Answer:
17.9375 square yards
Step-by-step explanation:
Let us have a common unit
What we have here is the case of inches and ft
10 ft 3 inches
1 ft = 12 inches
so 3 inches is 3/12 = 0.25 ft
= 10+0.25 = 10.25 ft
15 ft 9 in
= 15 + 9/12 = 0.75 + 15 = 15.75 ft
So let us convert to yards ;
Mathematically, 3 ft = 1 yard
so 10.25 ft = 10.25/3 = 3.4167 yards
15.75 ft = 15.75/3 =5.25 yards
So the square yards would be the product of this two;
which is;
(10.25/3) * (15.75/3) = 17.9375 square yards
Choose the function that has:
Domain: x*-1
Range: y# 2
O
Ax)= x+2
x-1
O
2x+1
Ax)=
x+1
2x+ 1
(x) =
x-1
Given:
[tex]Domain\neq -1[/tex]
[tex]Range\neq 2[/tex]
To find:
The function for the given domain and range.
Solution:
A function is not defined for some values that makes the denominator equals to 0.
The denominator of functions in option A and C is [tex](x-1)[/tex].
[tex]x-1=0[/tex]
[tex]x=1[/tex]
So, the functions in option A and C are not defined for [tex]x=1[/tex] but defined for [tex]x=-1[/tex]. Therefore, the options A and C are incorrect.
In option B, the denominator is equal to [tex]x+1[/tex].
[tex]x+1=0[/tex]
[tex]x=-1[/tex]
So, the function is not defined for [tex]x=-1[/tex]. Thus, [tex]Domain\neq -1[/tex].
If degree of numerator and denominator are equal then the horizontal asymptote is [tex]y=\dfrac{a}{b}[/tex], where a is the leading coefficient of numerator and b is the leading coefficient of denominator.
In option B, the leading coefficient of numerator is 2 and the leading coefficient of denominator is 1. So, the horizontal asymptote is:
[tex]y=\dfrac{2}{1}[/tex]
[tex]y=2[/tex]
It means, the value of the function cannot be 2 at any point. So, [tex]Range\neq 2[/tex].
Hence, option B is correct.
Find the probability of no failures in five trails of a binomial experiment in which the probability of success is 30%
which of the following statements must be true, given that ΔABC≅ΔXYZ, and the measure of ∠C is 32°
[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]
Given,
ΔABC ≅ ΔXYZ
If these 2 triangles are congruent with each other then,
∠ A = ∠ X [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]
∠ B = ∠ Y [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]
∠ C = ∠ Z [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]
Now,
We saw that ∠ C = ∠ Z.
⟹ So, if ∠ C = 32°, then even ∠ Z will be equal to 32°. [tex]\boxed{\sf{Equal \ angles \ have \ equal \ measurements}}[/tex]
ᶛɲƧཡэʀ ↦ C. m ∠X = 32°
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
What is 1,485÷ 0.09 answer please let me y
Answer:
16,500
Step-by-step explanation:
Just use a calculator-simple
What do you mean "let me y"?
Answer:
the answer is 16500 or sixteen thousand five hundred
Step-by-step explanation:
:)
identify the maximum and minimum values of the function y=10cosx in the interval [-2pie, 2pie]. Use your understanding of transformations, not your graphing calculator.
Answer:
3 x + 2 y + z/ x + y + z , x = 2 , y = 3 , z = 1
tan ( x ) , x = − π
cot ( 3 x ) , x = 2 π /3
Step-by-step explanation:
**who can help me**
Answer:
.
Step-by-step explanation:
The temperature of a chemical solution is originally 21^\circ\text{C}21 ∘ C21, degrees, start text, C, end text. A chemist heats the solution at a constant rate, and the temperature of the solution is 75^\circ\text{C}75 ∘ C75, degrees, start text, C, end text after 121212 minutes of heating. The temperature, TTT, of the solution in ^\circ\text{C} ∘ Cdegrees, start text, C, end text is a function of xxx, the heating time in minutes. Write the function's formula. T=
Answer:
T(x) = 21 + 4.5x
Step-by-step explanation:
Given :
Original temperature = 21°C
Final temperature = 75°C
Time, x = 12 minutes
The temperature, T as a function of x, heating time in minutes :
We need to obtain the constant heating rate per minute :
Final temperature = initial temperature + (constant rate change,△t * time)
75 = 21 + 12△t
75 - 21 = 12 △t
54 = 12 △t
△t = 54 / 12
△t = 4.5°C
Hence, temperature change is 4.5°C per minute.
Hence,
T(x) = 21 + 4.5x
Answer:
T= 21+4.5x
Step-by-step explanation:
I got it right on Khan Academy
PLEASE MARK BRAINLIEST
Five number have amean of 12,when one number is removed, the mean becomes 11,what is the removed number
Answer:
The removed number is 16
Step-by-step explanation:
Five numbers have a mean of 12.
