Evaluate the expression: 5 + (1 + 1)3 × 2.

Answer: Approximately 5.22%

========================================================

Work Shown:

A = true value = 13.4 seconds

B = measured value (erroneous value) = 14.1 seconds

C = percent error

C = [ (B-A)/A ] * 100%

C = [ (14.1-13.4)/(13.4) ] * 100%

C = 0.0522 * 100%

C = 5.22%

This value is approximate.

Given:

A figure of a circle.

To find:

The value of x.

Solution:

First label the given figure as shown below.

In triangle ABO,

[tex]OA=OB[/tex]                                          (Radii of same circle)

[tex]\Delta ABO[/tex] is an isosceles triangle.      (By the definition of isosceles triangle)

[tex]\angle OAB\cong \angle OBA[/tex]                               (Base angles of an isosceles triangle)

[tex]m\angle OAB=m\angle OBA[/tex]

[tex]42^\circ=m\angle OBA[/tex]

In triangle ABO,

[tex]m\angle AOB+m\angle OAB+m\angle OBA=180^\circ[/tex]      (Angle sum property)

[tex]m\angle AOB+42^\circ+42^\circ=180^\circ[/tex]

[tex]m\angle AOB=180^\circ-42^\circ-42^\circ[/tex]

[tex]m\angle AOB=96^\circ[/tex]

Now,

[tex]m\angle AOB+m\angle BOC=180^\circ[/tex]         (Linear pair)

[tex]96^\circ+x=180^\circ[/tex]

[tex]x=180^\circ-96^\circ[/tex]

[tex]x=84^\circ[/tex]

Therefore, the value of x is 84 degrees.

Answer:

Step-by-step explanation:

Add 0.32 and 0.18 to get 0.5.

0.5=0.25 - 1.95

subtract 1.95 from 0.25 to get —1.7.

0.5=—1.7

compare 0.5 and —1.7.

flase

Answer:

1min = 0.25miles

5.25miles / 0.25miles = 25 = 25minutes

Step-by-step explanation:

Hope this is right I'm not the best at worded time/distance math questions.

9514 1404 393

Answer:

  0 ≤ t < 52.5 minutes

Step-by-step explanation:

Riko will be behind Yuto until her distance traveled matches his. That is, she will be behind for ...

  0.35t < 5.25 +0.25t

  0.10t < 5.25

  t < 52.5

Riko will be behind Yuto on the interval 0 ≤ t < 52.5 minutes.

_____

Additional comment

distance = speed × time

Here, time is measured from when Riko starts riding. In addition to the 5.25 miles that Yuto has already gone, his distance will be the product of his speed (0.25 mi/min) and the travel time (t min). Then Yuto's total distance is 5.25+0.25t miles. The speed×time product is also used to find Riko's distance traveled. In her case, it is 0.35t miles.

9514 1404 393

Answer:

  (a) 6² +3² +1² +1² = 47

  (b) 5² +4² +2² +1² +1² = 47

  (c) 3³ +4² +2² = 47

Step-by-step explanation:

It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.

The approach where a cube is required can work the same way.

(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1

__

(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...

__

(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2

Answer:

17

Step-by-step explanation:

Answer:

[tex](\frac{-3}{4})^3 = -\frac{27}{64}[/tex]

Step-by-step explanation:

Given

[tex](\frac{-3}{4})^3[/tex]

Required

Evaluate

The expression can be represented as:

[tex](\frac{-3}{4})^3 = (\frac{-3}{4})*(\frac{-3}{4})*(\frac{-3}{4})[/tex]

So, we have:

[tex](\frac{-3}{4})^3 = \frac{-3*-3*-3}{4*4*4}[/tex]

[tex](\frac{-3}{4})^3 = \frac{-27}{64}[/tex]

Rewrite as:

[tex](\frac{-3}{4})^3 = -\frac{27}{64}[/tex]

Answer:

B  -27/64

Step-by-step explanation:

Answer:

I think its 43%

Explanation

math

The probability of Pier choosing a boy is 0.43 or 43%.

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

Example:

The probability of getting a head in tossing a coin.

P(H) = 1/2

We have,

The total number of students in the class is:

13 boys + 17 girls

= 30 students

The probability of Pier choosing a boy is the number of boys in the class divided by the total number of students:

Probability of choosing a boy.

= number of boys / total number of students

Probability of choosing a boy.

= 13 / 30

Probability of choosing a boy.

