Different nutrients play different roles in our bodies. Which is the energy-storing nutrient?
O carbohydrates
O minerals
O proteins
O fats

Answers

Answer 1

Answer:

D. Fats

Explanation:

they are the long term energy storing nutrient carbohydrates are a quick way for energy minerals dont contain any energy and neither do proteins

Answer 2

fats

Explanation:

it is nutrient kept in the body


Related Questions

PLEASE HEEEEEEELP
Assume that the velocity of the soda bottle falling from a height of 0.8 m will be 4 m/s. Record this velocity for each mass in Table A, and use it in calculating the predicted kinetic energy of the soda bottle for the masses of 0.125 kg, 0.250 kg, 0.375 kg, and 0.500 kg using the equation: KE=1/2 mv^2 When solving for kinetic energy (KE), m is mass, and v is the speed (or velocity).

Answers

[tex]\large{\underbrace{\underline{\fcolorbox{White}{pink}{\bf{ANSWER♥︎}}}}}[/tex]kinetic energy is given as

KE = (0.5) m v²

given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg

KE = (0.5) m v² = (0.5) (0.125) (4)² = 1 J

when m = 0.250 kg KE = (0.5) m v² = (0.5) (0.250) (4)² = 2 J

when m = 0.375 kg KE = (0.5) m v² = (0.5) (0.375) (4)² = 3 J

when m = 0.0.500 kg KE = (0.5) m v² = (0.5) (0.500) (4)² = 4 J

The direction equivalent to {40° W of S} is:
A. 40 ° E of S
B. 40° W of N
C. 40° E of N
D. 50° S of W
E. 50° E of N

Answers

Answer:

c

Explanation:

Drag each label to the correct location on the image. Identify the particles and characteristics on this model of an atom.
Positively charged
Electron
Proton
Neutron
Negatively charged

Answers

Answer:

cant see picture

Explanation:

Answer:

please add picture so i can help you

Explanation:


A steel ball is released just below the surface of thick oil in a cylinder.
During the first few centimetres of travel, what is the acceleration of the ball?
A constant and equal to 10 m / s2
B constant but less than 10 m / s2
C decreasing
D increasing

Answers

Answer:

Increasing

Explanation:

I Hope it Helps

Example to measure the interval of time of a small stone dropped from 1m height.

Answers

Answer:

The time required is 0.45 s.

Explanation:

Height, h = 1 m

initial velocity, u = m/s

Let the time is t.

Use second equation of motion

[tex]h = u t + 0.5 at^2\\\\1 = 0 +0.5 \times 9.8 \times t^2\\\\t = 0.45 s[/tex]

what will be the magnitude of work if a force of 25N pulls a stone through a distance of 5m in its direction?​

Answers

Explanation:

125 is your answer........

What is the volume of a cone with a height of 27 cm
and a radius of 13 cm? Round your answer to the
nearest tenth.
Use the button on your calculator to complete this
problem.
V =
cm?

Answers

Explanation:

Volume of cone = πr² × h/3

Here,

Radius (r) = 13 cmHeight (h) = 27 cm

→ Volume of cone = π(13)² × 27/3 cm³

→ Volume of cone = 169π × 9 cm³

→ Volume of cone = 1521π cm³

→ Volume of cone = 1521 × 22/7 cm³

→ Volume of cone = 33462/7 cm³

→ Volume of cone = 4780.28 cm³

Answer:

4,778.4 is correct

Explanation:

What does the m stand for in the enthalpy equation?

Answers

Answer:

Use the formula ∆H = m x s x ∆T to solve.

Explanation:

Once you have m, the mass of your reactants, s, the specific heat of your product, and ∆T, the temperature change from your reaction, you are prepared to find the enthalpy of reaction. Simply plug your values into the formula ∆H = m x s x ∆T and multiply to solve.

satellite does not need any energy to revolve around the earth why​

Answers

Answer:

An artificial satellites revolves around the earth under the influence of its gravitational force. So it does not require any energy to revolve around energy.

or maybe god:)))(

Why are simple everyday actions considered
thermodynamic reactions?

they transform energy

they destroy energy

they create energy

Answers

they create energy ……………….

