During​ spring, young​ moose, unfamiliar with roads and​ traffic, are wandering around at night in a​ province, causing risk and road accidents. Suppose that the average number of road accidents involving moose was per day. The government increased the number of hunting licenses and cleared brush to improve​ drivers' visibility. On one day after these measures were​ implemented, there were road accidents involving moose. ​

Required:
a. What would be the chance of such accidents or​ fewer, assuming the​ government's measures were​ ineffective? ​
b. Do you think the​ government's measures were​ effective? State your reasons clearly.

Step-by-step explanation:

24. = 249030/30

=8,301 rs

Answer:

24. 8301, divide 249030 by 30

25. 9989001, but i dont know the property

Step-by-step explanation:

Answer:

The solutions are w=0 ,7

Step-by-step explanation:

3w^2 – 21w = 0

Factor out 3w

3w(w-7) =0

Using the zero product property

3w=0  w-7=0

w =0    w=7

The solutions are w=0 ,7

Answer:4 ma boi

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

because I am god at meth and very smart

Answer:

432x^13

Step-by-step explanation:

(4x^2)^2 • (3x^3)^3

We know that a^b^c = a^(b*c)

4^2 x^2^2  * 3^3 x^3^3

16 x^4  * 27 x^9

We know that a^b ^ a^c = a^(b+c)

16*27 x^(4+9)

432x^13

Answer:

432x¹³

Step-by-step explanation:

( 4x² ) ² • ( 3x³ ) ²

( 16x²)² • ( 27x³)²

[tex]16 x{}^{2 \times 2} \times 6 {}^{3 \times 3 } \\ 16x {}^{4} \times27 {}^{9} [/tex]

[tex](16 \times 27)x {}^{4 + 9} [/tex]

432x¹³

In an arithmetic sequence, every pair of consecutive terms differs by a fixed number c, so that the n-th term [tex]a_n[/tex] is given recursively by

[tex]a_n=a_{n-1}+c[/tex]

Then for n ≥ 2, we have

[tex]a_2=a_1+c[/tex]

[tex]a_3=a_2+c = (a_1+c)+c = a_1 + 2c[/tex]

[tex]a_4=a_3+c = (a_1 + 2c) + c = a_1 + 3c[/tex]

and so on, up to

[tex]a_n=a_1+(n-1)c[/tex]

Given that [tex]a_3=126[/tex] and [tex]a_{64}=3725[/tex], we can solve for [tex]a_1[/tex]:

[tex]\begin{cases}a_1+2c=126\\a_1+63c=3725\end{cases}[/tex]

[tex]\implies(a_1+63c)-(a_1+2c)=3725-126[/tex]

[tex]\implies 61c = 3599[/tex]

[tex]\implies c=59[/tex]

[tex]\implies a_1+2\times59=126[/tex]

[tex]\implies a_1+118 = 126[/tex]

[tex]\implies \boxed{a_1=8}[/tex]

Answer:

x-intercept: (3,0)

y-intercept: (0,-4)

Step-by-step explanation:

To find the x and y-intercepts, we first need to understand what they are. X and y-intercepts are points on the line that passes through the x-axis and y-axis. When a point is an x-intercept, it passes through the x-axis. This means the x-coordinate is an integer, while the y-coordinate is always 0. This can be denoted by (x,0). When a point is a y-intercept, it passes through the y-axis. This means the y-coordinate is an integer, while the x-coordinate is always 0. This can be denoted by (0,y).

Now that we know what x and y-intercepts are, we can plug in x=0 and y=0 to find the intercepts.

x-intercept

4x-3y=12            [plug in y=0]

4x-3(0)=12          [multiply]

4x-0=12              [add both sides by 0]

4x=12                 [divide both sides by 4]

x=3

---------------------------------------------------------------------------------------------------------

y-intercept

4x-3y=12            [plug in x=0]

4(0)-3y=12         [multiply]

0-3y=12             [subtract both sides by 0]

-3y=12               [divide both sides by -3]

y=-4

Therefore, the x-intercept is (3,0) and y-intercept is (0,-4).

Answer:

80 Seconds

I dont really want to type the whole thing out, just think about it again, or go to a tutor website, you should be able to get it, you have to use these, multiplication of three numbers, and multiplication and division by factorization of numbers.

