What is the period of the graph of y = 5 sin (pi x) + 3?
Equate whats inside (arguments) [tex]\sin[/tex] with base period of sine function [tex]2\pi[/tex] and solve for x to get period,
[tex]\pi x=2\pi\implies x=2[/tex]
So the period of the graph of the given function is precisely 2.
Hope this helps :)
Answer:
Step-by-step explanation:
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NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! PLEASE explain thoroughly. Chapter 9 part 1
1. How can you determine the end behaviors for a graph from the function? What are the possible behaviors?
2. How is solving a polynomial inequality different from a solving a polynomial equation? How do the solutions differ?
3. What is a composite function? How does order of the composite function play a role in solving the composition?
9514 1404 393
Explanation:
1. End behavior is the behavior of the function when the value of the independent variable gets large (or otherwise approaches the end of the domain). There are generally four kinds of end behavior:
the function approaches a constant (horizontal asymptote)the function approaches a function (slant asymptote, for example)the function oscillates between two of the above end behaviorsthe function tends toward +∞ or -∞Of these, behavior 2 will ultimately look like one of the others.
For polynomials, the function will always approach ±∞ as the independent variable approaches ±∞. Whether the signs of the infinities agree or not depends on the even/odd degree of the polynomial, and the sign of its leading coefficient.
For exponential functions, the end behavior is a horizontal asymptote in one direction and a tending toward ±∞ in the other direction.
For trig functions sine and cosine, the end behavior is the same as the "middle" behavior: the function oscillates between two extreme values.
For rational functions (ratios of polynomials), the end behavior will depend on the difference in degree between numerator and denominator. If the degree of the denominator is greater than or equal to that of the numerator, the function will have a horizontal asymptote. If the degree of the numerator is greater, then the end behavior will asymptotically approach the quotient of the two functions—often a "slant asymptote".
__
2. A polynomial inequality written in the form f(x) ≥ 0, or f(x) > 0, will be solved by first identifying the real zeros of the function f(x), including the multiplicity of each. For positive values of x greater than the largest zero, the sign of the function will match the sign of the leading coefficient. The sign will change at each zero that has odd multiplicity, so one can work right to left to identify the sign of the function in each interval between odd-multiplicity zeros.
The value of the function will be zero at each even-multiplicity zero, but will not change sign there. Obviously, the zero at that point will not be included in the solution interval if the inequality is f(x) > 0, but will be if it is f(x) ≥ 0. Once the sign of the function is identified in each interval, the solution to the inequality becomes evident.
As a check on your work, you will notice that the sign of the function for x > max(zeros) will be the same as the sign of the function for x < min(zeros) if the function is of even degree; otherwise, the signs will be different.
The solution to a polynomial inequality is a set of intervals on the real number line. The solution to a polynomial equation is a set of points, which may be in the complex plane.
__
3. A composite function is a function of a function, or a function of a composite function. For example f(g(x)) is a composite function. The composition can be written using either of the equivalent forms ...
[tex](f\circ g)(x)\ \Leftrightarrow\ f(g(x))[/tex]
It can be easy to confuse an improperly written composition operator with a multiplication symbol, so the form f(g(x)) is preferred when the appropriate typography is not available.
When simplifying the form of a composition, the Order of Operations applies. That is, inner parenthetical expressions are evaluated (or simplified) first. As with any function, the argument of the function is substituted wherever the independent variable appears.
For example, in computing the value f(g(2)), first the value of g(2) is determined, then that value is used as the argument of the function f. The same is true of other arguments, whether a single variable, or some complicated expression, or even another composition.
Note that the expression f(g(x)) is written as the composition shown above. The expression g(f(x)) would be written using the composition operator with g on the left of it, and f on the right of it:
[tex](g\circ f)(x)\ \Leftrightarrow\ g(f(x))[/tex]
That is, with respect to the argument of the composition, the functions in a composition expression are right-associative. For example, ...
for h(x)=2x+3, g(x)=x^2, f(x)=x-2 we can evaluate f(g(h(x)) as follows:
f(g(h(x)) = f(g(2x+3) = f((2x+3)^2) = (2x+3)^2 -2
It should be obvious that g(h(f(x)) will have a different result.