Answer:

They transform energy

Explanation:

thermodynamics deals with transfers of energy from one place to another and from one form to another and it's also deal with the relationship between heat and other forms of energy

If the electric force between two charges is 4.2 × 10-2 N, what would the new force be if the distance between the charges is doubled and the charge on one of the charges is tripled?

Answers

Answer:

New force = 0.063 N

Explanation:

Given that,

The electric force between two charges is[tex]4.2\times 10^{-2}\ N[/tex]

The formula for the electric force is:

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

If the distance between the charges is doubled, r' = 2r and one of the charges is tripled, q₁' = 2q₁, q₂' = 3q₂

Put all the values,

[tex]F'=\dfrac{kq_1'q_2'}{r'^2}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{kq_1q_2}{r^2}}{\dfrac{kq_1'q_2'}{r'^2}}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{q_1\times q_2}{r^2}}{\dfrac{2q_1\times 3q_2}{(2r)^2}}\\\\\dfrac{F}{F'}=\dfrac{4}{6}=\dfrac{2}{3}\\\\F'=\dfrac{3\times 4.2\times 10^{-2}}{2}\\\\F'=0.063\ N[/tex]

So, the new force is 0.063 N.

Answer:

The force becomes 0.0315 N.

Explanation:

Force, F = 4.2 x 10^-2 N

When the distance is doubled, a charge is tripled, Let the force is F'.

The force between the two charges is

[tex]F = \frac{K qq'}{r^2}\\[/tex]

when, q' = 3 q' and r is 2 r so

[tex]F' = \frac{K 3qq'}{4r^2} = \frac{3 F}{4} = \frac {3\times 4.2\times 10^{-2}}{4}=0.0315 N[/tex]

A student initially 10.0 m East of his school walks 17.5 m West. The magnitude of the student's displacement, relative to the school is _________ m? The direction of the student's displacement, relative to the school is ______?

Answers

Answer:

1. 7.5 m

2. towards west side

explanation:

I hope it will help you

79. A skater glides along a circular path of radius 5.00 m in clockwise direction. When he coasts around one-half of the circle, starting from the west point, find (a) the magnitude of his displacement vector and (b) how far he actually skated. (c) What is the magnitude of his displacement vector when he skates all the way around the circle and comes back to the west point

Answers

a. 10m

b. 15.71m

c. 0m

Topics

The potential difference across a resistor increases by a factor of 4. How
does the current change? (Ohm's law: V = IR)
A it increases by a factor of 4
B it decreases by a factor of 4
C it increases by a factor of 2
D it decreases by a factor of 2

Answers

Answer:

Correct option is C it decreases by a factor of 2

Answer: A - it increases by a factor of 4

Explanation:

Ohm's law is V = IR where V = potential difference, I = current, and R = resistance. Assuming that resistance stays constant (since the question mentioned no change in resistance), we only need to look at "V" and "I" in the equation V = IR.

"V" and "I" are directly proportional. In other words, whatever change happens to "V" will also occur to "I". Since "V" increases by a factor of 4, then "I" will also increase by a factor of 4.

You could also approach this problem by plugging in a change of 4 for the potential difference in the equation: V = I*R.

If we plug in 4V for V, we now have:

4V = I*R

Since the left side increases by a factor of 4, then the right side (only looking at current in this case) will also need to increase by a factor of 4 in order to have the right side stay equal to the left. Therefore, current will also increase by a factor of 4.

Question 12 of 15
If nitrogen, which has an electronegativity of 2.0, bonds with hydrogen, which
has an electronegativity of 2.1, the bond between the two atoms will be
classified as a(n)
covalent bond.
Answer here
SUBMIT

Answers

Answer:

Covalent bond.

Explanation:

There are 4 main types of bonds:

Covalent, ionic, metallic, and hydrogen.

