The conjugate base of a neutral acid that donates a proton will have a charge of -1.
When a neutral acid donates a proton, it is undergoing a process called deprotonation, meaning it has lost a proton from its molecular structure. In this reaction, the neutral acid becomes an anion (negatively charged ion) and the proton is picked up by the base, which is then referred to as the conjugate base of the acid. The conjugate base will have a charge of -1 because it now has one extra electron relative to the original neutral acid.
To illustrate this reaction, consider acetic acid (CH3COOH) donating a proton to a base. When the acid donates a proton, it becomes an anion, CH3COO-, and the base, which has gained a proton, is the conjugate base and has a charge of -1.
In summary, when a neutral acid donates a proton, the conjugate base will have a charge of -1.
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Which of the following are volume ratios from this equation? Select all that apply.
2H2 + O2 --> 2H2O
The volume ratios from the equation 2H2 + O2 → 2H2O are:
2 L H2 : 1 L O2 (or 2 mol H2 : 1 mol O2)1 L O2 : 2 L H2O (or 1 mol O2 : 2 mol H2O)The coefficients in a balanced chemical equation give the ratio of moles of reactants and products. From the equation 2H2 + O2 → 2H2O, we can see that:
2 moles of H2 react with 1 mole of O2 to produce 2 moles of H2O.Therefore, the following volume ratios are valid:
2 L H2 : 1 L O21 L O2 : 2 L H2OWhat are the reactants?
The reactants are the substances that participate in a chemical reaction and are consumed to form new products. In the equation 2H2 + O2 → 2H2O, the reactants are hydrogen gas (H2) and oxygen gas (O2). These reactants undergo a chemical reaction to form water (H2O) as the product.
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Using C2H4 + 3 O2 -> 2 CO2 + 2 H2O. If 20 moles of fuel are combusted in the above equation, how many moles of O2 are consumed?
Answer:
Using C2H4 + 3 O2 -> 2 CO2 + 2 H2O. If 20 moles of fuel are combusted in the above equation, how many moles of O2 are consumed?
Explanation:
According to the balanced chemical equation:
1 mole of C2H4 reacts with 3 moles of O2
Therefore, for 20 moles of C2H4 combusted, we would need:
20 moles C2H4 × (3 moles O2 / 1 mole C2H4) = 60 moles O2
So, 60 moles of O2 are consumed in the combustion of 20 moles of C2H4.
Which of the following molecules is drawn in a conformation that has a proton and a leaving group anti-periplanar? H₂C, Br Ph. H CH3 Br H H₂C Br H₂C Ph H₂C CH3 H Ph H₂C, Br H Ph Save for Later CH3 CH3 CH3 CH3 CH3 Sul
The molecule that is drawn in a conformation that has a proton and a leaving group anti-periplanar is H₂C, Br.
The A, B, C, and D bond angles of a molecule are referred to as anti-periplanar, or antiperiplanar, in organic chemistry. The dihedral angles of the A–B and C–D bonds in this conformer are larger than +150° or less than 150°. In textbooks, the term "anti-periplanar" is frequently used to refer to a strictly anti-coplanar structure with a 180° AB CD dihedral angle. The anti-periplanar functional groups will be 180° apart from one another and in a staggered configuration in a Newman projection of the molecule.
Conformation is an essential factor in predicting reactivity in organic molecules. The anti-periplanar conformation of a molecule is one that occurs when two atoms in a molecule are in the same plane and are separated by 180 degrees. In this case, the proton and leaving group are placed in a perpendicular plane to the atoms directly in between them. This is the most stable conformer of the molecule. A significant factor in predicting reactivity in organic molecules is conformation. In this case, the molecule H₂C, Br is drawn in a conformation that has a proton and a leaving group anti-periplanar.
Therefore, the correct option is H₂C, Br.
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Calculate the pH of a 0.40 M solution of sodium acetate (NaCH3COO) given that the Ka of acetic acid (CH3COOH) is 1.8 x 10-5 a. 9.26 c. 2.57 O d. 4.83 e. 11.43
Option (C) is correct. The pH of the solution of sodium acetate (NaCH3COO) given that the Ka of acetic acid (CH3COOH) is 2.57.
