Answer:
When the Earth's magnetic field reverses, a new stripe, with the new polarity, begins. Such magnetic patterns led to recognition of the occurrence of sea-floor spreading, and they remain some of the strongest evidence for the theory of plate tectonics.
Explanation:
how does the final temperature of the gas compare with its initial temperature? express your answer using two significant figures. tcta
Step 1: Calculate the ratio of the final and beginning temperatures using the ideal gas law solved for temperature.
Step 2: Calculate the ratio after eliminating any constant values.
Step 3:Solve for the final temperature after substituting the beginning temperature into the ratio.
Perfect Gas Law: According to the ideal gas law, a gas's pressure, P, is inversely proportional to its volume, V, temperature, T, and the number of moles it contains, n, in the sample. The equivalent statement is: For these issues, we'll use the ratio of two temperatures. Because the ratio of starting to end volume and pressure will be the same regardless of the units used to express them, the volume and pressure can be expressed in any form. exhibited in (as long as the initial and final of each are expressed in the same units).PV= nRT
However, for this method to work properly, the temperature must be stated in Kelvin. This is true because Kelvin's zero point is absolute zero. Theoretically, molecules are entirely immobile at 0 Kelvin.
T = PV/nR
The ideal gas law equivalency is used to compute the final temperature in the next two issues.
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(1) A table tennis ball is dropped
onto the floor from a height of
4m and it rebounds to a height of
3m. If the time of contact with the floor is 0.01s, what is the magnitude and direction of the acceleration during the contact.
Answer:
Here, h1=4.00m,h92)=3.00m,Delta t =0.01 s.Letv1 be the velocity of the ball (actind downwards) just before striking the floor an dv20 be the velocity of the ball (acting upwaeds) ust after striking the floor. Then, change in velocity of the ball in time Δtv2−(−v1)v2+v1
:. acceleration, a=v2+v1Δt ..(i)
When body falls from height h1,
then u=o,v1,a=gandS=h1
As, v21=u2+2aS,
:. v_(1) ^(2) =0 + g h_(10 or v12–√gh1
Taking motion of the ball after striking the floor, then u=v2,v=0,a=−g,S=h2
As, v2=u22as,∴v21=0+2gh1orv_(1) =sqrt 32 g h_(1)Tak∈gmotionoftheballa>erstrik∈gthe⌊,⌋thenu=v_(2), v=0, a=- g, S=h_(2)As,v2=u2+2aS,wehave0 = v_(2)^(2) +2 (-g) h_92) otr v2=2–√gh2
Putting values in (i) we get,
a=2–√gh2+2–√gh1Δt)
a=2–√×9.8×3+2–√×9.8×40.01
= 1652m/s2.
Explanation:
which of the following sequences lists methods for determining distance in the correct order from nearest to farthest?
Parallax, main-sequence fitting, cepheid variables, Tully-Fisher relation, and Hubble's law are the sequence lists methods for determining distance.
Parallax is the closest method for determining distance. This method uses the principle of triangulation to measure the distance of a nearby star relative to Earth. Main-sequence fitting is another method used to measure the distance of stars. This method compares the brightness of a star to other stars of known distance and luminosity to determine its distance.
Cepheid variables are stars whose brightness varies in a predictable way over time. This method uses the period of the star's brightness to determine its intrinsic luminosity, and then its distance. The Tully-Fisher relation is a method for measuring the distance of galaxies. This method uses the rotation speed of the galaxy and its brightness to calculate its distance.
Finally, Hubble's law is the most distant method for determining distance. This law states that the farther away a galaxy is, the faster it moves away from us. This allows us to calculate the distance of galaxies by measuring their rate of recession.
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Two frequency generators are creating sounds of frequencies 460 and 471 Hz simultaneously. Randomized Variables f1 = 460 Hz f2 = 471 Hz Part (a) What average frequency will you hear in Hz?
The average frequency will be 465.5 Hz.
The frequency of light can be described as the number of waves passing through a point in a medium (or vacuum) per second.
