ERROR ANALYSIS Describe and correct the error in identifying the terms, coefficients, and constants in the algebraic expression 2x2y

Answers

Answer 1

Given the algebraic expression,  [tex]2x^2y[/tex], the error in the analysis shown in the diagram attached is the wrong listing of terms.

The correct analysis is:

Term: [tex]2x^2y[/tex]Coefficient: 2Constant: None

Recall:

Given an expression, say, [tex]2x^2 + 4x + 5[/tex].

The expression has 3 terms, namely: [tex]2x^2, 4x, $ and 5[/tex]The coefficients are: 2 and 4.The constant is: 5

Thus, we are given the expression, [tex]2x^2y[/tex],

The expression has only 1 term: [tex]2x^2y[/tex]

1 coefficient: 2

It has no constant.

Therefore, given the algebraic expression,  [tex]2x^2y[/tex], the error in the analysis shown in the diagram attached is the wrong listing of terms.

The correct analysis is:

Term: [tex]2x^2y[/tex]Coefficient: 2Constant: None

Learn more here:

https://brainly.com/question/4839601

ERROR ANALYSIS Describe And Correct The Error In Identifying The Terms, Coefcients, And Constants In

Related Questions

Is 7164 divisible by 6?

yes?
no?

Answers

Answer:

yes

7164 is divisible bt 6

Answer:

Yes

Step-by-step explanation:

Any number will be divisible by 6 if they be divisible by 2 & 3

- we know 7164 is divisible by 2

- also any number which sum of their digits are divisible by 3, the number will be divisible by 3

in this case (7164) 7+1+6+4=18 & 18 is divisible by 3 so 7164 is divisible by 3 as well.

so 7164 is divisible by 6

PLEASE HELP!!! I NEED THIS DONE AS SOON AS POSSIBLE 20 points Make a table of order pairs for the equation y=-1/3+4 then plot two points to graph the equation

Answers

Answer:

ok so.u grit da he on 40/ rock cause u got a andriodnh on gf


Write down an example to show that each of the following two siatements is not correct
a) The factors of an even number are always even

Answers

Answer:

a) 2 * 3 = 6.

b) 123 is odd but contains an even digit (2).

Step-by-step explanation:

combine like the like terms
34w - 4g + 4g - 36w

Answers

the answer is -2w (i have the write at least 20 words to dont worry about this)

Answer:

-2w

Step-by-step explanation:

Like terms have same variable.

34w - 4g + 4g - 36w = 34w - 36w - 4g + 4g

                                  = - 2w + 0 = -2w


If the sum of a number and two is tripled, the result is one less than twice the number. Find the number.

Answers

Answer:

z

Step-by-step explanation:

hqvqhqvw karrar ras wallah a part

what is the percentage discount when a stereo is reduced from $258 to $199?

Answers

23% if you’re rounding it

In a certain​ chemical, the ratio of zinc to copper is 3 to 14. A jar of the chemical contains 630 grams of copper. How many grams of zinc does it​ contain?

Answers

Answer:

135 grams of Zinc

Step-by-step explanation:

zinc:copper

3:14

3/14=x/630

x=135

If f (x) = 3x + 1 and g(x) = 2x + 1, what is the value of f (g(2))?

Answers

Step-by-step explanation:

= f( g(2) )

= 3(2x + 1) + 1

= 6x + 3 + 1

= 6x + 4

= 6(2) + 4

= 12 + 4

= 16

f(g(2)) = 16

3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1

Answers

Answer:

Option D)  [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]

Step-by-step explanation:

Given the equation, T = 15 + c × n, where:

T = represents the total monthly gym cost

c =  represents the additional charge for a group class, and

n = represents the number of group classes attended

Solution:

In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n  algebraically.

The first step is to subtract 15 from both sides:

T = 15 + c × n

T - 15 = 15 - 15 + c × n

T - 15 = c × n

Next, divide both sides by c to isolate n :

[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]

[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]

Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].

Express the tan G as a fraction in simplest terms.

Answers

Answer:

[tex]\frac{\sqrt{70} }{5}[/tex]

Jayden's snow cone machine makes 3 snow cones from 0.5 pounds of ice. How many snow cones can be made with ice please show your work, not an explanation!!!!

Answers

Answer:

30

Step-by-step explanation:

3 snow cones per 0.5 pounds of ice

0.5 pounds of ice x 10 = 5 pounds of ice

3 snow cones X 10 = 30 snow cones.

Please I need help ASAP. Can someone help me?

Answers

Answer: The second bubble thing is correct you have picked the wrong one.

C+X=G
what is X?
this is a literal equation.​

Answers

Answer:

x=g-c

Step-by-step explanation:

x= g - c
hope this helps!

The corner section of a football stadium has 6 seats on the first row. Each row after that has an additional 3 seats. How many seats would be on the 20th row?

32


63


103


342

Answers

9514 1404 393

Answer:

  63

Step-by-step explanation:

The number of seats in a row will give an arithmetic sequence:

  6, 9, 12, 15, ...

The first term is 6; the common difference is 3. The general term is ...

  an = a1 +d(n -1) . . . . . . n-th term of sequence with first term a1, difference d

The 20th term of the sequence is ...

  a20 = 6 +3(20 -1) = 6 +57 = 63

There would be 63 seats on the 20th row.

Which integer can you multiply by itself to get 400 as the square number?

a. 10
b. 20
c. 30
d. 40.

