Answer:
[tex]\large \boxed{\sf B. \ 34}[/tex]
Step-by-step explanation:
[tex]5(14 - 2^3 ) +8 \div 2[/tex]
[tex]\sf Solve \ brackets.[/tex]
[tex]2^3 =8[/tex]
[tex]5(14 - 8 ) +8 \div 2[/tex]
[tex]14-8=6[/tex]
[tex]5(6 ) +8 \div 2[/tex]
[tex]\sf Multiply \ and \ divide.[/tex]
[tex]5(6)=30[/tex]
[tex]8 \div 2 = 4[/tex]
[tex]30 +4[/tex]
[tex]\sf Add.[/tex]
[tex]34[/tex]
Answer: 34
Step-by-step explanation: It's very easy to make mistakes in order of operations problems if you try to do too much of the problem in your head.
It really is worth the extra time it takes to write out every step.
P E M D A S
Parenthses
Exponents
Multiplication/Division
Addition/Subtraction
In this problem, simplify (14 - 2³) first
because it's located inside the parenthses.
2³ is 8 so our second step reads 5(14 - 8) + 8 ÷ 2.
14 - 8 is 6 so we have 5(6) + 8 ÷ 2.
Now multiplication and division are based on order of appearance.
Since multiplication comes first, we do it first.
5(6) is 30 so we have 30 + 8 ÷ 2.
Now we can do the division.
8 ÷ 2 is 4 and we have 30 + 4 which is 34.
A man traveled to his country home, a distance of 150 miles and then back. His average rate of speed going was 50 miles an hour and his average return speed was 30 miles per hour. His average rate of speed for the entire trip was Need help will mark brainlist
Answer:
37.5 mi/h
Step-by-step explanation:
time = distance / speed
On the trip 'going', the time was (150 mi)/(50 mi/h) = 3 h.
On the return trip, the time was (150 mi)/(30 mi/h) = 5 h.
__
speed = distance / time
The average speed for the whole trip was ...
speed = (150 mi +150 mi)/(3 h +5 h) = (300 mi)/(8 h) = 37.5 mi/h
His average rate of speed was 37.5 miles per hour.
For a quadratic function y = ax² + bx + c, suppose the constants a, b, and c are consecutive terms of a geometric sequence. Show that the function does not cut the x axis.
Hello, because of the geometric sequence we can say that:
[tex]\alpha = \dfrac{b}{a}=\dfrac{c}{b}\\\\\dfrac{c}{a}=\dfrac{c*b}{a*b}=\dfrac{c}{b}\dfrac{b}{a}=\alpha^2\\\\\text{So the equation becomes.}\\\\ax^2+bx+c=0<=>x^2+\dfrac{b}{a}x+\dfrac{c}{a}=0\\\\<=>x^2+\alpha x+ \alpha^2=0\\\\\Delta=b^2-4ac = \alpha^2-4\alpha^2=-3\alpha^2 < 0[/tex]
So there is no real root, so the function does not cut the x axis.
Thank you
For the given quadratic function, the x-axis is not cut by the function because there is no true root.
What is a quadratic function?To determine values for various parameters, quadratic functions are employed in a variety of scientific and engineering disciplines. A parabola is used to graphically illustrate them. The orientation of the curve is defined by the highest degree factor.
As per provided data in question,
α = b/a = c/b
c/a = (c × b)/(a × b) = (c/b) (b/a) = α²
For the equation,
ax² + bx + c = 0
x² + b/a(x) + c/a = 0
⇒ x² + ax + α² =0
Δ = b² - 4 ac = α² - 4α²
Δ = -3α² < 0, which means that no real root is there.
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Finding which number supports the idea that the rational numbers are dense in the real numbers.
Answer:A terminating decimal between -3.14 and -3.15.
Step-by-step explanation:
A natural number includes non-negative numbers like 5, 203, and 18476.
It is encapsulated by integers, which include negative numbers like -29, -4, and -198.
Integers are further encapsulated by rational numbers, which includes terminating decimals like 3.14, 1.495, and 9.47283.
