Explain how bats use ultrasound to catch a prey​

Answers

Answer 1

Answer:

Ultrasound is used by bats to navigate (move) and catch prey. Ultrasonic squeaks are produced by bats. These squeaks ponder prey and then return to the bat's ear. This provides bats with information about the location of prey, allowing them to catch it.

Explanation:


Related Questions

Do I add squared or not?​

Answers

Answer: add it

Explanation:

Select the correct answer.

Planet A Planet B
Distance from Sun 0.72 AU 9.54 AU
Planet composition rocky mantle, iron core hydrogen, helium
Gases in atmosphere very dense atmosphere that is 96.5% poisonous carbon dioxide and 3.5% nitrogen mostly hydrogen and helium
Number of moons 0 62
Rings no rings visible rings
Which planet is planet A?

A.
Mars
B.
Saturn
C.
Uranus
D.
Venus

Answers

Answer:

D, Venus

Explanation:

Using the facts

most of the waves in the electromagnetic spectrum are

Answers

Answer:

The entire electromagnetic spectrum, from the lowest to the highest frequency (longest to shortest wavelength), includes all radio waves (e.g., commercial radio and television, microwaves, radar), infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

Which layer is the igneous rock type?

options:

A


B


C


D

Answers

The answer is D that is the only one of the answers that’s right.

Please help me thank you
Fr+Cl=FeCl3

Answers

Fe+3Cl->FeCl3

Wish you always happy

Which statement identifies the chemical property of iron that results in the formation of rust?

A. It is nonflammable.

B. It reacts with oxygen to form a new substance.

C. It has a very high melting point.

D. It conducts electricity.​

Answers

Answer:

B, It reacts with oxygen to form a new substance

Explanation:

B

You need low pressure to walk on
snow and ice. True or faulse

Answers

Answer:

True

Explanation:

Answer: false please give brainliest

Explanation:  Reducing air pressure will not give you more traction and your tires could become seriously underinflated, affecting steering.

What distance does a police car travel if it is going 3.0 m/s for 20 seconds

Answers

Answer:

60 meters

Explanation:

If you are going 3 meters in a second, and you are traveling for 20 seconds, you have to multiply

3meters/second*20seconds

cross out the seconds and you have

3 meters*20

60 meters

Who is most likely to be offered a higher auto loan rate based on their credit-
to-debt ratio?
A. Juan has $10,000 in credit and owes $6,000.
B. Chester has $5,000 in credit and owes $750
C. Jalissa has $5000 in credit and owes $500.
credjtar
D. Nancy has $10,000 in credit and owes $2,000.
SUBMIT
HELP ME PLEASE

Answers

jalissa

hope this helps :)

Answer:

A - Juan

Explanation:

I took the test!

PLEASE HELP!!!!
1. Suppose a planet orbits a star at the same distance
as Earth (1 AU) but with a period of roughly 200
Earth days. The mass of the central star is:
a. less than the mass of our sun.
b. the same as the mass of our sun.
c.greater than the mass of our sun.
d. impossible to determine without
knowing the mass of the planet.

Answers

Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun. The answer is option C

According to Kepler's third law of planetary motion for planets and satellites, he described circular orbit about the same center body stating that:

The squared of the period is directly proportional to the cube of the radius. That is,

[tex]T^{2} \alpha r^{3}[/tex]

The orbital period formula is expressed as :

[tex]T^{2}[/tex] = 4[tex]\pi ^{2}[/tex] [tex]r^{3}[/tex]  ÷ GM

Suppose a planet orbits a star at the same distance as Earth (1 AU) but with a period of roughly 200 Earth days. The mass of the central star will be greater than the mass of our sun based on the formula given above.

In a geostationary orbit, whatever the mass of the satellite may be, they will travel at the same speed in a particular orbit. mass M in the above formula becomes the mass of the sun or the center mass.

Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun.

Therefore, the correct answer is option C

Learn more here: https://brainly.com/question/19680441

See screen shot...momentum in collision

Answers

Please find attached photographs for your answer.

Hope it helps.

Do comment if you have any query.

The sandbox of the previous exercises had 10kg of sand. It was initially at 15°C and the specific heat of this sand is 830 j/(kg°C). What will be the final temperature of the sand? (-8100J=|0kg)

Answers

Answer:

Sorry I need points [tex] \boxed{}[/tex]

Please help...
Describe energy transformations in your own words.

Answers

Energy transformations is a process of an energy form transforming into a new form of energy. Like thermal energy, mechanical, etc. An example; when we eat; it turns from chemical energy to mechanical or electrical to heat. Like a plug and to activate a toaster.

