explain how balanced and unbalanced forces effect an objects motion differently

Answers

Answer 1
Balanced Forces acting on an object will not change the object's motion. Unbalanced Forces acting on an object will change the change the object's motion.
Answer 2

Answer:

Balanced Forces will not change the object's motion.

Unbalanced Forces will change the object's motion.

Explanation:


Related Questions

What type of electrical cord has a ground?

3 pronged cord

2 pronged cord

Answers

Answer: A) 3 pronged cord

Explanation:

One prong is known as the hot wire, where the electricity comes in, while the second prong is the neutral wire and electricity leaves. Recall that a circuit must be made for electrons to flow. This means that electrons enters your house through the transmission wires and then the electrons leave along the same lines they entered (just along a different wire).

This set up describes a 2 pronged cord. Adding a third prong allows for a grounding to happen. In the event of an electrical surge, when too many electrons are flowing, disaster is likely to happen without some kind of safety features. The grounding prong allows electrons to seek the ground. You can think of it like a drain in a bathtub when too much water gets in the tub.

Answer:

3 pronged cord

Explanation:

Help Please!

Think about how you can get the color white from using light versus how you can get the color white from using paint or dye. Now, think about how you can get the color black from using light versus from paint or dye. Using this, explain why we call coloring from light “additive” and coloring from paint or dyes “subtractive”.

Answers

Answer: Subtractive colors absorb OR subtract some lights causing it to reflect, and creating white.

Explanation:

Subtractive colors are created by completely or partially absorbing (or subtracting) some light wavelengths and reflecting others.

How far will a car travel in 30 seconds at 12 m/s​

Answers

Answer:

30*12=360m,it would travel 360 m.

360m hope this helps

can someone please help me it’s 15 points of my major grade..

Answers

a.

b.

c.

e.

f.

g.

character limit thing

A 50Kg girl jumps off a 5-meter-high diving board. What is her kinetic energy right before she
hits the water?
A. 0 J
B. 25 J
C. 1225 J
D. 2450 J

Answers

Answer:

D is the correct answer

Explanation:

Ek=m*g*h=50*9.8*5=2450

The kinetic energy right before she hits the water is 2450J. So, the correct option is D.

What is Kinetic energy?

Kinetic energy is defined as the energy that is due to the motion of an object. If we want to accelerate an object, we must apply a force, by applying a force we need to do work. After the work is done, energy has been transferred to the object, and the object will continue to move with a new constant speed.

A 50Kg girl jumps off a 5-meter-high diving board.

We need to find the kinetic energy of the girl before she enters the water which means that the kinetic energy becomes equal to the potential energy such that,

P.E.=K.E. = mgh

where, m=mass of the object

g= acceleration due to gravity [tex](9.8m/s^2)[/tex]

h= height

So, K.E= 50* 9.8*5 = 2450 J

Thus, the kinetic energy right before she hits the water is 2450J. So, the correct option is D.

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A vector
of magnitude 5 units and another vector ū of magnitude 3 units point in directions
differing by 60°. Find out (a) the scalar product of the two vectors and (b) the vector product of the two vectors​

Answers

Answer:

7.5 units

13 units

Explanation:

[tex]|v|=5\ \text{units}[/tex]

[tex]|u|=3\ \text{units}[/tex]

[tex]\theta[/tex] = Angle between the vectors = [tex]60^{\circ}[/tex]

Scalar product is given by

[tex]u\cdot v=|u||v|\cos\theta\\ =3\cdot 5\cdot \cos60^{\circ}\\ =7.5\ \text{units}[/tex]

The scalar product of the vectors is 7.5 units.

Vector product is given by

[tex]u\times v=|u||v|\sin\theta\\ =3\times 5\sin60^{\circ}\\ =13\ \text{units}[/tex]

The vector product of the vectors is 13 units.

whats the result of rounding 52.8015 into five significant figures​

Answers

Answer:

52.802

Explanation:

"Significant figures" in Mathematics refer to the digits that give accuracy to the value of a measurement. There are specific rules when it comes to determining the significant figures. For example, all non-zero digits are considered significant and zeroes located in-between non-zero numbers are significant. In the number given above, the digit "0" is located between "8" and "1," therefore, it is significant. All the digits above are significant.

