Find the array to finish 976 divided by 8. NO LINKS!!!
​

Answer:

21%

Step-by-step explanation:

Area of one sprinkler

a = πr²

a = π10²

a = 314.159 ft²

8 sprinklers

a = 8 * 314.159

a = 2,513.272

---------------------

area of field

a = lw

a = 80 * 40

a = 3200

------------------------

area not watered

a = 3200 - 2,513.272

a = 686.728

------------------

percentage not watered

p = 686.728 / 3200 * 100%

p = 21.46025%

Rounded

21%

Answer:

its x^4

Step-by-step explanation:

its x^4

Answer:

4 weeks = 105

16 weeks = 42

24 weeks = 0

Step-by-step explanation:

the function is missing the 'w'

it should be : C(w) = 126 - 5.25w

'w' is the number of weeks

Substitute number of weeks in the 'w' spot

first one is 4 weeks, so

C(w) = 126 - 5.25(4)

= 126 - 21

= 105

Answer:

Given:

Cost = £ 800

Tax = 20%

To find:

The total cost

Solution:

Total cost = Cost + Tax

Tax = 20 % of cost

20 / 100 * 800

Tax = £ 160

Hence,

Total cost =  £ 800 + £ 160

Total cost = £ 960

Answer:

-46

Step-by-step explanation:

To find your score, take Bill's score which is -17 and if it is 29 less than, you subtract 29

So, - 17 - 29 is -46

Answer:

(A) 89 (B) 91 (C) 92 (D) 95 4.If |x−2| = p, where x < 2, then x+1 equals (A) −2 (B) 3− p (C) |2p−2| (D) 2p−2 5.A

Step-by-step explanation:

Following are the calculation to the find the value of x:

Given:

Please find the question.

To find:

x=?

Solution:

[tex]\frac{71}{7} <\frac{x}{9} < \frac{113}{11}\\\\10 <\frac{71}{7} < 11 \\\\10< \frac{113}{11}<11\\\\\frac{x}{9} >10\\\\x>90\\\\\text{When}\ x=91 \\\\\frac{71}{7} > \frac{91}{9}\\\\x=92\\\\ \frac{71}{7}< \frac{92}{9} <\frac{113}{11}\\\\[/tex]

so, x= 92 \\\\

by compare score value x= 92

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Answer:

[tex]3\sqrt{5}i[/tex]

Step-by-step explanation:

[tex]\sqrt{-45}[/tex]

[tex]\sqrt{-9*5}[/tex]

[tex]\sqrt{-9}\sqrt{5}[/tex]

[tex]3i\sqrt{5}[/tex]

[tex]3\sqrt{5}i[/tex]

Answer:

c is equal to e

Step-by-step explanation: a

Answer:

I think it might be SAS. (side angle side)

Answer:

Step-by-step explanation:

Given that:

[tex]P = \left[\begin{array}{ccc}0.22&0.20&0.65\\0.62&0.60&0.15\\0.16&0.20&0.20\end{array}\right][/tex]

For a steady-state of a given matrix [tex]\bar X[/tex]

[tex]\bar X = \left[\begin{array}{c}a\\b\\c\end{array}\right][/tex]

As a result P[tex]\bar X[/tex] = [tex]\bar X[/tex] and a+b+c must be equal to 1

So, if P[tex]\bar X[/tex] = [tex]\bar X[/tex]

Then;

[tex]P = \left[\begin{array}{ccc}0.22&0.20&0.65\\0.62&0.60&0.15\\0.16&0.20&0.20\end{array}\right]\left[\begin{array}{c}a\\b\\c\end{array}\right] =\left[\begin{array}{c}a\\b\\c\end{array}\right][/tex]

[tex]\implies \left\begin{array}{ccc}0.22a+&0.20b+&0.65c\\0.62a+&0.60b+&0.15c\\0.16a+&0.20b+&0.20c\end{array} \right = \left \begin{array}{c}a ---(1)\\b---(2)\\c---(3)\end{array}\right[/tex]

Equating both equation (1) and (3)

(0.22a+ 0.2b + 0.65c) - (0.16a + 0.2b + 0.2c) = a - c

0.06a + 0.45c = a - c

collect like terms

0.06a - a = -c - 0.45c

-0.94 a = -1.45 c

0.94 a = 1.45 c

[tex]c =\dfrac{ 0.94}{1.45}a[/tex]

[tex]c =\dfrac{ 94}{145}a --- (4)[/tex]

Using equation (2)

0.62a + 0.60b + 0.15c = b

where;

c = 94/145 a

[tex]0.62a + 0.60b + 0.15(\dfrac{94}{145}) a= b[/tex]

[tex]0.62a + 0.15(\dfrac{94}{145}) a= -0.60b+b[/tex]

[tex]0.62a + (\dfrac{141}{1450}) a= 0.40b[/tex]

[tex](0.62+\dfrac{141}{1450}) a= 0.40b[/tex]

[tex](\dfrac{62}{100}+\dfrac{141}{1450}) a= 0.40b[/tex]

[tex](\dfrac{1043}{1450})a= 0.40b[/tex]