Answers

Answer:

20

Step-by-step explanation:

20*20 = 400

OR

[tex]20 {}^{2} = 400[/tex]

(2x+y)2-y2 if x=-3 y=4 and z=-5

Answers

Answer:
-12
Hope this helps!
So your equation it (2x+y)2-y2 so then you will substitute meaning your equation will now be 2(-3)+4*2-(4)2 and I assume it’s squared and there is a lot of things missing but I get -6+8-16 all together it would be 14 that’s what I get at least

PLEASE READ THIS!!! Don't answer my questions with a link. Someone already answered this question, but they gave me a link and it was blocked on my school Chromebook, so it was an entirely useless answer. Thank you. If you answer this question without using a link I will give you an easy to earn 100 points. I just need to know how to turn this shape into as many triangles as possible. Thank you for reading this message.

Answers

Answer: 9 triangles

Step-by-step explanation:

(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme​

Answers

Step-by-step explanation:

[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]

[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

We can write as :

27 = 3 × 3 × 3 = 3³

8 = 2 × 2 × 2 = 2³

243 = 3 × 3 × 3 × 3 × 3 = 3⁵

32 = 2 × 2 × 2 ×2 × 2 = 2⁵

[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now, we can write as :

(3³/2³) = (3/2)³

(3⁵/2⁵) = (3/2)⁵

[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now using law of exponent :

[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]

[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]

Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²​

Answers

Solution:

[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]

Answer:

[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]

Hope it helps.

Do comment if you have any query.

When there’s a power to the second outside of the parentheses, you multiply the entire equation by its self, so (4a - 5b)(4a-5b)=16a^2-40ab+25b^2

Which of the following is true?

|−5| < 4
|−4| < |−5|
|−5| < |4|
|−4| < −5

Answers

Answer:

|-4| < |-5|

Step-by-step explanation:

because if modules is given sub sign will be deducate

What is the common ratio of the sequence 3, 21, 147, … ?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, … ?


Use the given formula to find the indicated terms of the sequence.

a4 =
1029
a5 =
7203

Answers

It is 7, C,
A= 1029
B=7203

Answer:

What is the common ratio of the sequence 3, 21, 147, …?  

7

Which formula can be used to find the nth term of the sequence 3, 21, 147, …?

c)

Use the given formula to find the indicated terms of the sequence.

a4 = 1029

a5 = 7203

Step-by-step explanation:

Answers for all three questions<3

Y-2=-3(x-7) written in standard form

Answers

Y=2-3(x-7)
You just add +2 to each side and the positive and negative cancel out and it switches it over

you are renting a house in the seychelles for a week at $1500. What is the cost per day?

Answers

Step-by-step explanation:

cost per day

= $1500 / week

= $1500 / 7 days

= $1500 ÷ 7 / 7 ÷ 7

≈ $214,29 / day

labron has $15,300 of total liabilities and $52,580 of total assets.what is his net worth​

Answers

Answer:

.......................

9 DNG AKUM
Solve for x :
N
M
5
U7
X+7
D 8 G
K 35 J

Answers

Answer:

x = 49

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are in proportion, that is

[tex]\frac{DN}{KJ}[/tex] = [tex]\frac{DG}{KM}[/tex] , substitute values

[tex]\frac{5}{35}[/tex] = [tex]\frac{8}{x+7}[/tex] ( cross- multiply )

5(x + 7) = 280 ( divide both sides by 5 )

x + 7 = 56 ( subtract 7 from both sides )

x = 49

Which equation, in slope-intercept form, matches the equation shown?


a line that goes through the points (0, -4) and (6, -9)


Question 4 options:


y=47x−4


y=56x+1


y=−56x−4


y=−47x+1


Please help!

Answers

Answer: i think it is y=−56x−4

Step-by-step explanation:

The equation in the slope intercept form which passes through the points ( 0, -4 ) and ( 6 , 9 ) is y = (-5 / 6)x - 4.

The correct answer is Option C.

Given data:

To find the equation of a line in slope-intercept form (y = mx + b) that passes through the points (0, -4) and (6, -9), we need to determine the slope (m) and the y-intercept (b).

First, calculate the slope (m):

m = (change in y) / (change in x)

m = (-9 - (-4)) / (6 - 0)

m = (-9 + 4) / 6

m = -5 / 6

Now that we have the slope, we can use one of the given points (let's use (0, -4)) to solve for the y-intercept (b):

-4 = (-5 / 6) * 0 + b

-4 = b

So, the y-intercept (b) is -4.

Now, we can write the equation of the line in slope-intercept form:

y = (-5 / 6)x - 4

Hence, the equation of the line is y = (-5 / 6)x - 4.

To learn more about equation of line, refer:

https://brainly.com/question/14200719

#SPJ3

The complete question is attached below:

Which equation, in slope-intercept form, matches the equation shown?

a line that goes through the points (0, -4) and (6, -9)

A) y = ( 4/7 )x - 4

B) y = ( 5/6 )x + 1

C) y = ( -5/6 )x - 4

D) y = ( -4/7 )x + 1

24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right

Answers

Answer:


It a acute

Hope this help you :)

Help me plz i wanna make an an A

Answers

You can’t even read the numbers on that picture upload a new one!
I would help you but I can’t read the numbers for the graph. I am sorry that I can’t help

which input value produces the same output value for the two funcions on the graphs
Rox) = x+1
9(x) = 3x-2

Answers

Answer: i solved on my channel

Step-by-step explanation: https://youtu.be/rTgj1HxmUbg

The perimeter of a rectangular field is 312m. If the width of the field is 61m,what is the length.

Answers

Answer:

95m

Step-by-step explanation:

312 - 61 - 61 = 190

190/2 = 95

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