Find the area of the irregular figure. Round to the nearest hundredth.

Answer:

See explanation

Step-by-step explanation:

Required

Effect of replacing [tex]f(x)[/tex] with [tex]f(x - h)[/tex]

f(x) is represented as: (x,y)

While

f(x - h) is represented as (x - h, y)

Notice the difference in both is that, the x value in f(x - h) is reduced by a constant h while the y value remain unchanged.

This means that the graph of f(x) will shift horizontally (i.e. along the x-axis) to the left by h units

Answer:

269 and 1/16 feet total (or 269.0625 feet to be precise)

Step-by-step explanation:

20 and 1/2 = 20.5

13 and 1/8 = 13.125

20.5 * 13.125 = 269.0625 feet = 269 and 1/16 feet

Answer:

See Below.

Step-by-step explanation:

We can write a two-column proof.

Statements:                                                Reasons:

[tex]\displaystyle 1)\, \angle 4\cong \angle 2[/tex]                                                   Given

[tex]\displaystyle 2)\, \angle 3 \cong \angle 4[/tex]                                                   Vertical Angles are Congruent

[tex]\displaystyle 3) \, \angle 1 + \angle 2 = 180[/tex]                                          Linear Pair

[tex]\displaystyle 4)\, \angle 1 + \angle 4 = 180[/tex]                                          Substitution

[tex]\displaystyle 5) \, \angle 1 + \angle 3 = 180[/tex]                                          Substitution

[tex]\displaystyle 6) \, \text{$\angle 3$ and $\angle 1$ are supplementary}[/tex]                  Definition of Supplementary Angles

Answer:

66 m

Step-by-step explanation:

First, lets add up the numbers you know. It should be:

16, 8, 17, and 7.

Add them all up, and you will get:

48.

For the last two sides, subtract 7 from 16 to get 9.

For the last slide, subtract 8 from 17 to get 9.

Add them all up, and get 66.

Answer:

upper bound for the error, | Error |  ≤ 0.0032

Step-by-step explanation:

Given the data in the question;

[tex]e^{0.4[/tex] < e < 3

Using Taylor's Error bound formula

| Error | ≤ ( m / ( N + 1 )! ) [tex]| x-a |^{N+1[/tex]

where m = [tex]| f^{N+1 }(x) |[/tex]

so we have

| Error |  ≤ ( 3 / ( 3 + 1 )! ) [tex]|[/tex] -0.4 [tex]|[/tex]⁴

| Error |  ≤ ( 3 / 4! ) [tex]|[/tex] -0.4 [tex]|[/tex]⁴

| Error |  ≤ ( 3 / 24 ) [tex]|[/tex] -0.4 [tex]|[/tex]⁴

| Error |  ≤ ( 0.125 ) [tex]|[/tex] -0.0256 [tex]|[/tex]

| Error |  ≤ ( 0.125 ) 0.0256

| Error |  ≤ 0.0032

Therefore, upper bound for the error, | Error |  ≤ 0.0032

Answer:

The gradient is -0.25

Step-by-step explanation:

Given

[tex](x_1,y_1) = (-5,3)[/tex]

[tex](x_2,y_2) = (5,0.5)[/tex]

Required

The gradient (m)

This is calculated as:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m = \frac{0.5-3}{5--5}[/tex]

[tex]m = \frac{-2.5}{10}[/tex]

[tex]m = -0.25[/tex]

Answer:

The answer is C.

as for C . the value of f(x) increases by 7 and so the graph goes up by units 7.

OR

g(x) = |x| + 7

we know that |x| is f(x), so :-

g(x) = f(x) + 7

and since f(x) is plot on y- axis the graph climbs the y axis by 7 units

*The graph shifts right or left for the other functions*

Answer:

2

Step-by-step explanation:

Answer:

The average value of the cost function over the interval  is of $23,500.

Step-by-step explanation:

Average value of a function:

The average value of a function, over an inteval [a,b], is given by:

[tex]A = \frac{1}{b-a} \int_{a}^{b} f(x) dx[/tex]

In this case:

Function [tex]C(x) = 20000 - 10x[/tex], interval with [tex]a = 0,b = 700[/tex]

So

[tex]A = \frac{1}{700} \int_{0}^{700} 20000+10x dx[/tex]

[tex]A = \frac{1}{700} (20000x+5x^2)|_{0}^{700}[/tex]

So

[tex]A = \frac{20000(700)+5(700)^2}{700} = 23500[/tex]

The average value of the cost function over the interval  is of $23,500.

