Every mass exerts a gravitational force on every other mass.

a. True
b. False

Answers

Answer 1

Answer:

A

Explanation:

newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses


Related Questions

Add these two velocity vectors to find the magnitude of their resultant vector.
5.8 meters/seconds + 1.2 meters/seconds

Answers

The  magnitude of their resultant vector is 4.6 meters/seconds

Since we are to add the  velocity vectors in order to  find the magnitude of their resultant vector.

Hence:

Resultant vector magnitude=5.8 meters/seconds + (1.2 meters/seconds)

Resultant vector magnitude=5.8 meters/seconds-1.2 meters/seconds

Resultant vector magnitude 4.6 meters/seconds

Inconclusion The  magnitude of their resultant vector is 4.6 meters/seconds

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In Physics what's does cos and sin stand for?

Answers

Answer:

Sin = Sine

Cos = Cosine

Explanation:

Sin(θ) = Opposite/Hypotenuse

Cos(θ) = Adjacent/Hypotenuse

Write any three condition required for nuclear fussion that are found in the sun.​

Answers

Answer:

High pressure squeezes the hydrogen atoms together. They must be within 1x10-15 meters of each other to fuse. The sun uses its mass and the force of gravity to squeeze hydrogen atoms together in its core. We must squeeze hydrogen atoms together by using intense magnetic fields, powerful lasers or ion beams.

Convert the following in to SI units without changing its values

A. 4000 g

b. 2.4 km

Answers

Answer :

A. The S.I unit of mass is kg . therefore we have to convert 4000g into kg from gram

i.e 4000g = 4 kg

B. The S.I unit of length is meter. so we have to convert 2.4 km into meters,

i.e 2.4 km = 2400 m

#A

[tex]\boxed{\sf 1kg=1000g}[/tex]

[tex]\\ \sf\longmapsto 4000[/tex]

[tex]\\ \sf\longmapsto \dfrac{4000}{1000}[/tex]

[tex]\\ \sf\longmapsto 4kg[/tex]

#B

[tex]\boxed{\sf 1km=1000m}[/tex]

[tex]\\ \sf\longmapsto 2.4km=2.4(1000)[/tex]

[tex]\\ \sf\longmapsto 2400m[/tex]

Identify the parts of the body based on the medical terminology given:

1. mr. heart describes pain that is midline, superior to the chest but inferior to the chin.
2. miss triangle says that she has a ‘tweak’ that is superior to the waist, inferior to the breast bone, lateral to the umbilicus on the left side of the body on the anterior surface.
3. mr. square states that he has pulled a muscle, inferior to the buttocks, superior to the knee, medial to the right side of the body on the posterior surface.
4. miss circle complains of a sharp pain inferior to her ears, superior to the scapula at midline on the posterior side of her body.
5. mr. x says that he has numbness and tingling on the anterior side of his left arm, distal to the wrist.
6. mrs. diamond describes a throbbing pain on the posterior side of her body, inferior to her shoulder blades and superior to her waist.
7. miss arrow states that she has had a pain on the left side of her body, superior to her neck and inferior to her forehead, lateral to her nose.
8. mr. teardrop says that he has been bitten by a spider lateral to his umbilicus on the anterior aspect of his body, superior to his hip on the right side of his body.
9. miss eight describes a burning sensation on the posterior side of her body, lateral to the spine on the left side of the body inferior to the shoulder blade, inferior to the waist but anterior to the knee.
10. mr. four shows you a deep wound on the anterior side of his body, medial to the left hip, lateral to the umbilicus, inferior to the collarbone and anterior to the waist.