It is measured in units of Hertz (Hz). Electromagnetic radiation propagates through space as a wave, and one type of radiation differs from another in the frequency of this wave. Electromagnetic radiation is categorized using the electromagnetic spectrum, which is usually organized by frequency.Frequency generated by generator 1 = f1 = 460 Hz
Frequency produced by generator 2 = f2 = 471 Hz
the average frequency will be (f1 + f2) / 2
f1 + f2 = 460 + 471
f1 + f2 = 931 Hz
Average frequency = A = 931/2
A = 465.5 Hz
The average frequency we hear will be 465.5 Hz.
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For a particular nonlinear spring, the relationship betweem the magnitude of the applied force F and the resultant displacement x from equilibrium is given by the equation F = k x^2 What is the amount of work done by stretching the spring a distace x0? A) kx0^3 B) (1/2)kx0 C) (1/2)kx0^3 D) (1/3)kx0^2 E) (1/3)kx0^3
To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo
[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]
The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]
The given parameters:
- Applied force on the spring [tex]$=F$[/tex]
- Extension of the spring [tex]$=x_0$[/tex]
The work done by stretching the spring to the given distance is calculated as follows;
[tex]W=\frac{k x_0}{3}[/tex]
[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]
Thus, the work done by stretching the spring to the given distance is
[tex]W=\frac{k x_0}{3}[/tex]
measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
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Two long parallel wires are placed side by side on a horizontal table. The wires carry equal currents in the same direction. Which of the following statements are true? Check all that apply. The magnetic field is a maximum at a point midway between the two wires The magnetic force between the two wires is attractive. The magnetic force between the two wires is repulsive. The magnetic field at a point midway between the two wires is zero.
When two long parallel wires are placed side by side on a horizontal table and the wires carry equal currents in the same direction, the magnetic field at a point midway between the two wires is zero.
When two parallel wires carry current in the same direction, they exert equal and opposite attractive forces on each other. Thus, the net magnetic field at midpoint is zero. While, Two parallel wires carrying current in opposite directions repel and try to move away from each other.
Similarly, if you have two parallel wires with current traveling in opposite directions, as you do in the series circuit, then the magnetic fields of the two wires will be traveling in the same direction at the point at which they intersect, and therefore repel each other.
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During the collision, the car and truck exert forces on each other. Which of the following is a correct statement about these forces and gives evidence to support this statement? The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the truck changes. B The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the car changes. С The forces the truck and car exert on each other must be external to the truck-car system because the momentum of both the truck and car change. D The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same E The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system changes.
The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same. Option D
What is the Collison?We know that it is possible for an object to be able to bump into another object when this occurs, we would have to apply the law of the conservation of linear momentum. Recall that from the law of the conservation of linear momentum, momentum before collision is equal to the momentum after collision.
We would also have to consider the fact that the weight of the truck is much lager than the weight of the car. The forces that the two vehicles would exert on each other can not be the same. It is clear that the truck is going to exert more force than the car.
With that said, we must have in mind that the total momentum of the system does not change because we are going to approximate the system to function as a closed system.
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What does the law of conservation of energy state?
energy cannot be destroyed but it can change forms
energy always gets used up in every chemical reaction
energy can be destroyed but not created
energy is always the same and it cannot be changed
I think it is "energy cannot be destroyed but it can change forms".
NAME THAT DISORDER
For the following scenarios, identify the psychological disorder indicated (if there is definitely a disorder). Indicate the reason why you chose that diagnosis (i.e., what are the symptoms/behaviors presented). According to your textbook (or any other source you would like to use), what might be an appropriate course of treatment (use all that could apply) for the diagnosis you chose. Try to be as specific as possible.
Homework assignment is due prior to the start of class on WEDNESDAY, DECEMBER 14TH.
1. When Lila saw the policeman turn on his flashing blue lights and motion her to pull over, her heart rate increased, her mouth felt dry, and she quite nervous about what was going to happen.
2. Although doctors could find no evidence of brain damage, Ralph could not remember driving the car that was involved in the accident that resulted in the deaths of his wife and son.
3. When Sammi saw Andrea three months ago, Andrea was too busy to talk. She was involved in all kinds of plans for a vague new business that she was sure to make her a fortune. But just last week, Sammi heard that Andrea was feeling very low, was sleeping most of the time, and had given up all plans to do just about anything.