g(h(f(x)) = g(h(x-2)) = g(2(x-2)+3) = (2(x-2)+3)^2
evaluate (5^0-4^-1)×3/4
Answer:
[tex](5^{0} -4^{-1} )(\frac{3}{4} )\\\\=(1-\frac{1}{4^{1}} )(\frac{3}{4} )\\\\=(\frac{4}{4} -\frac{1}{4} )(\frac{3}{4} )\\\\=(\frac{3}{4} )(\frac{3}{4} )\\\\=\frac{9}{16}[/tex]
kofi earned 50 cedis mowing lawn. today, kofi earned 60% of what he earned yesterday mowing lawns. how much money did kojo earn mowing lawn today
Answer:
Kofi earned today = 30 cedis
Step-by-step explanation:
Given:
Kofi earned yesterday = 50 cedis
Kofi earned today = 60% of Kofi earned yesterday
Find:
Kofi earned today
Computation:
Kofi earned today = 60% of Kofi earned yesterday
Kofi earned today = 60% x 50
Kofi earned today = 0.60 x 50
Kofi earned today = 30
Kofi earned today = 30 cedis
An urn contains 12 balls, five of which are red. Selection of a red ball is desired and is therefore considered to be a success. If three balls are selected, what is the expected value of the distribution of the number of selected red balls
The expected value of the distribution of the number of selected red balls is 0.795.
What is the expected value?The expected value of the distribution is the mean or average of the possible outcomes.
There are 12 balls in an urn, five of which are crimson. The selection of a red ball is desired and hence considered a success.
In this case, the possible outcomes are 0, 1, 2, or 3 red balls.
To calculate the expected value, we need to find the probability of each outcome and multiply it by the value of the outcome.
The probability of selecting 0 red balls is :
[tex]$\frac{7}{12} \cdot \frac{6}{11} \cdot \frac{5}{10} = \frac{105}{660}$[/tex].
The probability of selecting 1 red ball is :
[tex]$3 \cdot \frac{5}{12} \cdot \frac{7}{11} \cdot \frac{6}{10} + 3 \cdot \frac{7}{12} \cdot \frac{5}{11} \cdot \frac{6}{10} + 3 \cdot \frac{7}{12} \cdot \frac{6}{11} \cdot \frac{5}{10} = \frac{315}{660}$[/tex].
The probability of selecting 2 red balls is
[tex]:$\dfrac{5}{12} \cdot \frac{7}{11} \cdot \frac{6}{10} + \frac{7}{12} \cdot \frac{5}{11} \cdot \frac{6}{10} + \frac{7}{12} \cdot \frac{6}{11} \cdot \frac{5}{10} = \frac{105}{660}$.[/tex]
The probability of selecting 3 red balls is
[tex]$\dfrac{5}{12} \cdot \frac{4}{11} \cdot \frac{3}{10} = \frac{15}{660}$[/tex]
The expected value is then :
[tex]$0 \cdot \frac{105}{660} + 1 \cdot \frac{315}{660} + 2 \cdot \frac{105}{660} + 3 \cdot \frac{15}{660} = \frac{525}{660} = \frac{175}{220} \approx \boxed{0.795}$[/tex]
To learn more about the expected value of the distribution click here:
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Please help !!! Plzzzz
Explanation:
Because we have a midsegment, this means that it is half as long as the side it's parallel to. You can think of "mid" as "middle" and that could lead to "halfway" to remember to take half.
So z = 14/2 = 7
compute (-12)+(-8)+30
Answer:
10
Step-by-step explanation:
(-12) + (-8) +30
-(12+8)+30
-20 + 30
10
please help i dont wanna fail
Answer:
4
Step-by-step explanation
Plug in the numbers for x and y.
4/4 ( 2 + (6) - (4))
Remove the parenthesis. Since 4/4 is equal to 1, you can put down 1 as well.
1 (2 + 6 - 4)
Distribute the 1. When anything is multiplied by 1, it remains the same.
2 + 6 - 4
Simplify.