When might people use data tables and graphs in their everyday lives? How are these uses similar to and different from the way in which scientists use these same tools?
Do you think scientists need data tables and graphs to do their work?
Which fields of science do you think might use data tables and graphs more than others?

Answers

Answer:

hahaha bisa aja ente gan di download di sini adalah salah satu

what is pole of magnet
and
define the term magnetic line of force​

Answers

Answer:

1. The magnetic pole is the region at each end of a magnet where the external magnetic field is the strongest.

2. magnetic line of force - a line of force in a magnetic field. field line, line of force - an imaginary line in a field of force; direction of the line at any point in the direction of the force

Explanation:

could someone answer this

Answers

The given kinematic equations of motion are derived from Newton's Laws

of Motion.

A) The ball's speed the instant it left the soccer player's foot is approximately 11.074 m/s.

B) The time it took the ball to rise to its maximum height is approximately 1.129 seconds.

Reasons:

The direction the ball is kicked = Upwards in the air

Maximum height to which the ball rises = 6.25 m

A) The speed of the ball the instant it left the soccer player's foot

Solution:

The equation to use is; v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)

[tex]a_y[/tex] = The acceleration due to gravity ≈ -9.81 m/s²

At the maximum height, y - y₀ = 6.25 m

The velocity at the maximum height, v = 0

v₀ = The speed of the ball the instant it left the soccer player's foot

Which gives;

v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)

0 = v₀² - 2 × 9.81 × (6.25) = v₀² - 122.625

v₀² = 122.625

v₀ = √(122.625) ≈ 11.074

The ball's speed the instant it left the soccer player's foot, v₀ ≈ 11.074 m/s.

B) Required:

The time it takes the soccer ball to rise to the maximum height.

Solution:

The equation of motion required is v = v₀ + [tex]a_y[/tex]·t

At the maximum height, v = 0

v₀ ≈ 11.074 m/s

v = v₀ + [tex]a_y[/tex]·t

Which gives;

0 = 11.074 - 9.81 × t

[tex]t \approx \dfrac{11.074}{9.81} \approx 1.129[/tex]

The time it took the ball to rise to its maximum height, t ≈ 1.129 seconds

Learn more here:

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The position-time graph for two drivers (A and B) are shown in the figure below. Which of the following statements is correct?

a. The two drivers are for sure moving in parallel directions
b. Driver B is moving faster than driver A.
c. Driver A is moving faster than driver B.
d. The two drivers are moving at the same speed

Answers

Answer:

A

Explanation:



©
Question 4 of 5
Which pair of objects would repel each other?
O A. A positively charged particle and a neutral particle

OB. A negatively charged particle and a neutral particle

O C. Two positively charged particles

OD. A positively charged particle and a negatively charged particle

Answers

Answer:

Two positively charged particles

Explanation:

I said two positively charged particles because if I say c or d what ever it is for you guy it can be wrong so just pick the one that says Two positively charged particles

Answer: C  Two positively charged particles.

Explanation:

just trust me on it, i've done the same quiz.

Consider the following arrangement with a frictionless/massless pulley. Determine the force F required to move block A if the coefficient of static friction between block A and the floor is 0.35 and the coefficient of static friction between block A and block B is 0.25

Answers

Answer: The free - body diagrams for blocks A and B. frictionless surface by a constant horizontal force F = 100 N. Find the tension in the cord between the 5 kg and 10 kg blocks. The string that attaches it to the block of mass M2 passes over a frictionless pulley of negligible mass. The coefficient of kinetic friction Hk between M.

Explanation: Hope this helped :)

Convert 9/4 hours into minutes

Answers

Am guessing;

9/4 × 60/1 =135

A person travels from C to D. One third of the time travels at v1 = 42km/h, the rest of the time travels at v2 = 36km/h. Find his average speed as he travels from C to D.

Answers

Answer:39km/h

Explanation:we know V=(u+v)/2. Here is u=42 and v=36

A 9.0V battery is connected across a 2.2kilo ohms and 6.8kilo omhs resistors connected in series. what is the potential differences across 2.2kilo ohms resistor.​

Answers

Answer:

[tex]V_{2.2} =2.2V[/tex]

Fast and loose: that's a classic voltage divider. the drop from the i-th resistor is [tex]R_i \over {\sum R}[/tex] of the drop across the whole series. In our situation, it's [tex]2.2\cdot 10^3 \over {2.2\cdot10^3 + 6.8\cdot 10^3[/tex] of 9 V. By plugging numbers in a calculator, it's 22/90 of 9V, or 2.2V