4. Timothy was having an increasingly difficult time completing his reading assignments. He was becoming unsure if what he was reading was really there or if his mind was making things up. This was not helped by the “kryptonite rays” being emitted by the smoke detector and the hidden camera spying on him from behind the mirror in his room.
5. Ever since her home was burglarized, Maria double checks to make sure the doors are locked before going to bed.
6. Randall is so afraid of bacteria that each day he must wash each dish and utensil three times in scalding, soapy water and then rinse each dish exactly twenty seconds. If he deviates from this ritual in the slightest way, he must wash all the dishes and utensils again.
7. Everything was hopeless. Francine felt that because she was such a horrible wife and mother she felt she didn’t deserve to live and that her husband should find a better person to be with. She cried all the time and couldn’t escape her sadness.
8. When the helicopter crash landed, Yusef was horrified. He and he pilot were injured and the gas tank could blow at any time. Although he had a broken arm, Yusef was able to pull both himself and the unconscious pilot out of the plane and to safety before it blew. But ever since that time, the unbroken arm he used to save himself and the pilot has been ‘paralyzed’ and Yusef does not appear to be too upset about it.
9. Carlos, who is turning 40, is very worried about having about having a heart attack since his brother, father, and grandfather died of heart attacks in their 40s.
10. On the way home, Celia found herself having difficulty breathing, and her heart was pounding so hard that she could barely see clearly. She pulled off the road where she continued to hyperventilate, feel dizzy, and have sweaty palms. After about 10 minutes or so, her breathing returned to normal and she continued on her drive home.
Where the exercise here is to name the disorder, note that:
It should be mentioned that medication (such as antidepressants or benzodiazepines) and/or counseling may be used to treat a panic disorder such as cognitive-behavioral therapy.
A suitable course of treatment for dissociative disorders may involve counseling (such as cognitive-behavioral therapy, trauma-focused therapy, or psychodynamic therapy) and/or medication.
The focus of psychodynamic therapy is on unconscious processes as they show in the client's current behavior. Client self-awareness and knowledge of the effect of the past on present behavior are the aims of psychodynamic therapy.
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Students will design an experiment to determine how the magnitude of the force on a segment of straight, current-carrying wire depends on the length of the wire segment and on the strength of the magnetic field. Which of the following experimental procedures will allow the students to determine both of these relationships? A Making measurements of the force on several different straight segments of wire, increasing the length of the wire and increasing the magnetic field strength with each measurement. B Making measurements of the force on several different straight segments of wire, increasing the length of the wire and decreasing the magnetic field strength with each measurement с Making measurements of the force on several different straight segments of wire, keeping the length of the wire constant while increasing the magnetic field strength with each measurement. D Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength the same with each measurement, then repeating the measurements while decreasing the length of the wire and increasing the magnetic field strength with each measurement E Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength constant with each measurement, then repeating the measurements while keeping the length of the wire constant while increasing the magnetic field strength with each measurement.
The experimental procedures that will allow the students to determine both of these relationships is option E:
Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength constant with each measurement, then repeating the measurements while keeping the length of the wire constant while increasing the magnetic field strength with each measurement.What happens to the magnetic field when the length of wire increases?The formula F = IL x B calculates the magnetic force acting through a magnetic field on a current-carrying wire. The magnetic field acts on a wire when a current is conducted through it in a direction that is perpendicular to both the magnetic force.
By increasing the amount of current flowing through the wire, the magnetic field's strength can be enhanced. As you get further from the wire, the strength gets weaker. If the amount of current flowing through it stays constant, its length and thickness have no bearing.
Therefore, the length of the wire in the magnetic field has an impact on the magnetic force's strength as well. The force acting on a wire increases with wire length in a magnetic field.
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A small box of mass m is kicked up an inclined plane with an initial velocity v, and slides up the incline a distance L before it stops. The inclined plane makes an angle a with the horizontal, and the friction coefficient is u. What is the distance L the box slides up the ramp before it stops? (Hint: The known quantities are the mass, the initial speed, the angle, the coefficient of friction, and the acceleration of gravity:{m, Vo, a,u,9). Solve for the distance L in terms of these quantities.)