4
[tex]\huge\boxed{\textsf{Hey there!}}[/tex]
[tex]\huge\boxed{\mathsf{\dfrac{x}{4}(2 + y - x)}}[/tex]
[tex]\huge\boxed{\mathsf{= \dfrac{4}{4}(2 + 6 - 4)}}[/tex]
[tex]\huge\boxed{\mathsf{= 1(8 - 4)}}[/tex]
[tex]\huge\boxed{\mathsf{= 1(4)}}[/tex]
[tex]\huge\boxed{\mathsf{= 4}}[/tex]
[tex]\huge\boxed{\textsf{Therefore, your answer is: 4}}\huge\checkmark[/tex]
[tex]\huge\boxed{\boxed{\textsf{Good luck on your assignment \& enjoy your day!}}}[/tex]
~[tex]\huge\boxed{\boxed{\huge\boxed{\mathsf{Amphitrite1040:)}}}}[/tex]What is the slope of the line that passes through the points listed in the table?
x l y
8 l 3
10 l 7
A. -4
B. -2
C. 2
D. 4
Answer:
2
Step-by-step explanation:
The slope is given by
m = ( y2-y1)/(x2-x1)
= (7-3)/(10-8)
= 4/2
= 2
75% increase followed by 50% decrease is it greater than to original
Answer:
Set original amount = xAfter a 75% increase, it would become
x + 75%x = x + 0.75x = x(1 + 0.75) = 1.75x
After a 50% decrease, it would become
1.75x - 50%(1.75x) = 1.75x - 0.5(1.75x) = 1.75x - 0.875x = 0.875x = [tex]\frac{7}{8} x[/tex]
Because [tex]\frac{7}{8} x[/tex] is less than x, the new amount would be less than the original.
If a teacher's guide to a popular SAT workbook is to be printed using a special type of paper, the guide must have at most 400 pages. If the publishing company charges 1 cent per page printed, what is the largest price, in dollars, that can be charged to print 20 copies of the workbook using the special paper?
Answer:
$80
Step-by-step explanation:
To find the largest price, assume that all 20 copies of the workbook will have 400 pages.
Since the company charges 1 cent per page, this means each workbook will cost 400 cents. This is equivalent to 4 dollars.
Find the total cost by multiplying this by 20:
20(4)
= 80
So, the largest price to print 20 copies is $80
w • (-4+ z) = mz + 17
z = ____
solve for z.
ps.. pls help me lol. i need the answer
Answer:
z = (17+4w)/(w-m)
Step-by-step explanation:
w • (-4+ z) = mz + 17
Distribute
-4w +wz = mz+17
Subtract mz from each side
-4w +wz - mz = mz+17-mz
-4w +wz-mz = 17
Add 4w to each side
-4w +4w+wz-mz = 17+4w
wz-mz = 17+4w
Factor out z
z(w-m) = 17+4w
Divide by (w-m)
z(w-m)/(w-m) = (17+4w)/(w-m)
z = (17+4w)/(w-m)
Given the parent graph h(x) = x, what happens when it is changed to h(x + 9)?
Answer:
If the parent graph is h(x) = x, then h(x+9) would actually be shifting the graph 9 units to the LEFT.
Let me know if this helps!
Enter a value that would not make relation a function (-4,0),(?,8),(9,0),(-5,2)
Answer:
Step-by-step explanation:
? = -4, 9, or -5
The solution is, b.) y = 2(x+9) ( x - 4) and, c.) y = - 2(x+9) ( x - 4), these function's graph has a zeros at (4,0) and (-9,0).
What are zeros of quadratic function?The zero of the function is where the y-value is zero. The zero of a function is any replacement for the variable that will produce an answer of zero. Graphically, the real zero of a function is where the graph of the function crosses the x‐axis; that is, the real zero of a function is the x‐intercept(s) of the graph of the function.
here, we have,
from the given the information , we get,
If one zero is x= 4, then one factor of the expression would be (x - 4).
Similarly if another zero is x=-9, then another factor of the expression would be (x+9)
We have two answers with these two factors and both are possible. So, the answers are b and c.
Hence, The solution is, b.) y = 2(x+9) ( x - 4) and, c.) y = - 2(x+9) ( x - 4), these function's graph has a zeros at (4,0) and (-9,0).
To learn more on zeros of quadratic function click:
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complete question:
Which function's graph has a zeros at (4,0) and (-9,0)?
Jim took a loan of R30 000.00 for 18 months at a simple interest rate of 12.5% per year. Determine the amount that Jim
will pay in 18 months.
Answer:
R35625
Step-by-step explanation:
(R30,000×.125×18/12)+R30000
=R35625
If Y / 4 - 12 = 3.5, what is the value of y?
A couple decide to have 5 children what if the probability that they will have at least one girl
Answer:
31/32
Step-by-step explanation:
There are 2^5, or 32 combinations.