Sodium acetate is defined as the salt of a weak acid and strong base from the equation:
C2H3NaO2 ---> CH3COO−+Na+
CH3COO− + H2O ⇌ CH3COOH + OH−
As it is a weak acid and strong base, this is a good indicator of a fairly high pH value.
Kb = [HB+] + [OH−] / [B]
where, [B] is the concentration of the base[HB+] is the concentration of base ions.[OH−] is the concentration of the hydroxide ions.
Ka Kb=1⋅10−14
So, Kb=1⋅10−14 / 1.8⋅10−5
=5.555...⋅10−10
Putting the value of this in the expression of pH we get the value of pH .
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The air trapped inside a 240 mL glass bottle has a pressure of 1.0 atm and a temperature of 25.0 °C. You put the glass bottle into a freezer. After several hours, the air trapped inside the bottle has a temperature of -35.0 °C and a pressure of 0.80 atm. Determine the value of k for the air trapped inside the glass bottle before and after cooling to show that P equals kT.
The value of k for the air trapped inside the glass bottle before and after cooling is 0.2021, thus proving that P equals kT.
The air trapped inside a 240 mL glass bottle has a pressure of 1.0 atm and a temperature of 25.0 °C. To determine the value of k for the air trapped inside the glass bottle before and after cooling to show that P equals kT, we need to use the ideal gas law equation, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature. When the bottle is put into the freezer, the temperature decreases from 25.0 °C to -35.0 °C and the pressure decreases from 1.0 atm to 0.80 atm. Therefore, we can calculate the value of k by plugging in the values of pressure and temperature into the equation: PV = nRT. By rearranging the equation and solving for k, we find that k = PV/nRT. Plugging in the values, we get k = (1.0 atm x 240 mL) / (n x 0.0821 atm•L/mol•K x (25.0°C - (-35.0°C)) = 0.2021. This means that the value of k for the air trapped inside the glass bottle before and after cooling is 0.2021, thus proving that P equals kT.
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how many different alkenes result when 2-bromooctane is treated with a strong base? select answer from the options below
Strong bases like sodium ethoxide (NaOEt) or sodium hydroxide (NaOH) are used to treat 2-bromooctane, which then goes through an elimination process (also known as dehydrohalogenation) to produce various alkenes.
Which 4 alkenes are there?Ethene, propene, butene, and pentene are the first four alkenes.
Alkenes are a group of unsaturated hydrocarbons (i.e., molecules with solely carbon and hydrogen) that include at least one double bond from carbon to carbon. Olefins is a different name for alkenes. Due to the double bond, alkenes are more reactive than alkanes.
Both the hydrocarbons alkene and alkyne are unsaturated.
Whereas two Carbon atoms in Alkyne are joined by a triple bond, two Carbon atoms in Alkene only have a double bond.
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Calculate Delta H r* n for Ca(s) + 1/2 * O_{2}(g) + C*O_{2}(g) -> CaC*O_{3}(s)
a. -813.4 kJ. enthalpy of the reaction is -813.4 kJ
One of the characteristics of a thermodynamic system is enthalpy, which is calculated by multiplying the internal energy of the system by the sum of its pressure and volume. The total enthalpy of a system cannot be directly calculated because the internal energy's components are either unknown, hard to access, or unimportant to thermodynamics.The overall reaction can be represented as: [tex]Ca(s) +\frac{ 1}{2}O_2(g) + CO2(g) \rightarrow CaCO_3(s).[/tex]
The reaction enthalpy [tex](\Delta H_{rxn})[/tex]is the result of adding the reaction's separate enthalpies.The enthalpy of each of the individual reactions is given as:
[tex]Ca(s) + \frac{1}{2}0_2(g) \rightarrow Cao(s) \Delta H_{rxn} = -635.1 kJ CaCO_3(s) \rightarrow Cao(s) + CO2(g) \Delta H_{rxn} = 178.3 kJ[/tex]
Therefore, the overall enthalpy change for the reaction is given as:
[tex]\Delta H_{rxn} = \Delta H_{rxn}(Ca(s) +\frac{ 1}{2}0_2(g) \rightarrow Cao(s)) +\Delta H_{rxn} (CaCO_3(s) \rightarrow Cao(s) + CO2(g))[/tex]
[tex]\Delta H_{rxn} = -635.1 kJ + 178.3 kJ \Delta H_{rxn} = -813.4 kJ[/tex]
Therefore,The reaction's enthalpy is -813.4 kJ.