By showing a terminating decimal between -3.14 and -3.15, you are showing that rational numbers include integers (because integers include negative numbers.
If 2x3 – 4x2 + kx + 10 is divided by (x + 2), the remainder is 4. Find the value of k using remainder theorem. Please help :)
The polynomial remainder theorem states that the remainder of the division of a polynomial [tex]P(x)[/tex] by [tex]x-a[/tex] is equal to [tex]P(a)[/tex].
Therefore
[tex]P(-2)=4\\2\cdot(-2)^3 - 4\cdot(-2)^2 + k\cdot(-2) + 10=4\\-16-16-2k=-6\\-2k=26\\k=-13[/tex]
Is a 118 supplementary or complementary?pls ASAP!!
Answer:
[tex]\huge\boxed{Supplementary \ Angle}[/tex]
Step-by-step explanation:
118 is a supplementary angle. It is not a complementary angle because complementary angles add up to 90 and 118 is greater than 90 degrees. So, 118 is a supplementary angle and it is an angle adding up to 180 degrees with any other angle measuring 62 degrees.
Answer:Supplementary
Step-by-step explanation:You should remember that complementary refers to any number from 0-90 and supplementary refers to any number from 90 onwards..
Hereby giving the answer as ''Supplementary''
SP=2x+3, and LN=5x−14. Find SP.
Answer:
43
Step-by-step explanation:
Using Thales theorem:
● SP/LN = RP /RN
Notice that RN = 2×RP
● SP/LN = RP/2RP
● SP /LN = 1/2
● SP / (5x-14) = 0.5
● (2x+3)/(5x-14) = 0.5
● 2x+3 = 0.5(5x-14)
● 2x+3 = 2.5x -7
Add 7 to both sides
● 2x+3+7 = 2.5x-7+7
● 2x+10 = 2.5x
Sustract 2x brom both sides
● 2x+10-2x = 2.5x-2x
● 10 = 0.5x
Multiply both sides by 2
● 10×2 = 0.5x×2
● 20 = x
Replace x with 20 in Sp expression:
● SP = 2x+3
● SP = 2×20+3
● SP = 43
I don’t really understand this
Answer
pretty sure its a or c, sorry I cant be more specific
Step-by-step explanation:
PLS ANSWER BRAINLIST AND A THANK YOU WILL BE GIVEN!!!!
Answer:
[tex]\huge\boxed{Option \ D}[/tex]
Step-by-step explanation:
4x + 5x = 180 [They are angles on a "straight" line so they will add up to 180 degrees)
Answer:
D
Step-by-step explanation:
The sum of angles that are formed on a straight line is 180.
4x + 5x = 180
Shane biked 1 mile less than three times the number of miles Lissette biked. Shane biked a total of 7 miles. Write an equation to determine how many miles Lissette biked.
7 = 3x − 1
x − 1 = 3(7)
x over seven = 3(1)
7 + 3x = 1
Answer
Equation : x + 1 + 3x = 7
Miles Lissette biked : 3/2 miles
Step-by-step explanation:
Step 1: Determine the total number of miles biked.
From my understanding. 7 miles is the total number of miles biked by both.
Step 2: Assume the values
Miles Lissette biked = x
Miles Shane biked = 1 + 3x
Step 3: Add miles biked by Lissette and Shane which will be equal to total miles.
Equation for miles Lissette biked: x + 1 + 3x = 7
4x + 1 = 7
x = 6/4
Step 4: Simplify
x = 6/4
x = 3/2
Therefore, the equation for miles Lissette biked is x + 1 + 3x = 7 and Lissete biked for 3/2 miles.
Hope it helped if yes mark me BRAINLIEST
Tysmm
Answer:
7 = 3x - 1
Step-by-step explanation:
Miles Shane biked = y
Miles Lissette biked = x
The equation is
(x ⋅ 3) - 1 = y
And we know y = 7, so
(x ⋅ 3) - 1 = 7
3x - 1 = 7
Please answer this question now
Answer:
Approximately 439.6 square millimeters.
