Answer:
∠ DCV = ∠ VBD = 50°
Step-by-step explanation:
The inscribed angles DCV and VBD are half the measure of their intercepted arcs, that is
∠ DCV = [tex]\frac{1}{2}[/tex] DV = [tex]\frac{1}{2}[/tex] × 100° = 50°
∠ VBD = [tex]\frac{1}{2}[/tex] DV = [tex]\frac{1}{2}[/tex] × 100° = 50°
(8) The average daily temperatures in July of some cities in Texas are shown in the table. Which
of the following fiets the cities from greatest temperature to least temperatura
City
Average Daily
Temperature
Austin
84.52F
Dallas
85.9°F
San Antonio
85 F
Fort Worth
85.31°F
a. Dallas, Fort Worth, San Antonio, Austin
b. Austin, Dallas, San Antonio, Fort Worth
c. Austin, San Antonio, Fort Worth, Dallas
d. Dallas, San Antonio, Fort Worth, Austin
Answer:
A.
Step-by-step explanation:
85.9 > 85.31 > 85 > 84.52
Dallas, Fort Worth, San Antonio, Austin
3. Rita is applying for a job as an engineer. Hier starting salary at Company will be $30,000 a $300 yearly
raise. Her starting salary at company will be $65.000 with a 5% increase sach year. If Rata is working at a
company for 5 years. Which company should she pick?
Answer:
The 65,000 salary
Step-by-step explanation:
Because the 30,000 salary after 5 years would be 31,500.
30,000+300=30,300
30,300+300=30,600
30,600+300=30,900
30,900+300=31,200
31,200+300=31,500
The 65,000 paying company
65,000x1.05=68,250
68,250x1.05=71.662.5
71,662.5x1.05=75,245.625
75,245.625x1.05=79,007.90625
79,007.90625x1.05=82,958.3015625
her salary after 5 years would be 82,958.3015625
WILL MARK BRAINLIEST
picture included^^^^
need help asap please n thank you!
^^^^
Answer:
14
Step-by-step explanation:
The a value is from the center to the maximum
We want from minimum to max so we need 2 times the amplitude
a = 7
2 *7 = 14
Four cans of cat food and 3 cans of dog food cost $1.99. Four cans of the same cat food and 1 can of the same dog food cost $1.33 hat is the cost of one can of cat food
Answer:
$0.25
Step-by-step explanation:
We can use System of Equations to find out how much a can of cat food costs.
Let's use variables to represent the cat food and dog food:
x = cost of 1 cat food can
y = cost of 1 dog food can
Here are our 2 equations based on the scenarios in the question:
4x + 3y = 1.99
4x + y = 1.33
Now let's set the second equation to y using basic algebra:
4x + y = 1.33
y = -4x+1.33
And we're going to plug that value of y, which is -4x+1.33 into the first equation and solve:
4x + 3y = 1.99
4x + 3(-4x+1.33) = 1.99
4x + -12x+3.99 = 1.99
-8x + 3.99 = 1.99
-8x = -2
x = 1/4
x = 0.25
1 can of cat food costs $0.25
Hope that helps (●'◡'●)
Answer:
.25
Step-by-step explanation:
set up equations
1)4c+3d=1.99
2)4c+d=1.33
Method of use:Elimination
4c+3d=1.99
- (4c+d)=-(1.33)
___________
=2d=.66
divide by two on both sides to get .33 for d.
plug in
4c+.33=1.33
subtract .33 on both sides
4c=1
divide by four on both sides to get c
c=1/4 or .25
Pls help me this is my homework
Answer:
C) 840
C) 87
D) 3000-150n
Step-by-step explanation:
Answer:
c
c
d
Step-by-step explanation:
What is the tangent ratio of angle x?
tan x= 20/21
tan x= 21/29
tan x= 20/29
tan x= 21/20
Answer:
[tex]\tan x=21/20[/tex]
Step-by-step explanation:
In any right triangle, the tangent of an angle is equal to its opposite side divided by its adjacent side. (o/a)
For angle [tex]x[/tex], its opposite side is 21 feet and its adjacent side is 20 feet. Therefore, we have:
[tex]\boxed{\tan x=21/20}[/tex]
This Venn diagram shows the pizza topping preferences for 9 students.