Now;
Mean = Σx/x
Thus; Σx = 12 × 5 = 60
Now,we are told that if one number is removed, the mean is 11.
Thus;
(60 - x)/4 = 11
60 - x = (11 × 4)
60 - x = 44
x = 60 - 44
x = 16
Thus,the removed number is 16
A strawberry and banana juice blend is made with a ratio of strawberry to banana of 2:3. Fill in the table to show different proportional amounts. Amount of strawberry Amount of banana 1 b. Explain why these amounts are proportional.
Answer:
See Explanation
Step-by-step explanation:
Given
Let
[tex]S \to[/tex] Strawberry
[tex]B \to[/tex] Banana
[tex]S : B = 2 : 3[/tex]
Solving (a):
Complete the table
The table, to be complete, is not given; so, I will generate one myself.
[tex]\begin{array}{cccccc}S & {2} & {3} & {4} & {5} & {6} \ \\ {B} & {3} & {4.5} & {6} & {7.5} & {9} \ \end{array}[/tex]
The table is generated as follows:
[tex]S : B = 2 : 3[/tex]
Multiply by 1.5
[tex]S : B = 2 * 1.5 : 3 * 1.5[/tex]
[tex]S : B = 3 : 4.5[/tex]
Multiply by 2
[tex]S : B = 2*2 : 3*2[/tex]
[tex]S : B = 4 : 6[/tex]
And so on....
In summary, whatever factor is multiplied to S must be multiplied to B; in order to keep the ratio constant
Solving (b): Why the amount are proportion
Because the ratio is constant and it remains unchanged all through.
Divisor mayor común de 28 y 48
Answer:
mcd(28,48) = 4
Para encontrar el mcd de 28 y 48:
Los factores de 28 son 28, 14, 7, 4, 2, 1.
Los factores de 48 son 48, 24, 16, 12, 8, 6, 4, 3, 2, 1.
Los factores en común de 28 y 48 son 4, 2, 1, los cuales intersectan los dos conjuntos arriba.
En la intersección de los factores de 28 ∩ factores de 48 el elemento mayor es 4.
Por lo tanto, el máximo común divisor de 28 y 48 es 4.
PLEASE HELP DESPERATE
tan=sin/cos so tan=3/5/4/5=3/4
Answer:
SOH CAH TOA
3/5 opposite over hypotenuse
4/5 adjasent over hypotenuse
tan= opposite over adjasent which is 3/4
Step-by-step explanation:
Write the equation of the line from the graph(serious answers only pls)
Answer:
x = -3
Step-by-step explanation:
Here, this is a vertical line
What this mean here is that the x-value remains constant irrespective of the y value
For all the y values, we have a single x-value
so what this mean is to simply locate the x-axis. value and equate it to x
We have this as;
x = -3
Find the coordinates of the other endpoint when given midpoint (point M) and one of the endpoints (point P). P=(3,5) and M=(-2,0)
Answer:
About Points
S = (x,y) searched point (it will be in the third quadrant )
M = (-2,0) Midpoint | SP |
P = (3,5) one end of the segment | SP |
You have to draw Cartesian.
we set in a point M and P. We both points by a simple and we extend it for the third quarter of the system. Compass measure the distance from the point M to the point P. From the point M we set a compass point S. Figure attached. Received point S = ( -7 , -5 ) . It sought a point that calculate .
We use the information that | SM | = | MP |
Answer : S = (-7,-5)
Step-by-step explanation:
[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad \underline{Q}(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x+3}{2}~~,~~\cfrac{y+3}{2} \right)=\stackrel{M}{(-2,0)}\implies \begin{cases} \cfrac{x+3}{2}=-2\\[1em] x+3=-4\\ \boxed{x = -7}\\[-0.5em] \hrulefill\\ \cfrac{y+3}{2}=0\\[1em] y+3=0\\ \boxed{y=-3} \end{cases}[/tex]
SOMEONE HELP ME !!!
The side length of a smaller square is one-third the side length of a larger square.ee
the following statements describes the area of the smaller square?
F The area of the smaller square is I the area of the larger square.
27
G The area of the smaller square is 172 the area of the larger square.
H The area of the smaller square is the area of the larger square.
1 The area of the smaller square is
the area of the larger square,
3
1 / 2
SOMEONE HELP ME !!!
