Find a fraction equivalent to
that has a denominator of 10.

Answer:

u = 2

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj side / hypotenuse

cos 45 = sqrt(2) / u

u cos 45 = sqrt(2)

u = sqrt(2) / cos 45

u = sqrt(2) / 1/ sqrt(2)

u = sqrt(2) * sqrt(2)

u =2

u=2

Answer:

Solution given:

Cos 45°=base/hypotenuse

[tex]\frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{u}[/tex]

doing crisscrossed multiplication

[tex]\sqrt{2}*\sqrt{2}=1*u[/tex]

u=2

what? ;-;.............

Answer:

D represents a proportional relationship

Step-by-step explanation:

Proportional graphs always intersect with zero

Answer:

80 Seconds

I dont really want to type the whole thing out, just think about it again, or go to a tutor website, you should be able to get it, you have to use these, multiplication of three numbers, and multiplication and division by factorization of numbers.

Step-by-step explanation:

24. = 249030/30

=8,301 rs

Answer:

24. 8301, divide 249030 by 30

25. 9989001, but i dont know the property

Step-by-step explanation:

Answer:

3000

growth

2.2%

Step-by-step explanation:

Answer:

sorry I don't know the answer

Answer:

For the equation y=log(x-k), the domain depends on the value of K. Sliding K moves the left bound of the domain interval. The range and the right end behavior stay the same. For the equation y=log x+k, the domain is fixed, starting at an x-value of 0. The vertical asymptote is also fixed. The range of the equation depends on K.

Step-by-step explanation:

Answer:

-2,2

Step-by-step explanation:

Let

[tex]y_1=4x^2-c^2[/tex]

[tex]y_2=c^2-4x^2[/tex]

We have to find the value of c such that the are of the region bounded by the parabolas =32/3

[tex]y_1=y_2[/tex]

[tex]4x^2-c^2=c^2-4x^2[/tex]

[tex]4x^2+4x^2=c^2+c^2[/tex]

[tex]8x^2=2c^2[/tex]

[tex]x^2=c^2/4[/tex]

[tex]x=\pm \frac{c}{2}[/tex]

Now, the area bounded by two curves

[tex]A=\int_{a}^{b}(y_2-y_1)dx[/tex]

[tex]A=\int_{-c/2}^{c/2}(c^2-4x^2-4x^2+c^2)dx[/tex]

[tex]\frac{32}{3}=\int_{-c/2}^{c/2}(2c^2-8x^2)dx[/tex]

[tex]\frac{32}{3}=2\int_{-c/2}^{c/2}(c^2-4x^2)dx[/tex]

[tex]\frac{32}{3}=2[c^2x-\frac{4}{3}x^3]^{c/2}_{-c/2}[/tex]

[tex]\frac{32}{3}=2(c^2(c/2+c/2)-4/3(c^3/8+c^3/28))[/tex]

[tex]\frac{32}{3}=2(c^3-\frac{4}{3}(\frac{c^3}{4}))[/tex]

[tex]\frac{32}{3}=2(c^3-\frac{c^3}{3})[/tex]

[tex]\frac{32}{3}=2(\frac{2}{3}c^3)[/tex]

[tex]c^3=\frac{32\times 3}{4\times 3}[/tex]

[tex]c^3=8[/tex]

[tex]c=\sqrt[3]{8}=2[/tex]

When c=2 and when c=-2 then the given parabolas gives the same answer.

Therefore, value of c=-2, 2

Answer:

The total number of ways is 252.

Step-by-step explanation:

Number of girls = 18

number of boys = 14

Commitee of one girl and a boy

(18 C 1)(14 C 1)

= 252

Answer:

x = 2 - sqrt(19/6)

x = 2 + sqrt(19/6)

Step-by-step explanation:

Answer:

add 4

subtract 24 from 5

2

Step-by-step explanation:

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

[tex](a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) = Q(x)[/tex]  is a differential equation.