What elements are in A and B?
(Look at picture)
Answer:
I think the answer is C.
Jada worked at the bakery for 14 hours last week he spent $12 of his earnings on a cake for his father‘s birthday as he was last with $86 after buying the cake what is Gianna‘s hourly wage
Answer:
$7 is his Hourly Wage.
Step-by-step explanation:
We can start by finding out how much money Jada started with by adding the amount of money he had after buying the cake with how much he spent on the cake, 86 + 12 = 98.
We now know how much money he had before buying anything. Now we can just divide the total amount of money by how long he worked.
98 ÷ 14 = 7
b. Compare the similar triangle proof from question 3 with the inscribed square
proof. How are they different? Which method was easier for you to understand?
(1 point)
Answer:
i might be wrong but this is what i put
Step-by-step explanation:
In question 3 it was comparing three triangles where now it is using the triangles to find the area of a square instead of proving that they are the same.
find the measure of acute angle of a right angle triangle when one angle is 60°
Answer:
30 degrees.
Step-by-step explanation:
Let the acute angle be x.
Then as the 2 acute angles in a right triangle sum to 90 degrees,
x = 90 - 60
= 30.
We used the information we know to give us this equation.
90°+60°+x=180°
We add 90° and 60° to give 150°
150°+x=180°
x must therefore be 30°NEED THIS ASAP :)
What is the length of the y-component of the vector plotted below?
A. 3
B. 4
C. 1
D. 2
Answer:
4
Step-by-step explanation:
Length of the y component is how far the vector reaches vertically, so in this case it's 4
1)The sum of two consecutive multiples of 5 is55. Find these multiples.
2)The sum of three consecutive integers is 93. What are the integers?
3)If five is subtracted from three times a number, the result is 10. What is the number?
Part 1
Let the consecutive multiples be 5x and 5x + 5
ATQ
5x + 5x + 5 = 55
10x = 55 - 5
10x = 50
x = 5
Answer is 25 and 30
Part 2
Let the number be x , x + 1, x + 2
ATQ
x + x + 1 + x + 2 = 93
3x + 3 = 93
3x = 93 - 3
x = 90/3
x = 30
The integers are 30,31 and 32
Part 3
Let the number be x
ATQ
3x - 5 = 10
3x = 10 + 5
x = 15/3
x = 5
The number is 5
Answered by Gauthmath must click thanks and mark brainliest
please solve this please
Answer:
3
Step-by-step explanation:
What is the explicit formula for this sequence?
-9, -3, 3, 9, 15,
Answer:
+6
Step-by-step explanation:Look at the trend of numbers and notice. Maybe put it in a table.
In order for the parallelogram to be a rhombus, x=?
Answer:
Step-by-step explanation:
The diagonal must be an angle bisector for a rhombus.
That means that both bisected angles are equal.
2x + 16 = 5x - 8 Add 8 to both sides
2x + 16 + 8 = 5x
2x + 24 = 5x Subtract 2x from both sides
24 = 5x - 2x
24 = 3x Divide by 3
24/3 = x
x = 8
Parallelogram PARL is similar to parallelogram WXYZ. If AP = 7, PL = 15, and WZ = 45, find the value of c.
Answer:
c = 21
Step-by-step explanation:
**I assume that side WX in my diagram (attached as an image below) is the value of C that we're looking for. ALSO, the sizes and lengths of the parallelograms are NOT to scale.**
If two parallelograms are similar, that means the lengths of the corresponding sides have EQUAL ratios.
PL corresponds with WZ. To get from 15 to 45, you would multiply 15 by 3, so the ratio of the legnths of the corresponding sides between these two parallelograms is 1:3.
With that in mind, we can apply this ratio to find WX.
We know that AP has a length of 7, so we will multiply that by 3, getting a value of 21, and 7:21 ratio is the same as 1:3.
c = 21
Hope this helps (●'◡'●)
Mrs. Kennedy is teaching an 8th grade class. She is standing 7 meters in front of Catherine. Davis is sitting to Catherine’s left. If Davis and Mrs. Kennedy are 12 meters apart, how far apart are Davis and Catherine?
