Every time Liliana bakes a batch of brownies, she uses 34 cup of chocolate. If she has 128 cup(s) of chocolate remaining, how many batches of brownies can Liliana make? Input your answer as a whole number.

Answer:

3/4

Step-by-step explanation:

Given the following :

Number of boxes = 2

First box :

White balls = 3

Blue balls = 2

Second box:

White balls = 4

Blue balls = 1

What is the probability that Frida picked a ball from the first box if she has selected a blue ball?

Probability (P) = (required outcome / Total possible outcomes)

Probability of picking first box : P(F) = 1/2

Probability of not picking second box :P(S) 1/2

Probability of picking blue from first box : P(B | F) = 3/5

Probability of picking blue, but not from first box : P(Blue not from second box) P(B|S) = 1/5

probability that Frida picked a ball from the first box if she has selected a blue ball?

P(F) * P(B|F) ÷ (P(F) * P(B|F)) + (P(S) * P(B|S))

(1/2 * 3/5) ÷ ((1/2 *3/5) + (1/2 * 1/5)

3/10 ÷ (3/10 + 1/10)

3/10 ÷ 4/10

3/10 * 10/4

= 3/4

Answer:

u^18

Step-by-step explanation:

(u^3)^6

=

u^(3*6)

=

u^18

Hope this helps!

Answer:

11.6%

I hope this helps!

Answer:

  x = 1/2 or 2

Step-by-step explanation:

You can factor this as ...

  2x^2 -4x -x +2 = 0 . . . rewrite the middle term to enable factoring

  2x(x -2) -1(x -2) = 0 . . . . factor by grouping

  (2x -1)(x -2) = 0 . . . . factor out (x -2)

  x = 1/2, 2 . . . . . . values of x that make the factors zero

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

[tex]\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}[/tex], with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}[/tex]

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}[/tex]

[tex]\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5[/tex]

So B has two solutions of 5 and -1.5.

Now to C!

[tex]\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}[/tex]

[tex]\frac{44}{8} = 5.5[/tex]

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

Answer:

Step-by-step explanation:

A) 280 Km

B)  When D = 0:  speed, S = 280/59 = 4,9 Km/hour

C) 280 Km

D)  59 hours

Answer:

x = [tex]\frac{12-4y}{3}[/tex]

Step-by-step explanation:

Given

[tex]\frac{x}{4}[/tex] + [tex]\frac{y}{3}[/tex] = 1

Multiply through by 12 to clear the fractions

3x + 4y = 12 ( subtract 4y from both sides )

3x = 12 - 4y ( divide both sides by 3 )

x = [tex]\frac{12-4y}{3}[/tex]

Answer:

guys its 8cm its the most logic answer because 8x 4 is 32, correct me if im wrong

Step-by-step explanation:

Hello! :)

Answer:

[tex]\huge\boxed{BC = 6.4 }[/tex]

Given ΔABC ~ ΔDEF, we can set up a proportion to solve for BC, where:

[tex]\frac{AC}{DF} = \frac{BC}{EF}[/tex]

Let BC = x:

[tex]\frac{8}{15} = \frac{x}{12}[/tex]

Cross multiply:

[tex]8 * 12 = 15 * x[/tex]

[tex]96 = 15x[/tex]

[tex]x = 6.4[/tex]

Therefore, BC = 6.4 units.

Hope this helped you!

Answer:

(D) [tex]\begin{array}{*{20}c} {x=\frac{{ 5 \pm \sqrt {13} }}{{2}}} \end{array}[/tex]

Step-by-step explanation:

The quadratic formula is:

[tex]\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}[/tex]

Assuming that a is our x² term, b is our x term, and c is the constant, we can substitute inside the equation.

[tex]\begin{array}{*{20}c} {\frac{{ - (-5) \pm \sqrt {5^2 - 4\cdot1\cdot3} }}{{2\cdot1}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 12} }}{{2}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {13} }}{{2}}} \end{array}[/tex]

So the answer is D, [tex]\begin{array}{*{20}c} {x=\frac{{ 5 \pm \sqrt {13} }}{{2}}} \end{array}[/tex].