Main Answer:
The distance of L is [tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]
Explanation:
if the block will slide a distance 'L' then syoped;
The initial velocity given to the block is V m/s
So, Total K.E given will goes to gain in potential energy and work done by friction .
K.E=1/2mv^2
P.E at hight (Lsin[tex]\alpha[/tex]) will be = mgh
And work done by the Friction Force is given as = w.r = force*displacement= - uNL= -uMgGcos[tex]\alpha[/tex]L
so,
KE+WD by friction = gain in P.E
[tex]1/2mv^{2} +(-uMgGcos\alpha L)=MgLsin\alpha \\1/2V^{2} =glsin\alpha +uglcso\alpha \\v^{2} /2= Gl(sin\alpha +ucos\alpha )[/tex]
Hence by solving we get :
[tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]=L
So the distance = L
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short 10g rope is used to pull a 50g toy across a horizontal surface without friction. if a force of 3.0 x 10 -2 n is applied horizontally to the free
0.025 N the force of the string on the toy, at the other end of the rope.
What is friction?Friction is a force that resists the relative motion of two objects that are in contact with each other. It is caused by the interaction of the surfaces of the two objects and the molecules that make them up. Friction can be either static or kinetic. Static friction occurs when the two surfaces are not moving relative to each other, while kinetic friction occurs when the two surfaces are moving relative to each other. Friction is a type of force that can be both beneficial and detrimental.
Mass of the string (m) = 10 grams or 10⁻² kg
Mass of the toy (M) = 50 g or 5 x10⁻² kg
Mass of the system = M + m
= 10⁻² + 5 x 10⁻²
= 6 x 10⁻² kg
Force applied (F) = 3.0 x 10⁻² N
Acceleration of toy + string = (0.03/6) x 10⁻²
= 0.5m/s²
Thus force on the toy = 5 x10⁻² x 0.5
= 0.025 N
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The complete question is as follows:
A short 10g string is used to pull a 50g toy across a frictionless horizontal surface. if a 0.03N force is applied horizontally to the free end, the force of the string on the toy, at the other end, is:
according to the maxwellian speed distribution, as the temperature increases the number of molecules with speeds within a small interval: increases decreases increases at high temperatures and
According to the Maxwellian speed distribution, as the temperature increases, the number of molecules with speeds within a small interval decreases.
Temperature is a bodily quantity that expresses the perceptions of hotness and coldness. Temperature is measured by using a thermometer. Thermometers are calibrated in diverse temperature scales that have been trusted by various reference points and thermometric materials for definition.
Temperature plays a vital role in hospital treatment, food, drinks, and agriculture. Our health is often reliant upon the temperature in many methods as properly. Preserving the right temperature degrees in cold garage areas is crucial.
The SI unit of temperature as in line with the international machine of units is Kelvin that's represented by the symbol K.
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the use of the doppler effect in the study of astronomy
if an object producing sound is moving away from you, you would observe a wavelength than an object moving toward you. group of answer choices
If an object producing sound is moving away from us, the wavelength of the sound heard is longer than the actual wavelength. The conclusion is from the concept of Doppler effect.
What is the Doppler effect?The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.
The equation of the Doppler effect is
f₀ = [(v ± v₀)/(v ± vs)] × fs
Where
f₀ = observer frequency of soundv = speed of sound waves (340 m/s)v₀ = observer velocityvs = source velocityfs = actual frequency of sound wavesNote:
v₀ (+) if the observer moves closer to the sound source.vs (+) if the sound source moves away from the observer.When an object producing sound is moving away from us, the frequency of the sound we heard changed.
Let's say we are at rest, it means v₀ = 0. The sound source is moving away makes vs (+).
With the Doppler's effect, we get
f₀ = [(v+0) / (v+vs)] × fs
f₀/fs = v/(v+vs)
v < v+vs
f₀ < fs
The frequency of sound we heard is lower that the actual frequency.
The wavelength is inversely proportional to the frequency. It is described in the equation:
λ = c/f
It means that the lower the frequency, the longer the wavelength.
Hence, the phenomenon which the wavelength of the sound we heard is longer than the actual wavelength when the sound source is moving away from us is called the Doppler's effect.