13.90 meters
5 meters
9.75 meters
4.36 meters
Answer:
9.75 meters
Step-by-step explanation:
Davis and Catherine are approximately 13.90 meters apart.
How to determine distance apartTo find the distance between Davis and Catherine, we can use the concept of right triangles and apply the Pythagorean theorem.
Let's consider a right triangle where the distance between Davis and Mrs. Kennedy is the base, the distance between Mrs. Kennedy and Catherine is the height, and the distance between Davis and Catherine is the hypotenuse.
According to the given information, Mrs. Kennedy is 7 meters in front of Catherine, and Davis and Mrs. Kennedy are 12 meters apart.
Using the Pythagorean theorem, we have:
(Base)² + (Height)² = (Hypotenuse)²
Substituting the given values:
(12)² + (7)² = (Hypotenuse)²
Simplifying the equation:
144 + 49 = (Hypotenuse)²
193 = (Hypotenuse)²
Taking the square root of both sides:
√193 ≈ 13.89 = 13.90
Therefore, Davis and Catherine are approximately 13.90 meters apart.
Learn more about distance at
https://brainly.com/question/26550516
#SPJ2
Help, please, I'll give brainliest
Multiply. (Use photo). Enter your answer in simplest radical form.
Answer:
72√2
Step-by-step explanation:
3√2 × 2√8 × √3 × √6
The above can be simplified as follow:
3√2 × 2√8 × √3 × √6
Recall
a√c × b√d = (a×b)√(c×d)
3√2 × 2√8 × √3 × √6 = (3×2)√(2×8×3×6)
= 6√288
Recall
288 = 144 × 2
6√288 = 6√(144 × 2)
Recall
√(a×b) = √a × √b
6√(144 × 2) = 6 × √144 × √2
= 6 × 12 × √2
= 72√2
Therefore,
3√2 × 2√8 × √3 × √6 = 72√2
what is the value of a if va- vh is equals to 1
Answer:
[tex] \displaystyle a = \frac{1+vh}{v}[/tex]
Step-by-step explanation:
we want to figure out a value of a for the following condition
[tex] \displaystyle va - vh = 1[/tex]
to do so factor out v;
[tex] \displaystyle v (a - h )= 1[/tex]
divide both sides by v which yields:
[tex] \displaystyle \frac{(a-h) \cancel{(v)}}{ \cancel{v}}= \frac{1}{v} [/tex]
therefore,
[tex] \displaystyle a-h = { \frac{1}{v}}[/tex]
now,add h to both sides:
[tex] \displaystyle a = \frac{1}{v}+h[/tex]
further simplification if necessary:
[tex] \displaystyle a =\boxed{ \frac{1+vh}{v}}[/tex]
factor out of v
[tex]\sf{v(a-h)=1 }[/tex]Dividing both sides by (v)
[tex]\sf{\dfrac{v(a-h)}{(v)}=\dfrac{1}{(v)} }[/tex]cancel out (v)
[tex]\sf{\dfrac{\cancel{v}(a-h)}{\cancel{(v)}}=\dfrac{1}{(v)} }[/tex][tex]\sf{ a-h=\dfrac{1}{v} }[/tex]
add h in both sides
[tex]\sf{a-h+h=\dfrac{1}{v}+h }[/tex]cancelout h
[tex]\sf{a-\cancel{h}+\cancel{h}=\dfrac{1}{v}+h }[/tex] [tex]\sf{a=\dfrac{1}{v}+h }[/tex] [tex]\boxed{\sf{a=\dfrac{1+vh}{v} } }[/tex][tex]\sf{ }[/tex] [tex]\sf{ }[/tex]
Therefore:-the value of a if va- vh is equals to 1 is [tex]\bold{\dfrac{1+vh}{v} }[/tex]
What is the answer? How to solve?
Answer:
a +73°=90°
a= 90°-73°
a =17°
d+18°=90°
d=90°-18°
d =72 °
On a Job application Doris gave her age as 32 years. Her actual age at the time was about 27. What is the relative error fo her age?