Hope this helped!

Answer:

120

Step-by-step explanation:

Answer:

[tex] (x^2 - 9)(x + 2) [/tex]

Step-by-step explanation:

Given:

[tex] x^2 + 5x + 6 [/tex]

[tex] x^2 - x - 6 [/tex]

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

[tex] x^2 + 5x + 6 [/tex]

[tex] x^2 + 3x + 2x + 6 [/tex]

[tex] (x^2 + 3x) + (2x + 6) [/tex]

[tex] x(x + 3) + 2(x + 3) [/tex]

[tex] (x + 2)(x + 3) [/tex]

[tex] x^2 - x - 6 [/tex]

[tex] x^2 - 3x +2x - 6 [/tex]

[tex] x(x - 3) + 2(x - 3) [/tex]

[tex] (x + 2)(x - 3) [/tex]

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

[tex] x^2 + 5x + 6 = (x + 2)(x + 3) [/tex]

[tex] x^2 - x - 6 = (x + 2)(x - 3) [/tex]

The common factors would be: =>

[tex] (x + 2) [/tex] (this is common in both polynomials, so we would take just one of them as a factor.

[tex] (x + 3) [/tex] and,

[tex] (x - 3) [/tex]

Their product = [tex] (x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2) [/tex]

Answer:

d) More than 3.

Step-by-step explanation:

The polynomial (x - 5)(x + 2)  ( = x^2  - 3x + 10) has zeros of -2 and 5 but so have the polynomials formed by multiplying this by any integer:

- for example 2(x - 5)(x + 2) , 4(x - 5)(x + 2) and so on.

Answer:

5.83142789

Step-by-step explanation:

did it on a graphing calculator, hope this helps

Answer:

A. 10

Step-by-step explanation:

As we know that

The length of the major axis of the ellipse is 10

i.e

2 a = 10

Also, the ellipse is the curve that consists of 2 focal points  in order that the total of the distance to the 2 focal points would remain constant for each and every point displayed in the curve

Now we assume that P is the curve point

So,

PF1 + PF2

i.e

2 a (blue line) + (red line)

2 a = 10

Therefore the sum of the length is 10

Answer:

10

Step-by-step explanation:

we can subtract the trapezium (white part) formed after from the trapezium (including white and grey) to get area of striped part

area of trapezium is [tex]\frac H2(a+b)[/tex] where $a$ and $b$ are parallel sides.

for bigger trapezium, $h=4$ parallel sides are $5$ and $5$

hence area is $\frac{4(5+5)}{2}=20$

similarily area of white trapezium, $\frac{4(3+3)}{2}=12$

and area of striped part is $20-12=8$

Answer:

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

y = 2x + 4

comparing with the above equation for a line

The slope / m = 2

Since the lines are parallel their slope are also the same

Slope of parallel line = 2

So we have

The equation of the line using point

( 3 , -2) and slope 2 is

y + 2 = 2( x - 3)

y + 2 = 2x - 6

y = 2x - 6 - 2

We have the final answer as

Hope this helps you

Answer:

y=2x-8

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

Microsoft Excel is a great tool and has saved me on countless occasions in graphs and tables. I agree with the earlier answer by Hedland.

Answer:

1

Step-by-step explanation:

-f + 2 + 4f = 8 - 3

3f = 6 - 3

3f = 3

f = 1

Answer:

f=1

Step-by-step explanation:

-f+2+4f=8-3

First what you want to do i that you want to simplify as best as you can.

-f+2+4f=8-3 becomes 3f+2=8-3 because you add the 4f to the -1f.

Then, just subtract 2 from both sides to get 3f=8-5

Now, simplify even more

3f=8-5 becomes 3f=3

It should be easy now, but if you still need help, divide

f=1

Answer:

About 706.5 square inches.

Step-by-step explanation:

Surface area of a sphere is: [tex]SA=4\pi r^2[/tex]

The radius is half the diameter. So, the radius of the given sphere is 7.5 in.

