Answer:
[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex] would ensure that at least one real root exists for this equation when solving for [tex]x[/tex].
Step-by-step explanation:
Apply the Pythagorean identity [tex]1 - \sin^{2}(x) = \cos^{2}(x)[/tex] to replace the cosine this equation with sine:
[tex](1 - \sin^{2}(x)) - (m^2 - 3)\, \sin(x) + 2\, m^2 - 3 = 0[/tex].
Multiply both sides by [tex](-1)[/tex] to obtain:
[tex]-1 + \sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 3 = 0[/tex].
[tex]\sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 2 = 0[/tex].
If [tex]y = \sin(x)[/tex], then this equation would become a quadratic equation about [tex]y[/tex]:
[tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex].
[tex]a = 1[/tex].[tex]b = m^{2} - 3[/tex].[tex]c = -2\, m^{2} + 2[/tex].However, [tex]-1 \le \sin(x) \le 1[/tex] for all real [tex]x[/tex].
Hence, the value of [tex]y[/tex] must be between [tex](-1)[/tex] and [tex]1[/tex] (inclusive) for the original equation to have a real root when solving for [tex]x[/tex].
Determinant of this quadratic equation about [tex]y[/tex]:
[tex]\begin{aligned} & b^{2} - 4\, a\, c \\ =\; & (m^{2} - 3)^{2} - 4 \cdot (-2\, m^{2} + 2) \\ =\; & m^{4} - 6\, m^{2} + 9 - (-8\, m^{2} + 8) \\ =\; & m^{4} - 6\, m^{2} + 9 + 8\, m^{2} - 8 \\ =\; & m^{4} + 2\, m^{2} + 1 \\ =\; &(m^2 + 1)^{2} \end{aligned}[/tex].
Hence, when solving for [tex]y[/tex], the roots of [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] in terms of [tex]m[/tex] would be:
[tex]\begin{aligned}y_1 &= \frac{-b + \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) + \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) + (m^{2} + 1)}{2} = 2\end{aligned}[/tex].
[tex]\begin{aligned}y_2 &= \frac{-b - \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) - \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) - (m^{2} + 1)}{2} \\ &= \frac{-2\, m^{2} + 2}{2} = -m^{2} + 1\end{aligned}[/tex].
Since [tex]y = \sin(x)[/tex], it is necessary that [tex]-1 \le y \le 1[/tex] for the original solution to have a real root when solved for [tex]x[/tex].
The first solution, [tex]y_1[/tex], does not meet the requirements. On the other hand, simplifying [tex]-1 \le y_2 \le 1[/tex], [tex]-1 \le -m^{2} + 1 \le 1[/tex] gives:
[tex]-2 \le -m^{2} \le 0[/tex].
[tex]0 \le m^{2} \le 2[/tex].
[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].
In other words, solving [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] for [tex]y[/tex] would give a real root between [tex]-1 \le y \le 1[/tex] if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].
On the other hand, given that [tex]y = \sin(x)[/tex] for the [tex]x[/tex] in the original equation, solving that equation for [tex]x\![/tex] would give a real root if and only if [tex]-1 \le y \le 1[/tex].
Therefore, the original equation with [tex]x[/tex] as the unknown has a real root if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].
A local charity earns money to donate to flood victims. It receives $200 per day in cash donations and $150 in pledges. Its operating costs are $75 per day. After how many days will the charity have enough money to make a donation of at least $1000?
Answer:
4 days at least
Step-by-step explanation:
A group of 80 frogs was observed. The mean distance of their hops is 69 inches with a standard deviation of 3.5 inches. How many frogs would you expect to jump more than 72.5 inches?
