then the y-intercept b= 1000 since he owes $1000 when x = 0. He pays them back $60 each month The slope is then m = -60 . Substituting in b = 1000 and m = -60 into the slope-intercept form of a line then gives y= mx + b=-60x +1000.
Sin Ken borrows $600 from his parents, then the y-intercept b = 600 since he owes $600 When x= 0. He pays them back $20 per month so the amount he owes decreases $20 each month. The slope is then m = -20 . Substituting in
b= 600 and m = -20 into the slope-intercept form then gives y = mx +b = -20x + 600.
They will owe the same amount when they have the same y-coordinate. Therefore -60x+ 1000= y= -20x+600. Solve this equation for x:
-60x+ 1000 = -20x+ 600
1000 = 40x+ 600
400 = 40x
10=x
They will then owe the same amount after 10 months.
find the value of tanA when tan(A-45)=1÷3)
Answer:
63.44degrees
Step-by-step explanation:
Given that;
tan(A-45) = 1/3
A-45 = arctan(1/3)
A - 45 = 18.44
A = 18.44+45
A = 63.44degrees
Hence the value of A is 63.44degrees
What is the common ratio for the geometric sequence below, written as a fraction?
768, 480, 300, 187.5, …
/
9514 1404 393
Answer:
5/8
Step-by-step explanation:
Since the ratio is common, it can be found from the ratio of any pair of adjacent terms.
r = 480/768 = (5·96)/(8·96) = 5/8
The common ratio is 5/8.
which will result in a perfect square trimonial
Answer:
No choices listed.
Step-by-step explanation:
Find the surface area of each solid figure
Answer:
First find the SA of the triangular figure
4 x 3 = 12 cm^2 (the triangles on the sides)
2 x 3 = 6 cm^2 (the back square)
2 x 5 = 10 cm^2 (the slanted square)
*I'm not sure if this question includes the bottom of the triangle but here it is anyways
4 x 2 = 8 cm^2
Including the bottom the SA of the triangular figure is:
12 + 6 + 10 + 8 = 36 cm^2
Find the SA of the rectangular shape
4 x 2 = 8 cm^2 (the bottom square)
2 x 6 = 12 x 2 = 24 cm^2 (the sides)
4 x 6 = 24 x 2 = 48 cm^2 (the front and back)
Add them up
8 + 24 + 48 = 80 cm^2
If you wanted to find the SA of the whole figure it would be:
12 + 6 + 10 + 8 + 24 + 48 = 108 cm^2
Hope this helps!
A technical machinist is asked to build a cubical steel tank that will hold of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest .
Answer:
The smallest possible length is 0.83m
Step-by-step explanation:
Given
[tex]Volume = 565L[/tex]
Required
The smallest length of the tank
Since the tank is cubical, then the volume is:
[tex]Volume = Length^3[/tex]
This gives:
[tex]565L= Length^3[/tex]
Express as [tex]m^3[/tex]
[tex]\frac{565m^3}{1000} = Length^3[/tex]
[tex]0.565m^3 = Length^3[/tex]
Take cube roots of both sides
[tex]0.8267m = Length[/tex]
Rewrite as:
[tex]Length = 0.8267m[/tex]
Approximate
[tex]Length = 0.83m[/tex]
Simplify Expressions. Which expression is
equivalent to 5x - 2 + 2x - 6
7X-8
3X-8
7x - 4
3X - 4
Answer:
7x - 8
Step-by-step explanation:
Hope this helps!
Solve for X in the triangle. Round your answer to the nearest tenth
Answer:
[tex]\displaystyle x \approx 9.9[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityTrigonometry
[Right Triangles Only] SOHCAHTOA[Right Triangles Only] sinθ = opposite over hypotenuseStep-by-step explanation:
Step 1: Define
Identify variables
Angle θ = 64°
Opposite Leg = x
Hypotenuse = 11
Step 2: Solve for x
Substitute in variables [sine]: [tex]\displaystyle sin(64^\circ) = \frac{x}{11}[/tex][Multiplication Property of Equality] Multiply 11 on both sides: [tex]\displaystyle 11sin(64^\circ) = x[/tex]Rewrite: [tex]\displaystyle x = 11sin(64^\circ)[/tex]Evaluate: [tex]\displaystyle x = 9.88673[/tex]Round: [tex]\displaystyle x \approx 9.9[/tex]Which points are on the graph of the function rule f(x) = 10 - 4x
determine the missing angle.
The area of a square is64. Cm
What is the length of its side
Answer:
The length is 8 cm. Since its a square, so the length of both its sides are equal.
l^2=64
where l=length of side
square root both sides
then, l=8
Answer:
8cm is the length of its side.
Step-by-step explanation:
Which state ment is true regarding the graphed function
F(4)= g(4)
F(4)= g(-2)
F(2)= g(-2)
F(-2)= g(-2)
Answer:
F(-2)= g(-2)
Step-by-step explanation:
F(-2)= g(-2), both function have the same points of intersect.
Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/3
O y + 2 =1/3(x + 3)
O y-2=1/3(x-3)
O y + 3 = 1/3(x+ 2)
O y-3= 1/3(x-2)
Answer:
y - 2 = 1/3(x - 3)
Step-by-step explanation:
Point slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.
Plug in the slope:
y - y1 = m(x - x1)
y - y1 = 1/3(x - x1)
Plug in the given point:
y - y1 = 1/3(x - x1)
y - 2 = 1/3(x - 3)
So, the correct answer is y - 2 = 1/3(x - 3)
HELPPPPOOOPPPPOPPPPPPPP
Answer:
Your answer would be B
Step-by-step explanation:
So right away you can get rid of a and d since they are positive numbers, there is no positive numbers in the graph were the line is.
So we know that the y-intercept is -2 (as you can see the line pass through (0,-2))
And we know the y intercept is -8 (since the line pass through (-8,0))
so you are left with b and c, c is incorrect because the -2 goes through the y-intercept not the x.
The right choice is b, it states that the x-intercept -8 pass through the line, the y-intercept is -2
Your welcome and hoped this helped!
HELP plsssss I will GIVE YOU BRAINLYEST
Answer: B
Step-by-step explanation:
Answer:
-5ºC < 5ºC is an inequality that compares temperatures.
B is the correct answer for the multiple choice question.
PLEASE HELP! I really need to get this right
Answer:
27.3
Step-by-step explanation:
27.3
Answer:
Plays a musical instrument
Top left
Plays a sport: 0.46
Plays a musical instrument
Top right
Does not Play a sport: 0.54
Does not play a musical instrument
Bottom Left
Plays a sport: 0.73
Does not play a musical instrument
Bottom right
Does not Play a sport: 0.27
Step-by-step explanation:
I hope this helps you! :D
Ocuocktxjrxutxjxttuxudutx
Given:
The stem and leaf plot of a data set is given.
Legend:1|0 represents 10.
To find:
The original data set for the given stem and leaf plot.
Solution:
It is given that 1|0 represents 10 in the given stem and leaf plot. Using this, the original data set from the given stem and leaf plot is:
10, 11, 14, 21, 24, 24, 27, 29, 33, 35, 35, 35, 37, 38, 40, 41.
These values are in ascending order.
Therefore, the original set of data is 10, 11, 14, 21, 24, 24, 27, 29, 33, 35, 35, 35, 37, 38, 40, 41.