[tex](\dfrac{1043}{1450})a= \dfrac{4}{10} b[/tex]

[tex](\dfrac{1043 \times 10}{1450 \times 4})a = \dfrac{4}{10} \times \dfrac{10}{4}[/tex]

[tex]b = (\dfrac{1043}{580}) a --- (5)[/tex]

From a + b + c = 1

[tex]a + \dfrac{1043}{580}a + \dfrac{94}{145} a = 1[/tex]

[tex]a + \dfrac{1043}{580}a + \dfrac{94*4}{145*4} a = 1[/tex]

[tex]a + \dfrac{1043}{580}a + \dfrac{376}{580} a = 1[/tex]

[tex]\dfrac{580+ 1043+376 }{580} a= 1[/tex]

[tex]\dfrac{1999}{580} a= 1[/tex]

[tex]a = \dfrac{580}{1999}[/tex]

∴

[tex]b = \dfrac{1043}{580} \times \dfrac{580}{1999}[/tex]

[tex]b = \dfrac{1043}{1999}[/tex]

[tex]c = \dfrac{94}{145} \times \dfrac{580}{1999}[/tex]

[tex]c= \dfrac{376}{1999}[/tex]

∴

The steady matrix of [tex]\bar X[/tex] is:

[tex]\bar X = \left[\begin{array}{c}\dfrac{580}{1999} \\ \\ \dfrac{1043}{1999}\\ \\ \dfrac{376}{1999}\end{array}\right][/tex]

Answer:

Three of your next six donuts sold will be cake donuts.

Step-by-step explanation:

14:7 simplified to a unit ratio is 2:1. Using this information, we know that 6:3 is the ratio for the next 6 donuts.

Answer:

y = -x + 8

Step-by-step explanation:

First, plug in the slope.

y = mx + b

y = -1x + b

y = -x + b

Then, plug in the point.

7 = -(1) + b

7 = -1 + b

8 = b

Answer:

9.68*10^-10

Step-by-step explanation:

The problem above can be solved using the binomial probability relation :

Where ;

P(x = x) = nCx * p^x * q^(n-x)

n = number of trials = 25

p = 1/4 = 0.25

q = 1 - p = 0.75

x = 20

P(x > 20) = p(x = 21) + p(x = 22) +.. + p(x = 25)

Using the binomial probability calculator to save computation time :

P(x > 20) = 9.68*10^-10

Answer:

B. 4/3pi (7^3)

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

We know the radius is 7

V = 4/3 pi 7^3

Answer:

1,736 chocolate cover peanuts

Step-by-step explanation:

do 28×62 hope this helps

Answer:

1736 chocolate-covered peanuts

Step-by-step explanation:

[tex]\frac{1}{62} :\frac{28}{y}[/tex]

1 · y = 62 · 28

y = 1736

Answer:

Thirty rounded to the nearest whole number percent is 30% (%=percent)

Step-by-step explanation:

Well, you see that if you have 30 out of one hundred then that's when all you have to do is go with the same number and just add percent or % to the end.

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Hope this Helps

This is just evidence

Answer:

The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have that:

The mean number of penalties per game is [tex]\mu[/tex] and the standard deviation is [tex]\sigma[/tex].

Sample of n games:

This means that [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

What is the probability that, for a sample of college games to be played next week, the mean number of holding penalties will be X penalties per game or less?

The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.

Answer:

the volume of the solid is 1024/3 cubic unit

Step-by-step explanation:

Given the data in the question,

radius of the circular disk = 4

Now if the center is at ( 0,0 ), the equation of the circle will be;

x² + y² = 4²

x² + y² = 16

we solve for y

y² = 16 - x²

y = ±√( 16 - x² )

{ positive is for the top while the negative is for the bottom position }

A = b²

b = 2√( 16 - x² )           { parallel cross section }

A = [2√( 16 - x² )]²

A = 4( 16 - x² )

Now,

VOLUME = [tex]\int\limits^r -rA dx[/tex]

= [tex]\int\limits^4_4 {-4(16-x^2)} \, dx[/tex]

= 4[ 16x - (x³)/3 ]           { from -4 to 4 }

= 4[ ( 64 - 64/3 ) - (-64 = 64/3 0 ]

= 4[ 64 - 64/3 + 64 - 64/3 ]

= 4[ (192 - 64 + 192 - 64 ) / 3 ]

= 4[ 256 / 3 ]

= 1024/3 cubic unit

Therefore,  the volume of the solid is 1024/3 cubic unit

Answer:

10

Step-by-step explanation:

5

C

3

5!/(3!(5-3)!)

5!/(3!x2!)

120/12

10

In 10 ways can a supermarket manager display 5 brands of cereals

in 3 spaces on a shelf.

Combinations are mathematical operations that count the number of potential configurations for a set of elements when the order of the selection is irrelevant. You can choose the components of combos in any order. Permutations and combinations can be mixed up.

Given:

Total brands of cereals= 5

Using Combination, C(n, r)

= n!/ r! (n- r)!