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complete question:Calculate delta Hrxn for Ca(s) + 1/202(g) + CO2(g) => CaCO3(s) given the following set of reactions: Ca(s) + 1/202(g) => Cao(s) delta Hrxn = -635.1 kJ CaCO3(s) => Cao(s) + CO2(g) delta Hrxn = 178.3 kJ a. -813.4 kJ
b. -456.8 kJ
c. 813.4 kJ
d 456.8 kJ
e. None of these is within 5% of the correct answer.
molarity of a solution that contains 29.4 grams of NaCl in 250 ml of water?
Answer:
2.16 M
Explanation:
The molarity of the solution is 2.16 M. To calculate the molarity, you need to first determine the number of moles: 29.4 grams of NaCl is equal to 0.737 moles. Then, divide the number of moles, 0.737, by the volume of the solution, which is 250 mL. Multiplying the result by 1000 gives the molarity, which is 2.16 M.
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2ca + o2 - 2cao identify the oxidizing and reducing agents
Answer:
Ca is a reducing agent and O is the oxidizing agent.
Explanation:
calcium is the reducing agent as it reduces oxygen while it oxidize itself and oxygen is an oxidising agent because it oxidized others and reduces itself. in this equation oxygen is reducing and Calcium is oxidising. and as it is stated in the definition that oxidizing agent is the agent which oxidises others and reduces itself and it is also stated that reducing agent reduces others and oxidize itself. so based on this statement calcium is reducing agent and O is a oxidizing agent.
add curved arrows to show the mechanism of the propagation steps to form each monochlorination product shown.
To form each of the monochlorination products shown, you will need to draw curved arrows that demonstrate the propagation steps. The first step is when a chlorine radical combines with the double bond to form a chlorine radical cation, which then donates an electron to the double bond.
This results in the formation of two radical chlorides, one on each carbon atom. These radicals then combine with two hydrogen atoms to form the monochlorination product, completing the reaction.The curved arrows for this process should be drawn as follows:
An arrow pointing from the chlorine radical to the double bond, representing the attack of the radical all arrows have been drawn, the monochlorination product has been formed. The mechanism of propagation steps to form each monochlorination product is shown in the following reaction:To represent this reaction, you can draw a curved arrow to show the movement of electrons from the bond to the chlorine. The arrow should start from the carbon-carbon double bond and point towards the chlorine.
Then, another curved arrow can be drawn to represent the formation of the C-Cl bond. The arrow should start from the chlorine and point towards the carbon with the unpaired electron.This process can be repeated to form the second monochlorination product. The following diagram shows the mechanism of the propagation steps:Here, you can see that the curved arrows are used to represent the movement of electrons during the reaction. The arrows point towards the atom that is gaining the electrons.
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0.10 molL-1 NaCl solution contains 1.0 mole of NaCl
The volume of the 0.10 molL⁻¹ NaCl solution which contains 0.1 mole of sodium chloride, NaCl is 1 L
How do i determine the volume of the solution?Molarity of a solution is defined by the following formula:
Molarity = mole / volume
Cross multiply
Molarity × volume = Mole
Divide both sides by molarity
Volume = mole / molarity
With the above formula, we can obtain the volume of the solution. Details below:
Molarity of solution = 0.10 molL⁻¹Mole of NaCl = 0.1 moleVolume of solution =?Volume = mole / molarity
Volume of solution = 0.1 / 0.1
Volume of solution = 1 L
Thus, we can conclude that the volume of the solution is 1 L
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Complete question:
0.10 molL⁻¹ NaCl solution contains 1.0 mole of NaCl. What is the volume of the solution?
please answer the question for BRAINLIEST asap
Using the formula M1V1 = M2V2 , if I add water to 100.0 mL of a 0.15 M NaOH solution until the final volume is 150 mL, what will the molarity of the diluted solution be?