Answer:
Relative error = 0.19
Step-by-step explanation:
From the question given above, the following data were obtained:
Measured age = 32 years
Actual age = 27 years
Relative error =?
Next, we shall determine the absolute error. This can be obtained as follow:
Measured age = 32 years
Actual age = 27 years
Absolute error =?
Absolute error = | Measured – Actual |
Absolute error = | 32 – 27 |
Absolute error = 5 years
Finally, we shall determine the relative error. This can be obtained as follow:
Absolute error = 5 years
Actual age = 27 years
Relative error =?
Relative error = Absolute error / Actual years
Relative error = 5 / 27
Relative error = 0.19
What point lies on the line with point slope equation y-3=4(x+7)?
Answer:
(-7, 3)
General Formulas and Concepts:
Algebra I
Point-Slope Form: y - y₁ = m(x - x₁)
x₁ - x coordinate y₁ - y coordinate m - slopeStep-by-step explanation:
Step 1: Define
Identify
y - 3 = 4(x + 7)
↓ Compare to Point-Slope Form
Point (-7, 3)
Slope m = 4
An airplane from Singapore to Melbourne takes about 7 1/2 hours to cover a distance of 6057 km. What is the average speed of the airplane.
Answer: 13.46 km/h
Step-by-step explanation:
7 1/2 hr= 450 min
6057/450= 13.46
Wages and salaries
Kelly earns a salary of $68 430 pa how much does he earn each week, each fortnight and each month?
Answer:
Each week = $ 1311.41
Each fortnight = $ 2622.84
Each month = $ 5702.5
Step-by-step explanation:
Given that,
Annual salary of Kelly = $ 68,430
As we know,
There are 52.18 weeks in a year.
So,
Weekly income = Annual salary ÷ no. of weeks in the year
= $ 68,430 ÷ 52.18
= $ 1311.42
Fortnight income = 2 * weekly income
= 2 * $ 1311.42
= $ 2622.84
Each month's income = Annual income ÷ 12(no. of months)
= $ 68,430 ÷ 12
= $ 5702.5
-2/3a+5/6a-1/5a-1/6
Answer:
[tex]\frac{-1}{30} a - \frac{1}{6}[/tex]
Step-by-step explanation:
An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the
object's height s at time t seconds after launch is s(t) = - 4.9t2 + 19.6t + 58.8, where s is in meters. Create a
table of values and graph the function. Approximately what is the maximum height that the object will get?
O 76.4 meters
113.5 meters
O 78.4 meters
58.8 meters
Answer:
Step-by-step explanation:
The easiest way to do this is to complete the square on the quadratic. This allows us to see what the vertex is and answer the question without having to plug in a ton of numbers to see what the max y value is. Completing the square will naturally put the equation into vertex form:
[tex]y=-a(x-h)^2+k[/tex] where h will be the time it takes to get to a height of k.
Begin by setting the quadratic equal to 0 and then moving over the constant, like this:
[tex]-4.9t^2+19.6t=-58.8[/tex] and the rule is that the leading coefficient has to be a 1. Ours is a -4.9 so we have to factor it out:
[tex]-4.9(t^2-4t)=-58.8[/tex] Now take half the linear term, square it, and add it to both sides. Our linear term is a -4, from -4t. Half of -4 is -2, and -2 squared is 4, so we add a 4 to both sides. BUT on the left we have that -4.9 out front there as a multiplier, so we ACTUALLY added on to the left was -4.9(4) which is -19.6:
[tex]-4.9(t^2-4t+4)=-58.8-19.6[/tex] and now we have to clean this up. The right side is easy, that is -78.4. The left side...not so much.
The reason we complete the square is to create a perfect square binomial, which is the [tex](x-h)^2[/tex] part from above. Completing the square does this naturally, now it's just up to us to write the binomial created during the process:
[tex]-4.9(t-2)^2=-78.4[/tex] Now, move the constant back over and set the equation back equal to y:
[tex]-4.9(t-2)^2+78.4=s(t)[/tex] and we see that the vertex is (2, 78.4). That means that 2 seconds after launch, the object reached its max height of 78.4 meters, the third choice down.