Here is the group of answer choices:
(a) Band width
(b) Doppler's effect
(c) Sound refraction
(d) Vibrations
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schedules of reinforcement farm workers are paid x amount of dollars for every basket of fruit that they pick
Schedules of reinforcement farm workers are paid x amount of dollars for every basket of fruit that they pick is based on the concept of fixed ratio.
A strengthening timetable, during which an answer or reaction is only strengthened after yet another given reaction can be determined, could be determined as a fixed ratio schedule. The particular topic gives a variety of questionnaires/solutions and therefore is subsequently rewarded by the educator or coach.
The man is under a fixed interval schedule of reinforcement, while the woman is under a fixed ratio schedule of reinforcement. Fixed interval reinforcement is a type of reinforcement that gives reward only after a specific period of time has passed. A fixed ratio reinforcement is a type of reinforcement that is based on production rate.
The other type is variable ratio. Variable Ratio schedule of reinforcement will give a person rewards after he/she fulfil a specific amount of works.
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a long, straight, thin-walled cylindrical shell of radius r carries a current i. find the magnetic field outside the cylinder (r > r) and inside the cylinder (r < r).
The magnetic field inside the cylinder is zero and outside the cylinder is
B = μ₀ I/(2*π*r)
The circulation of the magnetic field along a circular path of radius, r , is given by:
⇒ B cosθ (2* π* r)
where, cos θ is 1 if the field forms circles. Now that the Amperian loop is closed, we may analyze the current inside of it. The net current that travels across the surface defined by the Amperian loop determines the enclosed current. The enclosed current is denoted by the letter I since the loop completely encloses the wire. Making use of Ampere's Law,
B cosθ (2* π* r) = μ₀ I
Since, the right-hand side of the equation is not zero at this moment, it is obvious that cos cannot be zero. As a result, we can draw the conclusion that, as we had previously predicted, the magnetic field must form concentric rings. The magnetic field's strength is determined by:
B = μ₀ I/(2*π*r)
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Design a parallel RLC circuit (see (Figure 1)) with a resonant radian frequency of 5000 rad/s. Take that L 10 mH.a) Find the value of C Express your answer to three significant figures and include the appropriate units. C= 4.00 μFb) Find the value of R so that the response is critically damped. Express your answer to three significant figures and include the appropriate units R- 25.0 Ω
The value of R so that the response is critically damped using the equation is 25.0Ω.
What is Farads?Farads is the unit of measure for capacitance, which is the amount of electrical charge stored for a given voltage. Farads can be used to measure the amount of energy stored in a capacitor, which is made up of two conductive plates separated by an insulating material. The higher the capacitance, the more energy can be stored in a given capacitor. Farads are named after Michael Faraday, the British scientist who discovered the relationship between electricity and magnetism.
The resonant frequency of an RLC circuit is given by the equation:
ω_r=1/sqrt(LC)
where ω_r is the resonant frequency in rad/s, L is the inductance in Henries, and C is the capacitance in Farads.
Given the resonant frequency of 5000 rad/s and the inductance of 10 mH, we can calculate the capacitance as follows:
C=1/(ω_r^2*L)
C=1/(5000^2*0.01)
C=4.00μF
We can find the value of R so that the response is critically damped using the equation:
R=2*sqrt(L/C)
R=2*sqrt(0.01/4.00)
R=25.0Ω
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In the figure, a climber leans out against a vertical ice wall that has negligible friction. Distance a is 0.945 m and distance L is 1.95 m. His center of mass is distance d = 0.89 m from the feet-ground contact point. If he is on the verge of sliding, what is the coefficient of static friction between feet and ground?
The coefficient of static friction between feet and ground is 0.2522.
What is static friction?Static friction is defined as when there is no motion between the two surfaces, the force that one surface applies to another. The friction that exists between two or more objects when they are not moving relative to one another is referred to as static friction.
The coefficient of static friction between his feet and the ground, denoted by the symbol s, determines how to express the frictional force as
fs =μsFN1
The μs can be calculated as
μs = a / √L² - a² x d / L
μs = 0.945 / √(1.95)² - (0.945)² x 0.89 / 1.95
μs = 0.945 / √2.91225 x 0.89 / 1.95
μs = 0.2522
Thus, the coefficient of static friction between feet and ground is 0.2522.