Question 3 options:
0.23M
1.0M
0.10M
1.0E5M
Answer:
M2= 0,1 M
Explanation:
M1=0,15 M
V1= 100 mL =0,1 L
M2= ?
V2= 150 mL = 0,15 L
M1V1= M2V2
(0,15 mol/L) (0,1 L) = M2 (0,15 L)
0,015 mol / 0,15 L = M2
M2= 0,1 M
Please help me Look at the picture below
The first two statements are false, whereas the last statement, which says that pressure and volume of a gas are inversely related, is true.
How are pressure and volume related to one another?Statement 1: This claim was incorrect because, according to the ideal gas law, PV=nRT, pressure (P) and volume (V) are inversely proportional to each other at a constant temperature (T) and amount of gas (n). This means that as pressure increases, volume decreases. This relationship is known as Boyle's law. Therefore, the statement that pressure has no effect on volume of a gas is false.
Statement 2: This claim was incorrect because, pressure and volume of a gas are inversely related according to Boyle's law, which states that at a constant temperature, the pressure of a gas is inversely proportional to its volume. This means that if the pressure of a gas increases, its volume will decrease, and if the pressure decreases, the volume will increase, as long as the temperature remains constant.
Statement 3: This claim was correct because, According to Boyle's law, the pressure and volume of a gas are inversely proportional to each other, which means that when the pressure of a gas increases, its volume will decrease and vice versa, as long as the temperature and the number of particles in the gas are kept constant. This relationship is expressed mathematically as P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
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why can't the enthalpy of formation of calcium carbonate be determined directly?
The enthalpy change can not be measured directly because you have to take into account how much energy was put into the reaction in the first place.
Hope this helps!!! :)
The standard enthalpy of formation of all elements in their standard states are assumed to be zero. It is not possible to determine the enthalpy of formation of calcium carbonate as it is formed from other compounds.
What is enthalpy of formation?The standard enthalpy of formation of a compound can be defined as the enthalpy change accompanying the formation of one mole of the compound from its constituent elements, all the substances being in their standard states.
The standard enthalpy of formation is usually denoted as ΔfH⁰. For example the enthalpy of formation of CO₂ and CH₄ are -393.5 kJ mol⁻¹ and -74.8 kJ mol⁻¹ respectively.
Here CaCO₃ is formed by the reaction:
CaO + CO₂ → CaCO₃
The enthalpy change for the given reaction is not an enthalpy of formation of CaCO₃. Since CaCO₃ is not formed from its constituent elements.
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Calculate the hydronium ion concentration, [H3O+], for a solution with a pH of 6.82.
[H₂0¹] =
M
The hydronium ion concentration, [H+] of a solution with a pH of 6.82 is 1.51 × 10-⁷ M.
How to calculate hydrogen ion concentration?The hydrogen or hydronium ion concentration of a solution can be calculated from the pH using the following formula;
pH = - log {H+}
[H+] = 10−pH
by exponentiating both sides with base 10, we can "undo" the common logarithm.
{H+} = 10-⁶.⁸²
{H+} = 0.000000151356
[H+] = 1.51 × 10-⁷ M
Therefore, the hydronium ion concentration with a pH of 6.82 is 1.51 × 10-⁷ M.
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Determine the pressure (in atm) of a 7.16-g sample of He gas at 692 K in a container with a volume of 55.9 L.
Answer:
1.82 atm
Explanation:
Ideal gas law
P=nRT/V
1) solve for n which is moles
7.16 / 4 = 1.79 mole He
2)
n=1.79
R=0.0821
T=692 K
V=55.9
P=1.79 X 0.0821 X 692 / 55.9 =1.82 atm
Seventy five percent of a compound is carbon. If you have 250 grams of this particular compound, how much carbon is contained?
Answer:
The compound has 187.5 g. of Carbon
Explanation:
If the 100% of the compound is 250 gr, then you can calculate the 75% of it by multiplying:
Amount of Carbon = (75%) 250 g.