With Ohm's Law

The series is equivalent of a single resistor of Resistance [tex]2.2\cdot 10^3+6.8\cdot 10^3 \Omega = 9.0 k\Omega[/tex]. By Ohm's first Law ([tex]V=Ri[/tex]) the current flowing through the resistor is [tex]9V = 9*10^3\Omega i \rightarrow i=1mA[/tex]. At this point, the drop across the first resistor is, again by Ohm's law[tex]V = 2.2 \cdot 10^3 \Omega \cdot 1\cdot 10^{-3} A = 2.2V[/tex]

Which type of electromagnetic radiation is useful in communications technology?
A. X-rays
B. visible light
C. radio waves
D. ultraviolet radiation

Answers

Radio waves: they are present in radios and also walkie-talkies

Watch the video and make a ninja star. Once you have made a ninja star, 5 Point Ninja Star. Explain the energy transfer in the ninja star once it has been assembled.
PLEASE HELP​

Answers

There is no video attached lol maybe put the transcript in the comments if there is a person explaining it

Answer:

kinetic energy because it is movement

Explanation:

An object on Earth weighs 600 N and on Mars 100 N. If its mass on Earth is approximately 60 kg what is the mass of the object on Mars?

Answers

Answer:

I think its

10 kg

plzz plzz plzz. mark as brainliest

If the mass of an object is approximately 60 kg on earth then its mass remains the same on Mars which is 60 kg because mass does not change from place to place.

What is mass?

Mass in physics is a numerical representation of inertia, a fundamental property of all matter. What a body of matter is fundamentally is the resistance it offers to a change in its speed or location brought on by the application of a force. The more mass a body has, the less of a change a force exerts results. The kilogram is the unit of mass in the International System of Units, and it is defined by Planck's constant as being equal to 6.62607015 × 10⁻³⁴ joules second (SI).

According to the question, the weight of an object depends on gravity which is different from place to place so weight also varies from place to place but the mass is constant everywhere it does not change. So, if the mass of an object is 60 kg on earth then it remains the same on mars also.

To get more information about Mass :

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What is the Scientific name for Ectoparasites?

Answers

Ectoparasites are a taxonomically diverse group of organisms that infest the skin of human beings and other animals. Ectoparasitic arthropods and nematodes are similar in that an individual organism can produce skin lesions that are large enough to see with the unaided eye. Ectoparasitic infestations are often intensely itchy, causing considerable annoyance and discomfort. These conditions are often focally hyperendemic in impoverished communities, with a particularly high prevalence in vulnerable families, households, and neighborhoods.

Pediculosis (infestation by head and body lice) and scabies are found to some degree in all human populations, but myiasis (fly larva infestation), tungiasis (sand flea disease), and cutaneous larva migrans occur mainly in tropical and subtropical environments. Except for body lice, the organisms discussed in this article are not vectors of pathogenic microorganisms. In other words, most ectoparasites do not carry disease-causing agents; they are, instead, the direct cause of disease. Mortality is low, but the cumulative morbidity from the direct discomfort, secondary bacterial infections, and sequelae of those infestations and infections is considerable.

Despite the abundant presence of ectoparasitic infestations across human populations, biomedical science lacks firm evidence-based practices to reliably control these organisms. In addition, head lice and scabies are developing resistance to some chemical compounds employed to treat infested individuals, prevent spread, and control outbreaks.

Please mark me brainliest.

Un bloque de cobre cuya masa es 250 gramos , absorbe calor y su temperatura se eleva de 20 ˚C a 150 `C. ¿Cuál es la cantidad de calor absorbida por el bloque de cobre?. Expresar el resultado en unidades caloríficas y en unidades mecánicas.

Answers

Dada la información de la pregunta, el calor absorbido por el cobre es de 12513 J o 2990 calorías.

El calor ganado se obtiene de la relación;

H = mcdt

Dónde;

H = calor absorbido

m = masa

c = capacidad calorífica del cobre

Δt = cambio de temperatura

La capacidad calorífica del cobre es de 385 J / kg / ° C

Entonces;

m = 250 gramos o 0,25 kg

Δt = 150 ° C - 20 ˚C = 130 ˚C

H = 0,25 kg * 385 J / kg / ° C * 130 ˚C

H = 12513 J o 2990 calorías

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H is a chemical (blank) and H2 is a chemical (blank)
Please I need help!​

Answers

Answer:

"H" is a chemical symbol and "H2" is chemical formula.

A Rocket took 5 minutes to travel the 185 km. How fast did the Rocket travel in kilometers per minute (km/min)?

Answers

Answer:

The rocket travelled 37km per minute

Explanation:

185÷5=37

Two Force 16N and 4N acts at rights angle each other calculate the resultant force​

Answers

16N-4N= 12N
The Greater force is 16
The Lesser force is 4
So it is 12N
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