Answers

Answer:

1. Right hypochondriac region (upper, right).

2.  Epigastric region (upper, middle).

3. Left hypochondriac region (upper, left).

4. Right lumbar region (middle, right).

5. Umbilical region (centre).

6. Left lumbar region (middle, left).

7. Right iliac region (lower, right).

8. Hypogastric region (lower, middle).

9. Left iliac region (lower, left).

Explanation:

1. Right hypochondriac region (upper, right)- Liver, gallbladder, right kidney, small intestine.

2.  Epigastric region (upper, middle)- stomach, liver, pancreas, duodenum, spleen, adrenal glands

3. Left hypochondriac region (upper, left)- Spleen, colon, left kidney, pancreas

4. Right lumbar region (middle, right)- Gallbladder, liver, right colon

5. Umbilical region (centre)- Umbilicus, parts of the small intestine, duodenum

6. Left lumbar region (middle, left)- Descending colon and left kidney

7. Right iliac region (lower, right)- Appendix and cecum

8. Hypogastric region (lower, middle)- Bladder, reproductive organs, sigmoid colon

9. Left iliac region (lower, left)- Descending and sigmoid colon.

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A mountain climber at the peak ha ___________ energy.

A.gravitational potential
B. Elastic potential
C.Kinetic

Answers

its Kinetic, hope this helps you

what is work - energy theorem ??​

Answers

The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object. After the net force is removed (no more work is being done) the object's total energy is altered as a result of the work that was done.

This idea is expressed in the following equation:

is the total work done

is the change in kinetic energy

is the final kinetic energy

is the initial kinetic energy

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I NEED THE ANSWER TO PASS SO I CAN GET MY PHONE BACK HELPPPPPPPPPPPPPP

Answers

Answer:

it would be c.

Explanation:

starts at zero and isn't a straight shot up

plz help me with this question ​

Answers

Explanation:

Here,

initial velocity(u)=25m/s

final velocity (v)=0m/s

time taken(t)= 5 second

Now,

Bella makes the 2.5m distance to her food bowl in 9.1 seconds. What is her average velocity?

Answers

Distance=2.5mTime=9.1s

Average Velocity=Total Distance/Total Time

[tex]\\ \sf\longmapsto \dfrac{2.5}{9.1}[/tex]

[tex]\\ \sf\longmapsto 0.3m/s[/tex]

Convert 4 centimeters to meters using dimensional analysis and scientific notation. Please go step by step as I am having difficulty with this subject. ​

Answers

Question:-

Convert 4cm to m

Solution:-

Lets do

First note down the below formula

[tex]\boxed{\sf 1m=10^{2}cm}[/tex]

Then

[tex]\boxed{\sf 1cm=10^{-2}cm}[/tex]

Now we are given 4cm

So convert

[tex]\\ \sf\longmapsto 4\times 10^{-2}m[/tex]

If we simplify to decimal

[tex]\\ \sf\longmapsto 4cm=0.04m[/tex]

Hence done .

Select the correct answer.
Calculate the force of gravity on a 1–kilogram box located at a point 1.3 × 107 meters from the center of Earth. (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)

A.
2.36 newtons
B.
3.58 newtons
C.
4.87 newtons
D.
8.95 newtons

Answers

Answer:

A. 2.36 Newtons

Explanation:

F = GmM/d²

F = 6.673 x 10⁻¹¹(1)(5.98 x 10²⁴) / (1.3 x 10⁷)²

F = 2.36121...

Very poor question design.

  mass of box... 1 significant digit

        distance... 2 significant digits

mass of earth... 3 significant digits

     value of G... 4 significant digits

Answer precision to 3 significant digits is not justifiable

An object is launched at a 60 degree angle with an initial velocity of 100
m/s. What is the objects height? How long is the object in the air? What is
the objects's range (distance)? *

PLS HELP QUICK LOL

Answers

Answer:

Explanation:

The first question asks for the object's height. That is a y-dimension thing so we will use the one-dimensional formula:

[tex]v^2=v_0^2+2a[/tex]Δx and we are looking for delta x, which is the displacement of the object (here, the height since displacement in the y-dimension is height). Before we do that, though, we need to know the initial upwards velocity, which is found in:

