Enter each intercept as an ordered pair (x, y). Use a comma to separate the ordered pairs of multiple intercepts. You may enter an exact answer or round to 2 decimal places. If there are no solutions or no real solutions for an intercept enter ∅.

Answer:

x = 10

Step-by-step explanation:

y = 2x + 1

21 = 2x + 1

21 - 1 = 2x

2x = 20

x = 10

Answer: 1.25 square feet

This converts to the improper fraction 5/4

===========================================================

Explanation:

The area of the triangle on the left is base*height/2 = 0.5*2/2 = 0.5 square feet. Note that 1/2 = 0.5

The area of the triangle on the right side is base*height/2 = 0.2*3/2 = 0.75 square feet. This converts to the fraction 3/4

Add up the two results: 0.5+0.75 = 1.25 square feet

-----------

If you need the answer as an improper fraction, then,

1.25 = 1 + 0.25

1.25 = 1 + 1/4

1.25 = 4/4 + 1/4

1.25 = (4+1)/4

1.25 = 5/4

Answer: the numbers with the plus sign are positive and the ones with the negative sign are negative

Step-by-step explanation:

Step-by-step explanation:

[tex] \sqrt{53} [/tex]

Answer:

x=12 .  

Step-by-step explanation:

See image below:)

Answer:

20

Step-by-step explanation:

l*w*h

4*5*1= 20

Answer: a) a) 0.700, (0.676, 0.724)

Step-by-step explanation:

Confidence interval for population proportion p :

[tex]\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

[tex]\hat{p}[/tex] = Sample proportion, n= sample size, z* = Critical value.

Let p denote the proportion of all people who voted.

As per given, n= 1000

[tex]\hat{p}=\dfrac{700}{1000}\\\\=0.7[/tex]

z* for 90% confidence = 1.645

Required confidence interval :

[tex]0.7\pm (1.645)\sqrt{\dfrac{0.7(1-0.7)}{1000}}\\\\=0.7\pm(1.645)\sqrt{0.00021}\\\\=0.7\pm (1.645)(0.0145)\\\\=0.7\pm 0.0238525\\\\=(0.7-0.0238525,0.7+0.0238525)\\\\=(0.6761475,\ 0.7238525)\approx(0.676, 0.724)[/tex]

hence, the correct option is a) a) 0.700, (0.676, 0.724)

Answer:

JK and LH

Step-by-step explanation:

if u look at it, they are the smaller arcs produced compared to HJ and KL which are much bigger

Answer:

[tex]x=2+\sqrt{21}\\\\x=2-\sqrt{21}[/tex]

Step-by-step explanation:

One is given the following equation;

[tex]x^2-4x-9=29[/tex]

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

[tex]x^2-4x-9=29[/tex]

[tex]x^2-4x-38=0[/tex]

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

[tex]ax^2+bx+c[/tex]

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]

Substitute the coefficients of the given equation in and solve for the roots;

[tex]\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}[/tex]

Simplify,

[tex]\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}[/tex]

Therefore, the following statement can be made;

[tex]x=2+\sqrt{21}\\\\x=2-\sqrt{21}[/tex]

Answer:

h = A/2πr - r

That's the formula. Hopefully it's understandable because I don't know any other way of typing it. You can always search it up and it'll show you. :)

Answer:

Step-by-step explanation:

Answer: C) a=18

Step-by-step explanation: Hope i helped :)

Answer:

12:24:6- divide by 3

4:8:2 - divide by 2

2:4:1- simplest form

Answer:

20 minutes

Step-by-step explanation:

20 minutes after 3:15 is 3:35, then 5 more minutes is 3:40. Therefore Sten has 20 minutes left until 4pm.

9514 1404 393

Answer:

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relationships.

  Sin = Opposite/Hypotenuse   ⇒   sin(B) = 12/13

  Cos = Adjacent/Hypotenuse   ⇒   cos(B) = 5/13

  Tan = Opposite/Adjacent   ⇒   tan(B) = 12/5

Answer:

Fraction of money spent on calculator = 2/5

Find the fraction of money left:

1 - 2/5 = 3/5

Find the fraction of money spent on a book:

4/7 x 3/5 = 12/35

Answer: She spent 12/35 of the money on a book

------------------------------------------------------------------------------------------------

To find the fraction of saving:

Fraction of money saved = 1 - calculator - book

Fraction of money saved = 1 - 2/5 - 12/35 = 9/35

Fraction of the money saved = 9/35

Step-by-step explanation:

Answer:

Step-by-step explanation:

11.04 = 10(1.02)^n

1.104 = 1.02^n

ln 1.104 = ln 1.02^n

ln 1.104 = n ln 1.02

n = ln 1.104/ ln 1.02

n = 4.99630409516

4.99 can be rounded to 5.