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Calibration of a bomb calorimeter is performed with: Select the correct answer below: a. a specific volume of water b. a specific mass of copper c. a reaction with known.
d. manually entered data
A reaction with a known q, such as a measured amount of benzoic acid ignited by a spark from a nickel fuse wire that is weighed before and after the reaction, is used to calibrate bomb calorimeters.
How is a bomb calorimeter calibrated?By releasing a known amount of thermal energy through an electric heater and measuring the subsequent rise in temperature, the calorimeter is calibrated. The energy released when a certain amount (for example, 1 mol, 1 g, or 1 L) of a substance burns entirely in oxygen is known as the heat of combustion.
What type of fuel is the reference fuel for bomb calorimeter calibration?A typical standard used in Bomb calorimeters, which keep a constant volume, is benzoic acid. If. Burning 1.2 g of benzoic acid at a temperature of 24 degrees, with excess oxygen present, releases 31.723 J of energy.
What does calorimeter calibration entail?When calibrating CALORIMETERS, a known electric current is frequently generated inside of them, and the measuring device is then watched for deflection while the system is in a steady condition. Heat loss along the leads through which the calibrating current is injected could be a drawback for this procedure.
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A 2.2-mm-diameter and 10-m-long electric wire is tightly wrapped with a 1-mm-thick plastic cover whose thermal conductivity is k = 0.15 W/m.K. Electrical measurements indicate that a current of 13 A passes through the wire and there is a voltage drop of 8 V along the wire. If the insulated wire is exposed to a medium at T = 30°C with a heat transfer coefficient of h = 24 W/m2.K, determine (a) the temperature (in °C) at the interface of the wire and the plastic cover in steady operation. Electrical wire To = 30°C Insulation 10 m (c). Continue the previous questions. Determine if doubling the thickness of the plastic cover will increase or decrease this interface temperature. will increase interface temperature because of heat transfer from interface decrease will decrease interface temperature because of heat transfer towards interface decrease will decrease interface temperature because of heat transfer from interface increase will increase interface temperature because of heat transfer towards interface increase will have no effect on interface temperature
Doubling the thickness of the plastic cover increases the rate of heat loss and decreases the interface temperature.
Given:
The diameter of the electric wire t=1mm
The diameter of plastic cover ro=1+1.1=2.1
Internal conductivity of plastic cover k=0.15w/MK
the current passed through circle I=13A
voltage drop v=8v
temperature T=30c
Heat transfer fluid h=24w/m^2k
Let To be the temperature of the wire and T1 is the temperature of the plastic cover.
the heat generated Q=>v*I=13*8=104 watt
Now the heat generated is connected and converted through wire
Q= To-T1/ln(ro/rc)/2pi*KL+1/hAo
104=To-30/ln(2.2/1.1)/2pi*0.15*10+1/24*20*0.00021*16
104=To-30/0.38439
To=69.9768c
To=70c
The temperature at the Interface of the wire is 70c
Now, the heat generated is connected to the wire
Q=To-T1/ln(ro/rc)/2piKL
104=70-T1/ln(2.1/1.1)/2pi*0.15*10
7.13536=10-T1
T1=6.2864c
The critical radius of Isolation:
rc=k/h=0.5/24
rc=6.25*10^-3m
rc=6.25mm
Now the thickness of isolation is increased to double
ro=1.1+2=3.1mm
Now,rc>ro ie critical radius of isolation is greater than the outer radius of the circle.
∴doubling the thickness of the plastic cover increases the rate of heat loss and decreases the interface temperature.
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The Sun's evolution from youngest to oldest stage is:
A) white dwarf, red giant, main-sequence, protostar
B) red giant, main-sequence, white dwarf, protostar
C) protostar, red giant, main-sequence, white dwarf
D) protostar, main-sequence, red giant, white dwarf
D) The Sun's evolution from youngest to the oldest stage is protostar, main-sequence, red giant, a white dwarf.
A protostar is the very beginning stage of a star's life. It is a cloud of gas and dust that starts to collapse due to its own gravitational pull. As it collapses, the gas and dust heat up, and eventually, nuclear fusion begins, creating a star.