Step-by-step explanation:
The formula for the surface area of a cone is the following:
[tex]A=\pi r^2+\pi r l[/tex]
Where, r is the radius and l is the slant height.
The radius is 7 and the slant height is 13. We also use 3.14 for π Thus:
[tex]A=(3.14)(7)^2+(3.14)(7)(13)\\\text{Use a Calculator}\\A\approx 439.6[/tex]
Answer:
292.77
Step-by-step explanation:
πr(r+[tex]\sqrt{h2+r2}[/tex])
13 x 2 = 26
7 x 2 = 14
26 + 14 = 40
[tex]\sqrt{40}[/tex] = 6.32
7 + 6.32 = 13.32
3.14 x 7 = 21.98
21.98 x 13.32 =
292.77
How to work out the medium in maths
Answer:
To find the median you cross off the first few numbers and the last few until you get to the middle then when you get the middle number that will be your median
Step-by-step explanation:
Answer:
Below.
Step-by-step explanation:
It's the middle value of a list of numbers arranged in order.
For example the median of the list 1 2 3 4 5 is 3.
If there are an even number of values, the median is the mean of the middle two. For example:
1 3 4 5 7 9:
The middle 2 numbers are 4 and 5 so
the median is (4 + 5) / 2 = 4.5
Please help!
Suppose that [tex]\alpha[/tex] is inversely proportional to [tex]\beta[/tex]. If [tex]\alpha=4[/tex] when [tex]\beta=9[/tex], find [tex]\alpha[/tex] when [tex]\beta=-72[/tex]
Answer:
The answer is
[tex] \alpha = - \frac{1}{2} [/tex]Step-by-step explanation:
From the question
[tex]\alpha[/tex] is inversely proportional to [tex]\beta[/tex] is written as
[tex] \alpha = \frac{k}{ \beta } [/tex]where k is the constant of proportionality
When
[tex]\alpha[/tex] = 4[tex]\beta[/tex] = 9Substituting the values into the formula
we have
[tex]4 = \frac{k}{9} [/tex]
cross multiply
k = 4 × 9
k = 36
So the formula for the variation is
[tex] \alpha = \frac{36}{ \beta } [/tex]
when
[tex]\beta[/tex] = - 72
That's
[tex] \alpha = \frac{36}{ - 72} [/tex]
Simplify
We have the final answer as
[tex] \alpha = - \frac{ 1}{2} [/tex]Hope this helps you
Dena uses 7.4 pints of white paint and blue paint to paint her bedroom walls. 2/5 of this amount is white paint, and the rest is blue paint. How many pints of blue paint did she use yo paint her bedroom walls
Answer:
4.44 pints
Step-by-step explanation:
7.4 times 3/5
A triangle and the coordinates of its vertices is shown in the coordinate plane below. Enter the area of this triangle in square units, rounded to the nearest tenth. square units
Answer:
22 units²
Step-by-step explanation:
1/2b*h=area
You can either count the units or use the distance formula.
[tex]d = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]
b = 4 units
h = 11 units
area = (1/2*4)*11 = 22 units²
The subject is operations on rational expressions.
The instructions are add or subtract the following expressions. Remember to find a common denominator when necessary. Reduce all answers to lowest terms.
Answer:
[tex]\frac{2(x-1)(2x+9)}{(x-3)(x-2)}[/tex]
Step-by-step explanation:
[tex]\frac{4x}{(x-3)}+\frac{6}{(x+2)}[/tex]
= [tex]\frac{4x(x+2)}{(x-3)(x+2)}+\frac{6(x-3)}{(x+2)(x-3)}[/tex]
Now we have done the denominators of each term of the expression equal.
Further we add the terms,
[tex]\frac{4x(x+2)}{(x-3)(x+2)}+\frac{6(x-3)}{(x+2)(x-3)}[/tex]
= [tex]\frac{4x(x+2)+6(x-3)}{(x-3)(x+2)}[/tex]
= [tex]\frac{4x^{2}+8x+6x-18}{(x-3)(x+2)}[/tex]
= [tex]\frac{4x^{2}+14x-18}{(x-3)(x-2)}[/tex]
Now factorize the numerator of the fraction.