So a reasonable domain would be 0 ≤ x < 5

PART B)

f(0) = 10(1.02)^0

f(0) = 10(1)

f(0) = 10

The y-intercept represents the height of the plant when they began the experiment.

f(1) = 10(1.02)^1

f(1) = 10(1.02)

f(1) = 10.2

(1, 10.2)

f(5) = 10(1.02)^5

f(5) = 10(1.1040808)

f(5) = 11.040808

f(1)=10(1.02)^1

f(1)=10.2

Average rate= (fn2-fn1)/(n2-n1)

                     =11.04-10.2/(5-1)

                    =0.22

the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.  

Answer:

y+1=7(x+4) for first one

y-4=5(x-0) for second one

Step-by-step explanation:

point slope form for both of those questions.

the formula for point slope form is

y-y1(y coordinate) = slope(x+x2(x coordinate))

y+1=7(x+4)

Second question:

-1,-1 to 0,4

change in x +1, change in y +5.

5/1 = 5

slope is 5

y-4=5(x-0)

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {Your\:answer\:is\:59.}}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {Step-by-step\:explanation:}}}[/tex]

1. My number has two digits.

2. Double my number is less than 150.

3. I am not divisible by 12.

4. My digits are different from each other.

5. The second digit in my number is divisible by an odd number.

6. My first digit is less than my second digit.

7. My digits add up to 14.

Therefore, the required number is [tex]\sf\pink{59}[/tex].

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

Answer:

59

Step-by-step explanation:

two digits, 59=118, unable to divide by twelve since its an odd number, 9÷3=3, 5<9, 5+9=14

Answer:

[tex]Outcomes = \{HHHH, HHHT,TTTH, TTTT\}[/tex]

Step-by-step explanation:

Given

[tex]S = \{HHHH, HHHT, HHTH, HHTT,HTHH, HTHT, HTTH, HTTT, THHH, THHT,[/tex]

[tex]THTH, THTT,TTHH, TTHT, TTTH, TTTT\}[/tex]

Required

The outcomes where the first three tosses are the same

To do this, we list out the outcomes that the first three are HHH or TTT.

So, we have:

[tex]Outcomes = \{HHHH, HHHT,TTTH, TTTT\}[/tex]

Answer:

45) 35.75 sq km

46) 24.5 sq km

Step-by-step explanation:

Area of Square:

A= [tex]\frac{(base)(height)}{2}[/tex]

45) A = (11)(6.5) ÷ 2 =

46) A = (10)(4.9) ÷ 2 =

Answer:

45) [tex]35.75[/tex] [tex]km^2[/tex]

46) [tex]24.5[/tex] [tex]km^2[/tex]

Step-by-step explanation:

------------------------------

The formula to find the area of a triangle is  [tex]A=\frac{1}{2}bh[/tex] where [tex]b[/tex] stands for the base and [tex]h[/tex] stands for the height.

So, let's solve and find out the answer.

--------------->>>>

45)

[tex]A=\frac{1}{2}(11)(6.5)[/tex]

[tex]A=\frac{1}{2}(71.5)[/tex]

[tex]A=35.75[/tex]

The area of this triangle is [tex]35.75[/tex] [tex]km^2[/tex]

--------------->>>>

46)

[tex]A=\frac{1}{2} (10)(4.9)[/tex]

[tex]A=\frac{1}{2} (49)[/tex]

[tex]A=24.5[/tex]

The area of this triangle is [tex]24.5[/tex] [tex]km^2[/tex]

------------------------------

Hope this is helpful

Answer:

21

Step-by-step explanation:

21

21

21

Answer:

Simple addition the answer is 21.

Answer:

Y is -1.

Step-by-step explanation:

If you substitute the values, you find that that's the correct answer.

Answer:

Not a 70%, but a 72.5% (or a 73%)

Step-by-step explanation:

Assuming that the 65% is the first grade and the 80% is your second, adding both numbers and dividing by 2 will get you 72.5%.

The best possible grade you can get from that 65% is an 82.5%, or 83% if you round the grade up. 100+65=165÷2 will get you 82.5.

Answer:

I. Length, L = 9.552 meters

II. Width, W = 7.96 meters

Step-by-step explanation:

Let the length = L

Let the width = W

Given the following data;

Perimeter = 35 m

Translating the word problem into an algebraic equation, we have;

Length = 1.2W

To find the dimension of the room;

The perimeter of a rectangle is given by the formula;

P = 2(L + W)

Substituting into the formula, we have;

35 = 2(1.2W + W)

35 = 2(2.2W)

35 = 4.4W

Width, W = 7.96 meters

Next, we would find the length of the rectangle;

L = 1.2*W

L = 1.2 * 7.96

Length, L = 9.552 meters

Answer:

7

Step-by-step explanation:

Answer:

He is wrong.  