Covalent bond: Involves the sharing of pairs of electrons, here the difference between the electronegativity of the atoms is not too large. Covalent bonds usually form an octet of electrons.

Ionic bond: This happens because the electrostatic attraction between the atoms whit very different electronegativities

Hydrogen bond: Electrostatic attractive force between an electronegative atom and a hydrogen atom covalently bonded to another electronegative atom.

Metallic bond: Type of bond that makes the metallic atoms to stay really tightly together. The atoms bond because of the electrostatic atractive force between conduction electrons and positively charged metal ions.

Now, in this case, we have the bond between Nitrogen (electronegativity = 2.0) and Hydrogen (electronegativity = 2.1)

So we can see that:

The elements are not metals, so we can discard metallic bond.

For a hydrogen bond, we need 3 atoms (one of which is hydrogen), here we have two, so we can discard this option.

Ionic bond needs different electronegativities, here the electronegativities are really close together, so the ionic bond can be discarded.

we can conclude that the bond will be a covalent bond.

True or false: Ultimate tensile strength increases as the thickness of a solid material sample increases.

True

False

Answers

Answer:

False.

Explanation:

Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.

Answer:

Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.FALSE

what means 10² what we call this​

Answers

we call it as well as 100 . so easey

Answer:

10 squared

Explanation:

10 squared

In Depth:

Let have a square that has a side length of 10.

A square four sides are equal and if we find the area of a squared, our formula is

[tex] {s}^{2} [/tex]

Our in this instance,

[tex] {10}^{2} [/tex]

or we call it

[tex]10 \: \: squared[/tex]

Using your Periodic Table, which of the following elements below has the largest atomic radius? A.) Aluminum B.) Sodium C.) Sulfur, D.) Fluorine

Answers

Answer:

sodium

Explanation:

it is highly reactive metal.

Answer:

aluminium

Explanation:

In a period , as we go from left to right in a periodic table, atomic number increases .

Differentiating electrons enters into same shell hence the effective nuclear charge decreases .

Hence atomic radius decreases along period.

Conculsion:

Aluminium is the element which has greater atomic radius and sulphur has smaller atomic radius.

PLS HELP ME I DONT HAVE MUCH TIME LEFT
The Euler buckling load of a 160-cm-long column will be _____ times the Euler buckling load of an equivalent 120-cm-long column.


1.78


0.56


0.75


2.37


1.33


0.42

Calculate the minimum area moment of inertia for a rectangular cross-section with side lengths 3 cm and 8 cm.


201 cm4


18 cm4


128 cm4


4 cm4


24 cm4

Answers

Answer:

A certain source of 12V with an internal resistance 1colomb is connected to 5colomb external resistance what is the current

how to find work done by load

Answers

Calculation involving work done
Example
work done = force × distance.
work done = 1,000 N × 5 m.
work done = 5,000 J (or 5 kJ)

Why gases are easily compressed?

Answers

Answer:

photosynthesis is the process by which green leaves prepare their food in the presence of sunlight,air and water

Water, H2O ,and methane ,CH4, are both covalent substances . why is water a liquid at room temperature while methane is a gas ? A. Carbon compounds tend to be gases . B. Water has a stronger intermolecular forces

Answers

This is because Water forms Hydrogen bonds whereas Methane only forms dispersion forces.This makes water have stronger intermolecular forces so the answer will be B

write some uses of magnetic force​

Answers

Answer:

television,radios, microwave ovens, telephone system and computer

(i). Compass.
(ii). MRI Scanners.
(iii). Electric Motor.
(iv). Speakers.
(v). Refrigerators.
(vi). Computer.
(vii). Microwave.
(viii). Cars.

Which model of the universe is the most widely accepted, and what does it
predict?