[tex]v_{0y}=100sin(60)\\v_{0y}=90\frac{m}{s}[/tex]

And we also have to know from previous physics experience that the final velocity of an object at its max height is 0. Filling in:

[tex]0=(90)^2+2(-9.8)[/tex]Δx

[tex]0=8000-20[/tex]Δx and

-8000 = -20Δx so

Δx = 400 m

Now for the time it was in the air...we will use the simple equation

[tex]v=v_0+at\\0=90-9.8t\\-90=-9.8t\\t=9[/tex]

So the object is in the air for 9 seconds. Now we go to the other dimension, the x-dimension, to find out how far it goes horizontally. We will use the equation:

Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] but first we have to find the horizontal velocity, which is NOT the same as the upwards velocity.

[tex]v_{0x}=100cos(60)\\v_{0x}=50\frac{m}{s}[/tex]

And another thing we need to know prior to solving problems like this is that the acceleration in the x-dimension is ALWAYS 0. Filling in the equation:

Δx = [tex]50(9)+\frac{1}{2}(0)(9)^2[/tex]

Δx = 500 m

Which of the following best represents R=A+B ?
A)

B)

C)

Answers

Answer:

C

Explanation:

Options A and B are not even pointing in the direction as the vectors in the question so they shouldn't even be considered.

Option C looks like the closes since vectors A and B are pointing in a similar direction (negative x-axis)

The best representation for the resultant vector representing the resultant R=A+B would be option C because the result is represented by the closing side of the triangle, therefore the correct answer would be C.

What is a vector quantity?

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

As given in the problem we have to find out the resultant vector from the sum of vector A and vector B,

The resultant of the vector can be calculated with the help of the triangle law of the vector addition in which the sum is given by the closing side of the triangle.

Thus, the correct answer is option C.

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How do we know how much
gravitational force objects have?

Answers

Answer:

With a force of 1 Newton, an object weighing 100 grams is dragged towards the planet's center. On Earth, an item with a mass of 100 grams has a gravitational pull of only 1%, or about kg.

Explanation:

i hope this helps

A vehicle starts from rest and travels 50 m in 5 s. What is its acceleration?

Answers

Well it depends 60 could be the acceleration

Bobo, the clown, wants to set the world record for the furthest range traveled by a clown shot out of a cannon. Write a sentence describing the cannon that Bobo would need to use to accomplish this feat. Be sure to include the necessary initial velocity and the required angle of the cannon. Score: 0 / 1

Answers

In the human cannonball act makes use of of a special type of "cannon" that more safely ejects a person who acts as the "cannonball"

The world record for the longest flight by a human cannonball is approximately 194 feet and therefore the human cannon catapult that Bobo would need is one that would be able to propel him with an initial velocity of more than 120 kilometer per hour (more than the speed of the current record holder) with the cannon directed at an angle 45 degrees above the horizonal

The reason the values given above are correct is as follows:

The world record of the furthest range of the human cannonball is 193 ft. 8.8 inches. The maximum claim for the furthest range of a human cannonball is 200 ft. 4 in. Therefore, to safely set the world record would be to reach a range of 194 feet

The speed with which the world record was accomplished (120 km/jhr)  should be expected to be exceeded given, horizontal speed in free fall motion is constant (decreasing in the presence of drag), and the conditions are likely to be more or less similar

In order to reach the furthest range, R, at the possible speed, the angle of inclination of the "cannon" required is 45°, according to the range formula, which is given as follows;

[tex]Range, \ R = \dfrac{v^2 \times sin(2\cdot \theta)}{g}[/tex]

The maximum range is given where θ = 45, such that sin(2·θ) = sin(90°) = 1

A further range than the world record van be obtained using the above values

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2. Determine the units of the quantity described by each of the following
combinations of units:

a. kg (m/s) (1/s)
b. (kg/s) (m/s)
c. (kg/s) (m/s)
d. (kg/s) (m/s)

