Find the center and radius of x^2 + y^2 +6x - 7=0

Answers

Answer 1

Answer:

The center (-3, 0)

Answer 2

9514 1404 393

Answer:

center: (-3, 0)radius: 4

Step-by-step explanation:

The desired parameters can be found by putting the equation into the standard form for the equation of a circle:

  (x -h)^2 +(y -k)^2 = r^2 . . . . . circle centered at (h, k) with radius r

The values of h and k will be half the coefficients of the linear x- and y-terms, respectively.

  x^2 +6x +9 +y^2 -7 = 9 . . . . . add 9 to complete the square

  (x +3)^2 +y^2 = 16 . . . . . . . . . add 7 to get the desired form

This equation shows us (h, k) = (-3, 0) and r = 4.

The center is (-3, 0), and the radius is 4.

Find The Center And Radius Of X^2 + Y^2 +6x - 7=0

Related Questions

33. Given the following algebraic expression 5x² + 10 Which statement is true?
a. The coefficient is 5
b. The constant is 2
C. The power is 10
d. The constant is 5

Answers

Answer:

Given the following algebraic expression 5x² + 10 Which statement is true?

a. The coefficient is 5. ( true)

b. The constant is 2

C. The power is 10

d. The constant is 5

the answer is A
hope this helps

Help me out plsssssss

Answers

120 the answer is 120

Answer:

125

Step-by-step explanation:

the bearing of b to a is equal to 85+45

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