Answer:

Part A

(1y^2+3y-6)+(4y-7+2y^2)+(3y^2-8+5y)

6y^2+12y-21

Answer:

4

9

Step-by-step explanation:

If X has 5 elements, and Y has 4 elements, and all 4 of Y's elements are the same as 4 of X's elements, then the intersection of the sets has 4 elements.

If X has 5 elements and Y has 4 elements, and they are all different, then the union of the sets has 9 elements.

Answer:

4

9

Explanation:

30 years = 30*12 = 360 months

If the monthly payment is $2,223.17 for 360 months, then you'll pay back a total of 2223.17*360 = 800,341.20 dollars overall.

Subtract off the amount financed, or amount loaned, to get the total interest.

800,341.20 - 275,000 = 525,341.20 is the amount of interest paid (in dollars).

This works because effectively, the total amount paid back consists of principal + interest. The principal is the amount the bank loans you.

So we could rephrase that last equation into saying

principal + interest = 275,000 + 525,341.20 = 800,341.20 = total amount paid back.

↦ [tex]\huge\underline{ \underline{Answer:-}}[/tex]

[tex]5x = 3x + 12 \\ 5x - 3x = 12 \\ 2x = 12 \\ x = \frac{12}{2} \\ x = 6[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Step-by-step explanation:

hope it is h helpful to you

Answer:

0.03 more flour per cupcake

Step-by-step explanation:

3.12/8 = 0.39

2.52/7 = 0.36

0.39 - 0.36 = 0.03

Hope this helps c:

Answer: 5

Step-by-step explanation: I think it is 5

Answer:

[tex]T =56.3[/tex]

Step-by-step explanation:

Given

The attached triangle

Required

Measure of T

This is calculated as:

[tex]\cos T = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos T = \frac{5}{9}[/tex]

Take arccos

[tex]T = \cos^{-1}{(5/9)}[/tex]

[tex]T =56.3[/tex]

Answer:

10

Step-by-step explanation:

the sum of 8,5,15,12,10 is 50 and there are 5 numbers so 50 divided by 5 is 10 and it's mean is also 10

hope this helps !

Answer:

9 ft^2 and 12.25 ft^2

Step-by-step explanation:

We need to figure out the area for a square with a perimeter of 12 feet and 14 feet.

A square has four sides that are all equal in length, therefore:

12/4 = 3

14/4 = 3.5

3 and 3.5 are the individual side lengths of the garden, so to find the area, we just multiply those numbers by themselves (since it is a square garden).

3*3 = 9

3.5*3.5 = 12.25

Therefore, the answer is 9 ft^2 and 12.25 ft^2

Evaluating the limand directly at x = 0 yields the indeterminate form 0/0. If L'Hopital's rule is known to you, you can compute the limit by applying it twice:

[tex]\displaystyle\lim_{x\to0}\frac{x\left(e^{3x}-1\right)}{2-2\cos(x)} = \lim_{x\to0}\frac{3xe^{3x}+e^{3x}-1}{2\sin(x)} \\\\\\ = \lim_{x\to0}\frac{9xe^{3x}+6e^{3x}}{2\cos(x)} = \frac62=\boxed{3}[/tex]

first speed --- x mph

return speed -- x+16 mph

6/x + 6/(x+16) = 1

times each term by x(x+16)

6(x+16) + 6x = x(x+16)

x^2 + 4x - 96 = 0

(x-8)(x+12) = 0

x = 8 or x is a negative

her first speed was 8 mph

her return speed was 24 mph

check:

6/8 + 6/24 = 1 , that's good!

9514 1404 393

Answer:

  k = 2

Step-by-step explanation:

The geometric mean theorem for the altitude tells you ...

  ON = √(OL·OM)

  ON² = OL·OM . . . . . square both sides

  4² = 8·k . . . . . . . . substitute values

  k = 16/8 = 2 . . . . divide by the coefficient of k

_____

Additional comment

The geometric mean theorem for the legs tells you ...

  MN = √(MO·ML)   ⇒   l = 2√5

  LN = √(LO·LM)   ⇒   m = 4√5

These relations come from the fact that corresponding sides of the right triangles are proportional. (All of the triangles are similar.)

Answer:

3 hrs

Step-by-step explanation:

5 * 24 = 120 miles

64x = 120 + 24x

40x = 120

x = 3 hrs

Answer:

0.9036

Step-by-step explanation:

Calculation to determine the probability that the proportion of Labradors

P(Proportion greater than 4%)

= P(z> 0.04 -0.05 /√0.05 * 0.95/806

= P(z > -1.30)

=0.9036

Thereforethe probability that the proportion of Labradors is =0.9036

Answer:

The insurance company should charge $1,873.5.