= 0.4333 or approximately 0.43

Therefore,

The probability of Pier choosing a boy is 0.43 or 43%.

Learn more about probability here:

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five I think I am not sure

Step-by-step explanation:

the sum of angels of a triangle is 180°

130+ ? + (180-160) = 180

130+ ? +20= 180

150+ ? = 180

? = 30°

the missing angle is 30°

Answer:

sum of five and 3 is divided by n

Answer:

x = 5

Step-by-step explanation:

5x + 10 = 35

Subtract 10 from both sides

5x + (10-10) = 35 - 10

Simplify

5x = 25

Divide both sides by 5

5x/5 = x

25/5 = 5

We're left with x = 5

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]\boxed{x = 5}[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'....}}\\\\5x + 10 = 35\\-------------\\\rightarrow 5x + 10 - 10 = 35 - 10\\\\\rightarrow 5x = 25\\\\\rightarrow \frac{5x=25}{5}\\\\\rightarrow \boxed{x = 5}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Step-by-step explanation:

here's the answer to your question

Answer:

-0.80

1.66

0.26

2.56

-0.50

Step-by-step explanation:

The values are the probability values either to the right or left of a given z - value ;

The Z - values could be obtained using the standard normal distribution table or a calculator :

Using the Z probability calculator ;

Area to the left of z is 0.2119

1.)

P(z < z) = 0.2119

z = - 0.8

2.)

Area between - z and z = 0.9030

Area to the left of z = 0.9030 plus

Area to the right of z = (1 - 0.9030) / 2 = 0.097/2 = 0.0485

(0.9030 + 0.0485) = 0.9515

P(z < z) = 0.9515

z = 1.66

3.)

Area between - z and z = 0.2052

Area to the left of z = 0.2052 plus

Area to the right of z = (1 - 0.2052) / 2 = 0.7948/2 = 0.3974

(0.2052 + 0.3974) = 0.6026

P(z < z) = 0.6026

z = 0.26

D.)

The area to the left of z is .9948

P(Z < z) = 0.9948

z = 2.562

E.)

The area to the right of z is .6915.

P(Z < z) = 1 - 0.6915

P(Z < z) = 0.3085

z = - 0.5

Answer:

Bobby can drive 352 miles with 16 gallons of gas.

Step-by-step explanation:

110 miles uses 5 gallons of gas.To find how many miles can be driven with one gallon we divide 110 by 5.

110 ÷ 5 = 22

Therefore to find the amount of miles that can be driven with 16 gallons we multiply 16 × 22 = 352

Answer:

C

Step-by-step explanation:

What you wrote is not the same thing as what the question is, or at least I don't think so. I'll answer the printed question.

First of all, the 13 is what separates each of the terms. In other words 7 is the first term. 13 must be raised to the n - 1 power.

It is written like this

an = 7 * 13^(n - 1)

you want a1 to be 7. The only way that can happen is if 13^0 which gives you 1.

So the correct answer is C

Answer:

A) 45=x

B) Yes, since both A and B are 90°

6x+90=360

6x=270

x=45

No lines are not parallel

Step-by-step explanation:

???????? what is easy??

Answer:

The lengths of the other sides would be 10, as well.

Step-by-step explanation:

Since we already know two of the three angles, we can subtract to find the other angle. The interior angles of a triangle will always add up to 180°. We have 60° and 60°, giving us 120°. 180 - 120 is equal to 60°, so that's the missing angle. Because all of the angles are the same, this is an equilateral triangle, which means the sides also have to be the same length. If one of the sides is 10, all of the sides are 10.

The triangle with sides 10 , 10 and 10 and all angles at 60° is an equilateral triangle

An equilateral triangle is a triangle in which all three sides have the same length.

Let the triangle be ΔABC , and

∠A = ∠B = ∠C = 60° and AB = BC = CA

Given data ,

Let the triangle be represented as ΔABC

Let the side length of the triangle be AB = 10

Now , the measure of ∠ABC = 60°

And , the measure of ∠BAC = 60°

So , the total sum of all the angles in a triangle = 180°

And , the measure of ∠ACB = 180° - ( 60° + 60° ) = 60°

Therefore , all the angles of the triangle are 60°

So , it is an equilateral triangle

And , the measure of side lengths of the triangle is 10

Therefore , AB = BC = CA = 10

Hence , it is an equilateral triangle

To learn more about equilateral triangle click :

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Answer:

[tex]x=0, \\x=\pi[/tex]

Step-by-step explanation:

Recall the trigonometric identity [tex]\sin 2x=2\sin x\cos x[/tex].