The main-sequence stage is the longest and most stable period of a star's life. During this stage, the star is converting hydrogen into helium in its core, producing energy and light. This stage can last for billions of years.
Once a star has used up its hydrogen fuel, it enters the red giant phase. This is when the star expands, becoming much larger and much brighter. The star is now converting helium into other elements in its core, such as carbon and oxygen.
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When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?
The centripetal force needed to keep the fly from sleeping will be zero point 0.00176 Newton in magnitude.
The mass of the fly is 2 gram and it is selling itself on a phonograph turntable.
The fly is at a distance of 4 cm away from the center of the phonograph turntable and when the turntable is turned on and retreats with 45 Revolution per minute the centripetal force that would be working on the fly will be given by,
F = Mw²R
Where,
M is mass of the fly,
w is the angular speed of the fly and,
R is the radius of the turnable.
Putting all the values,
F = 0.002×(4.7)²×0.04
F = 0.00176N.
So, a centripetal force of magnitude 0.00176 Newton will be required in order to keep the fly from slipping.
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Complete question- A fly of mass 2.00 g is sunning itself on a phonograph turntable at a location that is 4.00 cm from the center. When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?
supply drop design proposal
TRUE OR FALSE in physics, every physical quantity is measured with respect to a unit. time is measured in seconds, length is measured in meters, and mass is measured in kilograms. knowing the units of physical quantities will help you solve problems in physics.
The unit of G is found out to be m³/kg * s².
The force of gravitational attraction is represented by the equation.
F = (G m₁ m₂)/r²
where,
F is the magnitude of the gravitational attraction on either body
m₁ and m₂ are the masses of the bodies,
r is the distance between them
G is the gravitational constant
We need to find the unit of G,
G = (F * r²)/(m₁ m₂)
Let us place the units for the above formula,
G = (N * m²)/kg²
N = kg m/s²
G = (kg * m * m²)/ kg² * s²
G = m³/kg * s²
Thus, the correct option is m³/kg * s².
The question is incomplete. The complete question is 'Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation.
F= Gm1 m2 /r^2
where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distance between them, and G is the gravitational constant. In Sl units, the units of force are kg m/s^2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?
a. kg^3/ms^2
b. kgs^2/m^3
c. m^3/kgs^2
d. m/kgs^2
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A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page, as shown above. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines.
If wire loop is being pulled to the right with a constant velocity of 3 meters per second , then the potential difference induced between points X and Y is 3V .
it is given that a 5Ω resistor is connected between points X and Y ;
the magnetic field (B) = 0.5 ;
length of wire (l) [tex]=[/tex] 2 ;
velocity of the wire loop (v) = 3 m/s ;
the potential difference will be induced because charge separation on the vertical hand wire of wire loop.
Points X and Y are the same as the top and bottom of left wire.
The EMF(potential difference) induced in wire is given by
EMF = B*l*v
substituting the values ,
we get
= (0.5)(2)(3) = 3V
Therefore , the induced potential difference between points X and Y is 3V .
The given question is incomplete , the complete question is
A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines. The loop is being pulled to the right with a constant velocity of 3 meters per second. Make all determinations for the time that the left end of the loop is still in the field, and points X and Y are not in the field.
Determine the potential difference induced between points X and Y.
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Calculate the internal energy of 1.2moles of steam at 177degree
Answer:
18447 J
Explanation:
To calculate the internal energy of steam at a given temperature, we need to know the specific heat capacity of steam and the enthalpy of vaporization. The specific heat capacity of steam at a constant pressure is approximately 2.08 J/g*K, and the enthalpy of vaporization (latent heat) at 100°C is 2257 kJ/kg.
We can use the following equation to calculate the internal energy of steam at a given temperature:
U = m * Cp * (T - T_b) + m * L
Where U is the internal energy, m is the mass of the steam, Cp is the specific heat capacity of steam, T is the temperature of the steam, Tb is the boiling temperature of the steam, and L is the enthalpy of vaporization.
Since we are given the amount of steam in moles (1.2 moles) and the temperature (177°C), we can convert the moles of steam to mass using the molar mass of water (18 g/mol). The boiling temperature of water at standard atmospheric pressure is 100°C, so we can use this value for Tb.