4x² + 14x - 18 = 2(2x² + 7x - 9)
= 2(2x² + 9x - 2x - 9)
= 2[x(2x + 9) - 1(2x + 9)]
= 2(x - 1)(2x + 9)
Therefore, [tex]\frac{2(x-1)(2x+9)}{(x-3)(x-2)}[/tex] will be the answer.
Given that ∆MTW ≅ ∆CAD, which angles are corresponding parts of the congruent triangles? ∠W ≅ ∠C ∠W ≅ ∠D ∠W ≅ ∠A
Answer:
The Answer would be ∠W ≅ ∠C
Step-by-step explanation:
Only one that is congruent
The measure of the angle ∠TWM is congruent to the measure of the angle ∠ADC. Therefore, the correct option is B.
What are congruent triangles?Two triangles are said to be congruent if their corresponding sides and angles are equal.
A triangle is a three-sided polygon with three edges and three vertices in geometry.
Given that the triangle ∆MTW is congruent to the triangle ∆CAD.
So, we have
∠MTW ≅ ∠CAD
∠WMT ≅ ∠DCA
∠TWM ≅ ∠ADC
If two triangles are equivalent, the ratio of matching sides will stay constant.
The proportion of the point ∠TWM is harmonious with the proportion of the point ∠ADC.
Therefore, at that point, the right choice is B.
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Point B is on line segment AC. Given BC=9 and AB=11, determine the length AC.
Answer:
20
Step-by-step explanation:
If point B is on line segment AC, then we know for sure AB + BC = AC.
To understand this better, draw a line segment, then put a point anywhere on the line segment. There are two line segment divided by that point. If you combine those two line segments then you have your original figure.
So 11 + 9 = 20.
Jonas needs a cell phone. He has a choice between two companies with the following monthly billing policies. Each company’s monthly billing policy has an initial operating fee and charge per text message. Sprint charges $29.95 monthly plus .15 cents per text, AT&T charges $4.95 monthly plus .39 cents per text. Create equations for the two cell phone plans.
Answer:
Since both companies have a different plan, two equations are created to determine which company Jonas should choose with respect to the number of messages sent.
Step-by-step explanation:
- Sprint = $ 29.95 * X (0.15)
- AT & T = $ 4.95 * X (0.39)
One dollar equals 100 cents, so 0.15 cents equals $ 0.0015 dollars.
- Sprint = $ 29.95 * X (0.0015)
- AT & T = $ 4.95 * X (0.0039)
Si Jonas envía 500 mensajes de texto el valor mensual de cada empresa sería de:
- Sprint = $ 29.95 * 500 (0.0015) = 22.46 dollar per month.
- AT & T = $ 4.95 * 500 (0.0039) = 9.65 dollar per month.
The company Jonas should choose is AT&T.
AT&T also charges a little more per number of text messages, but since the phone's value is so low it would take thousands of text messages to compare to Sprint's monthly value.
A trader buys tea for $1200 and sells it for $1500. Per sack of tea he makes a profit of $50. How many sacks of tea did he have?
Answer:
6 sacks
Step-by-step explanation:
Buying Price = $1200
Selling Price = $1500
Total profit = Selling price - Buying Price
= $1500 - $1200
= $300
Given that the profit on each sack of tea is $50
Number of Sacks of Tea = Total Profit ÷ profit per sack
= $300 ÷ 50
= 6 sacks
The number of sacks of tea he has is 6.
The first step is to determine the total profit earned by the trader. Profit is the selling price less the cost price.
Profit = selling price - cost price
$1500 - $1200 = $300
The second step is to divide the total profit by the profit made per sack of tea.
Number of sacks = $300 / $50 = 6
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Bob has taken out a loan of $15,000 for a term of 48 months (4 years) at an interest rate of 6.5%. Using the amortization table provided, what will be his total finance
charge over the course of his loan?