Answer:
H
Step-by-step explanation:
lets say the first big square has side s, so the area will be s²
then the side of the small square is s/3, and the area is (s/3)²= s²/3² =s²/9
the area of the smaller square is 1/9 smaller than the area of the big square
x = 4y + 3, 2x + y = -3
System of Equations
Answer:
(- 1, - 1 )
Step-by-step explanation:
Given the 2 equations
x = 4y + 3 → (1)
2x + y = - 3 → (2)
Substitute x = 4y + 3 into (2)
2(4y + 3) + y = - 3 ← distribute parenthesis and simplify left side
8y + 6 + y = - 3
9y + 6 = - 3 ( subtract 6 from both sides )
9y = - 9 ( divide both sides by 9 )
y = - 1
Substitute y = - 1 into (1) for corresponding value of x
x = 4(- 1) + 3 = - 4 + 3 = - 1
solution is (- 1, - 1 )
Write the following phrase as an expression c less than 27
A C +27
B C -27
C c/27
D 27 - C
Answer:
(D) 27 - C
Step-by-step explanation:
The "less than" means we are subtracting C from 27, so 27 - C.
Hope it helps (●'◡'●)
Find the value of the constant a for which the polynomial x^3 + ax^2 -1 will have -1 as a root. (A root is a value of x such that the polynomial is equal to zero.)
Answer:
[tex]{ \bf{f(x) = {x}^{3} + {ax}^{2} - 1 }} \\ { \tt{f( - 1) : {( - 1)}^{3} + a {( - 1)}^{2} - 1 = 0}} \\ { \tt{f( - 1) : a - 2 = 0}} \\ a = 2[/tex]
The polynomial function [tex]$x^3 + ax^2 -1[/tex] will have -1 as a root at the value of
a = 2.
What is a polynomial function?A polynomial function exists as a function that applies only non-negative integer powers or only positive integer exponents of a variable in an equation like the quadratic equation, cubic equation, etc.
Given: A root exists at a value of x such that the polynomial exists equivalent to zero.
Let, the polynomial equation be [tex]$x^3 + ax^2 -1[/tex]
then [tex]$\mathbf{f}(\mathbf{x})=\mathbf{x}^{3}+a \mathbf{x}^{2}-\mathbf{1}$[/tex]
Put, x = -1, then we get
[tex]$\mathbf{f}(-1)=(-1)^{3}+\mathrm{a}(-1)^{2}-1=0$[/tex]
f(-1) = a - 2 = 0
a = 2
Therefore, the value of a = 2.
To learn more about polynomial function
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the area of the rectangle is 48cm^2
show that x satisfies the equation x^2 + 7x -78 = 0
Answer:
No its doesn't satisfy the equation.
[tex]{ \bf{area = 2(l + w)}} \\ { \tt{48 = 2((x + 10) + (x - 3))}} \\ { \tt{24 = 2x + 7}} \\ 2x = 17 \\ x = 8.5 \\ \\ { \bf{in : \: {x}^{2} + 7x - 78 = 0 }} \\ x = 6 \: \: and \: \: - 13[/tex]
Can someone please help me with this?
Can someone please be generous & help I’ve been struggling all night
Answer:
Slope-intercept
y = 3/4(x) - 7
Point slope
y -5= 3/4(x - 16)
Step-by-step explanation:
In slope-intercept
We have the general slope intercept as;
y = mx + b
where m is the slope and b is the y-intercept
in this case, m = 3/4 and b = -7
So we have;
y = 3/4(x) - 7
In point-slope
we have the general form as;
y-y1 = m(x-x1)
So what we have is as follows;
y -5= 3/4(x - 16)
Where we have (x1,y1) = (16,5)
A point P(3, k) is first transformed by E¹[0, 2] and then by E²[0,3/2] so that the final image is (9, 12), find the value of k.
Hello,
The first transform E1 is the homothetie of center (0,0) and ratio=2
The second transform E2 is the homothetie of center (0,0) and ratio=3/2
P=(3,k)
P'=E1(P)= E1((3,k))=(2*3,2*k)=(6,2k)
P''=E2(P')=E2(6,2k)=(3/2*6,3/2*2*k)=(9,3k)=(9,12)
==> 3k=12
k=4
Which equation represents a line that passes through (2,-) and has a slope of 3?
Oy-2 = 3(x + 2)
Oy - 3 = 2(x+)
Oy+ 1 = 3(x - 2)
Oy+ < = 2(x-3)
Help?
The equation of the line is y + 1 = 3(x - 2).
The correct option is (3).
What is an equation?Equation: A statement that two variable or integer expressions are equal. In essence, equations are questions, and the motivation for the development of mathematics has been the systematic search for the answers to these questions.
As per the given data:
The line passes through the point (2, -1)
slope of the given line is 3
By using the slope intercept form of line:
y = mx + c
where m is the slope
c is the y intercept
The line passes through the point (2, -1) so substituting the point in the equation also m = 3
y = 3x + c
-1 = 3(2) + c
c = -7
The equation of the line now can be written as:
y = 3x - 7
y + 1 = 3x - 7 + 1
y + 1 = 3(x - 2)
Hence, the equation of the line is y + 1 = 3(x - 2).