What is the slope of the line passing through the points
(-3, - 5) and (-1,6)? (URGENT)
Determine which equations have the same solution set as StartFraction 2 Over 3 EndFraction minus x plus StartFraction 1 Over 6 EndFraction equals 6 x. – x + = 6x by recognizing properties, rather than solving. Check all that apply.
Answer:
A, B, F
Step-by-step explanation:
2/3 - x + 1/6 = 6x
Collect like terms
2/3 + 1/6 = 6x + x
(4+1) / 6 = 7x
5/6 = 7x
x = 5/6 ÷ 7
= 5/6 × 1/7
x = 5/42
a) 4 - 6x + 1 = 36x
4 + 1 = 36x + 6x
5 = 42x
x = 5/42
Equivalent to the last step of the simplification above
b) 5/6 - x = 6x
5/6 = 6x + x
5/6 = 7x
This is equivalent to the third step of the simplification
c) 4 - x + 1 = 6x
4 + 1 = 6x + x
5 = 7x
x = 5/7
Not equivalent to any of the steps in the simplification above
d) 5/6 + x = 6x
5/6 = 6x - x
5/6 = 5x
x = 5/6 ÷ 5
= 5/6 × 1/5
x = 5/30
Not equivalent to any of the steps in the simplification above
e) 5 = 30x
x = 5/30
Not equivalent to any of the steps in the simplification above
f) 5 = 42x
x = 5/42
Equivalent to the last step of the simplification above
1. Determine the sum of the first 53 terms of the following series: 179+173+167+...
2. Determine the sum of the first 19 terms of the following series: 6−12+24−48+...
(1) This series consists of terms of an arithmetic sequence:
179 - 173 = 6
173 - 167 = 6
and so on, so that the n-th term in the series is (for n ≥ 1)
a(n) = 179 - 6 (n - 1) = 185 - 6n
Then the sum of the first 53 terms is
[tex]\displaystyle\sum_{n=1}^{53}(185-6n) = 185\sum_{n=1}^{53}1-6\sum_{n=1}^{53}n[/tex]
[tex]\displaystyle\sum_{n=1}^{53}(185-6n) = 185\times53-6\times\frac{53\times54}2[/tex]
[tex]\displaystyle\sum_{n=1}^{53}(185-6n) = \boxed{1219}[/tex]
(2) This series has terms from a geometric sequence:
-12 / 6 = -2
24/(-12) = -2
-48/24 = -2
and so on. The n-th term is (again, for n ≥ 1)
a(n) = 6 (-2)ⁿ⁻¹
and the sum of the first 19 terms is
[tex]\displaystyle\sum_{n=1}^{19}6(-2)^{n-1} = 6\left(1 + (-2) + (-2)^2 + (-2)^3 + \cdots+(-2)^{19}\right)[/tex]
Multiply both sides by -2 :
[tex]\displaystyle-2\sum_{n=1}^{19}6(-2)^{n-1} = 6\left((-2) + (-2)^2 + (-2)^3 + (-2)^4 + \cdots+(-2)^{20}\right)[/tex]
Subtracting this from the first sum gives
[tex]\displaystyle(1-(-2))\sum_{n=1}^{19}6(-2)^{n-1} = 6\left(1 -(-2)^{20}\right)[/tex]
and solving for the sum, you get
[tex]\displaystyle3\sum_{n=1}^{19}6(-2)^{n-1} = 6\left(1 -(-2)^{20}\right)[/tex]
[tex]\displaystyle\sum_{n=1}^{19}6(-2)^{n-1} = 2\left(1 -(-2)^{20}\right)[/tex]
[tex]\displaystyle\sum_{n=1}^{19}6(-2)^{n-1} = 2\left(1 -(-1)^{20}2^{20}\right)[/tex]
[tex]\displaystyle\sum_{n=1}^{19}6(-2)^{n-1} = 2\left(1 -2^{20}\right) = 2-2^{21} = \boxed{-2,097,150}[/tex]