Monthly Payment per $1,000 of Principal
Rate 1 Year 2 Years 3 Years 4 Years 5 Years
6.5% $86.30 $44.55 $30.65 $23.71 $19.57
7.0% $86.53 $44.77
$30.88
$23.95
$19.80
7.5% $86.76 $45.00
$31.11
$24.18
$20.04
8.0% $86.99 $45.23
$31.34
$24.41
$20.28
8.5% $87.22 $45.46
$24.65
$24.65
$20.52
9.0% $87.45 $45.68
$31.80
$24.89
$20.76
A.
$355.65
O
B.
$975.00
C.
$1,682.40
D.
$2,071.20
E. $17,071.20
Reset
Next
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Answer:
D. $2071.20
Step-by-step explanation:
The table tells you that Bob's monthly payment on a 4-year loan at 6.5% will be $23.71 per thousand borrowed. The sum of those 48 payments is ...
48 × $23.71 = $1138.08
That means, Bob pays $138.08 in total finance charge for each $1000 he borrows. He is borrowing 15 times $1000, so his total finance charge will be ...
finance charge = 15 × $138.08 = $2071.20 . . . matches choice D
I need help answering these two questions
Answer:
Step-by-step explanation:
1. Area=3b*b=300 inches^2
3b^2=300
:3 :3
b^2=100
b=V100inches ^2
b=10 inches
2. Area=4b*3b
so 12b^2=4800
:12 :12
b^2=400
b=V400
b=20 inches
A ship travels due north for 100 miles from point C to point A. From point A the ship travels to point B at 60° east of north. From point B, the ship returns to point C heading 45° west of south. What approximate distance did the ship travel from point A to point B? How far does it travel in total?
Answer:
AandB=80miles
Total=240miles
Step-by-step explanation:
Draw the figure first indicating the figures then find the distance each degrees then find the total
The distance ship travels from A to B is 273.2 miles and total distance covered by ship is 707.82 miles.
What is laws of sines?The law of sines specifies how many sides there are in a triangle and how their individual sine angles are equal. The sine law, sine rule, and sine formula are additional names for the sine law.
The side or unknown angle of an oblique triangle is found using the law of sine. Any triangle that is not a right triangle is referred to as an oblique triangle. At least two angles and their corresponding side measurements should be used at once for the sine law to function.
Given distance from C to A = 100 miles north
From B to A ship travels 60° east of north,
and From B to C 45° west of south,
the figure for problem is attached,
from figure we can calculate the angles of A, B and C
so ∠A makes supplementary with 60°
∠A + 60° = 180°
∠A = 120°
for ∠B we need to draw an imaginary perpendicular on the line extending from A, we get
∠B + 45° + 30° = 90° (30° is angle of imaginary right triangle)
∠B = 90 - 75 = 15°
and ∠C can be found by,
∠A + ∠B + ∠C = 180°
∠C = 180 - 15 - 120
∠C = 45°
now use sine formula for triangles,
sinA/a = sinB/b = sinC/c
where A, B and C are angles of triangle and a, b and c are length of opposite side of angle A, B and C respectively.
a = BC, b = AC, and c = AB
so
sinA/BC = sinB/AC = sinC/AB
we have AC = 100 miles
substitute the values
sinC/AB = sinB/AC
sin(45)/AB = sin(15)/100
AB = 100/(√2sin(15))
AB = 100/0.3659
AB = 273.298 miles
and sinA/BC = sinB/AC
BC = AC sinA/sinB
BC = 100(sin 120/sin15)
BC = 100(0.866/0.2588)
BC = 100 x 3.3462
BC = 334.62 miles
total distance = AB + BC + AC
total distance = 334.62 + 273.2 + 100
total distance = 707.82 miles
Hence the distance from A to B is 273.2 miles and total distance is 707.82 miles.
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What is the reflection image of
(5,−3)across the line
y=x
Answer: The Answer is (-5,-3)
hope so my answer is correct
Step-by-step explanation:
Which of the following is an example of the difference of two squares?
A x2−9
B x3−9
C (x+9)2
D (x−9)2
I know the answer is either A or B i might be wrong tho pls help im not sure.
Answer:
1) What does it mean when a polynomial equation is in standard form?