The problem is only asking for "five" significant figures. We can do this by counting from the left to the right. By this means, we know that the number will be rounded off to the nearest thousandths, which is "1." The number after 1 is 5, which means that 1 digit will be added to number 1, thus, making the digit into "2." The last digit (5) will then be removed.

Explanation:

five significant of 52.8015=52.801 ..

it serves as the fuctional unit of the nervous system

Answers

The neuron is the functional unit of the nervous system.

Answer:

i would say the neuron

A 5.75 g bullet is fired with a velocity of 1.50 x 102 m/s toward a stationary solid block resting on a frictionless surface. The bullet embeds but the block does not move. 1. What is the change in momentum of the bullet if it embeds in the block? 2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?

Answers

Answer:

1.  -0.863 kgm/s 2. -1.438 kgm/s

Explanation:

1. What is the change in momentum of the bullet if it embeds in the block?

Since the block does not move, the velocity of the bullet after hitting the block , v is zero. That is v = 0 m/s

Now, the momentum change of the bullet ΔP = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = 0 m/s (since it embeds in the block and the block does not move).

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(0 m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(- 1.50 × 10² m/s)

= -8.625 × 10⁻¹ kgm/s

= -0.8625 kgm/s

≅ -0.863 kgm/s

2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?

If it bounces off the block in the opposite direction with a speed of 100 m/s, then its final velocity is v = -100 m/s.

So, our momentum change ΔP' = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = -100 m/s = -1 × 10² m/s

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(-1 × 10² m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(-2.50 × 10² m/s)

= -14.375 × 10⁻¹ kgm/s

= -1.4375 kgm/s

≅ -1.438 kgm/s

what volume of alcohol will have the same mass as 4.2m^3 of petrol? (density of alcohol 0.4kg/m^3 and petrol is 0.3kg/m^3)​

Answers

Answer:

3.15m³

Explanation:

To solve this problem, let us first find the mass of the petrol from the given dimension.

       Mass  = density x volume

Volume of petrol  = 4.2m³

Density of petrol  = 0.3kgm⁻³  

       Mass of petrol  = 4.2 x 0.3  = 1.26kg

So;

      We can now find the volume of the alcohol

 Volume of alcohol = [tex]\frac{mass}{density}[/tex]  

Mass of alcohol  = 1.26kg

Density of alcohol  = 0.4kgm⁻³  

  Volume of alcohol  = [tex]\frac{1.26}{0.4}[/tex]   = 3.15m³

Please what is the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees ?

Answers

Answer:

No work is done since no distance is given

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

3. A bee flies forward at 4.9 for 33 s, lands on a flower and stays there for 7s, then flies back along its previous route at 1.9 for 39 s. What is the average speed of the bee
during the entire time?
O 1.701
O 3.001
O 4.466
O 3.801
None of these is correct.

Answers

Answer:

None of these is correct.

Explanation:

The average speed can be derived from the sum of the total distance traveled and the total time taken.

 Total distance = 4.9 + 1.9  = 6.8

  Total time taken  = 33 + 39  = 72

So;

 Average speed  = [tex]\frac{total distance}{total time}[/tex]  = [tex]\frac{6.8}{72}[/tex]   = 0.014

None of the answer choices given is correct.

Nina's measurements, shown in the table here, BEST represent a wave with
A)
decreasing frequency.
B)
increasing frequency.
C)
increasing amplitude.
D)
decreasing amplitude.

Answers

I think the answer will be B

Nina's data in this table most accurately depict a wave with decreasing frequency. Option A is right.

What is frequency?

A recurring event's frequency is measured by how many times it occurs in a unit of time.

To emphasize distinctions with spatial and angular frequencies, respectively, it is also sometimes referred to as ordinary frequency or temporal frequency.

If the duration, or time interval, required to complete one cycle or vibration is half a second, the frequency is 2 per second; if it is one hundredth of an hour, the frequency is 100 per hour.