First, we need to convert the temperature from degrees Celsius to kelvins:
T = 177°C + 273 = 450 K
Then, we can calculate the mass of the steam:
m = 1.2 moles * 18 g/mol = 21.6 g
Substituting these values into the equation for internal energy, we get:
U = 21.6 g * 2.08 J/g*K * (450 K - 273 K) + 21.6 g * 2257 kJ/kg
Solving for the internal energy, we get:
U = 18,447 J
Therefore, the internal energy of 1.2 moles of steam at 177°C is approximately 18,447 J.
a hydraulic lift (jack) has two pistons, one large and one small. the pistons are at the same elevation. if it is equilibrium, which piston exerts the greatest force
The force exerted at the large piston will be double in magnitude in comparison with the force applied at the smaller piston.
We know, according to the pascal's law,
The pressure applied at any point in the incompressible fluid is equal in magnitude at each and every point.
So,
P = Force/Area
Where P is pressure,
If pressure is same, then we can write,
F₁/A₁ = F₂/A₂
Where,
F₁ is the force applied at the small piston,
A₁ is the area of the smaller piston,
F₂ is the force at the larger piston,
A₂ is the area of the larger piston,
It is also given that, area if the larger piston is two times the area of the smaller piston so,
A₂ = 2A₁
So, putting the values we get,
F₂/F₁ = 2
So, F₂ = 2F₁
It means that the force exerted by the larger piston will be double in magnitude.
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compare the time it takes for light to travel 1000 m on the surface of the earth and in outer space.
Since light is faster in space, it takes less time for light to travel a distance of 1000m, a time difference of 0.977ns.
Light travels more slowly in a transparent medium than in the vacuum of empty space. The speed of light in any medium (air, water, glass) is determined by the refractive index of the medium. However, this exponent itself may be wavelength dependent (ie different colored rays travel at different speeds). In fact, this is why a prism splits white light into the colors of the rainbow.
The main reason that a light beam slows down in a medium has to do with the fact that the photons, or 'raw light beams', are excited by an electromagnetic field. When the field is in the ground state (vacuum), these excitations actually propagate at the vacuum speed of light. However, when there are positively charged atoms and negatively charged electrons, the electromagnetic field does not go to the ground state. There are many virtual photons. Yes, some of the photons of the passing light beam can be absorbed. After all, no material is completely transparent. But even those who aren't are moving in an environment so different from the vacuum that their paths will be different. It also depends on the structure that the molecule forms.
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location of inhibitors bound to group iva phospholipase a2 determined by molecular dynamics and deuterium exchange mass spectrometry. t/f
Location of inhibitors bound to group iva phospholipase a2 determined by molecular dynamics and deuterium exchange mass spectrometry. (True)
Combining deuterium exchange mass spectrometry (DXMS) and molecular dynamics, we investigated the binding of group IVA (GIVA) phospholipase A2 (PLA2) inhibitors (MD). On the basis of deuterium exchange results, models of the GIVA PLA2 inhibitors pyrrophenone and the 2-oxoamide AX007 docked into the protein were created, and comprehensive molecular dynamics simulations were performed to determine protein–inhibitor interactions. The models demonstrate that both inhibitors interact with crucial residues that modify the deuterium exchange pattern in response to inhibitor binding. Pyrrophenone is primarily associated with the protein through contacts close to the active site, whereas oxoamide is primarily attached through contacts remote from the active site. We also compare the dynamics of the two inhibitor-bound complexes around the active site. It is possible to create better inhibitors against GIVA PLA2 by combining computational and experimental approaches to define more precise inhibitor binding locations.
Mass Spectrometry:
In order to determine the mass-to-charge ratio (m/z) of one or more molecules found in a sample, mass spectrometry is a valuable analytical instrument. The precise molecular weight of the sample's constituent parts can frequently be determined using these measures as well. Mass spectrometers are typically used to quantify known substances, identify novel compounds by molecular weight determination, and assess the structure and chemical characteristics of molecules.
∴ Location of inhibitors bound to group iva phospholipase a2 determined by molecular dynamics and deuterium exchange mass spectrometry. (True)
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