Hello,
[tex]z=\dfrac{X-69}{3.5} \\\\For\ X=72.5, \\\\z=\dfrac{72.5-69}{3.5} =1\\[/tex]
Using table of a normal reduced law:
p(z≤1)=0.8413
Thus p(z≥1)=1-0.8413=0.1587
There are 80*0.1587=12.696 ≈13 (frogs)
Answer:
12 frogs
Step-by-step explanation:
Hello,
Using table of a normal reduced law:
p(z≤1)=0.8413
Thus p(z≥1)=1-0.8413=0.1587
There are 80*0.1587=12.696 ≈12 (frogs) you don't round up because you cant have .7 percent of a frog.
ps. I copy and pasted caylus's response but corrected their answer because it was correct except the rounding up part.
Amy earned $25 after babysitting for 3 hours if amy always charges the same rate,how much will she make after babysitting for 7 hours
Come get your point with me :)
Answer:
IK≅WY
Step-by-step explanation:
The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2000 there were about
1,150 fish. Write an exponential decay function to model this situation. Then find the population in
2006.
Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
in a quadrilateral abcd the bisector of angle c and angle d meet at e. if angle a =70°and b=100°,find the measure of angle ced
Answer:
Step-by-step explanation:
Let CE and DE be the bisectors of ∠C and ∠D respectively. Then, ∠1 = 1/2∠C and ∠2 = 1/2∠D
In △DEC, we have
→ ∠1 + ∠2 + ∠CED = 180° [Sum of angles of a triangle]
→ ∠CED = 180° - (∠1 + ∠2). .....(i)
Again, the sum od the angles of a quadrilateral is 360°.
∴ ∠A + ∠B + ∠C + ∠D = 360°
→1/2(∠A + ∠B) + 1/2∠C + 1/2∠D = 180°
→1/2(∠A + ∠B) + ∠1+ ∠2 = 180°
→1/2(∠A + ∠B) = 180° - (∠1+ ∠2)....(ii)
From (i) and (ii), we get 1/2(∠A + ∠B) = ∠CED
Hence, ∠A + ∠B = 2∠CED
If EC = 10cm what must AC be if ABCD is a parallelogram?
5
10
or 20?
Answer:
it is 20 vecause I say so yeah hey guts
help me to solve this question please faster thankyouu
Answer:
Step-by-step explanation:
u799
Find the measure of the indicated angle
Answer:
Step-by-step explanation:
This is an isosceles triangle because 2 of the sides are the same length (marked with single slashed through them). The Isosceles Triangle Theorem tells that if 2 sides are congruent to each other, then the angles opposite those sides are congruent to each other as well. That means that the bottom left angle measures 68. According to the Triangle Angle-Sum Theorem, all the angles of a triangle have to add up to equal 180, so:
x = 180 - 68 - 68 so
x = 44
A certain medical test is known to detect 59% of the people who are afflicted with the disease Y. If 10 people with the disease are administered the test, what is the probability that the test will show that:
Answer:
[tex]P(x = 3) = 0.048[/tex]
Step-by-step explanation:
Given
[tex]n = 10[/tex]
[tex]p=59\% = 0.59[/tex]
Required
[tex]P(x = 3)[/tex] --- probability that 3 are afflicted
This question illustrates binomial probability and it is calcuated using:
[tex]P(x) = ^nC_x * p^x * (1 - p)^{n-x}[/tex]
So, we have:
[tex]P(x = 3) = ^{10}C_3 * 0.59^3 * (1 - 0.59)^{10-3}[/tex]
[tex]P(x = 3) = ^{10}C_3 * 0.59^3 * 0.41^7[/tex]
[tex]P(x = 3) = 120 * 0.59^3 * 0.41^7[/tex]
[tex]P(x = 3) = 0.048[/tex]
can you explain it please and which method is correct?
Answer:
The second one (answer of 3), but the other ones could've worked, they were just calculated wrong.
Step-by-step explanation:
Here's why each one did or didn't work:
First answer- you had the right idea by cancelling out the two in the denominator, however if you're going to divide 2, you have to divide it from everything in the equation. Meaning you would divide 4 by 2 to get 2, and then add the 1 + 2 to get final answer 3.
Second answer- since you added the numerator separately and then did the basic division, this worked.