So, the number of ways

= C(5, 3)

= 5!/(3!(5-3)!) 5

= 5 x 4 x 3! / 3! x 2!

= 5 x 4 /2

= 10

Thus, the total number of ways is 10.

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Answer:

This identity holds as long as [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex].

For the proof, make use of the fact that:

[tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] (definition of tangents,) and

[tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] (Pythagorean identity,) which is equivalent to [tex]1 - \cos^{2}(\theta) = \sin^{2}(\theta)[/tex].

Step-by-step explanation:

Assume that [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex]. This requirement ensures that the [tex]\tan(\theta)[/tex] on the left-hand side takes a finite value. Doing so also ensures that the denominator [tex]\sqrt{1 - \sin^2(\theta)}[/tex] on the right-hand side is non-zero.

Make use of the fact that [tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] to rewrite the left-hand side:

[tex]\begin{aligned} & \tan(\theta) \cdot \sin(\theta) \\ =&\; \frac{\sin({\theta})}{\cos({\theta})} \cdot \sin(\theta) \\ =&\; \frac{\sin^{2}(\theta)}{\cos(\theta)}\end{aligned}[/tex].

Apply the Pythagorean identity [tex]\sin^{2}(\theta) = 1 - \cos^{2}(\theta)[/tex] and [tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] to rewrite this fraction:

[tex]\begin{aligned} & \frac{\sin^{2}(\theta)}{\cos(\theta)}\\ =\; &\frac{1 - \cos^{2}(\theta)}{\cos(\theta)}\\ =\; & \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}\end{aligned}[/tex].

Hence, [tex]\displaystyle \tan(\theta) \cdot \sin(\theta) = \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}[/tex].

Answer:

(a) The mean is 0

(b) The median is -30

(c) The mode is unimodal

Step-by-step explanation:

Given

[tex]Data: 15,-4,-10,8,14,-10,-2,-11[/tex]

Solving (a): The mean.

This is calculated using:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x =\frac{15-4-10+8+14-10-2-11}{8}[/tex]

[tex]\bar x =\frac{0}{8}[/tex]

[tex]\bar x =0[/tex]

Solving (b): The median

First, arrange the data

[tex]Sorted: -11,-10, -10, -4, -2,8,14,15[/tex]

There are 4 elements in the dataset. So, the median is the mean of the 4th and 5th item.

[tex]Median = \frac{-4-2}{2}[/tex]

[tex]Median = \frac{-6}{2}[/tex]

[tex]Median = -3[/tex]

Solving (c): The mode

The item that has occurs most is -10.

Hence, the mode is -10. The dataset is unimodal because it has only 1 mode (-10).

Answer:

1/13

Step-by-step explanation:

there are total no of 52 cards

out of that there are 4 queen

propability = tatal no of favorable outcomes / total no of possible outcomes

=4 / 52

=1/13

Answer:

1/13

Step-by-step explanation:

Total cards = 52

Number of Queen = 4

Probability of the chosen card to be queen

                                                                   [tex]=\frac{Number \ of \ queen}{total \ number \ of \ cards}\\\\=\frac{4}{52} \\\\= \frac{1}{13}[/tex]

Answer:

The time-mean speed of the minivans is of 105.8 seconds.

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the number of values.

Five minivans, times of: 98.0, 108.0, 113.0, 108.0, 102.0, in seconds.

Thus, the mean is:

[tex]M = \frac{98 + 108 + 113 + 108 + 102}{5} = 105.8[/tex]

The time-mean speed of the minivans is of 105.8 seconds.

Answer:

C) f(x) = 1500(2.15)x

Step-by-step explanation:

Got it right on Edge :)

Answer:

to put the equation into standard for we must multiply the terms on the right side of the equation. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

Step-by-step explanation:

y

=

(

x

−

13

)

(

x

−

12

)

becomes:

y

=

(

x

×

x

)

−

(

x

×

12

)

−

(

13

×

x

)

+

(

13

×

12

)

y

=

x

2

−

12

x

−

13

x

+

156

We can now combine like terms:

y

=

x

2

+

(

−

12

−

13

)

x

+

156

y

=

x

2

+

(

−

25

)

x

+

156

y

=

x

2

−

25

x

+

156

Answer:

[tex]x\approx 5.48[/tex]

Step-by-step explanation:

Draw a line from the center of the circle O to the end of either side of the line marked as 4. This line represents two things:

In this case, both are important. Since [tex]x[/tex] is also a radius of the circle, the line must be equal to [tex]x[/tex], since all radii of a circle are equal. To find the length of this line, use the Pythagorean Theorem:

[tex]a^2+b^2=c^2[/tex], where [tex]c[/tex] is the hypotenuse of the triangle and [tex]a[/tex] and [tex]b[/tex] are the two legs of the triangle.

Since we're solving for the hypotenuse and the two legs are 5.1 and 2, we have:

[tex]5.1^2+2^2=c^2,\\26.01+4=c^2,\\c^2=30.01,\\c=5.47813836992\approx \boxed{5.48}[/tex] (round as necessary).

Answer:

The answer is C

Step-by-step explanation:

3    :    4

^          ^

II          II

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