All terms are on one side of the equation, and zero is on the other side.
2) When factoring 6x2−7x−20 by grouping, how should the middle term be rewritten?
It should be written as 8x−15x.
3) Is the given equation a quadratic equation? Explain.
x(x−6)=−5
The equation is a quadratic equation because there is an x2-term.
4) Which of the following factored forms given below represent the correct factorization of the trinomial x2+10x+16?
(2+x)(8+x)
5) Which of the following is an example of the difference of two squares?
x2−9
Step-by-step explanation:
I hope this helps you out ☺
A binomial whose first term and second term can be squared, and has a subtraction sign between both squared terms represents the difference of two squares, an example of the difference of two squares is:
A. [tex]x^2 - 9[/tex]
Recall:
Difference of two squares is when you have a binomial that is expressed as [tex]x^2 - y^2[/tex].The first and second term of the binomial will have an exponential of 2 wile the subtraction sign will be in the middle.Thus, from the options given, option A: [tex]x^2 - 9[/tex] is an example of a binomial that is the difference of two squares.
This is why:9 can be expressed as [tex]3^2[/tex].
In summary, a binomial whose first term and second term can be squared, and has a subtraction sign between both squared terms represents the difference of two squares, an example of the difference of two squares is:
A. [tex]x^2 - 9[/tex]
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The product of 2 rational numbers is -16/9 . If one of the numbers is -4/3 find the other plz fast
Answer:
4/3
Step-by-step explanation:
let the other number be x.
-4/3 x=-16/9
x=-16/9×-3/4=4/3
Chantal is driving on a highway at a steady speed. She drives 55 miles every hour. Let d be the total distance in miles and let h be the number of hours.
Write an equation that represents the situation. I'll give out the brainliest if you get it right.
Answer:
[tex] d = 55h [/tex]
Step-by-step explanation:
We are given that Chantal drives at a constant speed of 55 miles per hour.
If, d represents the total distance in miles, and
h represents number of hours, the following equation can be used to express the given situation:
[tex] d = 55h [/tex]
For every hour, a distance of 55 miles is covered.
Thus, if h = 1, [tex] d = 55(1) = 55 miles [/tex]
If h = 2, [tex] d = 55(2) = 110 miles [/tex].
Therefore, [tex] d = 55h [/tex] , is an ideal equation that represents the situation given in the question above.
in exponential growth functions, the base of the exponent must be greater than 1. How would the function change if the base exponent were 1? How would the function change if the base of the exponent were between 0 and 1?
Answer:
GREAT QUESTION!!
Step-by-step explanation:
Bases of exponential functions CANNOT be 1.
It the base was between 0 and 1, .25 for example, then it would be exponential decay, because as x would increase y would decrease.
Just search up exponential decay to see what it looks like, or type in y=.25^x in google search bar.
if this helped, Please give brainly, I need it! Thank you!
Answer:
If the base of the exponent were 1, the function would remain constant. The graph would be a horizontal line. If the base of the exponent were less than 1, but greater than 0, the function would be decreasing.
Step-by-step explanation:
If the base were 1, the function would be constant.
If the base were 1, the graph would be a horizontal line.
If the base were between 0 and 1, the function would be decreasing.
30 PTS!! Can someone PLEASE rephrase this? The compass and straightedge is more important in constructing geometric structures than other drawing tools such as rulers and protractors. Because steps taken with a compass and straightedge cannot be seen at first glance and this situation become a problem for students.
Answer:
Step-by-step explanation:
This study investigated three mathematics teachers' construction process of geometric structures using compass and straightedge. The teacher-student-tool interaction was analysed. The study consists of the use of a compass and straightedge by the teachers, the ideas of the teachers about their use, and the observations regarding the learning process during the construction of the geometric structures. A semi-structured interview was conducted with the teachers about the importance of the use of a compass and straightedge to construct geometric structures. It was found that teachers taught compass and straightedge constructions in a rote manner where learning is little more than steps in a process. The study concludes with some suggestions for the use of a compass and straightedge in mathematics classes based on the research results. SUMMARY Purpose and significance: For more than 2,000 years, the way in which geometric structures could be constructed with the help of compasses and straightedges has caught the attention of mathematicians. Nowadays, mathematics curriculums place an emphasis on the use of the compass and straightedge. The compass and straightedge is more important in constructing geometric structures than other drawing tools such as rulers and protractors. Because steps taken with a compass and straightedge cannot be seen at first glance and this situation become a problem for students. However, 'doing compass and straightedge construction early in the course helps students to understand properties of figures'
kinda confused buttttt anyone know this?