Answer:

A) quadratic

Step-by-step explanation:

ax2 + bx+c=0

Since the highest power of the equation is 2

A) quadratic -2

B) quartic- 4

C) linear- 1

D) cubic-3

Step-by-step explanation:

here's the answer to your question

Answer: Distance = 11

Step-by-step explanation:

Concept:

Here, we need to know the idea of the distance formula.

The distance formula is the formula, which is used to find the distance between any two points.

If you are still confused, please refer to the attachment below for a clear version of the formula.

Solve:

Find the distance between A and B, where:

[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]Distance=\sqrt{(4+7)^2+(-4+4)^2}[/tex]

[tex]Distance=\sqrt{(11)^2+(0)^2}[/tex]

[tex]Distance=\sqrt{121+0}[/tex]

[tex]Distance=\sqrt{121}[/tex]

[tex]Distance=11[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

a = -6

b = 1

Step-by-step explanation:

The gradient of the tangent to the curve y = ax + bx^3, will be:

dy/dx = a + 3bx²

at (2, -4)

dy/dx = a+3b(2)²

dy/dx = a+12b

Since the gradient at the point is 6, then;

a+12b = 6 ....1

Substitute x = 2 and  y = -4 into the original expression

-4 = 2a + 8b

a + 4b = -2 ...2

a+12b = 6 ....1

Subtract

4b - 12b = -2-6

-8b = -8

b = -8/-8

b = 1

Substitute b = 1 into equation 1

Recall from 1 that a+12b = 6

a+12(1) = 6

a = 6 - 12

a = -6

Hence a = -6, b = 1

Answer:

A. multi-way split.

Step-by-step explanation:

Multi way split consists of internal at decision tree branches. Gini index measures probability of impurity in the random variables chosen. Entropy is measure of uncertainty in the sample selected. Binary splitting is used to speed up numerical evaluation.

Answer:

sorry I don't know the answer

Answer:

For the equation y=log(x-k), the domain depends on the value of K. Sliding K moves the left bound of the domain interval. The range and the right end behavior stay the same. For the equation y=log x+k, the domain is fixed, starting at an x-value of 0. The vertical asymptote is also fixed. The range of the equation depends on K.

Step-by-step explanation:

Answer:

I think the power is 4

Step-by-step explanation:

480J / 120 = 4

Put 2 mins into seconds which is 120 seconds

Sorry if it is wrong :)

Answer:

[tex]4\text{ watts}[/tex]

Step-by-step explanation:

In physics, the power of a machine is given by [tex]P=\frac{W}{\Delta t}[/tex], where [tex]W[/tex] is work in Joules and [tex]\Delta t[/tex] is time in seconds.

Convert 2 minutes into seconds:

2 minutes = 120 seconds.

Substitute [tex]W=480[/tex] and [tex]\Delta t=120[/tex] to solve for [tex]P[/tex]:

[tex]P=\frac{480}{120}=\boxed{4\text{ watts}}[/tex]

Answer:

-2,2

Step-by-step explanation:

Let

[tex]y_1=4x^2-c^2[/tex]

[tex]y_2=c^2-4x^2[/tex]

We have to find the value of c such that the are of the region bounded by the parabolas =32/3

[tex]y_1=y_2[/tex]

[tex]4x^2-c^2=c^2-4x^2[/tex]

[tex]4x^2+4x^2=c^2+c^2[/tex]

[tex]8x^2=2c^2[/tex]

[tex]x^2=c^2/4[/tex]

[tex]x=\pm \frac{c}{2}[/tex]

Now, the area bounded by two curves

[tex]A=\int_{a}^{b}(y_2-y_1)dx[/tex]

[tex]A=\int_{-c/2}^{c/2}(c^2-4x^2-4x^2+c^2)dx[/tex]

[tex]\frac{32}{3}=\int_{-c/2}^{c/2}(2c^2-8x^2)dx[/tex]

[tex]\frac{32}{3}=2\int_{-c/2}^{c/2}(c^2-4x^2)dx[/tex]

[tex]\frac{32}{3}=2[c^2x-\frac{4}{3}x^3]^{c/2}_{-c/2}[/tex]

[tex]\frac{32}{3}=2(c^2(c/2+c/2)-4/3(c^3/8+c^3/28))[/tex]

[tex]\frac{32}{3}=2(c^3-\frac{4}{3}(\frac{c^3}{4}))[/tex]

[tex]\frac{32}{3}=2(c^3-\frac{c^3}{3})[/tex]

[tex]\frac{32}{3}=2(\frac{2}{3}c^3)[/tex]

[tex]c^3=\frac{32\times 3}{4\times 3}[/tex]

[tex]c^3=8[/tex]

[tex]c=\sqrt[3]{8}=2[/tex]

When c=2 and when c=-2 then the given parabolas gives the same answer.