There is only 1 combination which is all 5 children are boys.
So the probability that will have at least 1 girl is: 1 - 1/32 = 31/32
can somebody help with this please
Answer:
"D"
Step-by-step explanation:
just add the two functions
5x^2 - 8x^2 = -3x^2 etc
prove that Sin^6 ϴ-cos^6ϴ=(2Sin^2ϴ-1)(cos^2ϴ+sin^4ϴ) please sove step by step with language it is opt maths question please sove i will mark you the best
Answer:
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14) Students at East Central High School earned $246
selling pennants. They want to make $3810 for a
club trip. What percent of their goal has been
reached? Round to the nearest tenth of a percent,
if necessary.
Answer:
6.46%
Step-by-step explanation:
246 ÷ 3810 × 100% = 6.46%
40+30+10 in commutative property
Answer:
10 + 40 + 30
Step-by-step explanation:
Commutative property states that the order in which we add numbers does not affect the answer, so we just need to change the order of numbers
Answered by Gauthmath
What is the remainder when x2+ 3 is divided by x - 1?
Answer:
Step-by-step explan
Name three different ways a bar graph can be drawn.
Can someone please help me solve the equation?
Answer:
(0,0) is the x and y intercept of the function
Step-by-step explanation:
The parabola touches the x and y axis at 0
The x intercept is (0,0) and the y intercept is (0,0)
Answer:
(0, 0) is the x and y intercepts
Step-by-step explanation:
intercepts are where the curve of the equation contacts an axis
The equation is y = x²
fernando charges a flat fee of 4.50 plus 2.00 per mile for his taxi service, when he got to the airport the cab fare was 12.50 how many miles was the trip to the airport
the trip to the airport was 6.25 miles.
in a children of 700 inmates,25% are living with polio and 30% are girls . if 30% og the girls have polio, how many are the boys without polio
Answer: 378 Boys
Explanation:
Total no. Inmates = 700
Living with polio = 25/100×700
= 175 inmates
Total girls = 30/100×700
= 210 Girls
30% of girls Having polio = 30/100×210
= 63 Girls
Total Boys = 700 - 210
= 490 Boys
Total boys with polio = 175 - 63
= 112 boys
Boys without polio = 490 - 112
= 378 boys
Must click thanks and mark brainliest
Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. (Enter your answers as a comma-separated list.) F(x) = sin(x/2) , [π/2,3π/2]
Answer:
The numbers 3(pi)/2, 5(pi)/2 satisfy the conclusion of Rolle's Theorem
Step-by-step explanation:
1. The function must be continuous.
Trigonometric functions are continuous.
2. It must be true that f(a) = f(b) = 0
For this case sin(pi) = sin(3pi) = 0
3. Therefore by Rolle's Theorem, there exist a point, x, such that f(x) = 0
For this case f(x) = cos(x)
And cos(x) = 0 at x = 3(pi)/2,5(pi)/2
Please Help me! I will mark brainliest for correct answer!!!
Answer:
y=2/3x+1
Step-by-step explanation:
Identify the terminal point for a 45° angle in a unit circle.
O A (231)
O B.
O c.
V2 72
Answer:
D
Step-by-step explanation:
x- coordinate = cos45° = [tex]\frac{1}{\sqrt{2} }[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex]
y- coordinate = sin45° = [tex]\frac{1}{\sqrt{2} }[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex]
That is ( [tex]\frac{\sqrt{2} }{2}[/tex] , [tex]\frac{\sqrt{2} }{2}[/tex] ) → D
The life of light bulbs is distributed normally. The standard deviation of the lifetime is 2525 hours and the mean lifetime of a bulb is 590590 hours. Find the probability of a bulb lasting for at most 622622 hours. Round your answer to four decimal places.
Answer:
0.8997 = 89.97% probability of a bulb lasting for at most 622 hours.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 590 hours, standard deviation of 25 hours.
This means that [tex]\mu = 590, \sigma = 25[/tex]
Find the probability of a bulb lasting for at most 622 hours.
This is the p-value of Z when X = 622.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{622 - 590}{25}[/tex]
[tex]Z = 1.28[/tex]
[tex]Z = 1.28[/tex] has a p-value of 0.8997.
0.8997 = 89.97% probability of a bulb lasting for at most 622 hours.