Step-by-step explanation:

Expected earnings:

1 - 0.99813 = 0.00187 probability of the company losing $1 million(if the client dies).

0.99813 probability of the company earning x(price of the insurance).

What premium would an insurance company charge to break even on a one-year $1 million term life insurance policy?

Break even means that the earnings are 0, so:

[tex]0.99813x - 0.00187(1000000) = 0[/tex]

[tex]0.99813x = 0.00187(1000000)[/tex]

[tex]x = \frac{0.00187(1000000)}{0.99813}[/tex]

[tex]x = 1873.5[/tex]

The insurance company should charge $1,873.5.

Answer:

3. The scale factor is 3, which means the length of the image of segment KL will be 3 times as long.

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, reflection and dilation.

Dilation is the increase or decrease in the size of a figure. If a point A(x, y) is dilated about the center of dilation located at O(a, b), the new point is at A'[k(x - a) + a, k(y - b) + b].

Quadrilateral KLMN has vertices at K(2, 1), L(-1, -5), M(6, -5) and N(6, 1). If it is dilated by 3, about the center M(6, -5), the new points are:

K' = (3(2 - 6) + 6, 3(1 - (-5)) + (-5)) = (-6, 13)

L' = (3(-1 - 6) + 6, 3(-5 - (-5)) + (-5)) = (-15, -5)

M' = (3(6 - 6) + 6, 3(-5 - (-5)) + (-5)) = (6, -5)

N' = (3(6 - 6) + 6, 3(1 - (-5)) + (-5)) = (6, 13)

Therefore the image of segment KL will be 3 times long.

Hey there!

[tex]\mathsf{\dfrac{2}{9}\div\dfrac{5}{6}}[/tex]

[tex]\mathsf{= \dfrac{2\times6}{9\times5}}[/tex]

[tex]\mathsf{2\times 6 = \bf 12}[/tex]

[tex]\mathsf{9\times5 = \bf 45}[/tex]

[tex]\boxed{\mathsf{=\bf \dfrac{12}{45}}}[/tex]

[tex]\large\textsf{BOTH NUMBERS has the Greatest Common Factor (GCF) of 3}[/tex]

[tex]\mathsf{= \dfrac{12\div3}{45\div3}}[/tex]

[tex]\mathsf{12\div3=\bf 4}[/tex]

[tex]\mathsf{45\div3=\bf 15}[/tex]

[tex]\boxed{\mathsf{=\bf \dfrac{4}{15}}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf \dfrac{4}{15}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}\\\\\\~\frak{Amphitrite1040:)}}[/tex]

Answer:

5

Step-by-step explanation:

3-(-2) will become positive 5. so number line will go towards positive 5.

Answer:

[tex]\int (x+ 1) \sqrt{2x-1} dx = \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{15}(2x-1)^{\frac{5}{2}} + C[/tex]

Step-by-step explanation:

[tex]\int (x+1)\sqrt {(2x-1)} dx\\Integrate \ using \ integration \ by\ parts \\\\u = x + 1, v'= \sqrt{2x - 1}\\\\v'= \sqrt{2x - 1}\\\\integrate \ both \ sides \\\\\int v'= \int \sqrt{2x- 1}dx\\\\v = \int ( 2x - 1)^{\frac{1}{2} } \ dx\\\\v = \frac{(2x - 1)^{\frac{1}{2} + 1}}{\frac{1}{2} + 1}} \times \frac{1}{2}\\\\v= \frac{(2x - 1)^{\frac{3}{2}}}{\frac{3}{2}} \times \frac{1}{2}\\\\v = \frac{2 \times (2x - 1)^{\frac{3}{2}}}{3} \times \frac{1}{2}\\\\v = \frac{(2x - 1)^{\frac{3}{2}}}{3}[/tex]

[tex]\int (x+1)\sqrt(2x-1)dx\\\\ = uv - \int v du[/tex]                              

[tex]= (x +1 ) \cdot \frac{(2x - 1)^{\frac{3}{2}}}{3} - \int \frac{(2x - 1)^{\frac{3}{2}}}{3} dx \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ u = x + 1 => du = dx \ ][/tex]    

[tex]= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{3} \int (2x - 1)^{\frac{3}{2}}} dx\\\\= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{3} \times ( \frac{(2x-1)^{\frac{3}{2} + 1}}{\frac{3}{2} + 1}) \times \frac{1}{2}\\\\= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{3} \times ( \frac{(2x-1)^{\frac{5}{2}}}{\frac{5}{2} }) \times \frac{1}{2}\\\\= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{15} \times (2x-1)^{\frac{5}{2}} + C\\\\[/tex]