Answers

The future of universe is predicted from space time curve. There are many possibilities solutions or outcomes which on plotting are classified as open, close, flat and curved. Open Universe is when universe is expanding and it will continue to expand forever

what changes must be done to the wire to increase its conductance.​

Answers

Answer:

- Decreasing the resistance

- Using a shorter length

- Using a smaller area wire

Explanation:

Formula for conductance in wires is;

G = 1/R

Where;

G is conductance

R is resistance

This means that increasing the resistance leads to a larger denominator and thus a smaller conductance but to decrease the denominator means larger conductance.

Thus, to increase the conductance, we have to decrease the resistance.

Resistance here has a formula of;

R = ρL/A

Where;

ρ is resistivity

L is length of wire

A is area

Thus, to decrease the resistance, we will have to use a shorter length and smaller area of wire.

the distance between any two bodies is 10 M and the gravitational force between them is 3.2×10-⁹m. if the mass of one object is 40 kg, calculate the mass of another body. (And:119.9 kg)​

Answers

Answer:

0.8 x 10^-9 kg

Explanation:

Given,

Distance ( R ) = 10 m

Force ( F ) = 3.2 x 10^-9 N

Mass ( m1 ) = 40 kg

To find : Mass ( m2 ) = ?

Formula : -

F = m1.m2 / R^2

m2 = FR^2 / m1

= 3.2 x 10^-9 x 10 / 40

= 3.2 x 10^-9 / 4

= ( 3.2 / 4 ) x 10^-9

m2 = 0.8 x 10^-9 kg

Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough is commonly used with transverse waves!

Answers

Answer:

yes Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough are commonly used with transverse waves!

Explanation:

The world’s tallest building is the Burj Khalifa which stands at 828 m above the ground. An eccentric billionaire CEO has an office on the top floor. He insists on having a personal elevator installed that consists only of a giant spring that spans from the basement to his office when it is uncompressed. If his mass is 120 kg, what spring constant in N/m is required so that he momentarily comes to rest on the ground floor?

Answers

Answer:

The spring constant is approximately 2.84 N/m

Explanation:

The height of the building, h = 828 m

The mass of the billionaire that has an office on the top floor, m = 120 kg

Gravitational potential energy, P.E. = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

The gravitational potential energy of the billionaire at the top floor is therefore;

P.E. of billionaire at top floor = 120 kg × 9.81 m/s² × 828 m  = 974,721.6 J

The elastic potential energy of the spring, [tex]P.E._{spring}[/tex] is given as follows;

[tex]P.E._{spring} = \dfrac{1}{2} \cdot k \cdot h^2[/tex]

Where;

k = The spring constant of the spring in N/m

h = The extension of the spring = The height of the building = 828 m

Given that the energy of the spring is conserved, we have;

[tex]P.E._{spring}[/tex] = P.E. of billionaire = 974,721.6 J

Plugging in the values gives;

[tex]P.E._{spring} = 974,721.6 \ J = \dfrac{1}{2} \times k \times (828 \ m)^2[/tex]

Therefore;

2*974,721.6/(828^2)

[tex]k = \dfrac{2 \times 974,721.6 \ J}{(828 \ m)^2} \approx 2.84 \ N/m[/tex]

The spring constant, k ≈ 2.84 N/m.

define international employees ​

Answers

Answer:

An “international employee” is defined as an employee of Stanford University whose work site is located.

Explanation:

In practice, if a voltmeter was connected across any combination of the terminals, the potential difference would be less than what is calculated. State why this is so and explain how the difference is kept to a minimum in modern transformers.

Answers

Answer:

This difference is kept to a minimum because the resistance in transformers is a few tens of ohms and the resistance of modern voltmeters is of the order of MΩ.

Explanation:

A voltmeter is built by a galvanometer and a resistance in series, this set is connected in parallel to the resistance where the voltage is to be measured, therefore the voltage is divided between the voltmeter and the element to be measured, consequently the measured voltage It is less than the calculated one, since for them the resistance of the voltmeter is assumed infinite.

This difference is kept to a minimum because the resistance in transformers is a few tens of ohms and the resistance of modern voltmeters is of the order of MΩ.

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