75%= 0.75
250 (0.75)
= 187.5 g.
Need BIO help with both questions
Answer:
6. The light being reflected off changes the color shown
7. The bottom, the sugar looses its positive charge
Explanation:
A chemist must dilute 93.1 mL of 7.79 of uM aqueous mercury (I) chloride solution until the concentration falls to 3.00 uM. She’ll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate the final volume in liters.
Taking into account the definition of dilution, if chemist must dilute 93.1 mL of 7.79 of uM aqueous mercury (I) chloride solution until the concentration falls to 3.00 uM, the final volume is 0.24175 L.
Definition of dilutionDilution is a procedure by which the concentration of a solution is lowered, usually with the addition of a diluent.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volumeFinal volumeIn this case, you know:
Ci= 7.79 uMVi= 93.1 mLCf= 3 uMVf= ?Replacing in the definition of dilution:
7.79 uM× 93.1 mL= 3 uM× Vf
Solving:
(7.79 uM× 93.1 mL)÷ 3 uM= Vf
241.75 mL= 0.24175 L = Vf (being 1000 mL= 1 L)
In summary, the final volume is 0.24175 L.
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which of the following is the correct electron configuration for tc? select the correct answer below: [kr]5s24d5 [kr]4d7 [kr]5s24d2 [kr]5s25d5
The correct electron configuration for Tc (technetium) is [Kr] 5s² 4d⁵. Therefore, the correct answer is: [kr]5s²4d⁵.
What is technetium?Technetium (Tc) is a radioactive chemical substance with the atomic number 43 and symbol Tc. It is a silvery-gray metal that belongs to the transition metals group on the periodic table. Technetium is the first element to be artificially produced, and all of its isotopes are radioactive, with no stable isotopes. It is a highly toxic and dangerous element, and therefore has no significant commercial applications. Technetium has many nuclear and medical applications due to its radioactivity, and is used in medical imaging, cancer treatment, and scientific research.
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Answer:
C
Explanation:
edg 2023
What kind of scientist would study the effects of acid rain on marble statues? A. A physicist B. A biologist C. A chemist D. An economist
Scientists would research the impacts of marble monuments and acid rain. A chemist. Hoping this is useful.
The correct answer is :C.
What are the substances that change the earth's surface?Surface sediments are transported and large stones are broken up through wind, water, and ice. Years are often needed for weathering, erosion, and deposition to cause noticeable changes. Nonetheless, certain things change the Planet's surface far more quickly than others. Extreme events, earthquakes, and volcanic eruptions are a few of them.
What adjustments to the Planet's surface may rain makes?Weathering and erosion caused by water movement change the properties of the terrain. Regional wind patterns and climate are defined by several interactions, including the role of the ocean. The unique physical and chemical properties of water have a profound effect on the planet's dynamics.
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use the trendline equation in fig6.2 to determine the kelvin temperature at which the pressure equals .72 atm
When the pressure is 0.72 atm, the temperature in Kelvin is 156 K.
To determine the Kelvin temperature when the pressure is 0.72 atm, you will need to use the trendline equation given in Fig 6.2. First, find the equation of the trendline by using the graph's two points, (300 K, 1 atm) and (500 K, 2 atm).
The equation for the trendline is:
y = mx + b
Where y is pressure, x is the temperature in Kelvin, m is the slope, and b is the y-intercept. We can find the slope of the trendline by using the two points provided in the graph:
Slope (m) = (y2 - y1) / (x2 - x1)
Slope = (2 atm - 1 atm) / (500 K - 300 K)
Slope = 0.005 atm/K
The equation for the trendline can now be written: y = 0.005x + b. To find the y-intercept, b, we can use one of the two points: Solving for b:
1 atm = 0.005(300 K) + bb = 1.5 atm
Now we can use the equation for the trendline to find the temperature (x) at which the pressure (y) equals 0.72 atm:
0.72 atm = 0.005x + 1.5 atm
0.72 atm - 1.5 atm = 0.005x
-0.78 atm = 0.005xx
= -0.78 atm / 0.005x
= 156K
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3. Draw a Lewis dot structure for the fictitious molecular ion [ZO2]-1. Assume that the central Z atom is bonded to each of the outer O atoms by a single bond. What is the formal charge on the Z atom?