Answers

We have that the unit of the quantities are described

a.kg (m/s) (1/s)=Newton  

b. (kg/s) (m/s^2)=Newton

c. (kg/s) (m/s)^2=Newton  

d. (kg/s) (m/s)​=Newton

From the question we are give the units  

a.kg (m/s) (1/s)  

b. (kg/s) (m/s^2)  

c. (kg/s) (m/s)^2  

d. (kg/s) (m/s)​

a)  

Generally  

kg (m/s) (1/s) is Represented as Newton  

Where Newton is the unit Force and Weight

b)  

Generally  

(kg/s) (m/s) is the unit representation of Newton  

Therefore  

Newton

c)  

kg/s) (m/s) is the unit representation of Newton  

Therefore  

Newton

d)

Generally  

(kg/s) (m/s) is the unit representation of Newton  

Therefore  

Newton

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write two differences between practical machine and ideal machine​

Answers

Answer:

Ideal machines are said to have parts which are weightless , frictionless and strings if any are inextensible. Practical machines have parts which have weights, friction and it causes some loss of work done. So these are the differences between Ideal Machine and Practical Machines.

show that Newton's first law is the special case of Newton's second law of motion​

Answers

Please find attached photograph for your answer. Please do comment whether it is useful or not.

What is the kinetic energy of a 0.5 kg soccer ball that is traveling at a
velocity of 3 m/s?
What’s the answer

Answers

Answer:

kinetic energy = 1/2mv²

k.E =1/2 X 0.5 X 3²

k.e = 9/4

K.E = 2.25j

A car is accelerating at 6 m/s2. How long would it take the car to go 12 m/s faster?

Answers

Answer:

  2 seconds

Explanation:

Each second, it increases its speed by 6 m/s, so it will take 2 seconds for the speed to increase by 12 m/s.

find the final velocity of the initial velocity of 8m/s with an acceleration of 7 m/s2 over 3 second interval​

Answers

Please find attached photograph for your answer. Hope it helps! Please do comment.

explain 3points to be taken into consideration while measuring the length of a body​

Answers

Answer:

Y T and v

Explanation:

A car traveling at 90 m/s can stop in a distance of 110 m. What is the magnitude of the cars acceleration as it slows down?

Answers

I think I have already answer this question. Anyways please do let me know whether it is useful or not

When you put water in the ice tray in the freezer, water becomes ice. Ice is more ordered than water. Is this a violation of Second Law of Thermodynamics

Answers

Answer:

No because the heat that moved out of the water to make ice caused an even greater disorder in the environment around it.

Explanation:

a car is traveling north. can its acceleration vector ever Point South? explain​

Answers

Yes.

The acceleration vector WILL point south when the car is slowing down while traveling north

When a car is traveling north, its acceleration vector can point south when it is slowing down.

A vector quantity has both magnitude and direction. The direction of a vector is always shown by the direction to which the arrow points.

If the car is travelling north, the direction of the acceleration vector will continue to point northwards.

However, when the car slows down, the direction of the accelerating vector will now point southwards.

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If it takes Tanya 9.4 hours to get to her cousin's house while driving an average of 40 mph, how far away does her
cousin live?

Answers

Answer:

376 miles

Explanation:

speed = distance / time

therefore distance = speed * time

distance = 40 miles/hr * 9.4 hr

then

distance = 375 miles


1. Calculate the height of tree, 250 m away that produces
an image 1.5cm high
in a
pin-hole camera of width 30 cm.

Answers

Answer:

Explanation:

1.5/30 = x/250

x = 12.5 m

If you are given force and time, you can determine power if you can know

(a) watts
(b) energy
(c) distance

Answers

The answer would be A, because power is defined as the rate of doing work. Hence power = work / time then you obtain watts. Work is the product of force and displacement (distance). Hence in formula, w = F x s.

Answer:

joules/energy.

Explanation:

power is defined as the rate of work. Hence power=work/time, then you obtain Watts.

Work is the product of force and displacement.

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