If [tex]Q(x) \neq 0[/tex]

It is non homogeneous then,

The general solution  = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution =  complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

[tex]$(2D^3+15D^2+24D+11)y=0$[/tex]

Auxiliary equation,

[tex]$2m^3+15m^2+24m +11 = 0$[/tex]

-1  | 2    15    24     11

    | 0   -2    - 13    -11  

      2    13    11       0

∴ [tex]2m^2+13m+11=0[/tex]

The roots are

[tex]$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$[/tex]

[tex]$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$[/tex]

[tex]$=\frac{-13\pm9}{4}$[/tex]

[tex]$=-5.5, -1$[/tex]

So, [tex]m_1, m_2, m_3 = -1, -1, -5.5[/tex]

Then the general solution is :

[tex]$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$[/tex]

Answer:

432x^13

Step-by-step explanation:

(4x^2)^2 • (3x^3)^3

We know that a^b^c = a^(b*c)

4^2 x^2^2  * 3^3 x^3^3

16 x^4  * 27 x^9

We know that a^b ^ a^c = a^(b+c)

16*27 x^(4+9)

432x^13

Answer:

432x¹³

Step-by-step explanation:

( 4x² ) ² • ( 3x³ ) ²

( 16x²)² • ( 27x³)²

[tex]16 x{}^{2 \times 2} \times 6 {}^{3 \times 3 } \\ 16x {}^{4} \times27 {}^{9} [/tex]

[tex](16 \times 27)x {}^{4 + 9} [/tex]

432x¹³

In an arithmetic sequence, every pair of consecutive terms differs by a fixed number c, so that the n-th term [tex]a_n[/tex] is given recursively by

[tex]a_n=a_{n-1}+c[/tex]

Then for n ≥ 2, we have

[tex]a_2=a_1+c[/tex]

[tex]a_3=a_2+c = (a_1+c)+c = a_1 + 2c[/tex]

[tex]a_4=a_3+c = (a_1 + 2c) + c = a_1 + 3c[/tex]

and so on, up to

[tex]a_n=a_1+(n-1)c[/tex]

Given that [tex]a_3=126[/tex] and [tex]a_{64}=3725[/tex], we can solve for [tex]a_1[/tex]:

[tex]\begin{cases}a_1+2c=126\\a_1+63c=3725\end{cases}[/tex]

[tex]\implies(a_1+63c)-(a_1+2c)=3725-126[/tex]

[tex]\implies 61c = 3599[/tex]

[tex]\implies c=59[/tex]

[tex]\implies a_1+2\times59=126[/tex]

[tex]\implies a_1+118 = 126[/tex]

[tex]\implies \boxed{a_1=8}[/tex]

The width of the actual garden patio according to the scale drawing is 14 meters.

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.

Given the scale of 1 cm : 2 m

For a patio of 7 cm, then:

Actual patio = 7 cm / (1 cm/ 2m) = 14 m

The width of the actual garden patio according to the scale drawing is 14 meters.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

Answer:

option D (5 6 8 9) is the answer

Answer:

X [tex]\Longrightarrow -8\Longrightarrow -1\Longrightarrow 1\Longrightarrow 8[/tex]

Y[tex]\Longrightarrow 5\Longrightarrow 6\Longrightarrow 8\Longrightarrow 9[/tex]

[tex]Answer\hookrightarrow D)[/tex]

-------------------------

Hope it helps...

Have a great day!!

Answer:

52 is (a)

55 is.( d)

56. is (d)

Answer:4 ma boi

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

because I am god at meth and very smart

Answer:

Step-by-step explanation :

Let % increase in administrative secretary be = x

Let % increase in new faculty receive be = y

Administrative secretary salary = 28,000

New faculty receive Salary = 40,000

(8)*(x/100)* (28000) + (7)*(y/100)*(40000) = 5,000

2240x +2800 y = 5,000

224x +280 y = 500

56x +70y = 125

Therefore, x and y should be chosen such that it satisfy the above equation.

Answer:

A) quadratic

Step-by-step explanation:

ax2 + bx+c=0

Since the highest power of the equation is 2

A) quadratic -2

B) quartic- 4

C) linear- 1

D) cubic-3

Answer:

See answers below

Step-by-step explanation:

Given the following functions:

r(x) = x - 6

s(x) = 2x²

r(s(x)) = r(2x²)

Replacing x with 2x² in r(x) will give;

r(2x²) = 2x² - 6

r(s(x)) = 2x² - 6

(r-s)(x) = r(x) - s(x)

(r-s)(x) = x - 6 - 2x²

Rearrange

(r-s)(x) = - 2x²+x-6

(r+s)(x) = r(x) + s(x)

(r-s)(x) = x - 6 + 2x²

Rearrange

(r-s)(x) = 2x²+x-6

Answer:

A. multi-way split.

Step-by-step explanation:

Multi way split consists of internal at decision tree branches. Gini index measures probability of impurity in the random variables chosen. Entropy is measure of uncertainty in the sample selected. Binary splitting is used to speed up numerical evaluation.