The frequency and period, or time interval, are often reciprocally equal, therefore frequency = 1/period = 1 in most circumstances.

The Moon rotates about Earth about a little bit more than 12 times a year. In a violin A string vibrates at a frequency of 440 cycles per second.

Thus, the correct option is A.

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Puck 1 is moving 10 m/s to the left and puck 2 is moving 8 m/s to the right. They have the same mass, m.



a. What is the total momentum of the system before the collision? (Answer in terms of the mass, m.) (0.5 points)





b. What is the total momentum of the system after the collision? (Answer in terms of the mass, m.) (0.5 points)





c. Write puck 1's velocity after the collision in component form. (1 point)







d. What is the y-component of puck 2's velocity after the collision? (1 point)







e. What is the x-component of puck 2's velocity after the collision? (1 point)







f. At what angle does puck 2 move after the collision? Determine the angle and draw it on the diagram. (1 point)







g. What is the magnitude of puck 2's velocity after the collision? (1 point)

Answers

Answer:

(a) the total momentum of the system before the collision = -2m kg.m/s.

(b) the total momentum of the system after the collision = -2m kg.m/s.

(c) puck 1's velocity after the collision in component form = (5.44 i, 2.54 j)

Explanation:

Given;

mass of Puck 1 , = m

mass of Puck 2, = m (since they have the same mass m)

initial velocity of Puck 1, u₁ = 10 m/s to the left

initial velocity of Puck 2, u₂  = 8 m/s to the right

Let the rightward direction be positive direction

Let the leftward direction be negative direction

(a) the total momentum of the system before the collision;

P₁ = (initial momentum of Pluck 1) + (initial momentum of Pluck 2)

P₁ = (-mu₁) + mu₂

P₁ = mu₂ - mu₁

P₁ = m(u₂ - u₁)

P₁  = m(8 - 10)

P₁  = -2m kg.m/s

(b) the total momentum of the system after the collision;

Based on the principle of conservation of linear momentum, the total momentum before collision is equal to the total momentum after collision.

Thus, the total momentum of the system after the collision is -2m kg.m/s.

(c) puck 1's velocity after the collision in component form

[tex]v = (v_x, v_y)\\\\v = (vcos \theta , vsin \theta)\\\\v = (6cos 25^0 , 6sin25^0)\\\\v = (5.44i, 2.54j)m/s[/tex]

The phases of the moon are caused by which of the following

A. Earths rotation around its axis
B. Earths orbit around the sun
C. The moons orbit around the earth
D. Earths shadow falling on the moon

Answers

Answer: C: The moons orbit around the earth.

Explanation:

The middle one please it’s due in 40 min

Answers

Answer:

3240000000 Joules

Explanation:

A ball is thrown with 50J of kinetic energy, it hits a target which moves with 30J of kinetic energy, how much energy goes to the thermal store of the surroundings?

Answers

Answer:

The energy that will go will for thermal store of the surroundings is 20 J.

Explanation:

Given;

kinetic of the thrown ball, K.E₁ = 50 J

kinetic energy used to move the target, K.E₂ = 30 J

The excess energy that will go will for thermal store of the surroundings;

ΔK.E = K.E₁ - K.E₂

ΔK.E = 50J - 30J

ΔK.E = 20 J

Therefore, the energy that will go will for thermal store of the surroundings is 20 J.

A ball falls from a tower
a) The two forces acting on the tennis ball are equal and opposite. What is the resultant force
?acting on the ball

Answers

Answer:

Zero

Explanation:

The resultant force acting on the ball would be zero.

Since only two forces were acting on the tennis ball and these forces negate and cancel each other in magnitude, the resultant effect on the tennis ball would be zero.

Assuming that one of the forces is 5N and acting from the positive side and the other force is also 5N but acting from the negative side.

Resultant = -5 + 5 = 0 N

A 4.00 kg block is pushed along the ceiling with a constant applied force of 85.0 N that acts at an angle of 55.0 degrees with the horizontal. The block accelerates to the right at 6.00 m/s2. Determine the coefficient of kinetic friction between block and ceiling.