Third one- similarly to the first one, you would have to also divide the 2 by 2 to get 1, then adding 1 + 2 to get 3.
If you shift the quadratic parent function, f(x) = x2, right 10 units, what is the
equation of the new function?
A. g(x) = (x+ 10)
B. g(x) = x2 + 10
C. g(x) = (x - 102
D. g(x) = x2 - 10
Answer:
A.
Step-by-step explanation:
The equation of the new function is g(x) = f(x-10) = (x -10)²
What is graph?A graph can be defined as a pictorial representation or a diagram that represents data or values.
While adding to the input of a function moves the graph left, and subtracting from the input of a function moves the graph right.
If the quadratic parent function, f(x) = x² moves right 10 units,
Hence, the equation of the new function is g(x) = f(x-10) = (x -10)²
Learn more about graph here:
brainly.com/question/16608196
#SPJ2
Refer to pictures help asap please
Answer:
x = 76.58°
Step-by-step explanation:
hyp = 13.41
tan = opp/adj
tan = 1/2 = 26.57
x = 76.58
The number 6 is a solution to which of the following inequalities?
X - 13 > 7
6x < -12
6x > 32
21 + x < 28
Answer:
21 + x < 28
Step-by-step explanation:
27 is in fact greater than 28 if you where to input 6 into the x spot, this is the only one that's a true expression.
If €1 is £0.72
What is £1 in €
Answer:
€1.39
Step-by-step explanation:
£0.72 ÷ 0.72 = 1÷0.72
£1= €1.39
a. 32
b. 44
c. 22
d. 8
Answer:
sorry I don't know
Step-by-step explanation:
.........
HELP!!!!!!!!!!!!!!!! pls
Answer: y = 25 - 2x
Step-by-step explanation:
y = mx + b
m = slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{23-25}{1-0} =\frac{-2}{1} =-2[/tex]b = y-intercept = when x = 0 = 25y = -2x + 25
How do I solve for X HELP
Answer:
x = 4 degrees
Step-by-step explanation:
The two angles have the same measurement. They are opposite angles.
26x + 7 = 31x - 13
Group like terms:
26x - 31x = -13 - 7
-5x = -20
x = 4
Check if you want to make sure.
Step-by-step explanation:
[tex]here \: is \: your \: solution : - \\ \\ both \: angles \: are \: equal \: (vertical \: anges) \\ \\ 26x + 7 = 31x - 13 \\ \\ solving \: the \: equation \: \\ \\ 26x - 31x = - 13 - 7 \\ \\ - 5x = 20 \\ \\ x = -20 \div 5 \\ \\ x = \: 4 \: degrees \: \: \: \:(Answer ✓✓✓( \\ \\ \huge\mathcal\blue{happy \: life (. ❛ ᴗ ❛.) }[/tex]
cual es el 75% de 160¿
What is 75% of 160¿
Answer:
120
Step-by-step explanation:
calculator
It would be great if someone helped me with this
Answer:
Step-by-step explanation:
They appear to be linear so that's easy enough to find out. What we are being asked is to find the equation represented by each table. Knowing that they are linear, we need the slope of each one and then the y-intercept of each one (each "one" being each table). Let's begin with the y-intercept. The y-intercepts exist where x = 0. In the first table, where x = 0, y = -4; in the second table, where x = 0, y = 3.
The equation we will finally fill in is y = mx + b, where m is the slope and b is the y-intercept.
Solving for slope in the first table:
[tex]m=\frac{-4-(-7)}{0-(-1)}=\frac{3}{1}=3[/tex] and the equation for this table is
y = 3x - 4
Solving for the slope in the second table:
[tex]m=\frac{3-4}{0-(-1)}=\frac{-1}{1}=-1[/tex] and the equation for this table is
y = -1x + 3 or just y = -x + 3
That's the system, which happens to be choice D
If y = 2x3 - 4x and dx, dt equals 4 , find dy, dt when x = 1. Give only the numerical answer. For example, if dy, dt = 3, type only 3
Work Shown:
y = 2x^3 - 4x
dy/dt = 2*3*x^2*dx/dt - 4*dx/dt
dy/dt = 2*3*1^2*4 - 4*4
dy/dt = 8
notice how I used the chain rule for step 2.