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Se tienen tres tanques de la misma altura (5 metro) pero sus formas son diferentes. El primero es de base circular de 3 metros de radio, el segundo su base es elíptica y su eje mayor y menor mide 6 y 4 metros respectivamente. El último tanque es un cono invertido, con una base circular de 3 metros de radio. Si en todos se llena agua con un caudal de 1.5 litros por cada segundo, determine la razón de cambio de la altura respecto al tiempo.
Answer:
1.-dh/dt = 5.31*10⁻⁵ m/seg
2.-dh/dt = 1.99*10⁻⁵ m/seg
3.-dh/dt = 1.59*10⁻⁴ m/seg
Step-by-step explanation:PREGUNTA INCOMPLETA NO SE INDICAN LAS FORMAS DE LOS TANQUES.
Asumiremos que los tres tanques son:
el primero cilindro recto de Vc = π*r²*h ( r es radio de la base y h la altura)
el segundo asumiremos que es eliptico recto de Ve = π*a*b*h aqui a y b son los ejes de la elipse y h la altura
El tercero es un cono invertido Vco = 1/3 *π*r²*h ( r es el radio de la base.
1.-Caso del cilindro
Vc = π*r²*h
Derivando en ambos miembros de la expresión tenemos:
dV(c) / dt = π*r²*dh/dt
Sustituyendo
1.5 Lts/seg = 3.14 * (3)²*dh/dt
1.5/1000 m³/seg = 28.26 m² dh/dt
1.5/ 28260 m = dh/dt
Despejando dh/dt
dh/dt = 1.5 / 28260 = 5.31*10⁻⁵ m/seg
dh/dt = 5.31*10⁻⁵ m/seg
2.-La elipse
Ve = π*a*b*h
Aplicando el mismo procedimiento tenemos:
DVe/dt = 1.5 Lts/seg = π* 6*4* dh/dt
1.5 /1000 = 75.36 *dh/dt
dh/dt = 1.5 / 75360 m/seg
dh/dt = 1.99*10⁻⁵ m/seg
3. El cono invertido
Vco = (1/3)*π*r²*h
DVco/dt = (1/3)*π*r²*dh/dt
1.5/1000 = 9.42 *dh/dt
dh/dt = 1.5/9420
dh/dt = 1.59*10⁻⁴ m/seg
Which long division problem can be used to prove the formula for factoring the difference of two perfect cubes?
Answer:
a-b divided into [tex]a^{3} + 0a^{2} b + 0 ab^{2} - b^{3}[/tex]
the reason is that the (a-b) vs (a+b) in the "SOAP"
same, opposite, always a plus the "-" in the "a-b" has to match the
sign between the two cubes
Step-by-step explanation:
given the nth term of geometric expression is (as in the diagram)
a) state the value of k
b) the first term of progression
Step-by-step explanation:
a) k = 1
b) geometric progression formula:
Tn = ar^(n-1)
first term, a = 3/2
What is the slope of the line whose equation is y-4=5/2(x-2)?
Answer:
[tex]slope = \frac{ - 1 - 4}{0 - 2} \\ = \frac{ - 5}{ - 2} \\ = { \tt{ \frac{5}{2} }}[/tex]
sue has 18 pieces of candy
tony has 18 pieces of candy
sue then gives some to tony
sue then eats five of hers
tony eats half of his
write the expressions for the number of pieces candy sue and tony now have?
Answer:
Sue candy = 13 - x
Tony candy = 9 + 1/2x
Step-by-step explanation:
Sue candy = 18
Tony candy = 18
Let x = some candy gives to tony
Sue candy = 18 - x
Tony candy = 18 + x
sue then eats five of hers
Sue candy = 18 - x - 5
= 13 - x
tony eats half of his
Tony candy = 1/2(18 + x)
= 18/2 + x/2
= 9 + 1/2x
Expressions for the number of pieces candy sue and tony now have:
Sue candy = 13 - x
Tony candy = 9 + 1/2x
The volume of a cone is 329.6 cubic inches, and the height is 5.4 inches. Which of the following is the closest to the radius r of the cone, in inches?
Answer:
329.6=1/3×16.97r
5.66r=329.6/÷5.66
r=58.23
If g(x) = 2 |x| − 1, what is g(−2.3)?
Answer:
g(-2.3) = 3.6
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
FunctionsFunction NotationStep-by-step explanation:
Step 1: Define
Identify
g(x) = 2|x| - 1
Step 2: Evaluate
Substitute in x [Function g(x)]: g(-2.3) = 2|-2.3| - 1Absolute values: g(-2.3) = 2(2.3) - 1Multiply: g(-2.3) = 4.6 - 1Subtract: g(-2.3) = 3.6If A =
[tex]if \: a \: = \binom{53}{24} \: and \: b = \binom{32}{10} then \: prove \: that |ab| = |a| . |b| [/tex]
and B = Prove that |AB| = |A| . |B|