The formal charge on the Z atom in the [ZO2]-1 ion is +1.
The Lewis dot structure for the [ZO2]-1 molecular ion is:
O
|
Z === O
|
O-
1. Determine the total number of valence electrons in the ion by adding the valence electrons of each atom and the charge of the ion.
Z has 4 valence electrons, while each O atom has 6 valence electrons.The ion has an overall negative charge of 1, so there is one extra electron.Total number of valence electrons = 4 + 6 + 6 + 1 = 172. Connect the Z atom to each O atom with a single bond, which uses up 2 electrons.
We now have 15 electrons left to distribute.3. Add the remaining electrons in pairs as lone pairs to each atom until all valence electrons are used up.
Each O atom needs 2 lone pairs (4 electrons).Z needs 2 lone pairs (4 electrons).4. Draw the Lewis dot structure.
The Lewis dot structure for [ZO2]-1 is:O
|
Z === O
|
O-
5. Calculate the formal charge on the Z atom using the formula:
Z has 4 valence electrons.Z has 2 lone pairs (4 electrons) and 2 bonding electrons (1 bond to each O).Formal charge = valence electrons - (number of lone pair electrons + 1/2 x number of bonding electrons)
Formal charge = 4 - (2 + 1/2 x 2) = 4 - 3 = +1
Therefore, the formal charge on the Z atom in the [ZO2]-1 ion is +1.
What is valence electron?
A valence electron is an electron in the outer shell associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed.
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Cryolite, Na3AlF6(s),
an ore used in the production of aluminum, can be synthesized using aluminum oxide.
equation:
Al2O3(s)+6NaOH(l)+12HF(g)⟶2Na3AlF6+9H2O(g)
If 10.3 kg of Al2O3(s),
55.4 kg of NaOH(l),
and 55.4 kg of HF(g)
react completely, how many kilograms of cryolite will be produced?
mass of cryolite produced:
The mass (in kilograms) of Cryolite, Na₃AlF₆ produced, given that 10.3 Kg of Al₂O₃, 55.4 Kg of NaOH, and 55.4 Kg of HF react completely is 42.4 Kg
How do i determine the mass of Na₃AlF₆ produced?The mass of Na₃AlF₆ produced from the reaction can be obtained as follow:
Al₂O₃(s) + 6NaOH(l) + 12HF(g) ⟶ 2Na₃AlF₆ + 9H₂O(g
Molar mass of Al₂O₃ = 102 g/molMass of Al₂O₃ from the balanced equation = 1 × 102 = 102 g = 102 / 1000 = 0.102 KgMolar mass of Na₃AlF₆ = 210 g/molMass of Fe from the balanced equation = 2 × 210 = 420 g = 420 / 1000 = 0.420 KgFrom the balanced equation above,
0.102 Kg of Al₂O₃ reacted to produce 0.420 Kg of Na₃AlF₆
Therefore,
10.3 Kg of Al₂O₃ will react to produce = (10.3 × 0.420) / 0.102 = 42.4 Kg of Na₃AlF₆
Thus, from the above calculation, it is evident that the mass of Na₃AlF₆ produced is 42.4 Kg
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Enter your answer in the provided box.
Answer the following questions about the fermentation of glucose (C6H12O6, molar mass 180.2 g/mol) to ethanol (C2H6O) and CO2.
C6H12O6(s) → 2 C2H6O(l) + 2 CO2(g) ΔH = −16 kcal/mol
glucose ethanol
How many kilocalories of energy are released from 40.0 g of glucose?
kcal of energy released
Report answer to TWO significant figures.
Answer:
Explanation:
40/ 180.2 x (-16 / 1 mole glucose)=-3.6 KJ
Consider a 0.238 M aqueous solution of sodium hydroxide, NaOH.
How many grams of NaOH are dissolved in 23.46 mL?