Domain and rang of these
Answer:
Domain: {-3, -1, 1}
Range: {-1, 2, 4, 5}
Step-by-step explanation:
The domain is all the x-values, and the range is all the y-values. When listing values, repeated values are only written down once.
Solve the following pair of linear equations using substitution method
[tex] x-3y = 13[/tex]
[tex]x+2y=8[/tex]
Answer:
(10, - 1 )
Step-by-step explanation:
Given the 2 equations
x - 3y = 13 → (1)
x + 2y = 8 → (2)
Rearrange (1) making x the subject by adding 3y to both sides
x = 3y + 13 → (3)
Substitute x = 3y + 13 into (2)
3y + 13 + 2y = 8
5y + 13 = 8 ( subtract 13 from both sides )
5y = - 5 ( divide both sides by 5 )
y = - 1
Substitute y = - 1 into (3) for corresponding value of x
x = 3(- 1) + 13 = - 3 + 13 = 10
solution is (10, - 1 )
Tommy's birthday party costs $2.94 for every guest the invites. If there are 4 guests, how much will Tommy's birthday party cost?
Answer:
$11.76
Step-by-step explanation:
2.94×4=$11.76
HELP WILL GIVE BRAINLIEST
Answer:
6
Step-by-step explanation:
Follow 1 hour on the y axis to where it meets the line of best fit. In this case it is about 6 puzzles.
what is the solution 2/3x+3 x=-2
Answer:
5/3 or 0.666666666667
Step-by-step explanation:
2/3*(-2)+3
5/3 or 0.666666666667 (Solved by calculator)
The numerical coefficient of -2pqr
Answer: -2
Explanation: The coefficient is the number to the left of the variable.
Another example would be that 10xy has the coefficient 10.
Something like x^2 has coefficient 1 because x^2 = 1x^2.
A radio tower is located on a coordinate system measured in miles. The range of a signal in a particular direction is modeled by a quadratic function where the boundary of the signal starts at the vertex at (4, 2). It passes through the point (5, 4). A linear road connects points (–3, 7) and (8, 2). Which system of equations can be used to determine whether the road intersects the boundary of the tower’s signal?
im sorry i dont know the answer
prove that:sin3A/sinA - cos3A/cosA=2
The result essentially follows directly from the triple-angle identities,
sin(3A) = 3 sin(A) cos²(A) - sin³(A)
cos(3A) = cos³(A) - 3 sin²(A) cos(A)
Then
sin(3A)/sin(A) = 3 cos²(A) - sin²(A)
cos(3A)/cos(A) = cos²(A) - 3 sin²(A)
and
sin(3A)/sin(A) - cos(3A)/cos(A)
= 3(cos²(A) + sin²(A)) - (sin²(A) + cos²(A))
= 3 - 1
= 2
p(x),f(x),g(x) are parabolas with positive coefficient, each pair of parabolas got common rational root, how to proof that p(x)+f(x)+g(x) have a rational root?
Answer:
[tex]{ \tt{p(x) : {y}^{2} = 4ax}} \\ { \tt{f(x) : {(y')}^{2} = 4a {x}'}} \\ { \tt{g(x) : {(y'')}^{2} = 4ax''}} \\ { \bf{since \: they've \: a \: common \: root}} : \\ {y}^{ 2} = {(y')}^{2} = {(y'')}^{2} \\ = > { \tt{4ax + 4ax' + 4ax''}} \\ = 4a(x + x' + x'') \\ common \: root \: is \: 4a \\ { \tt{ \infin {}^{ - } \leqslant 4a \leqslant \infin {}^{ + } }}[/tex]