Answers

Answer:

0.35

Explanation:

According to Newton's second law;

\sum Fx = ma

Fm - Ff =ma

Fm is the moving force = Wsin theta

Fm = 4(9.8)sin55

Fm = 32.1N

Ff is the frictional force = nmgcos theta

Ff = n(4)(9.8)cos55

Ff = 22.48n

Acceleration a = 6.0m/s²

Substitute the given values into the formula and get the coefficient of friction

32.11-23.48n = 4(6)

32.11-24= 23.48n

8.11 = 23.48

n = 8.11/23.48

n = 0.35

Hence the coefficient of friction is 0.35

An object, 5 cm high, is placed on the principal axis of a diverging lens of focal length 20 cm. The object is 30 cm from the lens.

Use a scaled diagram to locate the image formed by the lens.

Answers

Answer:

The answer is 70 cm

Explanation:

If you add All the numbers together, you receive an 55 cm then you add 15 because the points on the diagram also count.

Appliances connected so that they form a single pathway for
charges to flow are connected in a(n)
A. series circuit.
B. parallel circuit.
C. off circuit.
D. open circuit

Answers

Question:

Appliances connected so that they form a single pathway for charges to flow are connected in a(n)

Answer:

A. Series circuit

#CARRYONLEARNING #STUDYWELL

Appliances connected so that they create a single pathway for charges to flow are connected in a series circuit. Therefore, option (A) is correct.

What is the resistance of resistors connected in series?

In a series combination of appliances, they are connected end-to-end. Consider two resistors, R₁ and R₂ which are connected in a series combination then their effective resistance can be given by:

Total Resistance of the series circuit, R =  R₁ + R₂

In a series combination, the current flows through one appliance and then through another appliance. The same current flows through each appliance in one direction. The total voltage of the series circuit is equal to the sum of all the voltage drops across all appliances.

A potential difference of the series circuit, V  = V₁ + V₂

Therefore, when appliances are connected in a series circuit they form a single pathway for charges to flow.

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A jet aircraft is traveling at 262 m/s in horizontal flight. The engine takes in air at a rate of 85.9 kg/s and burns fuel at a rate of 3.92 kg/s. The exhaust gases are ejected at 921 m/s relative to the aircraft. Find the thrust of the jet engine. Answer in units of N Find the delivered power. Answer in units of W.

Answers

Answer:

[tex]F_T=60132.52N[/tex]

[tex]P=15814852.76W[/tex]

Explanation:

From the question we are told that

Velocity of aircraft  [tex]V=263m/s[/tex]

Engine air intake rate [tex]\triangle M_a=85.9kg/s[/tex]

Fuel burn rate  [tex]\triangle M_f =3.92kg/s[/tex]

Velocity of exhaust gas [tex]V_e =921m/s[/tex]

Generally the Mass change rate of Rocket is mathematically given by

 [tex]\triangle M = \triangle M_a+\triangle M_f[/tex]

 [tex]\triangle M= 85.9+3.92[/tex]

 [tex]\triangle M=89.82kg/s[/tex]

Generally the Trust of the rocket is given mathematically by

 [tex]F_T=(\triangle M *V_e)-(dM_a/dt)*(V)[/tex]

 [tex]F_T=(89.82 *921)-(85.9)*(263)[/tex]

 [tex]F_T=60132.52N[/tex]

Generally the Rocket's delivered power is mathematically given by

Delivered power P

 [tex]P=V*F_T[/tex]

 [tex]P=263*60132.52N[/tex]

 [tex]P=15814852.76W.[/tex]

How does your brain know which direction a sound comes from ?

Answers

Answer:

Your brain is able to do this by comparing tiny differences in the way that sounds affect each ear. ... Signals from the ear travel along the auditory nerve to the brainstem, where each individual cell responds to a specific time difference and direction.

Explanation:

It's because of your ears.

how to make measurements of length, volume and time?

Answers

Answer:

The volume of a regular object can be calculated by multiplying its length by its width by its height. Since each of those is a linear measurement, we say that units of volume are derived from units of length.