Answer:

I think the power is 4

Step-by-step explanation:

480J / 120 = 4

Put 2 mins into seconds which is 120 seconds

Sorry if it is wrong :)

Answer:

[tex]4\text{ watts}[/tex]

Step-by-step explanation:

In physics, the power of a machine is given by [tex]P=\frac{W}{\Delta t}[/tex], where [tex]W[/tex] is work in Joules and [tex]\Delta t[/tex] is time in seconds.

Convert 2 minutes into seconds:

2 minutes = 120 seconds.

Substitute [tex]W=480[/tex] and [tex]\Delta t=120[/tex] to solve for [tex]P[/tex]:

[tex]P=\frac{480}{120}=\boxed{4\text{ watts}}[/tex]

Answer:

The rate of change of f(x) is faster than the rate of change of g(x).

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

*Note:

Rate of Change is determined by slope.

Step 1: Define

f(x) = 3x + 5

↓ Compare to y = mx + b

Slope m = 3

g(x) = 2x + 5

↓ Compare to y = mx + b

Slope m = 2

Step 2: Answer

We can see that the slope of f(x) is greater than g(x).

∴ the rate of change of f(x) would be greater than g(x).

Answer:

[tex]7x {}^{2} + 5x[/tex]

Step-by-step explanation:

[tex]9x {}^{2} + 8x - (2x {}^{2} + 3x) \\ \\ = 9x {}^{2} + 8x - 2x {}^{2} - 3x (remove \: brackets) \\\ \\ = 7x {}^{2} - 5x [/tex]

Answer:

Symmetric with respect to the x-axis

Symmetric with respect to the y-axis

Symmetric with respect to the origin

Answer:

Maximum = 19

Minimum = 4

Median = 12

Step-by-step explanation:

The maximum number of phone sold per day is the value to the right of the horizontal axis as the values are arranged in ascending order ; Hence, the maximum number of phones sold per day is 19

Also, the minimum number of phones sold per day is the value to the left of the plot, Hence, minimum number of phones sold per day is 14.

The Median value : 4, 9, 14, 19

The median = 1/2(n+1)th term

1/2(5)th term = 2.5 th term

Median (9 + 14) /2 = 13 /2 = 11.5 = 12 phones

Answer:

Step-by-step explanation:

This is nice and simple. I'm going to walk through it like I do when teaching this concept to my class for the first time. This is a good problem for that.

We are given a square and we are looking for the rate at which the area is increasing when a certain set of specifics are given. That means that the main equation for this problem is the area of a square, which is:

[tex]A=s^2[/tex] where s is a side.

Since we are looking for the rate at which the area is changing, [tex]\frac{dA}{dt}[/tex], we need to take the derivative of area formula implicitly:

[tex]\frac{dA}{dt}=2s\frac{ds}{dt}[/tex] that means that if [tex]\frac{dA}{dt}[/tex] is our unknown, we need values for everything else. We are given that the initial area for the square is 49. That will help us determine what the "s" in our derivative is. We plug in 49 for A and solve:

[tex]49=s^2[/tex] so

s = 7

We are also given at the start that the sides of this square are increasing at a rate of 8cm/s. That is [tex]\frac{ds}{dt}[/tex]. Filling it all in:

[tex]\frac{dA}{dt}=2(7)(8)[/tex] and

[tex]\frac{dA}{dt}=112\frac{cm^2}{s}[/tex]

The surface area of a square of side L is given by

[tex]A = L^2[/tex]

The rate of change of the area per unit time is

[tex]\dfrac{dA}{dt} = 2L\dfrac{dL}{dt}[/tex]

We can express the length L on the right hand side in terms of the area A [tex](L = \sqrt{A})[/tex]:

[tex]\dfrac{dA}{dt} = 2\sqrt{A}\dfrac{dL}{dt}[/tex]

[tex]\:\:\:\:\:\:\:=2(\sqrt{49\:\text{cm}^2})(8\:\text{cm/s})[/tex]

[tex]\:\:\:\:\:\:\:=112\:\text{cm}^2\text{/s}[/tex]