In my answer I found the complete volume of the pool and then what the volume would be 10 cm empty.  You probably only need to find the 10 cm emptied  to answer, just a heads up.  if you have any questions though let me know.

Step-by-step explanation:

To most easily figure out the volume of the empty pool I think it is easiest to break it up into four parts..

First break off that skinny end bit so it will have 1 m in height, 4 m in length and 5m in width.  Width is never going to shange because of how we are breaking this up, and the width is the distance from you into the paper, if that makes sense.  Basically not up and down or left and right.

Next another rectangular prism  from the right side with 2 height, 2m length and again 5m width.

Now you have a trapezoidal prism with one base of length 1m, another of base 2m and a height of length 4m.

To fond the volume of prisms you want to find the area of their bases then multiply it by their heights.  In this instance height is going to be the width again, and the bases are th parts facing us on the picture.

For a rectangular prism area of the base is easy, just multiply length by height.  a trapezoid is taking the two bases (b1 and b2) ading them together and dividing that sum by 2, THEN taking this new number and multiplying it by what would be the height of the trapezoid.  the trapezoid has its bases as two heights, and its height then would be the horizontal length of the pool.  Sorry if that is confusing.  Here are the three volumes though.

Rectangular 1: 4*1*5 = 20 m^3

Rectangular 2" 2*2*5 = 20m^3

Trapezoidal: = ([1+2]/2)*4*5 = 30 m^3

So total it is 70 m^3

The question then says each cubic meter can contain 1,000 liters of water.  70 m^3 then is 70,000 liters

The question also says there are three barrels of 20,000 liters each, so combined that's 60,000 liters.

Finally it wants to know if Sam is right saying if you dump all of the 60,000 liters into the pool the surface of the water will not reach the top of the pool by 10 cm.  60,000 is less than 70,000, but we don't know how much lower it is in cm.  

The trick here is to know that we are lowering a specific dimension of each prism to a certain amount to be lower by 10cm

In the 4x1x5 rectangular prism the 1m side is lowering.

In the 2x2x5 rectangular prism  the 2m side representing the vertical length is getting some amount taken away.

int he trapezoidal prism both of the "bases" are getting an amount taken.

So the trick here is to set up the math again, except this time with 10 cm less being subtracted from each part, then solving t and see if it gets us the 60,000 liters or 60 m^3.  Since we are measurng in meters, 10 cm less is the same a subtracting .1, or if you prefer subtracting a decimeter.

4*1*5 becomes 4(.9)5 = 18

2*2*5 becomes 2(1.9)5 = 19

Trapezoidal: = ([1+2]/2)*4*5 becomes ([(.9)+(1.9)]/2)*4*5 = 28

Adding this all together gets us 65 or 65,000 liters.  This means that if the pool is filled 10 cm from the top the volume would be 65,000 liters, still more than if the three tankers are emptied completely into it.  

You could have probably just done the second part, where we sbtracted 10 cm from each of the dimensions, but I am going to leave it all since I wrote it.

9514 1404 393

Answer:

  Sam is not correct.

Step-by-step explanation:

As shown in the attachment, the "base" (front face) of this prism can be divided into a rectangle and a trapezoid. The relevant area formulas are ...

  A = LW . . . . area of a rectangle of length L and width W

  A = 1/2(b1 +b2)h . . . . area with parallel bases b1 and b2 and height h

__

The rectangle portion of the "base" of the pool has area ...

  A = (10 m)(1 m) = 10 m²

The trapezoid portion of the "base" of the pool has area ...

  A = 1/2(6 m +2 m)(1 m) = 4 m²

Then the "base" area is ...

  B = 10 m² +4 m² = 14 m²

__

The volume of the prism is given by ...

  V = Bh . . . . where B is the base area and h is the distance between bases

  V = (14 m²)(5 m) = 70 m³

We are told that 1 m³ = 1000 L and that 3 tankers of 20,000 L each are emptied into the pool. That leaves an unfilled volume of ...

  70 m³ -3×(20 m³) = 10 m³ . . . . unfilled volume

__

The surface area of the pool is ...

  A = LW = (10 m)(5 m) = 50 m²

So the unfilled volume has a height of ...

  V = Bh

  10 m³ = (50 m²)h

  h = (10/50) m = 20/100 m = 20 cm . . . . . the height of the unfilled space

The water in the pool will be 20 cm below the top, not 10 cm. Sam is not correct.

Answer:

The answer for number 1 is C