Explanation:

Answer:

length×Width×Height

Explanation:

Length×Width×Height is the formula for volume

A bucket is filled partly with water such that its combined mass is 2.5 kg. It is tied to a rope and whirled in a circle with a radius of 1.4 m. The speed at the top of the circle is 4.0 m/s and the speed at the bottom of the circle is 6.0 m/s. Determine the magnitude of the net force acting on the bucket at the bottom of the circle.

Answers

Answer:

1. Simply τ = m x g x r = 54kg x 9.8m/s² x 0.050m = 26 N·m

2. The bucket creates a torque

τ = 75kg x 9.8m/s² x 0.075m = 55 N·m,

so we must create the same torque with the handle.

55 N·m = F x 0.25m

F = 220 N

Explanation:

Hope this is helpful

What are five facts about magnets? Please help me

Answers

Answer

Over 80% of all households in the US have magnets on their refrigerator.

If you attach a bar magnet to a piece of wood and float it in a bowl of water, it will slowly turn in the water until the magnet’s North Pole points towards the Earth’s North Pole. Temporary magnets will do the same thing.

A magnet always has north and south poles. Cutting a magnet in half makes two magnets, each with two poles.

Magnets can be found in many common household items such as telephones, computers, stereos, refrigerators, TV’s and VCR’s.

Breakfast cereal often contains iron. Some cereals contain enough iron that it’s pieces are attracted to a magnet.

When can a high speed velocity cause damage?'

Answers

Answer:

50 Mph.

Explanation:

According to the National Severe Storms Laboratory, winds can really begin to cause damage when they reach 50 mph. But here’s what happens before and after they reach that threshold, according to the Beaufort Wind Scale (showing estimated wind speeds): - at 19 to 24 mph, smaller trees begin to sway.

A cell of e.M.F 1.5v and internal resistance 2.5ohm is connected in series with an ammeter of resistance 0.5ohm. Calculate the current in the circuit.

Answers

Given :

A cell of e.m.f  1.5 V and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm.

To Find :

The current in the circuit.

Solution :

We know, resistance of the ammeter is in series with the circuit.

So, total resistance is :

R = 2.5 + 0.5 ohm

R = 3 ohm

Also, e.m.f applied is 1.5 V .

Now, by ohm's law :

[tex]I = \dfrac{V}{R}\\\\I = \dfrac{1.5}{3}\\\\I = 0.5 \ A[/tex]

Therefore, the current in the circuit is 0.5 A.

How would I solve this? It's Newton's 2nd law

Answers

Answer:

5.65 m/s²

Explanation:

We'll begin by calculating the mass of PJ when in San Diego (i.e Earth). This can be obtained as follow:

Weight of PJ on Earth (Wₑ) = 545 N

Acceleration due to gravity (g) on Earth (gₑ) = 10 m/s²

Mass of PJ on Earth (mₑ) =.?

Wₑ = mₑ × gₑ

545 = mₑ × 10

Divide both side by 10

mₑ = 545 / 10

mₑ = 54.5 Kg

Thus, the mass of PJ on San Diego (i.e Earth) is 54.5 Kg

Finally, we shall determine the acceleration due to gravity of planet Koja. This can be obtained as follow:

Weight of PJ on Koja (Wₖ) = 308 N

Mass of PJ on Koja (mₖ) = mass of PJ on Earth (mₑ) because mass is constant irrespective of location.

Mass of PJ on Earth (mₑ) = 54.5 Kg

Mass of PJ on Koja (mₖ) = 54.5 Kg

Acceleration due to gravity of on Koja (gₖ) =?

Wₖ = mₖ × gₖ

308 = 54.5 × gₖ

Divide both side by 54.5

gₖ = 308 / 54.5

gₖ = 5.65 m/s²

Thus, the acceleration due to gravity on planet Koja is 5.65 m/s²

The eagles suck, so do the giants and the jets and jaguars are irrelevant

anyone wanna argue

Answers

Naw ur pretty accurate, heck collage is the only football worth watching most the time. Hook'um horns!

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