Answer:
0.2237 grams of NaOH
Explanation:
To calculate the grams of NaOH dissolved in 23.46 mL of a 0.238 M solution of NaOH, we can use the formula:
mass = molarity x volume x molar mass
where mass is the mass of NaOH dissolved in grams, molarity is the concentration of NaOH in moles per liter, volume is the volume of the solution in liters, and molar mass is the molar mass of NaOH in grams per mole.
First, we need to convert the volume of the solution from milliliters to liters:
volume = 23.46 mL / 1000 mL/L
volume = 0.02346 L
The molar mass of NaOH is 40.00 g/mol.
Now we can plug in the values and solve for mass:
mass = 0.238 M x 0.02346 L x 40.00 g/mol
mass = 0.2237 g
Therefore, there are 0.2237 grams of NaOH dissolved in 23.46 mL of a 0.238 M solution of NaOH.
When a mineral breaks along a weekly bonded plane it is called
Answer: Cleavage
Explanation:
When a mineral breaks along a weekly bonded plane it is called cleavage
For the partially completed Lewis structures, pick the correct Lewis structure.
How many Valence Electrons total overall?
The correct Lewis structures of the compounds that we have in the question have been shown in the images attached.
What is the Lewis structure?A Lewis structure is a diagram that shows the bonding between atoms in a molecule and the arrangement of electrons around the atoms. It is also known as a Lewis dot structure, Lewis dot diagram, or electron dot structure.
Lewis structures are useful in predicting the geometry of molecules and determining the polarity of molecules. They are also helpful in understanding the reactivity of molecules and how they interact with other molecules.
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a 0.100 mole sample of ethane, c2h6, contains which of these? hint: how many atoms are present in one c2h6 molecule?
0.100 mole sample of ethane contains approximately 1.204 x [tex]10^{24}[/tex] carbon atoms and 3.612 x [tex]10^{24}[/tex] hydrogen atoms.
What are the atoms?
In one molecule of ethane (C2H6), there are 2 carbon atoms and 6 hydrogen atoms.
To determine how many atoms are present in a 0.100 mole sample of ethane, we can use Avogadro's number, which relates the number of particles (in this case, molecules) to the amount of substance in moles. Avogadro's number is approximately 6.02 x [tex]10^{23}[/tex] particles per mole.
So, a 0.100 mole sample of ethane would contain:
0.100 x 6.02 x [tex]10^{23}[/tex]molecules of ethane2 x 0.100 x 6.02 x [tex]10^{23}[/tex] carbon atoms (since each ethane molecule contains 2 carbon atoms)6 x 0.100 x 6.02 x [tex]10^{23}[/tex] hydrogen atoms (since each ethane molecule contains 6 hydrogen atoms)Simplifying this expression, we get:
6.02 x [tex]10^{22}[/tex] molecules of ethane1.204 x [tex]10^{24}[/tex]carbon atoms (2 x 6.02 x [tex]10^{22}[/tex])3.612 x [tex]10^{24}[/tex] hydrogen atoms (6 x 6.02 x [tex]10^{22}[/tex])Therefore, a 0.100 mole sample of ethane contains approximately 1.204 x [tex]10^{24}[/tex] carbon atoms and 3.612 x [tex]10^{24}[/tex] hydrogen atoms.
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what is the formula for co3+ and se2-?
The formula for Co3+ is Co3+ because it represents the ion of cobalt that has lost three electrons, leaving it with a 3+ charge.
What is chemical formula and how they are formed ?
A chemical formula is a symbolic representation of a chemical compound that shows the types of elements present in the compound and the relative number of atoms of each element. For example, the chemical formula for water is H2O, which indicates that it is made up of two hydrogen atoms and one oxygen atom.
Chemical formulas are formed by identifying the elements that make up a compound and determining the relative number of each element in the compound. The number of each element is represented by a subscript following the chemical symbol of the element. For example, the chemical formula for methane is CH4, which indicates that there is one carbon atom and four hydrogen atoms in each molecule of methane.
The formula for Se2- is Se2- because it represents the ion of selenium that has gained two electrons, giving it a 2- charge.
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