Therefore, given [tex]\sin 2x=2\sin x[/tex], rewrite the left side of the equation:

[tex]2\sin x\cos x=2\sin x[/tex]

Subtract [tex]\sin x[/tex] from both sides:

[tex]2\sin x\cos x-2\sin x=0[/tex]

Factor out [tex]2\sin x[/tex] from both terms on the left:

[tex]2\sin x(\cos x-1)=0[/tex]

We now have two cases:

[tex]\begin{cases}2\sin x=0, x=k\pi\text{ for }k\in \mathbb{Z}\\\cos x-1=0,x=k2\pi\text{ for }k\in \mathbb{Z}\end{cases}[/tex]

Since the problem stipulates that [tex]x[/tex] is in the interval [tex][0, 2\pi)[/tex], we have:

[tex]\text{For }x\in [0, 2\pi):\\\sin x=0\rightarrow \boxed{x=0, x=\pi}\\\cos x-1=0\rightarrow \boxed{x=0}[/tex]

Recall that square brackets mean inclusive and parentheses mean exclusive. Therefore, [tex]2\pi \notin [0, 2\pi)[/tex].

Answer:

Augusto vivió durante 75 años cumplidos, muriendo casi un mes antes de cumplir 76 años.

Step-by-step explanation:

Dado que Augusto nació en Roma el 23 de septiembre del año 63 a. C y fue el primer emperador romano que gobernó entre el año 27 a. C y 14 d. C considerándose como el emperador con el reinado más prolongado de la historia, y después de su muerte el 19 de agosto del año 14 d. C el senado romano lo inmortalizó glorificando su legado, por esta razón, varios de los emperadores que lo siguieron adoptaron sus nombres, para determinar cuántos años cumplidos vivió Augusto se debe realizar el siguiente cálculo:

Nacimiento: 23/09/63 AC

Primer año: 23/09/62 AC

Tercer año: 23/09/60 AC

Sesenta y dos años: 23/09/01 AC

Sesenta y tres años: 23/09/01 DC

Setenta y tres años: 23/09/11 DC

Setenta y cinco años: 23/09/13 DC

Así, Augusto vivió durante 75 años cumplidos, muriendo casi un mes antes de cumplir 76 años.

Answer:

[tex]\displaystyle y=\frac{1}{2}x+5[/tex]

Step-by-step explanation:

We want to find the slope in slope-intercept form of a line that is parallel to:

[tex]\displaystyle y=\frac{1}{2}x-2[/tex]

And passes through the point (-8, 1).

Recall that parallel lines have equivalent slopes.

Since the slope of our given line is 1/2, the slope of our new line must also be 1/2.

We are also given that it passes through the point (-8, 1). Since we are given a slope and a point, we can use the point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

Substitute 1/2 for m and (-8, 1) for (x₁, y₁). Hence:

[tex]\displaystyle y-(1)=\frac{1}{2}(x-(-8))[/tex]

Since we want the equation in slope-intercept form, we can isolate y. Distribute:

[tex]\displaystyle y-1=\frac{1}{2}x+4[/tex]

Therefore, our equation is:

[tex]\displaystyle y=\frac{1}{2}x+5[/tex]

Answer:

a. Yes it's correct, reasons;

I) let x=1, f(1)=2^1=2, g(x)=1^2=1 this proves that when a higher number is used the value of f(x) will be higher than g(x).

ii) As x approaches zero f(x) approaches 1, but g(x) approaches 0. Which will make the rate at which the graph of f(x) increase be faster than g(x)

b. f(x) has an infinite degree but g(x) has a finite degree of 2.

Answer:

RQ = 9 units

Step-by-step explanation:

Answer:

fractions larger than 14 and one-half

decimals larger than 14 and one-half

whole numbers larger than 14 and one-half

Step-by-step explanation:

Which numbers are solutions to the inequality x greater-than 14 and one-half? Check all that apply.

Given that the inequality is represented by [tex]x>14\frac{1}{2}[/tex], i.e. x > 14.5

This inequality represent all the set of real numbers which are greater than 14.5. Whereas numbers including 14.5 and below are not involved. Hence the numbers that are a solution to this inequality are:

fractions larger than 14 and one-half

decimals larger than 14 and one-half

whole numbers larger than 14 and one-half

Answer:

equation A and equation c

Answer:

Equation A and Equation C