Therefore, value of c=-2, 2

Answer:

D represents a proportional relationship

Step-by-step explanation:

Proportional graphs always intersect with zero

Answer:

3000

growth

2.2%

Step-by-step explanation:

Answer:

3.39794000867

Step-by-step explanation:

first add log 125 and 625 and divide the answer by log 25 and minus the answer by 5

Answer:

The answer is 7.

Answer:

52 is (a)

55 is.( d)

56. is (d)

The width of the actual garden patio according to the scale drawing is 14 meters.

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.

Given the scale of 1 cm : 2 m

For a patio of 7 cm, then:

Actual patio = 7 cm / (1 cm/ 2m) = 14 m

The width of the actual garden patio according to the scale drawing is 14 meters.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

[tex]You can call c the number of children and a for adults; you get:5.20c+8.50a=1097.60anda=4c meaning that the number of adults was four times the children.Substituting this value of a into the first equation we get:5.2c+8.5(4c)=1097.65.2c+34c=1097.6rearranging:c=1097.639.2=28and so:a=4c=4⋅28=112[/tex]

I got:  28  children and  112  adults.

Answer:

C. 11x² - 3x

Step-by-step explanation:

(12x² - 5x) - (x² - 2x)

12x² - 5x - x² + 2x

12x - x² - 5x + 2x

11x² - 3x

Answer:

The rate of change of f(x) is faster than the rate of change of g(x).

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

*Note:

Rate of Change is determined by slope.

Step 1: Define

f(x) = 3x + 5

↓ Compare to y = mx + b

Slope m = 3

g(x) = 2x + 5

↓ Compare to y = mx + b

Slope m = 2

Step 2: Answer

We can see that the slope of f(x) is greater than g(x).

∴ the rate of change of f(x) would be greater than g(x).

Answer:

Maximum = 19

Minimum = 4

Median = 12

Step-by-step explanation:

The maximum number of phone sold per day is the value to the right of the horizontal axis as the values are arranged in ascending order ; Hence, the maximum number of phones sold per day is 19

Also, the minimum number of phones sold per day is the value to the left of the plot, Hence, minimum number of phones sold per day is 14.

The Median value : 4, 9, 14, 19

The median = 1/2(n+1)th term

1/2(5)th term = 2.5 th term

Median (9 + 14) /2 = 13 /2 = 11.5 = 12 phones

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

[tex](a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) = Q(x)[/tex]  is a differential equation.

If [tex]Q(x) \neq 0[/tex]

It is non homogeneous then,

The general solution  = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution =  complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

[tex]$(2D^3+15D^2+24D+11)y=0$[/tex]

Auxiliary equation,

[tex]$2m^3+15m^2+24m +11 = 0$[/tex]

-1  | 2    15    24     11

    | 0   -2    - 13    -11  

      2    13    11       0

∴ [tex]2m^2+13m+11=0[/tex]

The roots are

[tex]$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$[/tex]

[tex]$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$[/tex]

[tex]$=\frac{-13\pm9}{4}$[/tex]

[tex]$=-5.5, -1$[/tex]

So, [tex]m_1, m_2, m_3 = -1, -1, -5.5[/tex]

Then the general solution is :

[tex]$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$[/tex]

Answer:

Step-by-step explanation:

Combination of 4 out of 5 + 7 = 12 is:

Combination of 1 man and 3 women is:

Required probability:

Correct choice is B

what? ;-;.............

Answer:

x = 2 - sqrt(19/6)

x = 2 + sqrt(19/6)

Step-by-step explanation:

Answer:

add 4

subtract 24 from 5

2

Step-by-step explanation:

Answer:

option D (5 6 8 9) is the answer

Answer:

X [tex]\Longrightarrow -8\Longrightarrow -1\Longrightarrow 1\Longrightarrow 8[/tex]

Y[tex]\Longrightarrow 5\Longrightarrow 6\Longrightarrow 8\Longrightarrow 9[/tex]

[tex]Answer\hookrightarrow D)[/tex]

-------------------------

Hope it helps...

Have a great day!!

Answer:

Symmetric with respect to the x-axis

Symmetric with respect to the y-axis

Symmetric with respect to the origin