15/2 = 7.5

Find the surface area:

I use 3.14 for pi.

[tex]SA=4*3.14*7.5^2\\\\SA=4*3.14*56.25\\\\SA=12.56*56.25\\\\\boxed{SA=706.5}[/tex]

The surface area is about 706.5 square inches.

Hope this helps.

Answer:

SA=706.86 in²

Step-by-step explanation:

surface area of a sphere = 4πr²

radius r=d/2=15/2=7.5

SA=4(π)(7.5)²

SA=706.86 in²

Answer:

The unit price is $0.95 per pack.

Step-by-step explanation:

To find the unit price, we must find the price per pack of beaded necklaces.  To do this, we should divide the total price ($7.60) by the number of items in the package (8).

$7.60/8 = $0.95

Therefore, the answer is that the unit price is $0.95.

Hope this helps!

Answer:

(D) 6

Step-by-step explanation:

We can substitute the values of a (7) and b (-4) into the equation to find it's result.

[tex]\frac{|2a| -b}{3} \\\\\\\frac{|2\cdot7|-(-4)}{3}\\\\\frac{|14|+4}{3}\\\\\frac{14+4}{3}\\\\\frac{18}{3}\\\\ 6[/tex]

So 6 is the value of this expression when a is 7 and b is -4.

Hope this helped!

Answer:

Step-by-step explanation:

The area of a triangle is given by the formula:

● A = (b×h)/2

b is the base and h is the heigth.

■■■■■■■■■■■■■■■■■■■■■■■■■■

Draw the heigth. This gives you two small right triangles.

Let's focus on the right one containing 45°.

● sin 45° = h/8

● h = sin 45° × 8 = 4√(2)

■■■■■■■■■■■■■■■■■■■■■■■■■■

Replace h by its value in the area formula. The base is 17

● A = (17× 4√(2))/ 2

● A = 34√(2)

● A = 48.08

Round to the nearest unit

● A = 48

Answer:

Area = 48 sq. units

Step-by-step explanation:

will make it short and simple.

area of a triangle = 1/2 * a * b * sinФ

area = 1/2 * 17 * 8 * sin(45°) = 48 sq. units

Answer:

4y - 9

Step-by-step explanation:

y×4= 4y

4y-9

Answer:

the perimeter of ΔABC is 32in

Step-by-step explanation:

We know that intersection point of the angle bisectors refers to the incenter of the triangle,.

Given tmthe radius of 4inch for the centre of the incircle.

One of the properties of the incircle is that the distances (d) from vertex C to the nearest touchpoints are equal and have the value

In an incircle , the distances (d) along vertex C and touchpoints have equal value and can be expressed as

d = 1/2(a +b -c)

And a, b, c represent lengths of the sides

We were given the hypotenuse (c) as 12 in, with the radius of 4inch for the

distance from the right-angle vertex C to the incircle touchpoints .

We can determine the sum a+b as

4 = (1/2)(a+b -12) .

4/(1/2)= (a+b -12)

8= (a+b -12)

20=a+b

Which is the addition of length of the two legs of the triangle.

We can determine the perimeter which is the addition of the leg lengths as well as the hypotenuse length.

perimeter = 20 in + 12 in = 32 in

Therefore, the perimeter of ΔABC is 32in

Answer:

I got option 1.

Step-by-step explanation:

See pictures

Answer:

center=0,0 vertices=(0,5)(0,-5) foci=(0,4)(0,-4)  

Step-by-step explanation:

used calculator

Answer:

7 : 18

Step-by-step explanation:

1. Convert to the same units (cents)

70 cents = 70 cents

$1.80 = 180 cents

2. Simplify

70 : 180 (divide both by ten)

7 : 18

7 and 18 cannot be simplified any further.

Answer:

150 front tickets and 250 back tickets

Step-by-step explanation:

make 2 equations 25x + 15y = 7500 and x + y = 400 and do substitution on a graphing calculator or by your self.

let me know if this helps