Answer:
Hey there!
The overlapping part is the product.
Thus, the product is 1/8.
Hope this helps :)
Polygon ABCD is defined by the points A(-4, 2), B(-2, 4), C(1, 3), and D(2, 2). Match the coordinates of the points of the transformed polygons to their correct values. the coordinates of D′ if polygon ABCD rotates 90° counterclockwise to create A′B′C′D′ (-2, 2) the coordinates of C″ if polygon ABCD rotates 90° clockwise to create A″B″C″D″ (4, -2) the coordinates of A′′′ if polygon ABCD rotates 180° clockwise to create A′′′B′′′C′′′D′′′ (3, -1) the coordinates of B″ if polygon ABCD rotates 270° counterclockwise to create A″B″C″D″ (4, 2)
Answer:
The coordinates of D′ if polygon ABCD rotates 90° counterclockwise to create A′B′C′D′ is at (-2, 2)
The coordinates of C″ if polygon ABCD rotates 90° clockwise to create A″B″C″D″ is at (3, -1)
The coordinates of A′′′ if polygon ABCD rotates 180° clockwise to create A′′′B′′′C′′′D′′′ is at (4, -2)
The coordinates of B″ if polygon ABCD rotates 270° counterclockwise to create A″B″C″D″ is at (4, 2)
Step-by-step explanation:
A transformation is the movement of a point from its initial position to a new position. If a shape is transformed, all its points are also transformed. Types of transformation are reflection, rotation, dilation and translation.
Given Polygon ABCD is defined by the points A(-4, 2), B(-2, 4), C(1, 3), and D(2, 2).
If a point X(x, y) is rotated 90° counterclockwise, the new location X' is at (-y, x)
If a point X(x, y) is rotated 90° clockwise, the new location X' is at (y, -x)
If a point X(x, y) is rotated 180° clockwise, the new location X' is at (-x, -y)
If a point X(x, y) is rotated 270° counterclockwise, the new location X' is at (y, -x)
The coordinates of D′ if polygon ABCD rotates 90° counterclockwise to create A′B′C′D′ is at (-2, 2)
The coordinates of C″ if polygon ABCD rotates 90° clockwise to create A″B″C″D″ is at (3, -1)
The coordinates of A′′′ if polygon ABCD rotates 180° clockwise to create A′′′B′′′C′′′D′′′ is at (4, -2)
The coordinates of B″ if polygon ABCD rotates 270° counterclockwise to create A″B″C″D″ is at (4, 2)
Answer:
Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.
If a point A(x, y) is rotated 90° counterclockwise, the new point is at A'(-y, x).
If a point A(x, y) is rotated 90° clockwise, the new point is at A'(y, -x). If a point A(x, y) is rotated 180° counterclockwise, the new point is at A'(-x, -y).
If a point A(x, y) is rotated 270° counterclockwise, the new point is at A'(y, -x).
Polygon ABCD is defined by the points A(-4, 2), B(-2, 4), C(1, 3), and D(2, 2).
The coordinates of D′ if polygon ABCD rotates 90° counterclockwise to create A′B′C′D′ is D'(-2, 2)
The coordinates of C″ if polygon ABCD rotates 90° clockwise to create A″B″C″D″ is C"(3, -1).
The coordinates of A′′′ if polygon ABCD rotates 180° clockwise to create A′′′B′′′C′′′D′′′ is A''"(4, -2)
The coordinates of B″ if polygon ABCD rotates 270° counterclockwise to create A″B″C″D″ is B"(4, 2)
